Use column alias in dataProvider - yii

In my model I have a relation() like this.
'notRelUser' => array(
self::HAS_MANY,
'LocationUser',
'location_id',
'condition' => 'notRelUser.status is null',
'on' => 'notRelUser.user_id = ' . Yii::app()->user->getId(),
'with' => array('parent_location'),
'select' => array('*', 'name AS canApply'),
),
and this
public $canApply;
In my controller I have this
$regions = Location::model()->with('notRelUser')->findAll();
$arrayCanApply = new CArrayDataProvider($regions);
I then am trying to print out the value of canApply in a widget for datagrid
<?php $this->widget('bootstrap.widgets.TbGridView', array(
'dataProvider'=>$arrayCanApply,
'columns'=>array(
array('name'=>'name', 'header'=>'Name'),
array('name' => 'canApply', 'value'=>'$data->canApply', 'header'=>'CanApply'),
),
));
But the column with canApply is empty.
I have also tried without the $data-> part.
How can I print this alias?
(I know the value of the alias i trivial, but I will change that later)
UPDATE:
I can get the value by using select in CDbCriteria - but I want to do it in relation.
This does work.
$criteria = new CDbCriteria;
$criteria->select = '("foobar") AS canApply';
$regions = Location::model()->with('notRelUser')->findAll($criteria);
but it seems odd that I have to create a $criteria on everytime

you need to declare can canApply as an attribute of the model
in your model decalare canApply as an attribute
public $canApply;

I also had the same problem. Try 'value'=>'$data->notRelUser->canApply'
instead of 'value'=>'$data->canApply'. Also, you need to declare attribute
public $canApply;
in your LocationUser model, not in Location model.

Related

how to convert query with multiple group by columns to CActiveDataProvider in Yii 1.1.14?

I need to conver this sql statement that has a multi column group by clause into CActiveDataProvider in Yii version 1.1.4?
select * from my_table_name group by bookname,categorytitle,bookkey order by bookname,categorytitle,bookkey asc;
I need a CActiveDataProvider to feed a CGridView search function. Apparently, I only have a simple return in my model of the search function that runs my CGridView
return new CActiveDataProvider(get_class($this),
array(
'criteria' => $criteria,
'sort' => array(
'defaultOrder' => 'id ASC'
),
'pagination' => array('pageSize' => ActiveRecord::PAGE_SIZE),
));
so how to convert the sql statement that I gave into CActiveDataProvider format ?
You can do using two way -
Make sql view and than create yii model and use this in your
controller or page view.
Create custom search function in your existing model and use group by
e.g. -
<?php
public function new_search(){
$criteria = new CDbCriteria();
...
..
$criteria->group = "bookname, categorytitle, bookkey";
$criteria->order = "bookname, categorytitle, bookkey";
return new CActiveDataProvider($this, array(
'criteria'=>$criteria,
'pagination'=>array('pageSize'=>100)
));
}
?>

How to hide a column in yii

I want to hide a column in yii based on a condition. I have used a function in model. but visible functionality is not working in this column.
$this->widget('zii.widgets.grid.CGridview', array(
'id'=>'gridview',
'dataProvider'=>$dp,
'columns'=>array(
array(
'header' => 'Entries',
'value' => '$data->entry_name'
),
array(
'name' => 'value',
'value' => '$data->entry_name',
'visible'=>'$data->show()',
'type'=>'raw'
),
)
)
);
function in Model
public function show()
{
.........
return 1 or 0;
}
but it not working. Please help
I don't see a condition anywhere yet. You should use a comparison operator like return $this->attribute !== null; in your show function. Which returns true if attribute contains some value. Or if you want to do it on random you can return rand(0,1) == 1;.

