As written in the title: How to write this SQL statement correctly?
select
sl.switch_ip,
sl.switch_name,
count(m.switch_ip) as macentries,
(select arpentries from (select sl1.switch_ip, sl1.switch_name, count(ar.switch_ip) as arpentries
from my_switchlist sl1
left Join my_arptable ar on ar.switch_ip = sl1.switch_ip
group by sl1.switch_ip,sl1.switch_name
order by sl1.switch_ip))
from my_switchlist sl
left Join my_mactable m on m.switch_ip = sl.switch_ip
group by sl.switch_ip,sl.switch_name
order by sl.switch_ip
The select and the sub-select work fine if they are executed separately.
But as soon as I put them together I get the following error:
Error: A subquery has returned not exactly one row.
SQLState: 21000
ErrorCode: -284
Position: 470
Looks like you want both the 'count' aggregates, which should be possible with something like this:
select
macquery.switch_ip,
macquery.switch_name,
macquery.macentries,
arpquery.arpentries
from
(
select
sl.switch_ip as switch_ip,
sl.switch_name as switch_name,
count(m.switch_ip) as macentries
from my_switchlist sl
left outer join my_mactable m
on m.switch_ip = sl.switch_ip
group by
sl.switch_ip,
sl.switch_name
) macquery
join
(
select
sl1.switch_ip as switch_ip,
sl1.switch_name as switch_name,
count(ar.switch_ip) as arpentries
from my_switchlist sl1
left outer join my_arptable ar
on ar.switch_ip = sl1.switch_ip
group by
sl1.switch_ip,
sl1.switch_name
) arpquery
on (macquery.switch_ip = arpquery.switch_ip
and macquery.switch_name = arpquery.switch_name)
Probably there are more than one "sl1.switch_ip,sl1.switch_name" groups in your "my_switchlist, my_arptable" join.
select arpentries from (select sl1.switch_ip, sl1.switch_name, count(ar.switch_ip) as arpentries
from my_switchlist sl1
left Join my_arptable ar on ar.switch_ip = sl1.switch_ip
group by sl1.switch_ip,sl1.switch_name
order by sl1.switch_ip)
The above query should not return more than one result in order you to use its result in your outer query. So probably there is more than one "sl1.switch_ip,sl1.switch_name" group.
Related
EDIT:
The result supposed to be like this:
desired result
I have this query:
SELECT DISTINCT mitarbeiter.mitarbnr, mitarbeiter.login, mitarbeiter.name1, mitarbeiter.name2
FROM vertragspos
left join vertrag_ek_vk_zuord ON vertragspos.id = vertrag_ek_vk_zuord.ek_vertragspos_id
left join mitarbeiter ON vertrag_ek_vk_zuord.anlage_mitarbnr = mitarbeiter.mitarbnr
left join vertragskopf ON vertragskopf.id = vertragspos.vertrag_id
left join
(
SELECT wkurse.*, fremdwaehrung.wsymbol
FROM wkurse
INNER join
(
SELECT lfdnr, Max(tag) AS maxTag
FROM wkurse
WHERE tag < SYSDATE
GROUP BY lfdnr
) t1
ON wkurse.lfdnr = t1.lfdnr AND wkurse.Tag = t1.maxTag
INNER JOIN fremdwaehrung ON wkurse.lfdnr = fremdwaehrung.lfdnr
) wkurse ON vertragskopf.blfdwaehrung = wkurse.lfdnr
left join
(
SELECT vertrag_ID, Sum (preis) preis, Sum (menge) menge, Sum (preis * menge / Decode (vertragskopf.zahlintervall, 1,1,2,2,3,3,4,6,5,12,1) / wkurse.kurs) vertragswert
FROM vertragspos
GROUP BY vertrag_ID
) s ON vertragskopf.id = s.vertrag_id
But I always get an error on line 21 Pos 145:
ORA-00904 WKURSE.KURS invalid identifier
The WKURSE table is supposed be joined already above, but why do I still get error?
How can I do join with all these tables?
I need to join all these tables:
Mitarbeiter, Vertragspos, vertrag_ek_vk_zuord, wkurse, fremdwaehrung, vertragskopf.
What is the right syntax? I'm using SQL Tool 1,8 b38
Thank you.
Because LEFT JOIN is executed on entire dataset, and not in row-by-row manner. So there's no wkurse.kurs available in the execution context of subquery. Since you join that tables, you can place the calculation in the top-most select statement.
EDIT:
After you edited the statement, it became clear where does vertragskopf.zahlintervall came from. But I don't know where are you going to use calculated vertragswert (now it is absent in the query), so I've put it in the result. As I'm not a SQL parser and have no idea of your tables, so I cannot check the code, but calculation now can be resolved (all the values are available in calculation context).
