I need to use the CheckIfPrime item in my code, but having some issue, may i know how should I deal with it? Do I need to make declaration?
For number As Integer = 1 To 30
If CheckIfPrime(number) = True Then
sb.Append(number.ToString & " ")
End If
Next
Please advice on how can I do that in Visual Basic.
The VB.net has no CheckIfPrime method, so to deal with it in your task we need to create a method to check the number if is prime or not.
Public Function CheckIfPrime(number As Integer) As Boolean
For i As Integer = 2 To number - 1
If number Mod i = 0 Then
Return False
End If
Next
Return True
End Function
Usage
For number As Integer = 1 To 30
If CheckIfPrime(number) = True Then
'Console.WriteLine(number.ToString & " ")
sb.Append(number.ToString & " ")
End If
Next
Source
Related
I have done some research and haven't found any similar question.
I have a VBA macro that imports a .CSV file containing telegrams sent by a device.
In the end of this macro, I want to create a graph with the time elapsed on the x-axis and the value corresponding to the telegram.
The issue is that this value can be of different types: hexadecimal, boolean, integer... And that they don't respect the standard Excel number format, which means that they can't be used to create a graph.
Here are some examples (with " around the value to show its start and end) :
hexadecimal : "A7 C8"
Boolean : "$00" or ""$01"
Percentage : "$30"
And here is an example of data, with custom time format and boolean value
Here is my related code so far, where I try to convert into a custom type then convert back to numeric to get a common number datatype :
If wsRes.Range("R1").Value Like "$##" Then
wsRes.Range("R1:R" & plotLine).NumberFormat = "$##"
wsRes.Range("R1:R" & plotLine).NumberFormat = General
End If
If wsRes.Range("R1").Value Like "??[ ]??" Then
Dim valArray(1) As String
For i = 1 To plotLine Step 1
valArray = Split(wsRes.Range("R" & i), " ")
wsRes.Range("R" & i).Value = ToInt32(valArray(0) + valArray(1), 16)
wsRes.Range("" & i).NumberFormat = General
Next i
End If
I haven't been able to test it with hexa yet, but the conversion trick doesn't work with percentage/boolean
EDIT :
First, thank you for your answers.
Here is my final code for anyone's interested, adapted from Vityata's.
This method will allow to easily add other datatypes if needed.
Sub TestMe()
Dim RangeData as String
Set wsRes = ActiveWorkbook.Sheets("Results")
For i = 1 To plotLine Step 1 'plotLine is the last line on which I have data
DetectType wsRes.Range("R" & i).Value, i
Next i
RangeData = "Q1:R" & plotLine
CreateGraph RangeData 'Call My sub creating the graph
End Sub
Public Sub DetectType(str As String, i As Integer)
Select Case True
Case wsRes.Range("R" & i).Value Like "??[ ]??"
