i want get a SQL like the pic~
now i want get the result by Top 3 projectId (4,3,2) total 8 result.
so how can i mody my sql?
( the SQL in real project is so complex~,about 10 my DBTable and 10 SAP table~ i concerned about efficiency so i don't want use temporary table)
can u help me~?
if you are using SQL Server, use TOP
SELECT *
FROM table1
WHERE ProjectID IN
(
SELECT DISTINCT TOP 3 ProjectID
FROM table1
ORDER BY ProjectID DESC
)
ORDER BY ProjectID Desc
SQLFiddle Demo
If using MySQL then:
SELECT * FROM TABLE1
ORDER BY PROJECTAID ASC
LIMIT 10;
Related
I have a column in a table with dates like 2017-04-13, 2018-05-15. How can we find the oldest record using a SQL query?
You can use the top clause that SQL Server has:
select top 1 *
from yourTable
order by dateColumn asc
This way only the first row is returned and, combined with the ordering provided, that row will be the oldest one
Select top 1 * from table order by {nameofcolumn} Asc
You can try this:
SELECT * FROM YOURTABLE WHERE YOURDATEFIELD = (SELECT MIN(YOURDATEFIELD) FROM YOURTABLE)
select top 1 * from tablename
order by columnname desc
I have a very simple query.
SELECT top 100 *
FROM logs
WHERE description LIKE '%5488826%'
ORDER BY id DESC
However it contains a LIKE clause which is searching a largish text field.
I know the table only has (for example) 200200 rows
(I'm only interested in finding something that happened in a row id > 200000).
I tried to optimise the query by adding in
SELECT top 100 *
FROM logs
WHERE ID > 200000
AND description LIKE '%5488826%'
ORDER BY id DESC
my thinking was that SQL would run the ID > 200000 constraint first and that would help speed up the query, but it still takes minutes to run, what should I do to make this run faster.
EDIT:
ID is PK and indexed
You could try to create a temp-table with only the entries with an id > 200000, and query that to see if it makes any difference:
SELECT * INTO #temp FROM logs WHERE id > 200000;
SELECT * FROM #temp WHERE description LIKE '%5488824%' ORDER BY id DESC;
See if this works:
SELECT top 100 * from
(select description FROM logs WHERE ID > 200000 ) s
where s.description LIKE '%5488826%'
ORDER BY s.id DESC
I would try subquery first constraint. Depends on DB which you use you can try something like:
SELECT TOP 100 * FROM (
SELECT ID, description FROM logs WHERE ID > 200000
) AS data
JOIN
logs
ON
logs.id = data.id
WHERE
data.description LIKE '%5488826%'
ORDER BY
ID DESC
OR (for SQL Server -- with CTE and read uncommitted hint):
;WITH data AS (
SELECT ID, description FROM logs WITH (NOLOCK) WHERE ID > 200000
)
SELECT
logs.*
FROM
data
JOIN
logs WITH (NOLOCK)
ON
logs.id = data.id
WHERE
data.description LIKE '%5488826%'
And make sure you have index on id column.
Very short answer ;-) Add an index to the columns.
My issue here is that i want to populate all the records except latest 100 records in the database. What could be the best approach to accomplish this?
Try using limit cause
SELECT *
FROM Table
order by id desc
limit 101 , totalrecords
Here id is auto increment field of your table
How about something like
SELECT t.*
FROM Table t LEFT JOIN
(
SELECT ID
FROM Table
ORDER BY ID DESC
LIMIT 100
) top100 ON t.ID = top100.ID
WHERE top100.ID IS NULL
Where ID would be the column to identify the order (latest) and Table from where you wish to select
SELECT *
FROM Table
WHERE ID < (SELECT ID
FROM Table
ORDER BY ID DESC
LIMIT 99, 1)
I have an SQL Query that i'm running but I only want to select a specific row. For example lets say my query was:
Select * from Comments
Lets say this returns 10 rows, I only want to select the 8th record returned by this query. I know I can do:
Select Top 5 * from Comments
To get the top 5 records of that query but I only want to select a certain record, is there anything I can put into this query to do that (similar to top).
Thanks
jack
This is a classic interview question.
