I have come across a very strange scenario. In a function I will receive a string of condition to be evaluated.
E.g.
(a>b and (b=2 or c!=3))
Where a,b and c are my variable names.
I tried and searched a lot but didn't get anything meaningful.
So my question is: Is it possible to evaluate a string like this? If yes, please provide me some hint on this.
Alternative way, add a reference to Microsoft Script Control
Dim vx As MSScriptControl.ScriptControl
Set vx = New MSScriptControl.ScriptControl
a = 100
b = 200
c = 300
Cond = "(a>b and (b=2 or c<>3))"
With vx
.Language = "VBScript"
.AddCode "function stub(a,b,c): stub=" & Cond & ": end function"
result = .Run("stub", a, b, c)
End With
MsgBox result
Note you will need to replace != with <> as the former is not valid in VB* (and and/or is not valid in jScript)
Here's a proper answer to your question, rather than just a comment.
You need to:
Set a reference to Microsoft Visual Basic for Applications Extensibility x.x (Tools/References) in the VBIDE.
Trust access to the VBA project object model (use Google to find out how to do this for your version of Excel).
Run initValues() then call getConstantValue("(a>b and (b=2 or c<>3))")
Code:
Option Explicit
Dim a As Long
Dim b As Long
Dim c As Long
Sub initValues()
a = 3
b = 2
c = 4
End Sub
Function getConstantValue(constStr As String) As Variant
Dim oMod As VBIDE.CodeModule
Dim i As Long, _
num As Long
Set oMod = ThisWorkbook.VBProject.VBComponents("Module1").CodeModule
For i = 1 To oMod.CountOfLines
If oMod.Lines(i, 1) = "Function tempGetConstValue() As Variant" Then
num = i + 1
Exit For
End If
Next i
oMod.InsertLines num, "tempGetConstValue = " & constStr
getConstantValue = Application.Run("tempGetConstValue")
oMod.DeleteLines num
End Function
Function tempGetConstValue() As Variant
End Function
Related
I would like to convert a range of numbers (and single digits) from a number-only format to alpha-numeric format. Entire statement is in a single, excel cell and would like the converted version to be in a neighboring cell.
As an example:
Assuming 1-24=B1-B24
Assuming 25-48=C1-C24
INPUT—
screen 1-3,5,7-9,11-30,32-37,39-40,41,44-46
DESIRED OUTPUT (all acceptable)
screen B1-B3,B5,B7-B9,B11-C6,C8-C13,C15-C16,C17,C20-C22
OR
screen B1-B3,B5,B7-B9,B11-B24,C1-C6,C8-C13,C15-C16,C17,C20-C22
OR
screen B1-B3,B5,B7-B9,B11-B24
screen C1-C6,C8-C13,C15-C16,C17,C20-C22
Using excel functions is proving quite cumbersome so excel macro would be better. I've looked for examples of requested conversion but haven't found anything.
Any help is greatly appreciated.
Cheers,
Bob
Hey here is a solution that i tested out. Not sure if "screen" needs to be in the string or not. Let me know and I will tweak it if that's the case.
Its a user defined function. So drop this vba in a module and then go to a worksheet and type in "=AlphaConvert(" + the cell reference.
Assumption here is that only one cell will be referenced at a time.
Last this could easily be converted to a sub routine and probably run a bit faster than the function.
Public Function AlphaConvert(TargetCell As Range)
Dim v As Long
Dim vArr() As String
Dim i As Long
Dim iArr() As String
Dim a As String
vArr = Split(TargetCell.Value, ",")
For v = LBound(vArr) To UBound(vArr)
If InStr(vArr(v), "-") > 0 Then
iArr = Split(vArr(v), "-")
For i = LBound(iArr) To UBound(iArr)
If i = LBound(iArr) Then
a = AlphaCode(iArr(i))
Else
a = a & "-" & AlphaCode(iArr(i))
End If
Next i
vArr(v) = a
Else
vArr(v) = AlphaCode(vArr(v))
End If
If v = LBound(vArr) Then
AlphaConvert = vArr(v)
Else
AlphaConvert = AlphaConvert & "," & vArr(v)
End If
Next v
End Function
Private Function AlphaCode(Nbr As Variant)
Select Case Nbr
Case 1 To 24
AlphaCode = "B" & Nbr
Case Else
AlphaCode = "C" & Nbr - 24
End Select
End Function
Is it possible to:
Access a list of all variables in a VBA runtime environment?
