Query for start and end date - sql

I already raided the net , yet still no answers.
Well, I'm creating a hotel room reservation system.
My room availability query works fine with this query :
SELECT r.roominv_id, r.room_id, m.room_type,r.room_number,r.room_status
FROM roominventory r
INNER JOIN room AS m ON m.room_id = r.room_id
WHERE m.room_type LIKE '%$roomtype%'
AND r.room_status = 'available'
AND r.roominv_id NOT IN (SELECT b.roominv_id
FROM reserve b
WHERE NOT (b.chckout < '$chckin'
OR b.chckin > '$chckout'))
I wanted February 2 as my start date in afternoon (hotel reservations must always start after 12 noon) and February 3 as my end date ( before 12 noon )
but in my current query , if I choose February 2 as startdate and February 3 as enddate , in database, it will appear as a 2 day reservation.
So my question is:
how will I query that clients can still choose the end date from a already reserved room?
I actually saw a site that have a datepicker that have somewhat like AM/PM http://reservations.directwithhotels.com/reservation/selectDates/148/campaign/ew
BUT I'm so noob at javascript.


Depending on your data type for chckout and chckin, you may just want to use the BETWEEN operator, or use inclusive equality operators (>=, <=).


I think you just need to change the where clause to:
WHERE NOT (b.chckout < '$chckin'
OR b.chckin >= '$chckout')
This assumes that chckin and chckout are stored as dates. Otherwise you need to convert them to dates, which depends on the database . . . here are some ways:
date(b.chckin)
cast(b.chckin as date)
trunc(b.chckin)

Related

SQL INNER JOIN tables with different row names

Thank you for taking the time to read this, it is probably a very basic question. Most search queries I did seemed a bit more in depth to the INNER JOIN operator.
Basically my question is this: I have a shipping and receiving table with dates on when the item was either shipped or received. In the shipping table (tbl_shipping) the date row is labeled as trans_out_date and for the receiving table (tbl_receiving) the date row is labeled as trans_in_date.
I can view transactions set on either table from a user entered form but I want to populate a table with information pulled from both tables where the criteria meets. ie. If the receiving table has 10 transactions done in April and 5 in June and the shipping table has 15 transactions in April and 10 in June... when the user wants to see all transactions in June, it will populate the 15 transactions that occurred in June.
As of right now, I can pull only from 1 table with
SELECT *
FROM tbl_shipping
WHERE trans_out_date >= ‘from_date’
AND trans_out_date <= ‘to_date’
Would this be the appropriate syntax for what I am looking to achieve?
SELECT *
FROM tbl_shipping
INNER JOIN tbl_receiving ON tbl_shipping.trans_out_date = tbl_receiving.trans_in_date
WHERE
tbl_shipping.trans_out_date >= ‘from_date’
AND tbl_shipping.trans_out_date <= ‘to_date’
Thank you again in advance for reading this.

You appear to want union all rather than a join:
SELECT s.item, s.trans_out_date as dte, 'shipped' as which
FROM tbl_shipping S
WHERE s.trans_out_date >= ? AND
s.trans_out_date <= ?
UNION ALL
SELECT r.item, NULL, r.trans_in_date as dte, 'received'
FROM tbl_receiving r
WHERE r.trans_out_date >= ? AND
r.trans_out_date <= ?
ORDER BY dte;
Notes:
A JOIN can cause problems due to data that goes missing (because dates don't line up) or data that gets duplicated (because there are multiple dates).
The ? is for a parameter. If you are calling this from an application, use parameters!
You can include additional columns for more information in the result set.
This may not be the exact result format you want. If not, ask another question with sample data and desired results.

