How to specify page size in dynamically in yii view? - yii

How to specify page size in dynamically in yii view?(not a grid view)
In my custom view page there is a search option to find list of users between 2 date
i need 2 know how to specify the page size dynamically? If number of rows less than 10 how to hide pagination ?
please check screen-shoot
I dont want the page navigation after search it confusing users..
my controller code
$criteria=new CDbCriteria();
$count=CustomerPayments::model()->count($criteria);
$pages=new CPagination($count);
// results per page
$pages->pageSize=10;
$pages->applyLimit($criteria);
$paymnt_details=CustomerPayments::model()->findAll($criteria);
$this->render('renewal',array('paymnt_details'=>$paymnt_details,'report'=>$report,'branch'=>$branch,'model'=>$model,'pages' => $pages,));
}
my view
Link

I'm assuming you want the entire list of search result be shown on a single page, no-matter how long it is?
If so, this is quite easy to achive.
As I can see in your code, you are now defining your pageSize to have a size of 10. You can update it to be dynamically be doing this:
$pages->pageSize = $count;
To remove the pagesizes you can change the css of your view file, but for that we would need your view file to see how you defined it.

Related

Vuetify Data Table jump to page with selected item

Using Vuetify Data Tables, I'm trying to figure out if there's a way to determine what page the current selected item is on, then jump to that page. My use case for this is, I'm pulling data out of the route to determine which item was selected in a Data Table so when a user follows that URL or refreshes the page that same item is automatically selected for them. This is working just fine, however, I can't figure out how to get the Data Table to display the correct page of the selection.
For example, user visits mysite.com/11
The Data Table shows 10 items per page.
When the user enters the site, item #11 is currently auto-selected, but it is on the 2nd page of items. How can I get this to show items 11-20 on page load?
I ended up using a solution similar to what #ExcessJudgement posted. Thank you for putting that code pen together, BTW! I created this function:
jumpToSelection: function(){
this.$nextTick(() => {
let selected = this.selected[0];
let page = Math.ceil((this.products.indexOf(selected) + 1) / this.pagination.rowsPerPage);
this.pagination.sortBy = "id";
this.$nextTick(() => {
this.pagination.page = page;
});
});
}
I'm not sure why I needed to put this into a $nextTick(), but it would not work otherwise. If anybody has any insight into this, it would be useful to know why this is the case.
The second $nextTick() was needed because updating the sortBy, then the page was causing the page to not update, and since I'm finding the page based on the ID, I need to make sure it's sorted properly before jumping pages. A bit convoluted, but it's working.

Drupal 7 - Print PDF and Panelizer

Hi guys ,
I'm currently working on a Drupal project which use the Panelizer module by overriding the default node display. The panel for this content type is made width a lot of rules and specifications in order to display some specific content (like views) according some fields.
Now I need to print in PDF the same content that is displayed by the panelizer module but in another display (in one column ), so I cloned the display I use and rearranged it to display what I want.Then I want to use this display width the print module but I didn't managed to do that.
Any idea how can I do that ?
I just can't use the default node render, because I would miss some informations dues to the specifications used in the panel, and I can't print the panelized content because it's not the same display.
I read this thread but how can I say to the print module to use the "print" display I cloned instead of the default one ?
Any suggestions or ideas will be appreciated or if you have another idea for doing that you're welcome :)
Thank you !
In your print pdf template you can load the node then create a view with the display and finally render it : drupal_render(node_view(node_load($node->nid), "name of your display")) ;
Another way is to alter node entity info, telling that 'print' view can be panelized, i.e.
/**
* Implements hook_entity_info_alter().
*/
function mymodule_entity_info_alter(&$entity_info) {
$entity_info['node']['view modes']['print']['custom settings'] = TRUE;
...
}
After that, you go to panelizer settings of your content type(s), and set whatever you want for the print view mode

