I want to create a chart that will represent the performance of some stores.
The x axis will represent the total revenue of the store over the average revenue of all the stores.
And the y axis will represent the average frequency the customers of a specific store visit this store over the average frequency all the customers visit all the stores.
This is what I have tried :
select
distinct [Order].shop_id
, SUM(total) /((select AVG(o.shopTotal)
from
(
select
distinct shop_id , SUM(total) as shopTotal
from [Order]
group by shop_id
)o)*0.1) as revPerAvgRev
,COUNT(distinct orderno) /((select AVG(orders)
from
(
select
distinct shop_id , room, COUNT(distinct orderno) as orders
from [Order]
group by shop_id , room
)o)*0.1) as freqPerAvgFreq
from [Order]
group by [order].shop_id
order by revPerAvgRev desc
select distinct shop_id ,room , count(distinct orderno)
from [Order]
group by shop_id , room
I believe the average frequency that the customers visit the stores is ok.
But I cannot manage to calculate correclty the average frequency each customer visit the store.
Note: Each customer only visits one store.
It is a little difficult to follow exactly what you want. You ask for frequencies but the code sample is showing revenue. You can get the proportion of revenue by using a window function to calculate the total:
select shop_id, shopTotal,
cast(shopTotal as float)/ sum(shopTotal) over () as Revenue,ProportionOfTotal,
numvisits,
cast(numvisits as float) / sum(numvisits) over () as VisitsProportionOfTotal
from (select shop_id , SUM(total) as shopTotal, count(*) as numvisits
from [Order]
group by shop_id
) s
Related
I want to sum up sales across agents, orders and the date. The following code runs, however, I just receive a duplicate of the total column instead of the sum. Any advice?
CODE:
(Select DISTINCT DATE, CUSTOMER, ORDERNR,
AREA, AGENT, Total, SUM(Total) AS TOTALSUM From data01 WHERE REPORT_DT between '2018-02-24' and '2018-02-25' GROUP BY DATE, CUSTOMER, ORDERNR,
AREA, AGENT, Total, ORDER BY AGENT)
Just a suggestion for clean your code that contain some error
You don't need distinct whe use GROUP BY and you have a wrong comma after the word Total in group by
(Select
DATE
, CUSTOMER
, ORDERNR
, AREA
, AGENT
, Total
, SUM(Total) AS TOTALSUM
From data01
WHERE REPORT_DT between '2018-02-24' and '2018-02-25'
GROUP BY DATE
, CUSTOMER
, ORDERNR
, AREA
, AGENT
, Total
ORDER BY AGENT)
Remove Total from the GROUP BY:
Select DATE, CUSTOMER, ORDERNR, AREA, AGENT, SUM(Total) AS TOTALSUM
From data01
where REPORT_DT between '2018-02-24' and '2018-02-25'
group by DATE, CUSTOMER, ORDERNR, AREA, AGENT;
I'm trying to sum a certain column over a certain date range. The kicker is that I want this to be a CTE, because I'll have to use it multiple times as part of a larger query. Since it's a CTE, it has to have the date column as well as the sum and ID columns, meaning I have to group by date AND ID. That will cause my results to be grouped by ID and date, giving me not a single sum over the date range, but a bunch of sums, one for each day.
To make it simple, say we have:
create table orders (
id int primary key,
itemID int foreign key references items.id,
datePlaced datetime,
salesRep int foreign key references salesReps.id,
price int,
amountShipped int);
Now, we want to get the total money a given sales rep made during a fiscal year, broken down by item. That is, ignoring the fiscal year bit:
select itemName, sum(price) as totalSales, sum(totalShipped) as totalShipped
from orders
join items on items.id = orders.itemID
where orders.salesRep = '1234'
group by itemName
Simple enough. But when you add anything else, even the price, the query spits out way more rows than you wanted.
select itemName, price, sum(price) as totalSales, sum(totalShipped) as totalShipped
from orders
join items on items.id = orders.itemID
where orders.salesRep = '1234'
group by itemName, price
Now, each group is (name, price) instead of just (name). This is kind of sudocode, but in my database, just this change causes my result set to jump from 13 to 32 rows. Add to that the date range, and you really have a problem:
select itemName, price, sum(price) as totalSales, sum(totalShipped) as totalShipped
from orders
join items on items.id = orders.itemID
where orders.salesRep = '1234'
and orderDate between 150101 and 151231
group by itemName, price
This is identical to the last example. The trouble is making it a CTE:
with totals as (
select itemName, price, sum(price) as totalSales, sum(totalShipped) as totalShipped, orderDate as startDate, orderDate as endDate
from orders
join items on items.id = orders.itemID
where orders.salesRep = '1234'
and orderDate between startDate and endDate
group by itemName, price, startDate, endDate
)
select totals_2015.itemName as itemName_2015, totals_2015.price as price_2015, ...
totals_2016.itemName as itemName_2016, ...
from (
select * from totals
where startDate = 150101 and endDate = 151231
) totals_2015
join (
select *
from totals
where startDate = 160101 and endDate = 160412
) totals_2016
on totals_2015.itemName = totals_2016.itemName
Now the grouping in the CTE is way off, more than adding the price made it. I've thought about breaking the price query into its own subquery inside the CTE, but I can't escape needing to group by the dates in order to get the date range. Can anyone see a way around this? I hope I've made things clear enough. This is running against an IBM iSeries machine. Thank you!
