Firebird cast integer as Time or Date - sql

I have a table which stores an amount of seconds as integer.
I want to display it and use it as Time or Date.
If I write this:
Select Cast(ColAmountofSeconds as Time) as ThisTime From MyTable;
same with:
Select Cast(ColAmountofSeconds as Date) as ThisTime From MyTable;
I get the following error:
Overflow occurred during data type conversion. conversion error from
string "14".
Note "14" is the value of the first row in the ColAmountofSeconds column.
This is so natural in SQL Server, that I can't believe the amount of time I've spent on figuring this out.
EDIT
I can't believe this is the answer:
Update MyTable
Set TIMESPENT = time '00:00:00' + ColAmountOfSeconds;


Firebird cast function does not support converting a numeric value to date, time or timestamp.
You can take advantage of the fact that Firebird supports arithmethic between dates and numeric values, so you can write your query like this:
select dateadd(second, ColAmountOfSeconds, cast('00:00:00' as time))
from myTable;
--or the equivalent:
select cast(cast('2013-01-01' as timestamp) + cast(ColAmountofSeconds as double precision) / 86400 as TIME)
from myTable;

Related

How to get the sum of hour, minutes, and seconds in 2 columns?

I'm using SQL Server as database. I have 2 columns in a table, newTime, oldTime.
Suppose I have value of 04:07:28 in the newTime column, and for oldTime, the value is 03:07:40.
The result should get the total of newTime and oldTime columns which is 07:15:08.
I tried the Split_String() function to easily split the numbers into hours, minutes, and seconds. But I have an issue in database the compatibility level is low and also I tried to set the compatibility_level to 130 but I don't have permission to alter the database.
Is there any other way to sum up the two columns? Thank you!

As mentioned in comments - if you're storing time values, you should really be using the TIME datatype - not a VARCHAR ..... always use the most appropriate datatype - no exceptions.
Anyway - since you have VARCHAR, the statement get a bit convoluted - but here you go:
SELECT
DATEADD(SECOND, DATEDIFF(SECOND, 0, CAST(NewTime AS TIME)), CAST(OldTime AS TIME))
FROM
dbo.YourTableNameHere
which would look a lot easier with TIME columns, of course:
SELECT
DATEADD(SECOND, DATEDIFF(SECOND, 0, NewTime), OldTime)
FROM
dbo.YourTableNameHere

i just want to get past 3 months transaction

need help. i just want to get past 3 months transaction.
SELECT *
FROM transaction
WHERE TransactionDate >= GETDATE()-90
transactionDate is a INT type with this format YYYYMMDD (ex. 20160812)
i got this error
Arithmetic overflow error converting expression to data type datetime.
any help will do

You can't convert an int directly to a date. However, you can convert a string in YYYYMMDD format. So, try this:
WHERE cast(cast(TransactionDate as varchar(255)) as date) >= GETDATE() - 90
Alternatively, you could do all the conversion on the current date side:
WHERE TransactionDate >= CONVERT(INT, CONVERT(VARCHAR(255), GETDATE() - 90, 112))
The advantage of this method is that the engine can use an index on TransactionDate.
That said, the right way to store the column is as a DATE. SQL Server has built-in date/time data types for a reason; there is a lot of direct support for them. Use the capabilities of the database.

Pass a column as parameter to dateadd in SQL Server

I want to convert a column of UTC time to local time.
My data looks like this:
time_utc TZID timezone
------------------------------------------------
2014-02-27 12:00:39.0 America/Toronto -5
2013-05-21 09:35:30.0 America/Goose_Bay -4
2015-01-08 06:58:58.0 America/Creston -7
I know that using
select *, DATEADD(hour, 5,time_utc)
from mytable
will add 5 hours to column time_utc.
However, as you can see, I have a variable time zone column.
How can I pass this variable to the dateadd function?
I tried the following 2 commands but they don't work:
Attempt #1:
select *, DATEADD(hour, timezone, time_utc)
from mytable
Attempt #2:
select *, DATEADD(hour, (select timezone from mytable), time_utc)
from mytable
Both throws this error:
Argument data type varchar is invalid for argument 2 of dateadd function. [SQL State=S0001, DB Errorcode=8116]
For decimal values of timezone, for instance -3.5, how would this work?
Thanks