Access the name of a variable with VBA?
Example:
function v2S(str as string) as string
For each variable in Variables
dim I as integer
for I = 1 to 10
v2S = replace(v2S,"%" & variable.name & "%", variable.value)
next
next
end function
Example use case:
Dim skyColor as string
skyColor = "green"
Debug.Print v2S("The sky is %skyColor% today!")
There is an application I can send commands to via a com object and I wish to do something along the lines of:
Dim i a integer
for i = 1 to MI.Eval("numtables()")
MI = GetObject(,"MapInfo.Application.x64")
debug.print MI.Eval(v2S("tableinfo(%i%,1)")) ' Print name of table
next
The above looks much cleaner than:
Dim i a integer
for i = 1 to MI.Eval("numtables()")
MI = GetObject(,"MapInfo.Application.x64")
debug.print MI.Eval(v2S("tableinfo(" & i & ",1)")) ' Print name of table
next
But of course if it were possible I would want it to be general which may be difficult...
For my own use case this is pretty good.
However it still isn't very readable. This is another option. It's more readable but also more cluttered:
Sub Main()
Dim Vars as object, myString as string
set Vars = CreateObject("scripting.Dictionary")
Vars.add "Var1","Val1"
Vars.add "Var2","Val2"
'...
myString = r("Var1: #{Var1} and Var2: #{Var2}", Vars)
End Sub
function r(byval s as string, byval o as object) as string
for each key in o.keys
s = replace(s,"#{" & key & "}",o.item(key))
next
r = s
end function
I wish string interpolation functionality existed by default in VBA.
Private Sub FillRow(programCell As Range, storedProgramCell As Range)
Dim counter As Integer
For counter = 3 To 9
Dim cellOffset As Integer
cellOffset = counter - 3
Dim currentStoredCell As Range
Set currentStoredCell = storedProgramCell.Offset(0, cellOffset)
Dim value As String
value = currentStoredCell.value
Dim currentTargetCell As Range
Set currentTargetCell = programCell.Offset(0, cellOffset)
MsgBox currentStoredCell.value 'Works correctly, prints correct value
currentTargetCell.value = value
Next counter
End Sub
The line:
currentTargetCell.value = value
causes the code to stop executing, with no error.
I added the expression to my watch list, then stepped through the routine. The expression was seen as a Boolean:
This makes me think the expression is being viewed as a comparison, and the program abruptly ends since the returned Boolean is not being stored or used anywhere. I wouldn't doubt if I were wrong though.
I'm new to VBA, struggling to debug my program, so please forgive me if this is a petty mistake. I couldn't find any sources online that explains this problem.
Replace your subroutine with following code:
Private Sub FillRow(Dst As Range, Src As Range)
Dim x As Integer
Dim v As Variant
Dim Srcx As Range
Dim Dstx As Range
Debug.Print "FillRow"
Debug.Print Src.Address
Debug.Print Dst.Address
Debug.Print "Loop"
For x = 0 To 6
Debug.Print x
Set Srcx = Src.Offset(0, x)
Debug.Print Srcx.Address
v = Srcx.Value
Debug.Print TypeName(v)
Set Dstx = Dst.Offset(0, x)
Debug.Print Dstx.Address
Dstx.Value = v
Next
Debug.Print "Completed"
End Sub
Run and post in your question Immediate window output.
Value is a reserved word, even if vba does not raise an error on this name, you should not use it. Name it something else. Also, try setting it as a variant.
I would like to extract a combination of text and numbers from a larger string located within a column within excel.
The constants I have to work with is that each Text string will
either start with a A, C or S, and
will always be 7 Characters long
the position of he string I would like to extract varies.
For example;
COB0012 WP0402 Electronic Payments - SME Consultancy
DCPY708 A850035 WP161 Configuration Manager Core General (Aman Ranjan)
A614019 WP0302 SQL 2005 Upgrade Project – WFCopiesChq - Next Stage
SUTP016 EPM Training T2
Output
COB0012
A850035
SUTP016
I have knowledge of the standard Left / Right / Mid / Search functions however my data set is vary large so I would like to create something which would automate this process. (1000's of rows)
I imagine a UDF function would do the trick but my familarity with UDF's is very basic.