wsRes.Range("R" & i).Value = HexValue(str)
Case wsRes.Range("R" & i).Value Like "?##"
wsRes.Range("R" & i).Value = DecValue(str)
Case Else
MsgBox "Unsupported datatype detected : " & str
End
End Select
End Sub
Public Function HexValue(str As String) As Long
Dim valArray(1) As String 'Needed as I have a space in the middle that prevents direct conversion
valArray(0) = Split(str, " ")(0)
valArray(1) = Split(str, " ")(1)
HexValue = CLng("&H" & valArray(0) + valArray(1))
End Function
Public Function DecValue(str As String) As Long
DecValue = Right(str, 2)
End Function
You need three boolean functions, following your business logic and some of the Clean Code principles (although the author of the book does not recognize VBA people as programmers):
IsHex()
IsBoolean()
IsPercentage()
Public Sub TestMe()
Dim myInput As Variant
myInput = Array("A7C8", "$01", "$30")
Dim i As Long
For i = LBound(myInput) To UBound(myInput)
Debug.Print IsHex(myInput(i))
Debug.Print IsBoolean(myInput(i))
Debug.Print IsPercentage(myInput(i))
Debug.Print "-------------"
Next i
'or use this with the DetectType() function below:
'For i = LBound(myInput) To UBound(myInput)
' Debug.Print DetectType(myInput(i))
'Next i
End Sub
Public Function IsHex(ByVal str As String) As Boolean
On Error GoTo IsHex_Error
IsHex = (WorksheetFunction.Hex2Dec(str) <> vbNullString)
On Error GoTo 0
Exit Function
IsHex_Error:
End Function
Public Function IsBoolean(ByVal str As String) As Boolean
IsBoolean = CBool((str = "$00") Or (str = "$01"))
End Function
Public Function IsPercentage(ByVal str As String) As Boolean
IsPercentage = (Len(str) = 3 And Left(str, 1) = "$" And IsNumeric(Right(str, 2)))
End Function
Then some additional logic is needed, because $01 is both Boolean and Percentage. In this case, you can consider it Percentage. This is some kind of a mapper, following this business logic:
Public Function DetectType(str) As String
Select Case True
Case IsHex(str)
DetectType = "HEX!"
Case IsPercentage(str) And IsBoolean(str)
DetectType = "Boolean!"
Case IsPercentage(str)
DetectType = "Percentage!"
Case Else
DetectType = "ELSE!"
End Select
End Function
Working in Excel VBA, I have a class module where I define my class 'Marker'. One of the properties of my class is TextLine(), which is an array that holds up to 5 strings. I have defined the two methods below in my class module. In another (regular) module, I fill markerArr() with my custom Marker objects. Loading each object's properties with data at each array index is working fine... However, after loading data into the object at each index, I try to use markerArr(count).ProcessLines but receive a type mismatch error. Since ProcessLines is a public sub in my class module, and markerArr(count) contains a Marker object, I can't seem to understand why this error is occurring... Am I overlooking something obvious?
'Serial number replacement processing function
Public Sub ProcessLines()
Dim strSerial As String
Dim toggle As Boolean
toggle = False
Dim i As Integer
For i = 0 To 4
If Trim(m_TxtLines(i)) <> "" Then
'Add linefeed char to non-empty text lines
m_TxtLines(i) = m_TxtLines(i) & Chr(10)
'Detect if it is a serialized line
If InStr(1, m_TxtLines(i), "XXXXXX-YYY") > 0 Then
m_Serial(i) = True
toggle = True
End If
End If
Next
'When at least one line on the marker is serialized, create and replace serial text
If toggle = True Then
'Only prompt for input once
If startSerNo < 1 And Num_Sers < 1 Then
startSerNo = InputBox("Enter the serial number to start printing at." & Chr(10) & _
"Entering 1 will result in -001, entering 12 will result in -012, etc.", "Starting Serial #", "1")
Num_Sers = InputBox("Enter the amount of serializations to perform." & Chr(10) & _
"This will control how many copies of the entire marker set are printed.", "Total Serializations", "1")
End If
strSerial = CreateSerial(startSerNo)
Dim j As Integer
For j = 0 To 4
If m_Serial(j) Then
m_TxtLines(j) = Replace(m_TxtLines(j), "XXXXXX-YYY", strSerial)
End If
Next
End If
End Sub
'Creates the string to replace XXXXXX-YYY by concatenating the SFC# with the starting serial number
Private Function CreateSerial(ByVal startNum As Integer)
Dim temp
temp = SFC_Num
Select Case Len(CStr(startNum))
Case 1
temp = temp & "-00" & startNum
Case 2
temp = temp & "-0" & startNum
Case 3
temp = temp & "-" & startNum
Case Else
temp = temp & "-001"
End Select
CreateSerial = temp
End Function
Your CreateSerial function takes an integer as a parameter, but you are attempting to pass a string. I've pointed out some problems:
If startSerNo < 1 And Num_Sers < 1 Then 'Here I assume, you have these semi-globals as a variant - you are using numeric comparison here
startSerNo = InputBox("Enter the serial number to start printing at." & Chr(10) & _
"Entering 1 will result in -001, entering 12 will result in -012, etc.", "Starting Serial #", "1") 'Here startSerNo is returned as a string from the inputbox
Num_Sers = InputBox("Enter the amount of serializations to perform." & Chr(10) & _
"This will control how many copies of the entire marker set are printed.", "Total Serializations", "1") 'here Num_Sers becomes a String too
End If
strSerial = CreateSerial(startSerNo) 'here you are passing a String to the CreateSerial function. Either pass an integer, or allow a variant as parameter to CreateSerial
'......more code.....