How can I pass this variable to datetime function?
Just reference the column in the function call:
select *, DATEADD(hour, timezone, time_utc)
from mytable
For decimal values of timezone, for instance -3.5, how would this work?
The "number" parameter of DATEADD takes an integer, so you'd have to change to minutes and scale the hour offset. Since your timezone colume is apparently a varchar column, convert it to a decimal value as well:
select *, DATEADD(minute, cast(timezone as decimal(4,2)) * 60 , time_utc)
from mytable

There is a character value (most probably blank) in your dataset. Sql does implicity conversion but for non numeric value it will fail. Check your table to see if you have blanks or non numeric values for timezone

Informix SQL Compare DateTime value on Where Statement

I have a datetime field called entrytimestamp, with content of the field is for example: 2014-01-07 16:20:00. I would like to query all the data that has entrytimestamp after 09:00:00 o'clock, regardless what date it was.
I have a prototype query:
select *
from trading
where to_char(entrytimestamp, "%H%M%S") >= "090000"
But I think it is logically a mistake, because it will compare the text string, not the sequence value. What is the right way to do it?

Use the EXTEND() function to extract the time part:
select *
from mytable
where extend(entrytimestamp, hour to second) > '09:00:00'

I dont know if it performs well,
but you could compare directly with the time portion of the datetime,
i think a cast here should perform pretty fast (just cuts off the date)
select *
from (select getdate() as mydatetime) as data
where cast(mydatetime as time) > cast('09:00:00' as time)
EDIT, just noticed this was for Informix SQL, so not sure it works then, Sorry

convert Excel Date Serial Number to Regular Date

I got a column called DateOfBirth in my csv file with Excel Date Serial Number Date
Example:
36464
37104
35412
When i formatted cells in excel these are converted as
36464 => 1/11/1999
37104 => 1/08/2001
35412 => 13/12/1996
I need to do this transformation in SSIS or in SQL. How can this be achieved?

In SQL:
select dateadd(d,36464,'1899-12-30')
-- or thanks to rcdmk
select CAST(36464 - 2 as SmallDateTime)
In SSIS, see here
http://msdn.microsoft.com/en-us/library/ms141719.aspx

The marked answer is not working fine, please change the date to "1899-12-30" instead of "1899-12-31".
select dateadd(d,36464,'1899-12-30')

You can cast it to a SQL SMALLDATETIME:
CAST(36464 - 2 as SMALLDATETIME)
MS SQL Server counts its dates from 01/01/1900 and Excel from 12/30/1899 = 2 days less.

tldr:
select cast(#Input - 2e as datetime)
Explanation:
Excel stores datetimes as a floating point number that represents elapsed time since the beginning of the 20th century, and SQL Server can readily cast between floats and datetimes in the same manner. The difference between Excel and SQL server's conversion of this number to datetimes is 2 days (as of 1900-03-01, that is). Using a literal of 2e for this difference informs SQL Server to implicitly convert other datatypes to floats for very input-friendly and simple queries:
select
cast('43861.875433912' - 2e as datetime) as ExcelToSql, -- even varchar works!
cast(cast('2020-01-31 21:00:37.490' as datetime) + 2e as float) as SqlToExcel
-- Results:
-- ExcelToSql SqlToExcel
-- 2020-01-31 21:00:37.490 43861.875433912

this actually worked for me
dateadd(mi,CONVERT(numeric(17,5),41869.166666666664)*1440,'1899-12-30')
(minus 1 more day in the date)
referring to the negative commented post

SSIS Solution
The DT_DATE data type is implemented using an 8-byte floating-point number. Days are represented by whole number increments, starting with 30 December 1899, and midnight as time zero. Hour values are expressed as the absolute value of the fractional part of the number. However, a floating point value cannot represent all real values; therefore, there are limits on the range of dates that can be presented in DT_DATE. Read more
From the description above you can see that you can convert these values implicitly when mapping them to a DT_DATE Column after converting it to a 8-byte floating-point number DT_R8.
Use a derived column transformation to convert this column to 8-byte floating-point number:
(DT_R8)[dateColumn]
Then map it to a DT_DATE column
Or cast it twice:
(DT_DATE)(DT_R8)[dateColumn]
You can check my full answer here:
Is there a better way to parse [Integer].[Integer] style dates in SSIS?