In Ms SQL 2005+ you can use the ROW_NUMBER() keyword and have the Predicate ROW_NUMBER = n
USE AdventureWorks;
GO
WITH OrderedOrders AS
(
SELECT SalesOrderID, OrderDate,
ROW_NUMBER() OVER (ORDER BY OrderDate) AS 'RowNumber'
FROM Sales.SalesOrderHeader
)
SELECT *
FROM OrderedOrders
WHERE RowNumber = 5;
In SQL2000 you could do something like
SELECT Top 1 *FROM
[tblApplications]
where [ApplicationID] In
(
SELECT TOP 5 [ApplicationID]
FROM [dbo].[tblApplications]
order by applicationId Desc
)
How about
SELECT TOP 1 * FROM
(SELECT TOP 8 * FROM Comments ORDER BY foo ASC)
ORDER BY foo DESC
First, you should say which RDBMS you're using.
Second, you should give careful thought to what it is you're trying to accomplish. Relational Databases are set-based. In general, the order of elements in a set does not matter. You'll want to ask why it matters in this case, then see if there's a better way to embed the concept of order into the query itself.
For instance, in SQL Server 2005 (and other RDBMS), you can use the ROW_NUMBER function to assign a sequential number to each row returned, based on the criteria you specify. You could then select rows based on the row number. Example from Books Online:
USE AdventureWorks;
GO
WITH OrderedOrders AS
(
SELECT SalesOrderID, OrderDate,
ROW_NUMBER() OVER (ORDER BY OrderDate) AS 'RowNumber'
FROM Sales.SalesOrderHeader
)
SELECT *
FROM OrderedOrders
WHERE RowNumber BETWEEN 50 AND 60;
SELECT * FROM comments WHERE ...conditions... LIMIT 1 OFFSET 8
OFFSET is a good thing for MySQL
For SQL Server 2005:
select rank() OVER (ORDER BY c.subject, c.date) as rank, c.subject, c.date
from comments c
where rank = 8
Well, in T-SQL (the dialect for SQL Server) you can do the following:
SELECT TOP 1 *
FROM (SELECT TOP 8 *
FROM Table
ORDER
BY SortField)
ORDER
BY SortField DESC
This way you get the 8th record.
I have read the question & your comments on you would want next 3 blog comments etc.
How is your tables structured?
Assume that you have blog post Id & comment Id is generated in ascending order for each blog post, you could do a SELECT based on the current Id.
e.g. if the blogpostId = 101, you get the top 3 comments order by posted Id. Now lets say, you want to get the next 3 comments - you could do a SELECT WHERE commentId between the last comment id shown TO the comment id - 3
But all that depends on how your tables are defined.
In SQL 2000 where you do not have ROW_NUMBER() function you could use a work-around like this:
SELECT CommentsTableFieldList, IDENTITY(INT, 1,1) as seqNo
INTO #SeqComments
FROM Comments
SELECT * FROM #SeqComments
WHERE seqNo = 8
select top 1 *
from TableName
where ColumnName1 in
(
select top nth ColumnName1
from TableName
order by ColumnName1 desc
)
order by ColumnName1 desc
From the SELECT reference, use the LIMIT keyword:
SELECT * FROM tbl LIMIT 5,10; # Retrieve rows 6-15
SELECT * FROM tbl LIMIT 5; # Retrieve first 5 rows
Note: this is for MySQL, other SQL engines may have a different keyword.
Select from tablename limit nthrow,1;
try This
Let us assume , We want select 5th row of WC_Video Table
And
Select * from (Select Row_Number() over (Order by Uploadedon) as 'rownumber',* from Wc_Video )as Temp where rownumber=5
This question already has answers here:
Implement paging (skip / take) functionality with this query
(6 answers)
Closed 1 year ago.
I have this query with MySQL:
select * from table1 LIMIT 10,20
How can I do this with SQL Server?
Starting SQL SERVER 2005, you can do this...
USE AdventureWorks;
GO
WITH OrderedOrders AS
(
SELECT SalesOrderID, OrderDate,
ROW_NUMBER() OVER (ORDER BY OrderDate) AS 'RowNumber'
FROM Sales.SalesOrderHeader
)
SELECT *
FROM OrderedOrders
WHERE RowNumber BETWEEN 10 AND 20;
or something like this for 2000 and below versions...
