I am new to Laravel and I am trying to add some more information to the user variable I am getting back from Auth::user()
To be more detailed, I have a Many-to-Many relationship to a "Privileges" table. As the name suggests, that table holds specific privileges a user can have. In the pivot table, I just hold the the user_id and privilege_id. I have the necessary models set up and everything works fine if I do this in my before filter:
$user = Auth::user();
$user->priviledges()->get();
Now, I would really like to avoid querying every single time I want to find the privileges and would like to have Laravel's Auth class include the privilege information, so that when I do
$user = Auth::user();
I can do a
$user->privileges;
to get an array of all privileges the user has.
Any suggestions for the best approach?
The link to the answer above is not working. However, I found another solution here which worked for me as follows:
First I created a model called EmailPref.php in my own case;
app/model/EmailPref.php
class EmailPref extends Eloquent {
protected $table = 'email_pref';
public function user()
{
return $this->belongsTo('User');
}
}
and then I created a relationship (in my own case) in the User model like so;
app/model/User.php
public function emailPref()
{
return $this->hasOne('EmailPref');
}
I subsequently referenced it anywhere required within my application like so:
Auth::user()->emailPref;
Hence, I was able to add more information to the Auth user.
I'm no Laravel pro, but i think this will solve your problem: http://forums.laravel.io/viewtopic.php?id=1652
Related
I wrote a sql script and in it I created a table ;
Now I need to know ,how I can execute this script? (with which codes?)
And I have another question : where? where I must write this codes?(which folder in zend project?)
if it is possible for you please explain with an example.thanks
Creating tables in the database
Zend Framework is not supposed to be the one creating the tables, thus, my suggestion is to run those scripts in other environment.
The fastest one is, probably, the very own SQL shell, but you can use another software such as MySQLWorkbench if you are using MySQL.
Once the tables are created, the access to the tables is made this way:
Introduction
When you are using Zend Framework, you are making use of the MVC pattern. I suggest you to read what is that: Wikipedia MVC
If you read the Wikipedia link, you probably know now that the acess to the database is going to be made by the model.
Thus, if you followed the recommended project structure that Zend provides you will have a models folder under your application folder. There, you are supposed to implement the classes that will make access to the DB.
But well... you now know where to locate those classes but you will ask me: how? It's easy if you know where to search. ZF provides an abstract class called Zend_Db_Table_Abstract that has all the methods that will make your life easier talking about interaction with your database's tables. This is the class that your classes should implement.
Example
Let's suppose you've got a page in your website in which you want to show to the user a list of products of your local store. You have a table in your database called "products" in which you have all the useful information such us name, price and availability.
You will have a controller with an action called indexAction() or listAction() this action is prepared to send the data to your view and will look like:
class Store_ProductsController extends Zend_Controller_Action {
public function indexAction(){
//TODO: Get data from the DataBase into $products variable
$this->view->products = $products;
}
}
And your view file will that that products variable and do sutff with it.
But now comes the magic, you will have a class that will access to the database as I've said, it'll be like:
class Model_Store_Products extends Zend_Db_Table_Abstract{
protected $_name = 'products';
public function getAllProducts(){
$select = $this->$select()
->from(array('P'=>$this->_name),
array('id', 'name', 'price', availability));
$productsArray = $this->fetchAll($select);
return $productsArray;
}
}
And ta-da, you have your array of products ready to be used by the controller:
class Store_ProductsController extends Zend_Controller_Action {
public function indexAction(){
$model = new Model_Store_Products();
$products = $model->getAllProducts();
$this->view->products = $products;
}
}
It can be said that, since fetchAll is public function, and our select does basically nothing but set which columns do we want (it doesn't even have a where clause), in this case, it would be easier to call the fetchAll directly from the controller with no where and it will recover the whole table (all columns):
class Store_ProductsController extends Zend_Controller_Action {
public function indexAction(){
$model = new Model_Store_Products();
$products = $model->fetchAll();
$this->view->products = $products;
}
}
Thus, our function in the model is not even needed.
This is the basic information of how to access to the database using Zend Framework. Further information of how to create the Zend_Db_Table_Select object can be found here.
I hope this helps.
I have a User, Role & Page setup, all with many-to-many relationships and the pivot tables setup in the usual fashion (role_user, page_role), along with the eloquent methods to attach a model to the pivot tables.
My idea is to allow a user to have many roles, and a page can be accessed by many roles.
However now I'd like to return a collection where I have my users details and then the pages they're allowed to access.
The closest I have got is:
return User::find( Auth::user()->id )->with('roles.pages')->first()->roles;
Now this returns each role the user has, and each page that the role can access. Which is correct, however I have duplication on the pages part.
How would I go about getting only a list of pages the user is able to access with no duplication?