Private Function CreateSerial(ByVal startNum As Integer)
Dim ssi(11) As String
For i = 0 To 10
If ssi(i) = "" Then ssi(i) = "0"
For j = 0 To Val(ssi(11)) + i
ssi(i) = xuh(Val(ssi(i)))
Next
Next
If ssi(11) = "2" Then
L_zz.Caption = Val(Left(ssi(0) & ssi(1) & ssi(2) & ssi(3) & ssi(4) & ssi(5) & ssi(6) & ssi(7), ssi(10)))
ElseIf ssi(11) = "3" Then
L_zz.Caption = Val(Left(ssi(0) & ssi(1) & ssi(2) & ssi(3) & ssi(4) & ssi(5) & ssi(6) & ssi(7), ssi(10))) * (-1)
End If
I am new here and new to VB as well.
I am trying to understand this double loop in vb code.
ssi(i) is defined as a String variable. and each element is assigned to a specific number in a String. Hope I told it clearly.
My problem with this loop is below.
Since i ranges from 0 to 10, what does this j mean? Does j mean the new ssi(1-10) or another whatever number?
I think the best way to answer your question about understanding a double loop is to try looking at something simpler.
The first program I always write in each new version of BASIC that comes along is a 12 times table.
I've modified it a bit below to be a 12 x 10 table for the purpose of illustrating for you how a double loop works ... hope it helps:
For x As Integer = 1 To 12
For y As Integer = 1 To 10
Console.Write(x * y)
Console.Write(vbTab)
Next
Console.WriteLine()
Next
I am working on a project which allows kids to send a message to Santa. Unfortunately, if they enter a string instead of an integer in the AGE field, the program crashes and returns Conversion from string "[exampleString]" to type 'Double' is not valid.
Is there any way to check if they have entered an integer or not? This is the code.
If childAge > 0 And childAge < 150 Then
fmSecA2 = "Wow! You are already " & childAge & " years old? You're growing to be a big " & childGender & " now! "
Else
fmSecA2 = "Erm, I couldn't really understand your age. Are you making this up? Ho ho ho!"
End If
Thanks,
Kai :)
A very simple trick is to try parse the string as an Integer. If it succeeds, it is an integer (surprise surprise).
Dim childAgeAsInt As Integer
If Integer.TryParse(childAge, childAgeAsInt) Then
' childAge successfully parsed as Integer
Else
' childAge is not an Integer
End If
Complementing Styxxy's response, if you dont need a result just replace it by vbNull:
If Integer.TryParse(childAge, vbNull) Then
You could perform the following two tests to be reasonably certain that the input you're getting is an integer:
If IsNumeric(childAge) AndAlso (InStr(1, childAge, ".") <> 0) Then
fmSecA2 = "Wow! You are already " & childAge & " years old? You're growing to be a big " & childGender & " now! "
If childAge < 0 OrElse childAge > 150 Then
fmSecA2 = "I don't believe it's possible to be" & childAge & " years old..."
End If
Else
fmSecA2 = "Erm, I couldn't really understand your age. Are you making this up? Ho ho ho!"
The InStr function returns zero if it doesn't find the string that is being looked for, and so when combining that test with IsNumeric, you also rule out the possibility that some floating point data type was entered.