Any help would be much appreciated.
#Gary's Student variant but has some difference
Public Function Xtractor(r As Range) As String
Dim a, ary
ary = Split(r.Text, " ")
For Each a In ary
If Len(a) = 7 And a Like "[SAC]*" Then
Xtractor = a
Exit Function
End If
Next a
End Function
output
Consider:
Public Function Xtractor(r As Range) As String
Dim CH As String, L As Long
ary = Split(r.Text, " ")
For Each a In ary
L = Len(a)
CH = Left(a, 1)
If L = 7 Then
If CH = "S" Or CH = "A" Or CH = "C" Then
Xtractor = a
Exit Function
End If
End If
Next a
Xtractor = ""
End Function
A regex will be very efficient - especially if you combine it with a variant array rather than a range.
Sub UseaRegex()
MsgBox StrChange("COB0012 WP0402 Electronic Payments - SME Consultancy [I would require COB0012]")
MsgBox StrChange("DCPY708 A850035 WP161 Configuration Manager Core General (Aman Ranjan)")
End Sub
function
Function StrChange(strIn As String) As String
Dim objRegex As Object
Set objRegex = CreateObject("vbscript.regexp")
With objRegex
.Pattern = "[ACS]\w{6}"
If .test(strIn) Then
StrChange = .Execute(strIn)(0)
Else
StrChange = "No match"
End If
End With
End Function
I'm writing a script that will count a numbers of days between few separate dates. I have a data in cell like:
1-In Progress#02-ASSIGNED TO TEAM#22/01/2013 14:54:23,4-On
Hold#02-ASSIGNED TO TEAM#18/01/2013 16:02:03,1-In Progress#02-ASSIGNED
TO TEAM#18/01/2013 16:02:03
That's the info about my transaction status. I want to count the numbers of days that this transaction was in "4-On Hold". So in this example it will be between 18/01/2013 and 22/01/2013.
I wrote something like this(sorry for ma native language words in text)
Sub Aktywnywiersz()
Dim wiersz, i, licz As Integer
Dim tekstwsadowy As String
Dim koniectekstu As String
Dim pozostalytekst As String
Dim dataztekstu As Date
Dim status4jest As Boolean
Dim status4byl As Boolean
Dim datarozpoczecia4 As Date
Dim datazakonczenia4 As Date
Dim dniw4 As Long
wiersz = 2 'I start my scrypt from second row of excel
Do Until IsEmpty(Cells(wiersz, "A")) 'this should work until there is any text in a row
status4jest = False 'is status 4-On Hold is now in a Loop
status4byl = False 'is status 4-On Hold was in las loop
dniw4 = 0 ' numbers od days in 4-On Hold status
tekstwsadowy = Cells(wiersz, "H").Value2 'grabing text
tekstwsadowy = dodanieprzecinka(tekstwsadowy) 'in some examples I had to add a coma at the end of text
For i = 1 To Len(tekstwsadowy)
If Right(Left(tekstwsadowy, i), 1) = "," Then licz = licz + 1 'count the number of comas in text that separates the changes in status
Next
For j = 1 To licz
koniectekstu = funkcjaliczeniadni(tekstwsadowy) 'take last record after coma
Cells(wiersz, "k") = koniectekstu
dataztekstu = funkcjadataztekstu(koniectekstu) 'take the date from this record
Cells(wiersz, "m") = dataztekstu
status4jest = funkcjaokreslenia4(koniectekstu) 'check if there is 4-On Hold in record
Cells(wiersz, "n") = status4jest
If (status4byl = False And staus4jest = True) Then
datarozpoczecia4 = dataztekstu
status4byl = True
ElseIf (status4byl = True And staus4jest = False) Then
datazakonczenia4 = dataztekstu
status4byl = False 'if elseif funkcion to check information about 4-On Hold
dniw4 = funkcjaobliczeniadniw4(dniw4, datazakonczenia4, datarozpoczecia4) 'count days in 4-On Hold
Else
'Else not needed...
