I need to add correct stress accents to every word in a Microsoft Word document. I have a script called "DoAccentuate" which determines the correct accentuation for any word that is input. However, I don't know how to capture the currently selected found word, process it with my DoAccentuate script, and replace that same word with the result (without effecting the formatting of the text). This is what I tried.
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim document As Word.Document
document = Globals.ThisAddIn.Application.ActiveDocument
Dim FindObject As Word.Find = document.Application.Selection.Find
With FindObject
.ClearFormatting()
.Text = "<*>"
.MatchWildcards = True
.Replacement.ClearFormatting()
.Replacement.Text = DoAccentuate(document.Application.Selection.Text)
.Execute(Replace:=Microsoft.Office.Interop.Word.WdReplace.wdReplaceAll)
End With
End Sub
Lets pretend for now this is your DoAccentuate script:
Private Function DoAccentuate(theWordToAccentuate As String)
theWordToAccentuate = theWordToAccentuate + "`"
DoAccentuate = theWordToAccentuate
End Function
Given this, the find/replace can be as simple as:
Public Sub FindWordAndReplaceWithAccentuatedForm()
Dim accentuatedText As String: accentuatedText = DoAccentuate(Selection.text)
Selection.Find.text = Selection.text
Selection.Find.Replacement.text = DoAccentuate(Selection.text)
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
This should not remove any formatting.
I am assuming that you desire a solution which requires user to select the word they want to accentuate, and then run the macro (since your method above assumes this ie: .Replacement.Text = DoAccentuate(document.Application.Selection.Text
Related
I would like to find/replace all inserted check box symbols with checkbox content controls. The symbol's font is Wingdings (either 111 or 168). Below is the code I started with, but I hit a wall when I realized that Word find doesn't recognize the symbol. I appreciate any help or guidance. Thank you.
Sub ReplaceUnicode168()
Dim objContentControl As ContentControl
With ActiveDocument
Set objContentControl = ActiveDocument.ContentControls.Add(wdContentControlCheckBox)
objContentControl.Cut
With Selection.Find
.ClearFormatting
.Replacement.ClearFormatting
.Forward = True
.Wrap = wdFindContinue
.MatchCase = False
.MatchWholeWord = True
.MatchWildcards = False
.Text = Chr(168)
.Replacement.Text = "^c"
.Execute Replace:=wdReplaceAll
End With
End With
End Sub
I suggest that you try to find/replace these two particular characters using
.Text = ChrW(61551)
for the "111" WingDings Character and
.Text = ChrW(61608)
for the "168" WingDings character.
Be aware that the way Word encodes these characters is not very helpful. As far as Find/Replace is concerned, you have to use these Unicode Private Use Area encodings.
If you actually select the character and use VBA to discover its code using e.g.
Debug.Print AscW(Selection)
the answer is always 40 (and the Font of the character will probably be the same as the Surrounding font) Pretty useless. In older versions of Word you used to be able to look for the 40 character and find these characters, but I don't think that's possible now. But if you select the character and use
Sub SymInfo()
With Dialogs(wdDialogInsertSymbol)
' You won't see .Font and .CharNum listed under the
' properties of a Word.Dialog - some older Dialogs add
' per-Dialog properties at runtime.
Debug.Print .Font
Debug.Print .CharNum
End With
End Sub
Then you get the font name (Wingdings in this case) and the private use area character number, except it's expressed as a negative number (-3928 for Wingdings 168). The character to use in the Find/Replace is 65536-3928 = 61608.
Alternatively, you can find the private use area code by selecting the character, getting its WordOpenXML code, then finding the XML element that gives the code (and the font). Ideally use MSXML to look for the element but the following gives the general idea.
Sub getSymElement
Dim finish As Long
Dim start As Long
Dim x As String
x = Selection.WordOpenXML
start = Instr(1,x,"<w:sym")
' Should check for start = 0 (not found) here.
finish = Instr(start,x,">")
Debug.Print Mid(x,start, finish + 1 - start)
and for the 168 character you should see something like
<w:sym w:font="Wingdings" w:char="F0A8"/>
(Hex F0A8 is 61608)
There may be a problem where Word could potentially map more than one font/code to the same unicode private use area codepoint. There is some further code by Dave Rado here but I do not think you will need it for this particular problem.
After some follow-up, the following seems to work reasonably well here:
Sub replaceWingdingsWithCCs()
Dim cc As Word.ContentControl
Dim charcode As Variant
Dim ccchecked As Variant
Dim i As Integer
Dim r As Word.Range
' Make sure the selection point is not in the way
' (If the selection contains one of the characters you are trying to
' replace, Word will raise an error about the selection being in a
' plain text content control.
