I have 3 table like below
table_1
securityno name price
1 a11 12.12
2 z11 44.4
table_2
name identifier Mainprice
a11_bond NO34 11
z22_bond NO98 22
table_3
securityno name identifier
1 a11 NO34
2 z11 NO98
I want to check whether table_1 is having correct price or not as per table_2
I just want to display output table_1 data and Mainprice column from table_2
securityno name price Mainprice
1 a11 12.12 11
2 z11 44.4 22
I was trying like
select * from table_1 left join table_2 on what about table_3?
failed to use 3 tables .
please help.
Try:
SELECT
t1.*,
t2.Mainprice
FROM table_1 AS t1
LEFT JOIN table_3 AS t3
ON t1.securityno = t3.securityno AND t1.name = t3.name
INNER JOIN table_2 AS t2
ON t2.identifier = t3.identifier
Simple use INNER JOIN
SELECT T1.*,
T2.mainprice
FROM TABLE1 T1
INNER JOIN Table3 T3 ON T3.securityno = T1.securityno
INNER JOIN Table2 T2 ON T2.identifier = T3.identifier
DEMO
Related
I have 3 tables with names and number of few of my friends.
Table 3 has correct data, table 2 has minute errors in data and table 1 has more than table 2.
if a user exists in table 2 and 3 then show table 3 details in output else table 2 details, if user is not even there in table 2 then show user data from table1.
more like a preference order.
DUMMY DATA:
table 1 :
name phone
abc 2343
bcd 3434
ccd 3455
ffc 4545
table 2 :
name phone
abc 2313
bcd 3414
ccd 3415
table 3 :
name phone
abc 2344
bcd 3431
expected output :
name phone
abc 2344
bcd 3431
ccd 3415
ffc 4545
I tried this query but unable to find correct output.
select phone,
coalesce(table1.name, TABLE2.name,TABLE3.name) as namee
FROM TABLE1
left JOIN TABLE2
ON table1.name = table2.name
INNER JOIN table3
ON table3.name = table2.name
Would be a huge, huge heeelppppp.
Gordon was close; he had the preference backwards. Please make sure you understand why the script works.
-- grab all our preferred data first
select t3.*
from table3 t3
union all
-- grab anything that doesn't exist in our preferred table
select t2.*
from table2 t2
where not exists (select 1 from table3 t3 where t3.name = t2.name)
union all
-- grab anything that doesn't exist in our preferred tables
select t1.*
from table1 t1
where not exists (select 1 from table2 t2 where t2.name = t1.name) and
not exists (select 1 from table3 t3 where t3.name = t1.name);
Use union all:
select t1.*
from table1 t1
union all
select t2.*
from table2 t2
where not exists (select 1 from table1 t1 where t1.name = t2.name)
union all
select t3.*
from table3 t3
where not exists (select 1 from table1 t1 where t1.name = t3.name) and
not exists (select 1 from table2 t2 where t2.name = t3.name);
Table1
ID SystemID Description
---------------------------
1 25 Test1
1 25 Test2
2 40 Test1
2 40 Test3
3 26 Test9
3 36 Test5
4 70 Test2
4 70 Test9
Table2
ID Department
------------------
1 Sales
2 Marketing
3 Accounting
4 Purchasing
I have these 2 tables, Table1 and Table2.
I need to select all the distinct ids from Table1 that have the same description as ID = 1 and SystemID = 25, and then select all the rows from Table2 from the query result.
Is there a better way to query for this, without using nested subqueries?
select *
from Table2
where ID in (select distinct(ID)
from Table1
where SystemID = 25
and Description in (select Description
from Table1
where ID = 1 and SystemID = 25))
Final output is
1 Sales
2 Marketing
4 Purchasing
Any help is appreciated. Thank you.
I think you want:
select t1.id, t2.department
from table1 t1 join
table2 t2
on t1.id = t2.id
where t1.description in (select tt1.description from table1 tt1 where tt1.id = 1 and tt1.systemid = 25);
This is standard SQL and should work in both SQL Server and Oracle.
You can also use a modification of an outer join to detect presence of a value.
SELECT DISTINCT t2.ID, t2.DEPARTMENT
FROM
table2 AS t2
INNER JOIN table1 AS t1a ON table2.ID = table1.ID
LEFT OUTER JOIN table1 AS t1b ON t1b.id = 1 AND t1b.systemID = 25 AND t1b.description = t1a.description
WHERE t1b.ID IS NOT NULL
AND t1a.systemID = 25
This will filter out all entries who don't have a description matching an entry with id 1 and systemID 25
I believe this should give you the same result. Instead of using an IN I used an EXISTS and then instead of a futher subquery you can then use a JOIN:
SELECT *
FROM Table2 T2
WHERE EXISTS (SELECT 1
FROM Table1 T1
JOIN Table1 T1t ON T1.[Description] = T1t.[Description]
WHERE T1.ID = T2.ID
AND T1t.ID = 1 AND T1t.SystemID = 25);
SELECT DISTINCT T2.* --Use a distinct for simplicity but a group by is better
FROM Table2 AS T2
INNER JOIN Table1 AS T1_Source ON T1_Source.SystemID = 25 AND T1_Source.ID = 1
/*^ Find table1 with System and ID
Expected Result
ID SystemID Description
1 25 Test1
1 25 Test2
Note Rows are duplicated use distinct or group by
*/
INNER JOIN Table1 AS T1_Target ON T1_Target.Description = T1_Source.Description
/*^ Find table1 with all the Description matching the result we found
Expected Result
ID SystemID Description
1 25 Test1
1 25 Test2
2 40 Test1
4 70 Test2
Note Rows are duplicated use distinct or group by
*/
I have the following tables where a few of the columns are included here:
Table 1:
Id RefId PhoneNumber
1 11 919191
2 11 888888
3 11 919191
Table 2:
Id RefId City UniqueId
1 11 Mumbai 111
2 11 Pune 222
3 11 Nashik 333
I want a few columns from Table1 and Table2. Common in both table is RefId. Table2 has UniqueId which is primary key of Table2. If I do an inner join based on RefId I will get 9 records, but I want 3. How do I get that?