SELECT DISTINCT mitarbeiter.mitarbnr, mitarbeiter.login, mitarbeiter.name1, mitarbeiter.name2, s.amount / Decode (vertragskopf.zahlintervall, 1,1,2,2,3,3,4,6,5,12,1) / wkurse.kurs) vertragswert
FROM vertragspos
left join vertrag_ek_vk_zuord ON vertragspos.id = vertrag_ek_vk_zuord.ek_vertragspos_id
left join mitarbeiter ON vertrag_ek_vk_zuord.anlage_mitarbnr = mitarbeiter.mitarbnr
left join vertragskopf ON vertragskopf.id = vertragspos.vertrag_id
left join (
SELECT wkurse.*, fremdwaehrung.wsymbol
FROM wkurse
INNER join (
SELECT lfdnr, Max(tag) AS maxTag
FROM wkurse
WHERE tag < SYSDATE
GROUP BY lfdnr
) t1
ON wkurse.lfdnr = t1.lfdnr AND wkurse.Tag = t1.maxTag
INNER JOIN fremdwaehrung ON wkurse.lfdnr = fremdwaehrung.lfdnr
) wkurse ON vertragskopf.blfdwaehrung = wkurse.lfdnr
left join (
SELECT vertrag_ID, Sum (preis) preis, Sum (menge) menge, Sum (preis * menge) as amount
FROM vertragspos
GROUP BY vertrag_ID
) s ON vertragskopf.id = s.vertrag_id
Rewriting the code using WITH clause makes it much clearer than select from select.
Also get the rate on last day before today in oracle is as simple as
select wkurse.lfdnr
, max(wkurse.kurs) keep (dense_rank first order by wkurse.tag desc) as rate
from wkurse
where tag < sysdate
group by wkurse.lfdnr
One option is a lateral join:
left join lateral
(SELECT vertrag_ID, Sum(preis) as preis, Sum(menge) as menge,
Sum (preis * menge / Decode (vertragskopf.zahlintervall, 1,1,2,2,3,3,4,6,5,12,1) / wkurse.kurs) vertragswert
FROM vertragspos
GROUP BY vertrag_ID
) s
ON vertragskopf.id = s.vertrag_id
Anybody know why this isn't working? I'm getting: ERROR: syntax error at or near "most_recent"
with most_recent as (SELECT MAX(public."Master_playlist".updated_at)
FROM public."Master_playlist")
SELECT * from public."Playlist"
JOIN public."Master_playlist_playlist" on public."Playlist".id = public."Master_playlist_playlist".playlist_id
JOIN public."Master_playlist" on public."Master_playlist_playlist".master_playlist_id = public."Master_playlist".id
WHERE public."Master_playlist".updated_at = most_recent;
Supposed to be getting the most recent date from Master_playlist and then using that to select a Master_playlist to join the inner query with
Thanks! HM
The with clause creates a derived table, which you need select from, using a join or a subquery. You also need to alias the column so you can refer to it afterwards, as in:
with most_recent as (
SELECT MAX(updated_at) max_updated_at
FROM public."Master_playlist"
)
SELECT *
from public."Playlist"
JOIN public."Master_playlist_playlist"
on public."Playlist".id = public."Master_playlist_playlist".playlist_id
JOIN public."Master_playlist"
on public."Master_playlist_playlist".master_playlist_id = public."Master_playlist".id
WHERE public."Master_playlist".updated_at = (SELECT max_updated_at FROM most_recent)
But here, it looks like it is simpler to use a row-limiting query:
select ...
from (
select *
from public."Master_playlist"
order by updated_at desc
limit 1
) mp
inner join public."Master_playlist_playlist" mpp
on mpp.master_playlist_id = mp.id
inner join public."Playlist" p
on p.id = mpp.playlist_id
I'm trying to get a top 1 returned for each code in this query but this is giving me syntax errors. Any ideas what I can do?
SELECT d.doc_no,
d.doc_short_name,
d.doc_name,
r.revision_code,
r.revision,
r.description,
dtg.group_name,
(SELECT top 1 di.index_user_id
FROM document_instance
WHERE doc_no = d.doc_no
ORDER BY entry_time DESC) AS 'last indexed by'
FROM documents d
LEFT JOIN document_revision r ON r.doc_no = d.doc_no
LEFT JOIN document_instance di ON di.doc_no = d.doc_no
LEFT JOIN document_type_group dtg ON dtg.doc_no = d.doc_no
Assuming Sybase ASE, the top # clause is only supported in derived tables, ie, it's not supported in correlated sub-queries like you're attempting.
Also note that order by is not supported in any sub-queries (derived table or correlated).