' If the first item in the document is not a CC,
' it's enouugh to do this:
ActiveDocument.Select
Selection.Collapse WdCollapseDirection.wdCollapseStart
' Put the character codes you need to look for here. Maybe you have some checked boxes too?
charcode = Array(61551, 61608)
' FOr each code, say whether you want a checked box (True) or an unchecked one.
ccchecked = Array(False, False)
For i = LBound(charcode) To UBound(charcode)
Set r = ActiveDocument.Range
With r.Find
.ClearFormatting
With .Replacement
.ClearFormatting
.Text = ""
End With
.Forward = True
.Wrap = wdFindStop
.MatchCase = False
.MatchWholeWord = True
.MatchWildcards = False
.Text = ChrW(charcode(i))
Do While .Execute(Replace:=True)
Set cc = r.ContentControls.Add(WdContentControlType.wdContentControlCheckBox)
cc.Checked = ccchecked(i)
r.End = r.Document.Range.End
r.Start = cc.Range.End + 1
Set cc = Nothing
Loop
End With
Next
Set r = Nothing
End Sub
I have a userform with a bunch of checkboxes. I want the VBA code to add a block of text (defined as a variable) if the checkbox is true and remove that block of text if it gets unchecked. As an example, this is what I have for one of the checkboxes:
Private Sub CheckBox1_Click()
Dim Text1 As String
Text1 = "Text test"
If CheckBox1.Value = True Then
Selection.TypeText Text:=Text1
Selection.InsertParagraph
End If
If CheckBox1.Value = False Then
Selection.Delete Text:=Text1
End If
End Sub
First of all, the Selection.Delete Text:=Text1 part is completely wrong. I've tried to google something similar and have been unable to find anything that deletes the content of a variable.
Second of all, there seems to be an error with the Selection.InsertParagraph code. I want it to add a new paragraph between each block of text/variable, however with the way that the code is now, it adds the text block and the paragraphs separately like this if I were to activate the macro 3 times:
Text testText testText test
(new paragraph)
(new paragraph)
(new paragraph)
What I want instead is this:
Text test
(new paragraph)
Text test
(new paragraph)
Text test
(new paragraph)
Answering the first question, for which there is sufficient information to provide an answer...
The best control of where something is inserted and foramtted in a Word document is to use Range objects. There can be only one Selection, but code can work with multiple Ranges.
For inserting a new paragraph immediately following text it's possible to append the new paragraph at the end of the text using the ANSI 13 character, which can be represented in VBA code using vbCr.
Example:
Private Sub CheckBox1_Click()
Dim Text1 As String
Dim rngTarget as Range
Text1 = "Text test"
Set rngTarget = Selection.Range
If CheckBox1.Value = True Then
rngTarget.Text = Text1 & vbCr
End If
'
'If CheckBox1.Value = False Then
' Selection.Delete Text:=Text1
'End If
'''Move to the end of the range and select that for the next iteration
rngTarget.Collapse wdCollapseEnd
rngTarget.Select
End Sub
I am attempting to create a macro in Word that alters the style of a set of ~150 unique headings. All styles must be identical. My current code works and changes the formatting correctly, but only one heading at a time.
Simply put, it's ugly.
I'm looking for something I can reuse, and possibly apply to more projects in the future.
Maybe using the loop command? I don't know, I'm still somewhat new using VBA.
Sub QOS_Headings()
Dim objDoc As Document
Dim head1 As Style, head2 As Style, head3 As Style, head4 As Style
Set objDoc = ActiveDocument
Set head1 = ActiveDocument.Styles("Heading 1")
Set head2 = ActiveDocument.Styles("Heading 2")
With objDoc.Content.Find
.ClearFormatting
.Text = "Section A.^p"
With .Replacement
.ClearFormatting
.Style = head1
End With
.Execute Wrap:=wdFindContinue, Format:=True, Replace:=wdReplaceOne
End With
End With
End Sub
If there is no way in which you can identify the heads you want automatically you may have to write everything once. Create a separate function for this purpose. It might look like this:-
Private Function SearchCriteria() As String()
Dim Fun(6) As String ' Fun = Designated Function return value
' The number of elements in the Dim statement must be equal to
' the number of elements actually declared:
' observe that the actual number of elements is one greater
' than the index because the latter starts at 0
Fun(0) = "Text 1"
Fun(1) = "Text 2"
Fun(2) = "Text 3"
Fun(3) = "Text 4"
Fun(4) = "Text 5"
Fun(5) = "Text 6"
Fun(6) = "Text 7"
SearchCriteria = Fun
End Function
You can add as many elements as you wish. In theory it is enough if they are unique within the document. I shall add some practical concerns below. Use the code below to test the above function.