End If
tekstwsadowy = resztatekstu(tekstwsadowy, koniectekstu) 'remove last record from main text
Next
Cells(wiersz, "L") = dniw4 ' show number of days in 4-On Hold status
wiersz = wiersz + 1
Loop
End Sub
Function funkcjaliczeniadni(tekstwsadowy As String)
Dim a, dl As Integer
dl = Len(tekstwsadowy)
a = 0
On Error GoTo errhandler:
Do Until a > dl
a = Application.WorksheetFunction.Find(",", tekstwsadowy, a + 1)
Loop
funkcjaliczeniadni = tekstwsadowy
Exit Function
errhandler:
funkcjaliczeniadni = Right(tekstwsadowy, dl - a)
End Function
Function dodanieprzecinka(tekstwsadowy As String)
If Right(tekstwsadowy, 1) = "," Then
dodanieprzecinka = Left(tekstwsadowy, Len(tekstwsadowy) - 1)
Else
dodanieprzecinka = tekstwsadowy
End If
End Function
Function resztatekstu(tekstwsadowy, koniectekstu As String)
resztatekstu = Left(tekstwsadowy, Len(tekstwsadowy) - Len(koniectekstu))
End Function
Function funkcjadataztekstu(koniectekstu As String)
funkcjadataztekstu = Right(koniectekstu, 19)
funkcjadataztekstu = Left(funkcjadataztekstu, 10)
End Function
Function funkcjaobliczeniadniw4(dniw4 As Long, datazakonczenia4 As Date, datarozpoczecia4 As Date)
Dim liczbadni As Integer
liczbadni = DateDiff(d, datarozpoczecia4, datazakonczenia4)
funkcjaobliczaniadniw4 = dniw4 + liczbadni
End Function
Function funkcjaokreslenia4(koniectekstu As String)
Dim pierwszyznak As String
pierwszyznak = "4"
If pierszyznak Like Left(koniectekstu, 1) Then
funkcjaokreslenia4 = True
Else
funkcjaokreslenia4 = False
End If
End Function
And for now I get
Run-time error "13"
in
dataztekstu = funkcjadataztekstu(koniectekstu) 'take the date from this record
I would be very grateful for any help.
You are getting that error because of Type Mismatch. dataztekstu is declared as a date and most probably the expression which is being returned by the function funkcjadataztekstu is not a date. You will have to step through it to find what value you are getting in return.
Here is a simple example to replicate that problem
This will give you that error
Option Explicit
Sub Sample()
Dim dt As String
Dim D As Date
dt = "Blah Blah"
D = getdate(dt)
Debug.Print D
End Sub
Function getdate(dd As String)
getdate = dd
End Function
This won't
Option Explicit
Sub Sample()
Dim dt As String
Dim D As Date
dt = "12/12/2014"
D = getdate(dt)
Debug.Print D
End Sub
Function getdate(dd As String)
getdate = dd
End Function
If you change your function to this
Function funkcjadataztekstu(koniectekstu As String)
Dim temp As String
temp = Right(koniectekstu, 19)
temp = Left(temp, 10)
MsgBox temp '<~~ This will tell you if you are getting a valid date in return
funkcjadataztekstu = temp
End Function
Then you can see what that function is returning.
I tried running your code, but it is a little difficult to understand just what it is that you want to do. Part of it is the code in your language, but the code is also hard to read beacuse of the lack of indentation etc. :)
Also, I do not understand how the data in the worksheet looks. I did get it running by guessing, though, and when I did I got the same error you are describing on the second run of the For loop - that was because the koniectekstu string was empty. Not sure if this is your problem, so my solution is a very general.
In order to solve this type of problem:
Use Option Explicit at the top of your code module. This will make you have to declare all variables used in the module, and you will remove many of the problems you have before you run the code. Eg you are declaring a variable status4jest but using a different variable called staus4jest and Excel will not complain unless you use Option Explicit.
Declare return types for your functions.
Format your code so it will be easier to read. Use space before and after statements. Comment everything! You have done some, but make sure a beginner can understand. I will edit you code as an example of indentation.
Debug! Step through your code using F8 and make sure all variables contain what you think they do. You will most likely solve your problem by debugging the code this way.
Ask for help here on specific problems you run into or how to solve specific problems, do not send all the code and ask why it is not working. If you break down your problems into parts and ask separately, you will learn VBA yourself a lot faster.
A specific tip regarding your code: look up the Split function. It can take a string and make an array based on a delimiter - Example: Split(tekstwsadowy, ",") will give you an array of strings, with the text between the commas.
Did I mention Option Explicit? ;)
Anyway, I hope this helps, even if I did not solve the exact error you are getting.