If I'm reading the query correctly, you want the index_user_id for the record with the max(entry_time); if this is correct, and assuming a single record is returned for a given doc_no/entry_time combo, you could try something like:
SELECT d.doc_no,
d.doc_short_name,
d.doc_name,
r.revision_code,
r.revision,
r.description,
dtg.group_name,
(SELECT d2.index_user_id
FROM document_instance d2
WHERE d2.doc_no = d1.doc_no
and d2.entry_time = (select max(d3.entry_time)
from document_instance d3
where d3.doc_no = d1.doc_no)
) as 'last indexed by'
FROM documents d
LEFT JOIN document_revision r ON r.doc_no = d.doc_no
LEFT JOIN document_instance d1 ON d1.doc_no = d.doc_no
LEFT JOIN document_type_group dtg ON dtg.doc_no = d.doc_no
I have to create SQL query that select persons datas. Every person has several grades and I have to select first by time for everyone. I don't know how do it because conditional is different for every person. Below is my current code which doesn't works.
SELECT s.sol_last_name,
g.grade_name,
MIN(sg.sol_grade_date_from)
FROM [dbo].[dim_s####] AS s
LEFT JOIN [dbo].[fact_s####_grade] AS sg ON s.sol_key = sg.sol_grade_sollers_key
LEFT JOIN [dbo].[dim_grade] AS g ON g.grade_key = sg.sol_grade_grade_key
GROUP BY s.sol_last_name,
g.grade_name
HAVING MIN(sg.sol_grade_date_from) = sg.sol_grade_date_from
You can put the earliest date in a subquery, and then inner join there:
SELECT s.sol_last_name,
g.grade_name,
sg.sol_grade_date_from
FROM [dbo].[dim_s####] AS s
INNER JOIN (
select sol_grade_grade_key
,min(sol_grade_date_from) as sol_grade_date_
from from [dbo].[dim_grade]
GROUP BY sol_grade_grade_key) AS g
ON g.grade_key = sg.sol_grade_grade_key
LEFT JOIN [dbo].[fact_s####_grade] AS sg
ON s.sol_key = sg.sol_grade_sollers_key
Use a Common Table Expression (cte) to save some typing. Then do a NOT EXISTS to return a row only if same sol_last_name has no older grade.
WITH CTE (sol_last_name, grade_name, grade_date_from) AS
(
SELECT s.sol_last_name,
g.grade_name,
sg.sol_grade_date_from
FROM [dbo].[dim_s####] AS s
LEFT JOIN [dbo].[fact_s####_grade] AS sg ON s.sol_key = sg.sol_grade_sollers_key
LEFT JOIN [dbo].[dim_grade] AS g ON g.grade_key = sg.sol_grade_grade_key
)
select sol_last_name, grade_name, grade_date_from
from cte as t1
where not exists (select 1 from cte t2
where t2.sol_last_name = t1.sol_last_name
and t2.grade_date_from < t2.grade_date_from)
Still trying to get used to writing queries and I've ran into a problem.
Select count(region)
where (regionTable.A=1) in
(
select jxn.id, count(jxn.id) as counts, regionTable.A
from jxn inner join
V on jxn.id = V.id inner join
regionTable on v.regionID = regionTable.regionID
group by jxn.id, regionTable.A
)
The inner query gives an ID number in one column, the amount of times they appear in the table, and then a bit attribute if they are in region A. The outer query works but the error I get is incorrect syntax near the keyword IN. Of the inner query, I would like a number of how many of them are in region A
You must specify table name in query before where
Select count(region)
from table
where (regionTable.A=1) in
And you must choose one of them.
where regionTable.A = 1
or
where regionTable.A in (..)
Your query has several syntax errors. Based on your comments, I think there is no need for a subquery and you want this:
select jxn.id, count(jxn.id) as counts, regionTable.A
from jxn inner join
V on jxn.id = V.id inner join
regionTable on v.regionID = regionTable.regionID
where regionTable.A = 1
group by jxn.id, regionTable.A
which can be further simplified to:
select jxn.id, count(jxn.id) as counts
, 1 as A --- you can even omit this line
from jxn inner join
V on jxn.id = V.id inner join
regionTable on v.regionID = regionTable.regionID
where regionTable.A = 1
group by jxn.id
You are getting the error because of this line:
where (regionTable.A=1)
You cannot specify a condition in a where in clause, it should only be column name
Something like this may be what you want:
SELECT COUNT(*)
FROM
(
select jxn.id, count(jxn.id) as counts, regionTable.A
from
jxn inner join
V on jxn.id = V.id inner join
regionTable on v.regionID = regionTable.regionID
group by jxn.id, regionTable.A
) sq
WHERE sq.a = 1