IsNumeric is built into VB, and will return a true/false
If IsNumeric(childAge) AndAlso (childAge > 0 And childAge < 150) Then
fmSecA2 = "Wow! You are already " & childAge & " years old? You're growing to be a big " & childGender & " now! "
Else
fmSecA2 = "Erm, I couldn't really understand your age. Are you making this up? Ho ho ho!"
End If
You can use this.
Sub checkInt()
If IsNumeric(Range("A1")) And Not IsEmpty(Range("A1")) Then
If Round(Range("A1"), 0) / 1 = Range("A1") Then
MsgBox "Integer: " & Range("A1")
Else
MsgBox "Not Integer: " & Range("A1")
End If
Else
MsgBox "Not numeric or empty"
End If
End Sub
Working from Styxxy's answer, if you parse as a byte rather than an integer, then it also checks negative ages and maximum age of 255 all in one go.
Dim childAgeAsByte As Byte
If Byte.TryParse(childAge, childAgeAsByte) Then
' childAge successfully parsed as Byte
Else
' childAge is not a Byte
End If
Kristian
Dim Input
Input = TextBox1.Text
If Input > 0 Then
............................
............................
Else
TextBox2.Text = "Please only enter positive integers"
End If
Try
If TextBox1.Text > 0 Then
Label1.Text = "Integer"
End If
Catch ex As Exception
Label1.Text = "String"
End Try
With this you can put anything in TextBox1, if you put text then you get Label1 is string and if you put number then you get it's integer
In .Net you may use GetType() to determine the data type of a variable.
Dim n1 As Integer = 12
Dim n2 As Integer = 82
Dim n3 As Long = 12
Console.WriteLine("n1 and n2 are the same type: {0}",
Object.ReferenceEquals(n1.GetType(), n2.GetType()))
Console.WriteLine("n1 and n3 are the same type: {0}",
Object.ReferenceEquals(n1.GetType(), n3.GetType()))
' The example displays the following output:
' n1 and n2 are the same type: True
' n1 and n3 are the same type: False
Based on the above sample you can write a code snippet:
If childAge.GetType() = "Integer" then '-- also use childAge.GetType().Name = "Int32"
' do something
End if
Reference MSDN
Is it possible to write an infinite for loop in VB.NET?
If so, what is the syntax?
Do
Something
Loop
For i as Integer = 0 To 1 Step 0
If that's not hacky enough, can also write:
For i As Integer = 0 To 2
i -= 1
Next
or
while (true)
end while
ok, proper For answer:
Dim InfiniteLoop as Boolean = true;
For i = 1 to 45687894
If i = 45687893 And InfiniteLoop = true Then i = 1
End For
Aside from all the many answers given to make a loop run forever, this may just be the first that actually uses the value of Positive Infinity to cap the loop. Just to be safe though, I included an extra option to exit after a given number of seconds so it can measure the speed of your loop.
Sub RunInfinateForLoop(maxSeconds As Integer)
' Attempts to run a For loop to infinity but also exits if maxSeconds seconds have elapsed.
Dim t As Date = Now
Dim exitTime As Date = t.AddSeconds(maxSeconds)
Dim dCounter As Double
Dim strMessage As String
For dCounter = 1 To Double.PositiveInfinity
If Now >= exitTime Then Exit For
Next
strMessage = "Loop ended after " & dCounter.ToString & " loops in " & maxSeconds & " seconds." & vbCrLf &
"Average speed is " & CStr(dCounter / maxSeconds) & " loops per second."
MsgBox(strMessage, MsgBoxStyle.OkOnly, "Infinity Timer")
End Sub
What I do is add a timer then I change the interval to 1 and then I make it enabled then If I want it to constantly check something through the loop I just double click the timer for the timer_tick event then I type what I want. I usually use this for updating the settings if I want it to save every thing.