Get Count for each Joined Record - sql

I have 2 tables which I'd like to join and..
A:
ID Otherfields..
1 ...
2
3
4
B:
ID aId Otherfields..
1 1 ...
2 1
3 2
4 1
So I'm perfectly capable of joining them by a.Id but how do get I get the count for the matches in Table B, like:
a.id count(b)
1 3
2 1
I figured it must be something with count() over() but cannot recall the exact use.
Thanks!

You can simply do this:
SELECT
A.ID, COUNT(b.ID)
FROM A
INNER JOIN B ON A.Id = b.aID
GROUP BY A.ID

You can have
SELECT A.ID, COUNT(b.ID)
FROM A
LEFT JOIN B ON A.Id = b.aID
GROUP BY A.ID
This will give you all a.IDs that don't exist in b.ID and hence show their count as 0.
E.g.,
ID Count
1 3
2 1
3 0
4 0

Related

how to execute query for each row result of another query

I have 2 tables , one stores IDs and another logs for each ID , i would like to get sum of log for each ID and ID number from these 2 tables
A B
------- -------------
ID ID_C LOG
1 1 15
2 1 30
3 4 44
4 2 14
5 3 88
3 10
2 10
for getting sum query is
SELECT SUM(LOG) FROM B WHERE ID_C ='2' ;
notice ID and ID_C are same but name is different in tables
and for getting all ids available query is
SELECT ID FROM A ;
I would like to get the following table result
result
--------------------
ID SUM
1 45
4 44
2 24
3 98
I tried
SELECT SUM(LOG) FROM B WHERE ID_C in (SELECT ID FROM A ) ;
but it result in sum of all IDs
It looks like you just need a join aggregation here:
SELECT a.ID, SUM(b.LOG) AS SUM
FROM A a
INNER JOIN B b
ON b.ID_C = a.ID
GROUP BY a.ID
ORDER BY a.ID;
Note that the inner join will also remove ID values from the A table which no entries whatsoever in the B table, which seems to be the behavior you want.
you should use inner join and GROUP BY:
SELECT A.ID as ID, SUM(LOG) AS SumLOG
FROM A inner join B ON A.ID = B.ID_C
GROUP BY A.ID
if you needed can use where for ID filter.

Update a table with data from another not related table

I have three tables A,B and C.
A and B are connected a foreign key A.category_id=B.id ,
A and C have the same number of rows.
A
id category_id value1 value2
1 null 'A' null
2 null 'B' null
3 null 'C' null
4 null 'D' null
B
id category
1 0
2 1
C
id category
1 0
2 1
3 1
4 0
Expected result:
A
id value
1 1
2 2
3 2
4 1
I would like to receive updated A table where category_id will be id from table B based on table C category.
I have tried
UPDATE A SET
A.category_id = (
select B.id from A
left JOIN C
ON A.id = C.id
left join B on B.category=C.category
)
WHERE A.id IN (SELECT C FROM C WHERE A.id = C.id);
but then I received ORA-01427 single-row subquery returns more than one row tips
You are missing a correlation clause in the subquery:
update A
set category_id = (select B.id
from C join
B
on B.category = C.category
where A.id = C.id
)
where exists (select 1 from C where A.id = C.id);
To correlated a query, you refer to the outer reference typically in a where condition. You don't repeat the table reference in the from clause.
Note that an outer join is unnecessary. If there is no match, the value will be NULL.

SQL apply different where condition (filter) for each group in table

i have following SQL table A in my database:
index, group, foo
1 A 2
2 A 2
3 A 0
4 A 1
5 B 2
6 B 1
7 C 1
There are few more groups and I need to write a query based on this filter table B. For each group in table A it's index should be equal or greater than index_egt from table B for the same group.
If the group is not listed in table B, the group won't be filtered.
index_egt, group
3 A
5 B
Expected result:
index, group, foo
3 A 0
4 A 1
5 B 2
6 B 1
7 C 1
Try this, the A.index>=B.index_egt will handle cases where the group is listed in TableB and the B.index_egt IS NULL will handle cases where the group is not listed:
SELECT
A.index,
A.group,
A.foo
FROM TableA AS A
LEFT JOIN TableB AS B ON A.group=B.group
WHERE A.index>=B.index_egt
OR B.index_egt IS NULL
select
a.*
from
A a
left join
B b ON b.group = a.group
where
a.index >= b.index_egt OR b.index_egt IS NULL
I always like this trick with coalesce
SELECT a.*
FROM a_table_with_no_name a
LEFT JOIN b_table_with_no_name b ON b.group = a.group
WHERE a.index >= COALESCE(b.index_egt,a.index)

How to find difference of two columns using in Left Outer Join in SQL Sever 2005?

I have two Tables
Let suppose A and B
Now suppose the structure of table A is Like that
id stock
37 1
40 1
37 1
40 1
37 1
37 1
And B is like that
id stock
37 1
37 1
40 1
Now i want to write a query that give me sum of specific id stock in (table A - Table B) and if that id does not exist in table B then only stock from A.
So i will expect result like that
id stock
40 1
37 2
I thought that left join will be possible option here and i write query like that
SELECT A.id,
SUM(CAST(isNull(A.Stock, 0) as int) - CAST(isNull(B.Stock, 0) as int) )'Stock'
from A
LEFT OUTER JOIN
B
ON A.id = B.id
group by A.id
But Problem is that the above query gives desired records but wrong quantity/Stocklevel as shown below:
id stock
37 0
40 1
How can I resolve Stock Level issue.
I guess you are looking for something like this.
select A.id, A.SumA - coalesce(B.SumB, 0) as stock
from (
select A.id, sum(A.stock) as SumA
from A
group by A.id
) as A
left outer join
(
select B.id, sum(B.stock) as SumB
from B
group by B.id
) as B
on A.id = B.id
Result:
id stock
----------- -----------
37 2
40 1
SE Data
SELECT A.id, A.Stock - isNull(B.stock, 0) as Stock from A
LEFT OUTER JOIN B
ON A.id = B.id
That would be it I think.
PS. you group by something that you did not include in your case scenario. Your expected result is also not understandable to me (it conflicts with your problem description)

sql query for 3 tables

i have 3 tables (A,B,C)
Table A -
ID Name
1 Sam
2 Manuel
3 Jane
Table B
ID Tab_A_ID Name
1 1 Meer
2 1 Kutti
3 2 Mikaro
Table C
ID Tab_B_ID Price
1 1 255.11
2 1 30.52
3 3 125.22
I need a query that shall pick up the top price for TableA-Name from TableC. So only 1 top price for 1 nae record.
e.g.-
Sam - 255.11
Manuel - 125.22
How can i get this?
To get the max price per entry in A:
SELECT a.Name,
MAX(c.price)
FROM a
INNER JOIN b
ON a.id = b.tab_a_id
INNER JOIN c
ON b.id = c.tab_b_id
GROUP BY a.id, a.name
To get the max price per entry A per entry B:
SELECT a.Name,
b.Name
MAX(c.price)
FROM a
INNER JOIN b
ON a.id = b.tab_a_id
INNER JOIN c
ON b.id = c.tab_b_id
GROUP BY a.id, b.id, a.name, b.name
Note that entries in A without corresponding entires in B or entries in B without corresponding entries in C will not appear in the result. Use LEFT JOIN if you want to include these in the result.