Group by date and and check for continuous dates - sql

Question

I have a set of data like this
date1 Price Availability ServiceID
2012-10-01 50 1 5
2012-10-02 60 1 5
2012-10-03 60 1 5
2012-10-04 60 1 5
2012-10-06 60 1 5
2012-10-07 60 0 5
2012-10-08 60 1 5
Now I want to check what is the total price, min availability and serviceid for a particular period
For example
from 2012-10-01 to 2012-10-03 results would be 170, availability 1 and serviceID 5
from 2012-10-06 to 2012-10-08 results would be 180, availability 0! and serviceID 5
from 2012-10-04 to 2012-10-06 results would be 120, availability 1! and serviceID 5 BUT there is a date missing so availability is 0!
I tried something like
select date1, sum(price), min(availability), service from #t
group by date1, price, availability, service
having count(date1) = datediff(day, #startdate, #enddate)
That does not work because if I group by date1, then count in not valid. Dont know how to get sum, min availability and check continuous dates.
EDIT
In case I want a results set to contain detailed spec. and filter out results with min(availability) = 0 or noncontinuous date
For example
from 2012-10-01 to 2012-10-03 results would be 170, availability 1 and serviceID 5
date1 Price Availability ServiceID
2012-10-01 50 1 5
2012-10-02 60 1 5
2012-10-03 60 1 5
from 2012-10-06 to 2012-10-08 results would be 180, availability 0! and serviceID 5
date1 Price Availability ServiceID
from 2012-10-04 to 2012-10-06 results would be 120, availability 1! and serviceID 5 BUT
date1 Price Availability ServiceID

Answer 1

Try this:
select sum(price) As TotalPrice,
service,
Case When Count(*) = DateDiff(Day, #Startdate, #EndDate) + 1
Then Min(Availability)
Else 0 End As Availability
from #T
Where Date1 >= #StartDate
And Date1 <= #endDate
group by service
By filtering the date in a where clause based on dates, and not grouping by the date, this allows you to get a count or rows which you can then match to the date diff. Note that you need to add 1 to the date diff because DateDiff from yesterday to today is only 1 but would represent 2 rows in your source data.
I should also mention that this is not actually checking for continuous dates. It's simply looking for a corresponding number of rows to match the calculated number of days.
Based on your comment and your edit, you may want to try this derived table solution.
Select T.date1,
SummaryData.TotalPrice,
SummaryData.Availability,
T.Service
From #T T
Inner Join (
select sum(price) As TotalPrice,
service,
Case When Count(*) = DateDiff(Day, #Startdate, #EndDate) + 1
Then Min(Availability)
Else 0 End As Availability
from #T
Where Date1 >= #StartDate
And Date1 <= #endDate
group by service
Having Case When Count(*) = DateDiff(Day, #Startdate, #EndDate) + 1
Then Min(Availability)
Else 0 End = 1
) As SummaryData
On T.Service = SummaryData.Service
Where Date1 >= #StartDate
And Date1 <= #endDate

Answer 2

If there wasn't for curveball with missing dates, query would be quite simple:
SELECT SUM(price), MIN(availability) AS Availibility, MIN(serviceID) AS serviceID FROM #t
WHERE date1 BETWEEN #Startdate AND #enddate
Howere, finding missing dates requires one additional CTE, I'll use idea from t-sql get all dates between 2 dates and it can look somehting like this:
;WITH dates AS (
SELECT #startdate AS dt
UNION ALL
SELECT DATEADD(dd, 1, dt)
FROM dates s
WHERE DATEADD(dd, 1, dt) <= #enddate
)
SELECT SUM(price),
CASE
WHEN EXISTS (SELECT * FROM dates WHERE dt NOT IN (SELECT date1 FROM #t WHERE date1 BETWEEN #Startdate AND #enddate)) THEN 0
ELSE MIN(availability)
END AS Availibility,
MIN(serviceID) AS serviceID FROM #t
WHERE date1 BETWEEN #Startdate AND #enddate