Depending on what you are looking for, this might be a better approach:
select 'by sales rep' breakdown
, salesRep
, '' year
, sum(price * amountShipped) amount
from etc
group by salesRep
union
select 'by sales rep and year' breakdown
, salesRep
, convert(char(4),orderDate, 120) year
, sum(price * amountShipped) amount
from etc
group by salesRep, convert(char(4),orderDate, 120)
etc
When possible group by the id columns or foreign keys because the columns are indexed already you'll get faster results. This applies to any database.
with cte as (
select id,rep, sum(sales) sls, count(distinct itemid) did, count(*) cnt from sommewhere
where date between x and y
group by id,rep
) select * from cte order by rep
or more fancy
with cte as (
select id,rep, sum(sales) sls, count(distinct itemid) did, count(*) cnt from sommewhere
where date between x and y
group by id,rep
) select * from cte join reps on cte.rep = reps.rep order by sls desc
I eventually found a solution, and it doesn't need a CTE at all. I wanted the CTE to avoid code duplication, but this works almost as well. Here's a thread explaining summing conditionally that does exactly what I was looking for.
Summary of revenues by region (in ranked order from highest to lowest, calculate % of total for each region). Basically, I am trying to write a query that will show the revenues of each region relative to the total revenue.
I am using SQL in Microsoft Access.
My table has the following columns: ID, Region, Revenue
There are 3 regions: West, Central, East
Heres what I have so far:
SELECT Region, Sum(Revenue) AS TotalRevenue
FROM Sales
GROUP BY Region
ORDER BY Sum(Revenue) DESC
Any help would be greatly appreciated
Try this:
SELECT Region, SUM(Revenue) AS TotalRevenue,
(SUM(Revenue)/(SELECT Sum(Revenue) FROM Sales)) AS percentage
FROM Sales
GROUP BY Region
ORDER BY Sum(Revenue) DESC
This is one way that I'd offer, for only three regions its really overkill, but it should work.
SELECT Region, Sum(Revenue) AS TotalRevenue, Sum(Revenue)/x.allRegionRevenue
FROM Sales s,
inner join (select sum(revenue) allRegionRevenue)) x
on s.revenue*0 = x.allRegionRevenue*0
GROUP BY Region
ORDER BY Sum(Revenue) DESC
*Edit: * Modified this a bit as Access doesn't support actual "cross join" syntax, but I think we can "fake" it with an inner join on a condition that's always true - klugey trick here is merely to multiply references from each to zero forcing all recs to match. Hope this helps.
How do I obtain the highest value for each year within a table. So let's say we have a table movies and I want to find the highest profiting film for each year.
This is my attempt so far:
SELECT year, MAX(income - cost) AS profit, title
FROM Movies m, Movies m2
GROUP BY year
I am pretty certain it is going to need some sub selects but I can't visualise what I need to do. I was also thinking probably some sort of distinct option to rule out duplicate years.
Title Year Income Cost Length
A 2000 10 2 2
B 2000 9 7 2
So from this the expected result would be
Title Year Profit
A 2000 8
I'm guessing slightly at what you want, but since you've not specified any RDBMS a generic solution would be:
SELECT m.Year, (m.Income - m.Cost) AS Profit, m.Title
FROM Movies m
INNER JOIN
( SELECT m.Year, MAX(m.Income - m.Cost) AS Profit
FROM Movies
GROUP BY m.Year
) MaxProfit
ON MaxProfit.Year = m.Year
AND MaxProfit.Profit = (m.Income - m.Cost)
ORDER BY m.Year
You can also do this using analytic functions if your DBMS permits. e.g. SQL-Server
WITH MovieCTE AS
( SELECT m.Year,
Profit = (m.Income - m.Cost),
m.Title,
RowNumber = ROW_NUMBER() OVER(PARTITION BY m.Year ORDER BY (m.Income - m.Cost) DESC)
FROM Movies
)
SELECT year, Profit, Title
FROM MovieCTE
WHERE RowNumber = 1
It is possible I have misunderstood your exact criteria, but I am sure the same priciples can be applied, you will just need to alter the grouping and the join in the first example, or the partition by in the second.
select m1year,m1profit,title
from
(
(select year as m1year, max(income- cost) as m1profit from movies group by year) m1
join
(select m2year, (income-cost) as m2profit ,title as profit from movies) m2
on
m1profit = m2profit
) m
This will give the highest profit movie for each year, and choose the first title in the event of a tie:
select a.year, a.profit,
(select min(title) from Movies where year = a.year and income - cost = a.profit) as title
from (
select year, max(income - cost) as profit
from Movies -- title, year, cost, income, number
group by year
) as a
order by year desc
I have a table with purchased orders data.
Each row contails the amount of certain item purchased, cost per item and the order number group. Each different item purchased is a new row with same order number.
I basically want to return the total cost for that order. I have tried the following but am getting nowhere:
SELECT order_number, SUM( sub_total ) AS `total`
FROM
SELECT order_number, SUM( SUM( amount ) * SUM( cost_per_item ) ) AS `sub_total`
FROM `ecom_orders`
WHERE member_id = '4'
GROUP BY order_number
ORDER BY purchase_date DESC
Pretty much any SQL-92 compliant RDBMS will take this:
SELECT
order_number
,SUM(amount * cost_per_item) AS total
,purchase_date
FROM
ecom_orders
WHERE member_id = '4'
GROUP BY order_number,purchase_date
ORDER BY purchase_date DESC