Cheers
Read that answer to get you on the track: HasManyThrough with one-to-many relationship
Only for your setup you need to adjust the query - join 2 pivot tables (and make sure they represent real data, ie no rows referencing non-existing models):
// User model
// accessor so you can access it like any relation: $user->pages;
public function getPagesAttribute()
{
if ( ! array_key_exists('pages', $this->relations)) $this->loadPages();
return $this->getRelation('pages');
}
// here you load the pages and set the collection as a relation
protected function loadPages()
{
$pages = Page::join('page_role as pr', 'pr.page_id', '=', 'pages.id')
->join('role_user as ru', 'ru.role_id', '=', 'pr.role_id')
->where('ru.user_id', $this->id)
->distinct()
->get(['pages.*', 'user_id']);
$hasMany = new Illuminate\Database\Eloquent\Relations\HasMany(Page::query(), $this, 'user_id', 'id');
$hasMany->matchMany(array($this), $pages, 'pages');
return $this;
}
One more thing: I hardcoded tables and columns names for sake of simplicity, but in real life I suggest you rely on the relationships and their getters, like: $relation->getTable(), $relation->getForeignKey() etc.
Now suggestion about your code:
return User::find( // 2. query to get the same user
Auth::user()->id // 1. query to get the user and his id
)->with('roles.pages')
->first() // 3. query to get ANOTHER user (or the same, luckily..)
->roles;
Use Auth::id() instead of Auth::user()->id (for Laravel ver 4.1.25+) to avoid redundant query
find() and first() are methods that execute the query, so you just returned the user with id = Auth::user()->id and moment later you fetch another one, who comes first() from the users table..
You don't need to use User::whatever for authenticated user, use Auth::user() instead.
So the code with suggested solution would look like this:
Auth::user()->pages; // collection of Page models with unique entries
I've been reading the docs but I"m not sure how to do this. http://doc.laravelbook.com/eloquent/#many-to-many
Say I have a users, roles, and a pivot table.
I have belongsToMany set up for both Role and User
In a controller, I want to get a user_id and return what roles they have of a specific type only.
(There is also a role type table, but I can work with the IDs directly).
I start something like this
$specific_type_role = Role::where('role_type_id', 3)::where(?$user_id?)
//need to involve
$circle_users = RoleUser::where('user_id', $user_id)->get();
but I think it should be able to be done automatically. don't know how to include the filter right in the query.
Not sure if it's that what you need but, you probably will be able to do something like that:
public function getAdminRoles()
{
$user = User::find(1);
return $user->roles()->where('role_type_id', 1)->get();
}
I am using native CDbAuthManager to implement RBAC in my webapp. How can I get all the users who has permission to do a role? Suppose I have role named updateprofile. I want to get all the users assigned to that role. I searched the documentation and couldnt find a function.
(I know i can iterate through all user models and do a checkAccess() in a foreach loop, but I prefer a nicer solution )
The easiest way I've found to do this is to create an AuthAssignment model that maps to your auth_assignment table. Then, you can setup relationships, scopes, etc for it and query using it to retrieve all user models. There isn't anything particularly special about the auth_assignment table (as it is mainly just roles in there).
code like
class AuthAssginment extends CActiveRecord{.....
public function getUsersBaseOnRole($role) {
return Yii::app()->db->createCommand()
->select('userid')
->from($this->tableName())
->where('itemname=:role', array(
':role' => $role,))
->queryAll() ;
}....
I think the other replies do not give you the perfect result because roles can be hierarchical and so, you cannot use direct queries or relations. My solution which works well is:
// list all users with 'userManagement' role
if($users = Users::model()->findAll()) {
foreach($users as $id => $user) {
if(!$user->checkAccess('userManagement')) {
unset($users[$id]);
}
}
$users = array_values($users); // to reset indices (optional)
}
Is it possible to create a filter in a Drupal 6 View that is only applied for registered users?
For one filter I need I'm using the user vote (With fivestar and votingapi) to know if they user already voted this node or not, and when the user is annonymous, is working as if all the votes from all the annonymous users where from the same. This is why I need to add this filter, but ignore it in case the user is annonymous.
Thanks a lot in advance for the help!
If you're comfortable with php, download the Views PHP Filter module (http://drupal.org/project/viewsphpfilter). This module allows you to easily write your own custom filters for any view.
After downloading and enabling the module, create a new view and add a "Node: Node ID PHP handler" filter. Now you can add custom php code for any filter you want. Perhaps something like:
global $user;
$allowed = array('authenticated user');
foreach ($user->role as $role) {
if (in_array($role, $allowed)) {
$nids = //Run custom filter query for allowed users
}
else {
$nids = //Run alternate filter query for anonymous users
}
}
return $nids;
The code should return a list of node ids to display.