Accessing field in related table through Foreign Key in Yii

I have three tables
1. tbl_employee: id(PK), name, position_id(FK), type_id(FK)
2. tbl_position: id, position
3. tbl_type : id, type
I want to display records in field position like what sql does below.
SELECT tbl_employee.name, tbl_position.position
FROM tbl_employee, tbl_position
WHERE tbl_employee.position_id = tbl_position.id AND tbl_position.position LIKE '%Designer';
In my EmployeeController
public function actionIndex(){
$dataProvider=new CActiveDataProvider('Employee', array(
'criteria'=>array(
'select'=>'t.name, tbl_position',
'with'=>array(
'position'=>array('select'=>'position'),
'type'=>array('select'=>'type'),
),
'condition'=>"tbl_position.position LIKE '%Designer'",
),
));
$this->render('index',array('dataProvider'=>$dataProvider,));
}
and in my models
public function relations(){
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'position' => array(self::BELONGS_TO, 'Position', 'position_id'),
'type' => array(self::BELONGS_TO, 'Type', 'type_id'),
);
}
and this is my view
<?php $this->widget('zii.widgets.CDetailView', array(
'data'=>$model,
'attributes'=>array(
'id',
'name',
array(
'name'=>'position_id',
'value'=>CHtml::encode($model->position->position),
),
array(
'name'=>'type_id',
'value'=>CHtml::encode($model->type->type),
)
),
)); ?>
The error I've got is:
Active record "Employee" is trying to select an invalid column "tbl_position".
Note, the column must exist in the table or be an expression with alias.
How can I access position field in tbl_position by using join?What is the correct syntax for achieving that purpose.
Many thanks
'select'=>'t.name, position.position',
'condition'=>"position.position LIKE '%Designer'",
or
$model = TblEmployee::model()->with('position','type')->findall(array("condition"=>"position.position LIKE '%Designer'"));
Here I find the solution, but actually your answer was very close
public function actionIndex(){
$dataProvider=new CActiveDataProvider('Employee', array(
'criteria'=>array(
'select'=>'t.name',
'with'=>array(
'position'=>array('select'=>'position'),
'type'=>array('select'=>'type'),
),
'condition'=>"position.position LIKE '%Designer'",
),
));
$this->render('index',array('dataProvider'=>$dataProvider,));
}

yii CGridView dataprovider and filter

I know we can show a gridview with a model and it's search method and filter the results, but can we make a gridview with another dataprovider and another model like this and filter its results? Does filter needs to be a part of dataprovider?
$attr = Yii::app()->request->getParam($name);
$model = new User('search');
$model->unsetAttributes();
$model->setAttributes($attr);
$this->widget('zii.widgets.grid.CGridView', array(
'dataProvider' => $myDataProvider,
'filter' => $model,
'columns' => array(
array(
'name' => 'username',
'type' => 'raw',
'value' => 'CHtml::encode($data->username)'
),
array(
'name' => 'email',
'type' => 'raw',
),
),
));
The above code doesn't work and I need to add a filter on a previously made data provider.
Btw $attr has a valid data, but grid is not filtered.
$model doesn't affect $myDataProvider since the data provider is not obtained using this model.
$model->search() returns a CActiveDataProvider which contains a CDbCriteria instance. Different CDbCriteria can be combined using mergeWith(). So if you would like the data to be filtered using the values from the $model
...
$model->setAttributes($attr);
$newDataProvider=$model->search();
$myDataProvider->criteria->mergeWith($newDataProvider->criteria);
$this->widget('zii.widgets.grid.CGridView', array(
...
Filter does not need to be a part of dataprovider, but data provider needs to take the model into account, if you want to use it for filtering.
The way this is done by default is to create the data provider using search method on your model, which sets conditions of your data provider based on model values, like so:
'dataProvider' => $model->search()
There is nothing preventing you from creating different data provider, for example:
'dataProvider' => $model->createAnotherDataProvider()
And in your User model:
public function createAnotherDataProvider() {
{
// create your second data provider here
// with filtering based on model's attributes, e.g.:
$criteria = new CDbCriteria;
$criteria->compare('someAttribute', $this->someAttribute);
return new CActiveDataProvider('User', array(
'criteria' => $criteria,
));
}

Problems returning result of CDbCriteria based query

I have a query as follows
$criteria1 = new CDbCriteria();
$criteria1->condition = 'id = 1';
$modelA=Table1::model()->find($criteria1);
I can pass it to a view and return the title and entry
$this->widget('bootstrap.widgets.TbBox', array(
title' => $modelA['title'],
'content' => $modelA['entry'] ));
Now I'd like to return a range of entries
$criteria2 = new CDbCriteria();
$criteria2->condition = 'id > 7';
$modelB=Table1::model()->findAll($criteria2);
(btw : I'm following a form as laid out here). I was expecting to be able to read the resulting array of values out as below, but ['title'] is now being seen as a undefined index (obviously I'm expecting to read this out in a loop but you get the point)
$this->widget('bootstrap.widgets.TbBox', array(
'title' => $modelB['title'][0],
'content' => $modelB['entry'][0]));
Where am I going wrong?
Thanks
No, the indexes should be specified in the different order: the number of a specific element first, then the name of the property. Additionally, it's better (=cleaner) to name the result of findAll so it'll show you (and any other reader) that it's a collection, not a single model:
$models = Table1::model()->findAll($criteria2);
// ...
$this->widget('bootstrap.widgets.TbBox', array(
'title' => $models[0]['title']
//...
));
But even that's not necessary if you use foreach (and you probably will):
foreach ($models as $model):
// ...
$this->widget('some.name', array(
'title' => $model['title']
);
endforeach;