SQL Server: compare only month and day - SARGable

I have a table storing a datetime column, which is indexed. I'm trying to find a way to compare ONLY the month and day (ignores the year totally).
Just for the record, I would like to say that I'm already using MONTH() and DAY(). But I'm encountering the issue that my current implementation uses Index Scan instead of Index Seek, due to the column being used directly in both functions to get the month and day.
There could be 2 types of references for comparison: a fixed given date and today (GETDATE()). The date will be converted based on time zone, and then have its month and day extracted, e.g.
DECLARE #monthValue DATETIME = MONTH(#ConvertDateTimeFromServer_TimeZone);
DECLARE #dayValue DATETIME = DAY(#ConvertDateTimeFromServer_TimeZone);
Another point is that the column stores datetime with different years, e.g.
1989-06-21 00:00:00.000
1965-10-04 00:00:00.000
1958-09-15 00:00:00.000
1965-10-08 00:00:00.000
1942-01-30 00:00:00.000
Now here comes the problem. How do I create a SARGable query to get the rows in the table that match the given month and day regardless of the year but also not involving the column in any functions? Existing examples on the web utilise years and/or date ranges, which for my case is not helping at all.
A sample query:
Select t0.pk_id
From dob t0 WITH(NOLOCK)
WHERE ((MONTH(t0.date_of_birth) = #monthValue AND DAY(t0.date_of_birth) = #dayValue))
I've also tried DATEDIFF() and DATEADD(), but they all end up with an Index Scan.

Adding to the comment I made, on a Calendar Table.
This will, probably, be the easiest way to get a SARGable query. As you've discovered, MONTH([YourColumn]) and DATEPART(MONTH,[YourColumn]) both cause your query to become non-SARGable.
Considering that all your columns, at least in your sample data, have a time of 00:00:00 this "works" to our advantage, as they are effectively just dates. This means we can easily JOIN onto a Calendar Table using something like:
SELECT dob.[YourColumn]
FROM dob
JOIN CalendarTable CT ON dob.DateOfBirth = CT.CalendarDate;
Now, if we're using the table from the above article, you will have created some extra columns (MonthNo and CDay, however, you can call them whatever you want really). You can then add those columns to your query:
SELECT dob.[YourColumn]
FROM dob
JOIN CalendarTable CT ON dob.DateOfBirth = CT.CalendarDate
WHERE CT.MonthNo = #MonthValue
AND CT.CDay = #DayValue;
This, as you can see, is a more SARGable query.
If you want to deal with Leap Years, you could add a little more logic using a CASE expression:
SELECT dob.[YourColumn]
FROM dob
JOIN CalendarTable CT ON dob.DateOfBirth = CT.CalendarDate
WHERE CT.MonthNo = #MonthValue
AND CASE WHEN DATEPART(YEAR, GETDATE()) % 4 != 0 AND CT.CDat = 29 AND CT.MonthNo = 2 THEN 28 ELSE CT.Cdat END = #DayValue;
This treats someone's birthday on 29 February as 28 February on years that aren't leap years (when DATEPART(YEAR, GETDATE()) % 4 != 0).
It's also, probably, worth noting that it'll likely be worth while changing your DateOfBirth Column to a date. Date of Births aren't at a given time, only on a given date; this means that there's no implicit conversion from datetime to date on your Calendar Table.
Edit: Also, just noticed, why are you using NOLOCK? You do know what that does, right..? Unless you're happy with dirty reads and ghost data?

Running a query over past date ranges

I have a rather interesting problem which I first thought would be straight-forward, but it turned out to be more complicated.
I have data like this:
Date User ID
2012-10-11 a
2012-10-11 b
2012-10-12 c
2012-10-12 d
2012-10-13 e
2012-10-14 b
2012-10-14 e
... ...
Each row has a Date, User ID couple which indicates that that user was active on that day. A user can appear on multiple dates and a date will have multiple users -- just like in the example. I have millions of rows like this which cover a time range of about 90 days.
Here's the question: For each day, I want to get the number of users who have not been active for the past 10 days. For instance, if the user "a" was active on 2012-05-31 and but hasn't been active on any of the days between 06-01 and 06-10, I want to count this user on 6/10. I wouldn't count him again on the following days though unless he becomes active and disappears again.
Can I do this in SQL or would I need to some kind of script to organize the data the way I want. What would be your recommendations? I use Hive.
Thank you so much!

I think you can do this in Hive-compatible SQL. Here is the idea.
For each user/date get the next date for the user.
Discard the original record if the next is less than 10 days after the current one.
Add 10 to the date
Aggregate and count
I am not sure of all the Hive functions for things like date. Here is an example of how to do it:
select date+10, count(*)
from (select t.userid, t.date,
min(case when tnext.date > t.date then tnext.date end) as nextdate
from t left outer join
t tnext
on t.userid = tnext.userid
group by t.userid, t.date
) t
where nextdate is null or nextdate - date >= 10
group by date+10;
Note that the inner subquery would be better written using:
on t.userid = tnext.userid and t2.date > t.date
However, I don't know if Hive supports such a join (it doesn't support non-equijoins and it not clear about whether one or all clauses have to be equal).

