I have a table for "branches", "orders" and "products. Each order and product are connected to a branch with branch_id. I need an sql statement to get a list of all branches with a field for how many orders and a field for how many products.
This works:
SELECT b.*, COUNT(o.id) AS orderCount FROM branches b
LEFT JOIN orders o ON (o.branch_id = b.id) GROUP BY b.id
but it only gets the amount of orders, not products.
If I change it to add amount of products, the amounts are wrong because it's getting amount of orders * amount of products.
How can I get the amount of both the orders and the products in the same SQL statement?
Something like this should work (on sql server at least - you didn't specify your engine).
SELECT
b.id
,COUNT(distinct o.id) AS orderCount
,COUNT(distinct p.id) AS productCount
FROM branches b
LEFT JOIN orders o
ON (o.branch_id = b.id)
left join products p
on p.product_id=b.id)
GROUP BY
b.id
Please try:
select
*,
(select COUNT(*) from Orders o where o.branch_id=b.id) OrderCount,
(select COUNT(*) from Products p where o.branch_id=p.id) ProductCount
From
branches b
Related
I have the following tables:
Orders (OID, Count, ProductID, TableNr)
Table (TableNr, Name, Number)
Products (ProductID, Prize)
Now I want to calculate how much was earned per table. I think to do this I have to Group By Orders.TableNr. But how can I multiply the Products.Prize with the Orders.Count and after that sum up this results within the group?
You are describing a join and aggregation:
select o.tableNr, sum(o.count * p.prize) totalEarned
from orders o
inner join products p on p.productId = o.productId
group by o.tableNr
If you want to display table information as well (say, the table name), then you can add another join:
select t.tableNr, t.name, sum(o.count * p.prize) totalEarned
from table t
inner join orders o on o.tableNr = t.tableNr
inner join products p on p.productId = o.productId
group by t.tableNr, t.name
Note that table is a SQL keyword, hence not a good choice for a table name.
Problem:
Find the net balance of the total order amount and total payments for each customer.
There are 4 tables involved: OrderDetails, Orders, Payments and Customer.
The total amount order = quantity order * price each [in OrderDetails]
The total payment = sum of different payments for the same order.
Customers are linked to Payments and Orders with CustomerNumber. Orders are linked to OrderDetails with OrderNumber.
I tried joining the 4 tables with the INNER JOIN function.
SELECT
c.customername,
SUM(od.quantityordered * od.priceeach) - SUM(p.amount) AS Net_Balance
FROM
(
(
orderdetails od
INNER JOIN orders o ON od.ordernumber = o.ordernumber
)
INNER JOIN customers c ON o.customernumber = c.customernumber
)
INNER JOIN payments p ON c.customernumber = p.customernumber
GROUP BY c.customername;
The expected results should be 0 for almost every customers.
However, what I have got is the total amount order and total payment are multiplied by some constants. Specifically, the total payment shown is multiplied by the number of payments for each order.
Anybody have any ideas to save my life?
This is a typical issue when dealing with N-M relationships. To solve it, one solution is to move the aggregation to subqueries:
SELECT c.customername, o.amt - p.amt AS Net_Balance
FROM customers c
INNER JOIN (
SELECT ord.customernumber, SUM(det.quantityordered * det.priceeach) as amt
FROM orders ord
INNER JOIN orderdetails det ON ord.ordernumber = det.ordernumber
GROUP BY ord.customernumber
) o ON o.customernumber = c.customernumber
INNER JOIN (
SELECT customernumber, SUM(amount) as amt
FROM payments
GROUP BY customernumber
) p ON p.customernumber = c.customernumber
SELECT c.customername, SUM(od.quantityordered*od.priceeach) as ordersum , SUM(p.amount) as paymentsum'
What's the result of the two columns ?
Is it what you want?
I need to find the amount of times a customer appears in the Orders and Requests tables respectively. However this script is producing the same count value for both places where COUNT is used. The value cannot possibly be the same so what am I doing wrong?