Yii2 Gridview get all selected row for all pagination

I wrapped my gridview with Pjax widget like this
\yii\widgets\Pjax::begin();
gridview
\yii\widgets\Pjax::end();
in order to make the gridview make ajax request when I click on each pagination.
I also use ['class' => 'yii\grid\CheckboxColumn'], in column as well.
and I find that when I'm on first pagination I checked some rows and then go to second page and check some rows but when I go back to first page what I've checked is gone.
My question is how can I keep all checkedrow for all pagination
With current conditions (Pjax, multiple pages, yii\grid\CheckboxColumn) it's impossible because of the way it works.
When you click on the pagination links all GridView html content is replaced by new one that comes from the AJAX response.
So obviously all selected checkboxes on the previous page are gone.
Few possible ways to solve that:
1) Write custom javascript and server side logic.
As one of the options, you can send AJAX request to server with parameter meaning that user has chosen to select all data for the bulk delete operation (or use separate controller action for bulk deletion). In this case actually we don't need to get the selected data from user, because we can simply get them from database (credits - Seng).
2) Increase number of displayed rows per page.
3) Use infinite scroll extension, for example this.
4) Break desired action in several iterations:
select needed rows on first page, do action (for example, delete).
repeat this again for other pages.
You can get selected rows like that:
$('#your-grid-view').yiiGridView('getSelectedRows');
[infinite scroll] : http://kop.github.io/yii2-scroll-pager/ will work good if you do not have any pjax filters. If you have filters also in play, do not use this plugin as it does not support pjax filters with it. For rest of the applications it is perfect to use.
Update1 : it seems to be straight forward than expected, here is the how I accomplished it
Add following lines to the checkbox column
'checkboxOptions' => function($data){
return ['id' => $data->id, 'onClick' => 'selectedRow(this)'];
}
Now add following JS to the common js file you will have in your project of the page where this datagrid resides
var selectedItems=[]; //global variable
/**
* Store the value of the selected row or delete it if it is unselected
*
* #param {checkbox} ele
*/
function selectedRow(ele){
if($(ele).is(':checked')) {
//push the element
if(!selectedItems.includes($(ele).attr('id'))) {
selectedItems.push($(ele).attr('id'));
}
} else {
//pop the element
if(selectedItems.includes($(ele).attr('id'))) {
selectedItems.pop($(ele).attr('id'));
}
}
}
Above function will store the selected row ids in the global variable array
Now add following lines to pjax:end event handler
$(document).on('pjax:end', function () {
//Select the already selected items on the grid view
if(!empty(selectedItems)){
$.each(selectedItems, function (index,value) {
$("#"+value).attr('checked',true);
});
}
});
Hope it helps.
I just solved this problem and it works properly with Pjax.
You may use my CheckboxColumn. I hope this can help. The checked items are recorded with cookies.
You can read the part with //add by hezll to understand how to fix it, because I didn't provide a complete general one.
Hope it works for you.
https://owncloud.xiwangkt.com/index.php/s/dGH3fezC5MGCx4H

How to create dropdownlist with static and dynamic values in Asp.net MVC with a divider between them

I want to create a dropdownlist which have three static values: Select All, Text Only, Numeric only. After that I like to add a line with some padding (just to separate these options) and then add some dynamic options.
I am not sure how to do this, Can some body please help?
So far I have created a List<SelectListItem> in my view model, and populated the static values from BLL. But I am not sure how to add a divider line in the middle now, and append some dynamic options after that.
Thanks
The normal select tag will not work like that, you will have to create custom dropdown using spans or divs.
See some examples here:
http://tympanus.net/codrops/2012/10/04/custom-drop-down-list-styling/

Titanium get current view on scrollableView and add an item

I have a scrollableView with several views inside and I'd like to add item to some of these view if they meet a certain criteria, like if they have data attached or not. Also I'm using Alloy, here's my markup
<ScrollableView id="scrollableView">
<View id="view" class='coolView'></View>
...
</ScrollableView>
To know if there are data attached I check the currentPage attribute like so:
function updateCurrentView(e) {
currentView = e.currentPage;
}
But I have no idea how to add an item to the current View.
Edit: To add some clarification, I have a label which when clicked allow me to choose two currencies, when chosen these currency pairs are saved in the database and should be displayed instead of the label. So my guess was to check whether the current view has currency pair saved.
There are 2 things to take care of here:
1.Whenever a currency is selected,immediately label on that particular view will change.
2.Whenever the scrollableView is loaded,it must always refer to the database if a currency is selected.
First one can be done as:
1.Get the instance of scrollableView using the getView method of alloy controller.Pass the id of the scrollableView to it.Lets call it myScrollableView.Refer this for more info.
http://docs.appcelerator.com/titanium/latest/#!/api/Alloy.Controller
2.Use var currentView=myScrollableView.getCurrentPage() to the get the current page which will be a number.
3.Now use the scrollableView instance to get all the views.
var viewArray=myScrollableView.getViews();
4.viewArray[currentView] will give you the view of current page.After you have got the view you can change the desired label using:
viewArray[currentView].children[positionOfTheView]
The "positionOfTheView" can be obtained by printing the viewArray[i].children array using Ti.API.info.
Second thing can be accomplished as follows:
1.Get the instance of scrollableView using the getView method of alloy controller.Pass the id of the scrollableView to it.Lets call it myScrollableView.Refer this for more info.
http://docs.appcelerator.com/titanium/latest/#!/api/Alloy.Controller
2.Now use the scrollableView instance to get all the views.
var viewArray=myScrollableView.getViews();
3.This is a JavaScript array of all the views in the scrollableView. Now iterate through this array and according to the data in the database,change the concerned view using:
viewArray[i].children[positionOfTheView]
The "positionOfTheView" can be obtained by printing the viewArray[i].children array using Ti.API.info.