Calculating working days including holidays between dates without a calendar table in oracle SQL

Okay, so I've done quite a lot of reading on the possibility of emulating the networkdays function of excel in sql, and have come to the conclusion that by far the easiest solution is to have a calendar table which will flag working days or non working days. However, due to circumstances out of my control, we don't have access to such a luxury and it's unlikely that we will any time in the near future.
Currently I have managed to bodge together what is undoubtedly a horrible ineffecient query in SQL that does work - the catch is, it will only work for a single client record at a time.
SELECT O_ASSESSMENTS.ASM_ID,
O_ASSESSMENTS.ASM_START_DATE,
O_ASSESSMENTS.ASM_END_DATE,
sum(CASE
When TO_CHAR(O_ASSESSMENTS.ASM_START_DATE + rownum -1,'Day')
= 'Sunday ' THEN 0
When TO_CHAR(O_ASSESSMENTS.ASM_START_DATE + rownum -1,'Day')
= 'Saturday ' THEN 0
WHEN O_ASSESSMENTS.ASM_START_DATE + rownum - 1
IN ('03-01-2000','21-04-2000','24-04-2000','01-05-2000','29-05-2000','28-08-2000','25-12-2000','26-12-2000','01-01-2001','13-04-2001','16-04-2001','07-05-2001','28-05-2001','27-08-2001','25-12-2001','26-12-2001','01-01-2002','29-03-2002','01-04-2002','06-04-2002','03-06-2002','04-06-2002','26-08-2002','25-12-2002','26-12-2002','01-01-2003','18-04-2003','21-04-2003','05-05-2003','26-05-2003','25-08-2003','25-12-2003','26-12-2003','01-01-2004','09-04-2004','12-04-2004','03-05-2004','31-05-2004','30-08-2004','25-12-2004','26-12-2004','27-12-2004','28-12-2004','01-01-2005','03-01-2005','25-03-2005','28-03-2005','02-05-2005','30-05-2005','29-08-2005','27-12-2005','28-12-2005','02-01-2006','14-04-2006','17-04-2006','01-05-2006','29-05-2006','28-08-2006','25-12-2006','26-12-2006','02-01-2007','06-04-2007','09-04-2007','07-05-2007','28-05-2007','27-08-2007','25-12-2007','26-12-2007','01-01-2008','21-03-2008','24-03-2008','05-05-2008','26-05-2008','25-08-2008','25-12-2008','26-12-2008','01-01-2009','10-04-2009','13-04-2009','04-05-2009','25-05-2009','31-08-2009','25-12-2009','28-12-2009','01-01-2010','02-04-2010','05-04-2010','03-05-2010','31-05-2010','30-08-2010','24-12-2010','27-12-2010','28-12-2010','31-12-2010','03-01-2011','22-04-2011','25-04-2011','29-04-2011','02-05-2011','30-05-2011','29-08-2011','26-12-2011','27-12-2011')
THEN 0
ELSE 1
END)-1 AS Week_Day
From O_ASSESSMENTS,
ALL_OBJECTS
WHERE O_ASSESSMENTS.ASM_QSA_ID IN ('TYPE1')
AND O_ASSESSMENTS.ASM_END_DATE >= '01/01/2012'
AND O_ASSESSMENTS.ASM_ID = 'A00000'
AND ROWNUM <= O_ASSESSMENTS.ASM_END_DATE-O_ASSESSMENTS.ASM_START_DATE+1
GROUP BY
O_ASSESSMENTS.ASM_ID,
O_ASSESSMENTS.ASM_START_DATE,
O_ASSESSMENTS.ASM_END_DATE
Basically, I'm wondering if a) I should stop wasting my time on this or b) is it possible to get this to work for multiple clients? Any pointers appreciated thanks!
Edit: Further clarification - I already work out timescales using excel, but it would be ideal if we could do it in the report as the report in question is something that we would like end users to be able to run without any further manipulation.
Edit:
MarkBannister's answer works perfectly albeit slowly (though I had expected as much given it's not the preferred solution) - the challenge now lies in me integrating this into an existing report!
with
calendar_cte as (select
to_date('01-01-2000')+level-1 calendar_date,
case when to_char(to_date('01-01-2000')+level-1, 'day') in ('sunday ','saturday ') then 0 when to_date('01-01-2000')+level-1 in ('03-01-2000','21-04-2000','24-04-2000','01-05-2000','29-05-2000','28-08-2000','25-12-2000','26-12-2000','01-01-2001','13-04-2001','16-04-2001','07-05-2001','28-05-2001','27-08-2001','25-12-2001','26-12-2001','01-01-2002','29-03-2002','01-04-2002','06-04-2002','03-06-2002','04-06-2002','26-08-2002','25-12-2002','26-12-2002','01-01-2003','18-04-2003','21-04-2003','05-05-2003','26-05-2003','25-08-2003','25-12-2003','26-12-2003','01-01-2004','09-04-2004','12-04-2004','03-05-2004','31-05-2004','30-08-2004','25-12-2004','26-12-2004','27-12-2004','28-12-2004','01-01-2005','03-01-2005','25-03-2005','28-03-2005','02-05-2005','30-05-2005','29-08-2005','27-12-2005','28-12-2005','02-01-2006','14-04-2006','17-04-2006','01-05-2006','29-05-2006','28-08-2006','25-12-2006','26-12-2006','02-01-2007','06-04-2007','09-04-2007','07-05-2007','28-05-2007','27-08-2007','25-12-2007','26-12-2007','01-01-2008','21-03-2008','24-03-2008','05-05-2008','26-05-2008','25-08-2008','25-12-2008','26-12-2008','01-01-2009','10-04-2009','13-04-2009','04-05-2009','25-05-2009','31-08-2009','25-12-2009','28-12-2009','01-01-2010','02-04-2010','05-04-2010','03-05-2010','31-05-2010','30-08-2010','24-12-2010','27-12-2010','28-12-2010','31-12-2010','03-01-2011','22-04-2011','25-04-2011','29-04-2011','02-05-2011','30-05-2011','29-08-2011','26-12-2011','27-12-2011','01-01-2012','02-01-2012') then 0 else 1 end working_day
from dual
connect by level <= 1825 + sysdate - to_date('01-01-2000') )
SELECT
a.ASM_ID,
a.ASM_START_DATE,
a.ASM_END_DATE,
sum(c.working_day)-1 AS Week_Day
From
O_ASSESSMENTS a
join calendar_cte c
on c.calendar_date between a.ASM_START_DATE and a.ASM_END_DATE
WHERE a.ASM_QSA_ID IN ('TYPE1')
and a.ASM_END_DATE >= '01/01/2012'
GROUP BY
a.ASM_ID,
a.ASM_START_DATE,
a.ASM_END_DATE

