Pardon me for the title. I have a table like this:
There will be thousands of rows and now I want to select the rows having the same group_id but vr_debit and vr_credit values must not be equal: ie;, in the image shown, none of the rows satisfy this criteria. If there is are two rows, say, (6,500.000,0) and(6,0,600.000), I want them as the result. Hope you get the idea.
Thank you.
Calculate each group using SUM() which is an aggregate function and filter them using HAVING clause.
SELECT GROUP_ID, SUM(vr_debit) totalDebit, SUM(vr_credit) totalCredit
FROM TableName
GROUP BY GROUP_ID
HAVING SUM(vr_debit) <> SUM(vr_credit)
if you want to get the uncalculated rows, you can join it on the subquery.
SELECT a.*
FROM TableName a
INNER JOIN
(
SELECT GROUP_ID
FROM TableName
GROUP BY GROUP_ID
HAVING SUM(vr_debit) <> SUM(vr_credit)
) b ON a.GROUP_ID = b.GROUP_ID
SQLFiddle Demo (for both queries)
Perhaps:
SELECT group_ID,
vr_debit,
vr_credit
FROM
dbo.TableName T1
WHERE
EXISTS(
SELECT 1 FROM dbo.TableName T2
WHERE T1.group_ID = T2.group_ID
AND T1.vr_debit <> T2.vr_debit
AND T1.vr_credit<> T2.vr_credit
AND T1.vr_debit <> T2.vr_credit
)
Also you can use this option
SELECT *
FROM dbo.test64 t
WHERE EXISTS (
SELECT 1
FROM dbo.test64 t2
WHERE t.group_id = t2.group_id
HAVING SUM(t2.vr_debit) - SUM(t2.vr_credit) != 0
)
Demo on SQLFiddle
Related
I have a table like this
I would like to select the Itemid that occurs more than once with a different Rate with group by Masterid
The output should be something like:
You might try the following:
SELECT masterid, detailid, itemid, rate FROM mytable
WHERE (masterid, detailid, rate) IN
(
SELECT masterid, detailid, rate FROM mytable t
JOIN mytable o ON o.masterid = t.masterid
AND o.detailid = t.detailid AND o.rate <> t.rate
GROUP BY t.masterid, t.detailid, t.rate
HAVING COUNT(*) >= 2
)
The inner join within the sub-query assures only rows appearing that have an unequal counter part. Alternatively you might add another sub-query condition to the outer query:
AND EXISTS
(
SELECT * FROM mytable o
WHERE o.masterid = t.masterid AND o.detailid = t.detailid AND o.rate <> t.rate
)
I believe you are looking for a query like below
select t1.* from t t1
join
(
select masterid,itemid
from t
group by masterid,itemid
having count(distinct rate )>1
)t2
on t1.masterid=t2.masterid and t1.itemid=t2.itemid
order by masterid,detailid
and here's a working db fiddle
Try following code:
Select masterid, detailid, rate, count(*) as count from Mytable
group by masterid, detailid, rate
having count(*) > 1
I don't know, if I made good title, but please let me visualize this.
So I have two tables and for given case I need to select row where payment currency was ONLY in EUR.
Correct document Id's will be: 2, 3, 4, 5
These are overall bigger tables with 900k+ records.
Can you please suggest me how query should look?
use correlated subquery with not exists
select distinct a.document_id from tablename a inner join tablename b b on a.document_id=b.payment_docid
where not exists
(select 1 from tablename b1 where b1.payment_docid=b.payment_docid and currency<>'EUR')
Try this query:
select payment_docId from MyTable
group by payment_docId
having max(currency) = 'EUR'
and min(currency) = 'EUR'
or you could use having count(*) = 1 with min or max as well.
use corelated subquery
select t1.* from table2 as t1
where exists( select 1 from table2 t2 where t1.payment_docid=t2.payment_docid
having count(distinct currency)=1)
and currency='EUR'
It is possible to use INNER JOIN with the following conditions to get all rows:
SELECT
pd.payment_doc_id
, pd.currency
FROM DocTable dt
INNER JOIN PaymentDocs pd
ON dt.document_id = pd.payment_doc_id AND pd.currency IN ('EUR')
If you want distinct rows, then you can apply operator GROUP BY:
SELECT
pd.payment_doc_id
, pd.currency
FROM DocTable dt
INNER JOIN PaymentDocs pd
ON dt.document_id = pd.payment_doc_id AND pd.currency IN ('EUR')
GROUP BY pd.payment_doc_id
, pd.currency
Aggregation is the only efficient want :
select doc_id
from table t
group by doc_id
having min(currency) = max(currency) and min(currency) = 'EUR';
I have a stored procedure in which i am trying to select all the columns of a table Table 1. There is another table which uses Table1 primary key as foreign key. I want to count number of records in this foreign key table with that select like this:
SELECT *, count(*) VacancyCount
FROM Table1 hc
LEFT JOIN Table2 hv
on hc.CompanyID = hv.CompanyID
WHERE hc.Deleted = 0
group by hc.CompanyID
ORDER BY NameLang1
but it gives error:
Column 'dbo.Table1.NameLang1' is invalid in the select list because it
is not contained in either an aggregate function or the GROUP BY
clause.
Please suggest how to fix this?