Here is my query:
SELECT T1.PhoneNumber,T2.City,T2.UniqueId,T2.RefId
FROM Table1 T1
INNER JOIN Table2 T2
ON T1.RefId = T2.RefId
If the ID is used to join as well then
SELECT t1.Id, t1.RefId, t1.PhoneNumber, t2.City, t2.UniqueId
FROM Table1 t1
INNER JOIN Table2 t2
ON t1.Id = t2.Id
AND t1.RefId = t2.RefId
If the Ids are randomly generated them you probably shouldn't join on them.
If the Ids were random but all of the PhoneNumbers were for the same place then you could just pick the Minimum value PhoneNumber (or Max)
SELECT t2.RefId, t1.PhoneNumber, t2.City, t2.UniqueId
FROM Table2 t2
INNER JOIN (
SELECT RefId, MIN(PhoneNumber) AS PhoneNumber
FROM Table1
GROUP BY RefId
) t1 ON t1.RefId = t2.RefId
how to solve 3 table and group same id?
t1
----------
Id a
1 100
1 600
2 800
t2
----------
Id b
1 600
2 700
3 400
t3
----------
Id c
2 400
3 800
4 100
i want result like this:
Id a b c
------------------------------
1 700 600
2 800 700 400
3 400 800
4 100
Same id group by
do the fact you have id in several table youn should get, eg: using union ,all the id you need for join
select t.id, t1.a, t2.b, t3.c
from (
select id
from t1
union
select id
from t2
union
select id
from t3 ) AS t
left join t1 on t.id = t1.id
left join t2 on t.Id = t2.Id
left join t3 on t.Id = t3.Id
and if you need sum for a,b,c
select t.id, sum(t1.a), sum(t2.b), sum(t3.c)
from (
select id
from t1
union
select id
from t2
union
select id
from t3 ) AS t
left join t1 on t.id = t1.id
left join t2 on t.Id = t2.Id
left join t3 on t.Id = t3.Id
group by t.id
To ensure that you are taking all possible values use full outer join. Though this will not work in mySQL. If that is the case then look at this answer
select coalesce(t1.id,t2.id,t3.id) as id, sum(t1.a) as a, sum(t2.b) as b,sum(t3.c) as c
from t1
outer join t2
on t1.id = t2.id
outer join t3
on t1.id = t3.id
or t2.id = t3.id
group by id
Might be misunderstanding you, but looks like you just need to join the table more than doing a Union Operation on them. Below statement will only return records where all three tables have at least one record with the same id.
SQL would be:
SELECT TBL1.ID,
TBL1.A,
TBL2.B,
TBL3.C
FROM A TBL1 (NOLOCK)
INNER JOIN B TBL2 (NOLOCK) ON TBL1.ID = TBL2.ID
INNER JOIN C TBL3 (NOLOCK) ON TBL1.ID = TBL3.ID
Two questions:
1. Which SQL engine to you use?
2. and do you need to return values where one table does not have the id?
Please, help me with join results of commands (MS SQL):
SELECT name,value FROM table1 WHERE idfoo1 IN(SELECT _id FROM table3 where id = 1);
SELECT value FROM table2 WHERE idfoo2 IN(SELECT _id_2 FROM table3 where id = 1) AND name='fooname';
And I get:
name value
John 2
Bill 32
Alex 11
value
434
234
144
But I need join results.
name value value
John 2 434
Bill 32 234
Alex 11 144
So, id == id, _id != _id_2,
Use this query:
SELECT t1.name,
t1.value,
t2.value
FROM table1 t1
INNER JOIN table3 t3 ON t1.idfoo1 = t3._id
INNER JOIN table2 t2 ON t2.idfoo2 = t3._id_2
WHERE t3.id=1 AND t2.name = 'fooname'
Select a.name,a.value,c.value FROM table1 as a inner join table3 as b
on a.idfoo1=b.id and b.id=1 inner join table3 as c
on c.idfoo2=b._id_2 and b.id=1 and c.name='fooname'
i guess this is what you need-
SELECT t1.name, t1.value, t2.value
FROM table1 t1, table2 t2, table3 t3
WHERE
t1.idfoo1 = t3._id
AND t2.idfoo2 = t3._id_2
AND t3.id = 1
AND t2.name='fooname';