There are a few ways to do this. Perhaps the simplest might be to create a CTE that produces a virtual calendar table, based on Oracle's connect by syntax, and then join it to the Assesments table, like so:
with calendar_cte as (
select to_date('01-01-2000')+level-1 calendar_date,
case when to_char(to_date('01-01-2000')+level-1, 'Day')
in ('Sunday ','Saturday ') then 0
when to_date('01-01-2000')+level-1
in ('03-01-2000','21-04-2000','24-04-2000','01-05-2000','29-05-2000','28-08-2000','25-12-2000','26-12-2000','01-01-2001','13-04-2001','16-04-2001','07-05-2001','28-05-2001','27-08-2001','25-12-2001','26-12-2001','01-01-2002','29-03-2002','01-04-2002','06-04-2002','03-06-2002','04-06-2002','26-08-2002','25-12-2002','26-12-2002','01-01-2003','18-04-2003','21-04-2003','05-05-2003','26-05-2003','25-08-2003','25-12-2003','26-12-2003','01-01-2004','09-04-2004','12-04-2004','03-05-2004','31-05-2004','30-08-2004','25-12-2004','26-12-2004','27-12-2004','28-12-2004','01-01-2005','03-01-2005','25-03-2005','28-03-2005','02-05-2005','30-05-2005','29-08-2005','27-12-2005','28-12-2005','02-01-2006','14-04-2006','17-04-2006','01-05-2006','29-05-2006','28-08-2006','25-12-2006','26-12-2006','02-01-2007','06-04-2007','09-04-2007','07-05-2007','28-05-2007','27-08-2007','25-12-2007','26-12-2007','01-01-2008','21-03-2008','24-03-2008','05-05-2008','26-05-2008','25-08-2008','25-12-2008','26-12-2008','01-01-2009','10-04-2009','13-04-2009','04-05-2009','25-05-2009','31-08-2009','25-12-2009','28-12-2009','01-01-2010','02-04-2010','05-04-2010','03-05-2010','31-05-2010','30-08-2010','24-12-2010','27-12-2010','28-12-2010','31-12-2010','03-01-2011','22-04-2011','25-04-2011','29-04-2011','02-05-2011','30-05-2011','29-08-2011','26-12-2011','27-12-2011')
then 0
else 1
end working_day
from dual
connect by level <= 36525 + sysdate - to_date('01-01-2000') )
SELECT a.ASM_ID,
a.ASM_START_DATE,
a.ASM_END_DATE,
sum(c.working_day) AS Week_Day
From O_ASSESSMENTS a
join calendar_cte c
on c.calendar_date between a.ASM_START_DATE and a.ASM_END_DATE
WHERE a.ASM_QSA_ID IN ('TYPE1') and
a.ASM_END_DATE >= '01/01/2012' -- and a.ASM_ID = 'A00000'
GROUP BY
a.ASM_ID,
a.ASM_START_DATE,
a.ASM_END_DATE
This will produce a virtual table populated with dates from 01 January 2000 to 10 years after the current date, with all weekends marked as non-working days and all days specified in the second in clause (ie. up to 27 December 2011) also marked as non-working days.
The drawback of this method (or any method where the holiday dates are hardcoded into the query) is that each time new holiday dates are defined, every single query that uses this approach will have to have those dates added.