Please try:
select
*,
(select COUNT(*) from Table2 hv where hv.CompanyID=hc.CompanyID) VacancyCount
from Table1 hc
where
hc.Deleted = 0
order by hc.NameLang1, VacancyCount desc
for ordering using the new column
select * from(
select
*,
CONVERT(NVARCHAR(100), (select COUNT(*) from Table2 hv where hv.CompanyID=hc.CompanyID)) VacancyCount
from Table1 hc
where
hc.Deleted = 0
)x
Order by CASE WHEN #OrderByParam = 1 THEN NameLang1 ELSE VacancyCount END
Provided column NameLang1 and VacancyCount are of same datatype.
You're doing grouping wrong. You need to use all the columns from Table 1 in SELECT instead of '*' and in GROUP BY clause as well.
Or you can try a different approach like this:
SELECT *
FROM Table1 hc
LEFT JOIN (SELECT CompanyID, COUNT(*) cnt FROM Table2 GROUP BY CompanyID) hv
on hc.CompanyID = hv.CompanyID
WHERE hc.Deleted = 0
ORDER BY NameLang1
You will have to list every column in the GROUP BY clause
These columns are those in the SELECT * bit.
This would be correct ANSI SQL anyway.
SELECT * itself is bad anyway: it is always better to explicitly list columns
Try in this way include column list in group by
SELECT column1,column2,column3..,NameLang1,count(*) VacancyCount
FROM Table1 hc
LEFT JOIN Table2 hv
on hc.CompanyID = hv.CompanyID
WHERE hc.Deleted = 0
group by column1,column2,column3
ORDER BY NameLang1
I have a large table but for the purposes of this question, let's assume I have the follwoing column strucure:
I'd like to have a Where statement that returns only rows where the e-mail address is distinct in that particular column.
Thoughts?
SELECT BillingEMail
FROM tableName
GROUP BY BillingEMail
HAVING COUNT(BillingEMail) = 1
OR HAVING COUNT(*) = 1
SQLFiddle Demo
I don't know what RDBMS you are using (the reason why i can't introduce of using analytical functions) but you can do this by joining with a subquery if you want to get all columns
SELECT a.*
FROM tableName a
INNER JOIN
(
SELECT BillingEMail
FROM tableName
GROUP BY BillingEMail
HAVING COUNT(BillingEMail) = 1
)b ON a.BillingEMail = b.BillingEMail
SQLFIddle Demo
In most databases, you can do this
select t.AccountId, t.BillingEmail
from (select t.*, count(*) over (partition by BillingEmail) as cnt
from t
) t
where cnt = 1
The advantage of this approach is that you can get as many columns as you like from the table.
I prefer JW's approach, but here is another one using NOT EXISTS.
SELECT AccountID, [Billing Email]
FROM table t1
WHERE NOT EXISTS (
-- Make sure that no other row contains the same
-- email, but a different Account ID.
SELECT 1
FROM table t2
WHERE t1.[Billing Email] = t2.[Billing Email]
AND t1.AccountID <> t2.AccountID
)
Table1 has columns (id, a, b, c, group). There are several rows that have the same group, but id is always unique. I would like to SELECT group,a,b FROM Table1 WHERE the group is distinct. However, I would like the returned data to be from the row with the greatest id for that group.
Thus, if we have the rows
(id=10, a=6, b=40, c=3, group=14)
(id=5, a=21, b=45, c=31, group=230)
(id=4, a=42, b=65, c=2, group=230)
I would like to return these 2 rows:
[group=14, a=6,b=40] and
[group=230, a=21,b=45] (because id=5 > id=4)
Is there a simple SELECT statement to do this?
Try:
select grp, a, b
from table1 where id in
(select max(id) from table1 group by grp)
You can do it using a self join or an inner-select. Here's inner select:
select `group`, a, b from Table1 AS T1
where id=(select max(id) from Table1 AS T2 where T1.`group` = T2.`group`)
And self-join method:
select T1.`group`, T2.a, T2.b from
(select max(id) as id,`group` from Table1 group by `group`) T1
join Table1 as T2 on T1.id=T2.id
2 selects, your inner select gets:
SELECT MAX(id) FROM YourTable GROUP BY [GROUP]
Your outer select joins to this table.
Think about it logically, the inner select gets a sub set of the data you need.
The outer select inner joins to this subset and can get further data.
SELECT [group], a, b FROM YourTable INNER JOIN
(SELECT MAX(id) FROM YourTable GROUP BY [GROUP]) t
ON t.id = YourTable.id
SELECT mi.*
FROM (
SELECT DISTINCT grouper
FROM mytable
) md
JOIN mytable mi
ON mi.id =
(
SELECT id
FROM mytable mo
WHERE mo.grouper = md.grouper
ORDER BY
id DESC
LIMIT 1
)
If your table is MyISAM or id is not a PRIMARY KEY, then make sure you have a composite index on (grouper, id).
If your table is InnoDB and id is a PRIMARY KEY, then a simple index on grouper will suffice (id, being a PRIMARY KEY, will be implictly included).
This will use an INDEX FOR GROUP-BY to build the list of distinct groupers, and for each grouper it will use the index access to find the maximal id.
Don't know how to do it in mysql. But the following code will work for MsSQL...
SELECT Y.* FROM
(
SELECT DISTINCT [group], MAX(id) ID
FROM Table1
GROUP BY [group]
) X
INNER JOIN Table1 Y ON X.ID=Table1.ID