SELECT o.CustomerID,
COUNT(o.CustomerID) as OrdersPerCustomer,
COUNT(r.CustomerID) as RequestsPerCustomer
FROM Orders o
INNER JOIN [Customers] c on c.ID = o.CustomerID
INNER JOIN [Request] r on r.CustomerID = c.ID
GROUP BY o.CustomerID
You are multiplying the number of order and request records. I.e. by joining the tables, you get for, say, 3 orders and 4 requests for a customer 12 result rows. As the IDs will never be null in a record, COUNT(o.CustomerID) and COUNT(r.CustomerID) are just COUNT(*) (12 in my example, and not 3 and 4 as you expected).
The easiest approach:
select
customer_id,
(select count(*) from orders o where o.customerid = c.id) as o_count,
(select count(*) from request r where r.customerid = c.id) as r_count
from customers c;
The same with subqueries (derived tables) in the from clause:
select
customer_id,
coalesce(o.total, 0) as o_count,
coalesce(r.total, 0) as r_count
from customers c
left join (select customerid, count(*) as total from orders group by customerid) o
on o.customerid = c.id
left join (select customerid, count(*) as total from request group by customerid) r
on r.customerid = c.id;
When aggregating from multiple tables, always aggregate first and join then.
I am using three tables in a PostgreSql database as:
Customer(Id, Name, City),
Product(Id, Name, Price),
Orders(Customer_Id, Product_Id, Date)
and I want to execute a query to get from them "the customers that have have ordered at least two different products alnong with the products". The query I write is:
select c.*, p.*
from customer c
join orders o on o.customer_id = c.id
join product p on p.id = o.product_id
group by (c.id)
having count(distinct o.product_id)>=2
It throws the error:
"column "p.id" must appear in the GROUP BY clause or be used in an aggregate function
LINE 1: select c.*, p.*".
However if I remove the the p.* from select statement (assuming that I one does not want the products, only the customers), it runs fine. How can I get the products as well?
Update: Having ordered two or more products, a customer must appear on the output as many times as its product he has ordered. I want as output a table with 5 columns:
Cust ID | Cust Name | Cust City | Prod ID | Prod Name | Prod Price
Is it possible in SQL given that group by should be used? Shoul it be used on more than one columns on different tables?
Try this out :
SELECT distinct c.* ,p.*
FROM Customer c
JOIN
(SELECT o.customer_id cid
FROM Product P
JOIN Orders o
ON p.id= o.product_id
GROUP BY o.customer_id
HAVING COUNT(distinct o.product_id)>=2) cp
ON c.id =cp.cid
JOIN Orders o
on c.id=o.customer_id
JOIN Product p
ON o.product_id =p.id
I hope it solves your problem.
I think you can use following query for this question -
SELECT C1.*, p1.*
FROM Customer C1
JOIN Orders O1 ON O1.Customer_Id = C1.Id
JOIN Product P1 ON P1.Id = O1.Product_Id
WHERE C1.Id IN (SELECT c.Id
FROM Customer c
JOIN Orders o ON o.Customer_Id = c.Id
GROUP BY (c.Id)
HAVING COUNT(DISTINCT o.Product_Id) >= 2)
I have two Tables
Product Details(About Product)
Sale Order Details(What Price is sold, quantity of products sold per order).
I am trying to do Join on Table 1 and Table 2 which should give the all the product details and sum(Quantity), Sum(Price)
Problem Facing: There are some products in Table 1 which are never sold, and those rows are missing in the result set, but I want details for all the rows in Table 1 with rows of Products never purchased should be NULL or 'o'
Query I am Using:
select
P.*,
ISNULL((sum([Q.Quantity])),0),
ISNULL((sum([Q.Price])),0)
From Table1 P
Left Outer Join Table2 Q on P.Product_ID = Q.Product_ID
Please help me with any suggestions that would work for me
How about this one:
select
P.Product_ID,
ISNULL(sum([Q.Quantity]),0),
ISNULL(sum([Q.Price]),0)
From Table1 P
Left Outer Join Table2 Q
on P.Product_ID = Q.Product_ID
group by
P.Product_Id