Private Sub TestSearchCriteria()
Dim Crits() As String
Dim i As Long
Crits = SearchCriteria
For i = 0 To UBound(Crits)
' prints to the Immediate Window:
' select from View tab or press Ctl+G
Debug.Print Crits(i)
Next i
End Sub
Now you are ready to try to actually work on your document. Here is the code. It will not effect any changes. It's just the infrastructure for testing and getting ready.
Sub ChangeTextFormat()
Dim Crits() As String
Dim Rng As Range
Dim Fnd As Boolean
Dim i As Long
Crits = SearchCriteria
For i = 0 To UBound(Crits)
' find the Text in the document
Set Rng = ActiveDocument.Content
With Rng.Find
.ClearFormatting
.Execute FindText:=Crits(i), Forward:=True, _
Format:=False, Wrap:=wdFindStop
Fnd = .Found
End With
If Fnd = True Then
With Rng
Debug.Print .Text
' .MoveStart wdWord, -2
' With .Font
' .Italic = True
' .Bold = True
' End With
End With
Else
Debug.Print "Didn't find " & Crits(i)
End If
Next i
End Sub
The first half of the procedure will find each of the search criteria in your document using the same kind of loop as you already know from the test procedure. But now the text is fed to the Find method which assigns the found text to the Rng range. If the item is found you now have a handle on it by the name of Rng.
The second half of the sub deals with the outcome of the search. If the text was found the found text (that is Rng.Text) is printed to the Immediate window, otherwise the original text Crits(i) with "didn't find".
If the text was found you want to assign a style to it. But before you can do so you should deal with the difference between the text you found and the text you want to format. This difference could be physical, like you didn't write the entire length of the text in the criteria, or technical, like excluding paragraph marks. In my above sub there is just random code (extending the Rng by two preceding words and formatting everything as bold italics). Consider this code a placeholder.
For your purposes code like this might do the job, perhaps. .Paragraphs(1).Style = Head1 Actually, that is rather a different question, and I urge you not to rush for this result too fast. The part you now have needs thorough testing first.
I am executing a style search in Microsoft Word using a VBA Macro.
My goal is to perform certain actions once for every style found in the document.
The macro works correctly on documents that have at least two paragraphs, but the macro does not alert the style correctly in a document that has exactly one paragraph in it. It seems strange that when I enter a new paragraph mark, the styles are found, even though I did not add any new text or styles to the document, just an extra blank paragraph mark. Does anyone know what is wrong with my macro and how I can fix this? Thanks for taking a look.
Sub AlertAllStylesInDoc()
Dim Ind As Integer
Dim numberOfDocumentStyles As Integer
Dim styl As String
Dim StyleFound As Boolean
numberOfDocumentStyles = ActiveDocument.styles.count
For Ind = 1 To numberOfDocumentStyles
styl = ActiveDocument.styles(Ind).NameLocal
With ActiveDocument.Content.Find
.ClearFormatting
.text = ""
.Forward = True
.Format = True
.Style = styl
Do
StyleFound = .Execute
If StyleFound = True Then
' actual code does more than alert, but keeping it simple here'
MsgBox styl
GoTo NextStyle
Else
Exit Do
End If
Loop
End With
NextStyle:
Next
End Sub
I don't understand why ActiveDocument.Content is not working, but replacing it with ActiveDocument.Range(0,0) appears to resolve the issue (tested in Word 2016).
With ActiveDocument.Range(0, 0).Find
This is my first time attempting VBA in Word although I've used it quite a bit in Excel. What I am trying to do is automatically execute my code after opening my Word template document. Here is the code I've placed in my Word template Module:
Private Sub AutoOpen()
Dim myValue
myValue = InputBox(prompt:="What is the client name", Title:="InputBox", Default:="Type your client name here")
stringReplaced = stringReplaced + "<Replace>"
For Each myStoryRange In ActiveDocument.StoryRanges
With myStoryRange.Find
.Text = "<Replace>"
.Replacement.Text = myValue
.Wrap = wdFindContinue
.ClearFormatting
.Replacement.ClearFormatting
.Replacement.Highlight = False
.Execute Replace:=wdReplaceAll
End With
Next myStoryRange
End Sub
I am using Word 2010. My code runs like I want it to when I manually go in and click run. However, when I close out of my Word document and reopen nothing happens at all. I've Googled the problem trying to find out a solution (and have attempt different versions of AutoOpen), but I can't figure out what I am doing wrong. Any ideas on why the AutoOpen doesn't execute automatically?
Thanks!
You should place your code in standard Module in your Template document. Next, change sub name from AutoOpen() into:
Sub AutoExec()
'..... your code here .....
End Sub