If you can't use a calendar table in Oracle, you might be better off exporting to Excel. Brute force always works.
Networkdays() "returns the number of whole working days between start_date and end_date. Working days exclude weekends and any dates identified in holidays."
Excluding weekends seems fairly straightforward. Every 7-day period will contain two weekend days. You'll just need to take some care with the leftover days.
Holidays are a different story. You have to either store them or pass them as an argument. If you could store them, you'd store them in a calendar table, and your problem would be over. But you can't do that.
So you're looking at passing them as an argument. Off the top of my head--and I haven't had any tea yet this morning--I'd consider a common table expression or a wrapper for a stored procedure.

SQL query with week days

I would like to know what is the best way of creating a report that will be grouped by the last 7 days - but not every day i have data. for example:
08/01/10 | 0
08/02/10 | 5
08/03/10 | 6
08/04/10 | 10
08/05/10 | 0
08/06/10 | 11
08/07/10 | 1
is the only option is to create a dummy table with those days and join them altogether?
thank you

Try something like this
WITH LastDays (calc_date)
AS
(SELECT DATEADD(DAY, DATEDIFF(DAY, 0, CURRENT_TIMESTAMP) - 6, 0)
UNION ALL
SELECT DATEADD(DAY, 1, calc_date)
FROM LastDays
WHERE DATEADD(DAY, 1, calc_date) < CURRENT_TIMESTAMP)
SELECT ...
FROM LastDays l LEFT JOIN (YourQuery) t ON (l.cal_date = t.YourDateColumn);

Many people will suggest methods for dynamically creating a range of dates that you can then join against. This will certainly work but in my experience a calendar table is the way to go. This will make the SQL trivial and generic at the cost of maintaining the calendar table.
At some point in the future someone will come along and ask for another report that excludes weekends. You then have to make your dynamic days generation account for weekends. Then someone will ask for working-days excluding public-holidays at which point you have no choice but to create a calendar table.
I would suggest you bite the bullet and create a calendar table to join against. Pre-populate it with every date and if you want to think ahead then add columns for "Working Day" and maybe even week number if your company uses a non-standard week-number for reporting

You don't mention the specific language (please do for a more detailed answer), but most versions of sql have a function for the current date (GetDate(), for instance). You could take that date, subtract x (7) days and build your WHERE statement like that.
Then you could GROUP BY the day-part of that date.

select the last 7 transactions and left join it with your query and then group by the date column. hope this helps.