Found this topic helpful so much so created a quick SQL UDF for it.
CREATE FUNCTION dbo.ConvertExcelSerialDateToSQL
(
#serial INT
)
RETURNS DATETIME
AS
BEGIN
DECLARE #dt AS DATETIME
SELECT #dt =
CASE
WHEN #serial is not null THEN CAST(#serial - 2 AS DATETIME)
ELSE NULL
END
RETURN #dt
END
GO

I had to take this to the next level because my Excel dates also had times, so I had values like this:
42039.46406 --> 02/04/2015 11:08 AM
42002.37709 --> 12/29/2014 09:03 AM
42032.61869 --> 01/28/2015 02:50 PM
(also, to complicate it a little more, my numeric value with decimal was saved as an NVARCHAR)
The SQL I used to make this conversion is:
SELECT DATEADD(SECOND, (
CONVERT(FLOAT, t.ColumnName) -
FLOOR(CONVERT(FLOAT, t.ColumnName))
) * 86400,
DATEADD(DAY, CONVERT(FLOAT, t.ColumnName), '1899-12-30')
)

In postgresql, you can use the following syntax:
SELECT ((DATE('1899-12-30') + INTERVAL '1 day' * FLOOR(38242.7711805556)) + (INTERVAL '1 sec' * (38242.7711805556 - FLOOR(38242.7711805556)) * 3600 * 24)) as date
In this case, 38242.7711805556 represents 2004-09-12 18:30:30 in excel format

In addition of #Nick.McDermaid answer I would like to post this solution, which convert not only the day but also the hours, minutes and seconds:
SELECT DATEADD(s, (42948.123 - FLOOR(42948.123))*3600*24, dateadd(d, FLOOR(42948.123),'1899-12-30'))
For example
42948.123 to 2017-08-01 02:57:07.000
42818.7166666667 to 2017-03-24 17:12:00.000

You can do this if you just need to display the date in a view:
CAST will be faster than CONVERT if you have a large amount of data, also remember to subtract (2) from the excel date:
CAST(CAST(CAST([Column_With_Date]-2 AS INT)AS smalldatetime) AS DATE)
If you need to update the column to show a date you can either update through a join (self join if necessary) or simply try the following:
You may not need to cast the excel date as INT but since the table I was working with was a varchar I had to do that manipulation first. I also did not want the "time" element so I needed to remove that element with the final cast as "date."
UPDATE [Table_with_Date]
SET [Column_With_Excel_Date] = CAST(CAST(CAST([Column_With_Excel_Date]-2 AS INT)AS smalldatetime) AS DATE)
If you are unsure of what you would like to do with this test and re-test! Make a copy of your table if you need. You can always create a view!

Google BigQuery solution
Standard SQL
Select Date, DATETIME_ADD(DATETIME(xy, xm, xd, 0, 0, 0), INTERVAL xonlyseconds SECOND) xaxsa
from (
Select Date, EXTRACT(YEAR FROM xonlydate) xy, EXTRACT(MONTH FROM xonlydate) xm, EXTRACT(DAY FROM xonlydate) xd, xonlyseconds
From (
Select Date
, DATE_ADD(DATE '1899-12-30', INTERVAL cast(FLOOR(cast(Date as FLOAT64)) as INT64) DAY ) xonlydate
, cast(FLOOR( ( cast(Date as FLOAT64) - cast(FLOOR( cast(Date as FLOAT64)) as INT64) ) * 86400 ) as INT64) xonlyseconds
FROM (Select '43168.682974537034' Date) -- 09.03.2018 16:23:28
) xx1
)

For those looking how to do this in excel (outside of formatting to a date field) you can do this by using the Text function https://exceljet.net/excel-functions/excel-text-function
i.e.
A1 = 132134
=Text(A1,"MM-DD-YYYY") will result in a date

This worked for me because sometimes the field was a numeric to get the time portion.
Command:
dateadd(mi,CONVERT(numeric(17,5),41869.166666666664)*1440,'1899-12-31')