SELECT TOP 10 * FROM (SELECT TOP 20 FROM Table ORDER BY Id) ORDER BY Id DESC
Starting with SQL SERVER 2012, you can use the OFFSET FETCH Clause:
USE AdventureWorks;
GO
SELECT SalesOrderID, OrderDate
FROM Sales.SalesOrderHeader
ORDER BY SalesOrderID
OFFSET 10 ROWS
FETCH NEXT 10 ROWS ONLY;
GO
http://msdn.microsoft.com/en-us/library/ms188385(v=sql.110).aspx
This may not work correctly when the order by is not unique.
If the query is modified to ORDER BY OrderDate, the result set returned is not as expected.
This is how I limit the results in MS SQL Server 2012:
SELECT *
FROM table1
ORDER BY columnName
OFFSET 10 ROWS FETCH NEXT 10 ROWS ONLY
NOTE: OFFSET can only be used with or in tandem to ORDER BY.
To explain the code line OFFSET xx ROWS FETCH NEXT yy ROW ONLY
The xx is the record/row number you want to start pulling from in the table, i.e: If there are 40 records in table 1, the code above will start pulling from row 10.
The yy is the number of records/rows you want to pull from the table.
To build on the previous example: If table 1 has 40 records and you began pulling from row 10 and grab the NEXT set of 10 (yy).
That would mean, the code above will pull the records from table 1 starting at row 10 and ending at 20. Thus pulling rows 10 - 20.
Check out the link for more info on OFFSET
This is almost a duplicate of a question I asked in October:
Emulate MySQL LIMIT clause in Microsoft SQL Server 2000
If you're using Microsoft SQL Server 2000, there is no good solution. Most people have to resort to capturing the result of the query in a temporary table with a IDENTITY primary key. Then query against the primary key column using a BETWEEN condition.
If you're using Microsoft SQL Server 2005 or later, you have a ROW_NUMBER() function, so you can get the same result but avoid the temporary table.
SELECT t1.*
FROM (
SELECT ROW_NUMBER OVER(ORDER BY id) AS row, t1.*
FROM ( ...original SQL query... ) t1
) t2
WHERE t2.row BETWEEN #offset+1 AND #offset+#count;
You can also write this as a common table expression as shown in #Leon Tayson's answer.
SELECT *
FROM (
SELECT TOP 20
t.*, ROW_NUMBER() OVER (ORDER BY field1) AS rn
FROM table1 t
ORDER BY
field1
) t
WHERE rn > 10
Syntactically MySQL LIMIT query is something like this:
SELECT * FROM table LIMIT OFFSET, ROW_COUNT
This can be translated into Microsoft SQL Server like
SELECT * FROM
(
SELECT TOP #{OFFSET+ROW_COUNT} *, ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS rnum
FROM table
) a
WHERE rnum > OFFSET
Now your query select * from table1 LIMIT 10,20 will be like this:
SELECT * FROM
(
SELECT TOP 30 *, ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS rnum
FROM table1
) a
WHERE rnum > 10
SELECT TOP 10 * FROM table;
Is the same as
SELECT * FROM table LIMIT 0,10;
Here's an article about implementing Limit in MsSQL Its a nice read, specially the comments.
This is one of the reasons I try to avoid using MS Server... but anyway. Sometimes you just don't have an option (yei! and I have to use an outdated version!!).
My suggestion is to create a virtual table:
From:
SELECT * FROM table
To:
CREATE VIEW v_table AS
SELECT ROW_NUMBER() OVER (ORDER BY table_key) AS row,* FROM table
Then just query:
SELECT * FROM v_table WHERE row BETWEEN 10 AND 20
If fields are added, or removed, "row" is updated automatically.
The main problem with this option is that ORDER BY is fixed. So if you want a different order, you would have to create another view.
UPDATE
There is another problem with this approach: if you try to filter your data, it won't work as expected. For example, if you do:
SELECT * FROM v_table WHERE field = 'test' AND row BETWEEN 10 AND 20
WHERE becomes limited to those data which are in the rows between 10 and 20 (instead of searching the whole dataset and limiting the output).
In SQL there's no LIMIT keyword exists. If you only need a limited number of rows you should use a TOP keyword which is similar to a LIMIT.
Must try. In below query, you can see group by, order by, Skip rows, and limit rows.
select emp_no , sum(salary_amount) from emp_salary
Group by emp_no
ORDER BY emp_no
OFFSET 5 ROWS -- Skip first 5
FETCH NEXT 10 ROWS ONLY; -- limit to retrieve next 10 row after skiping rows
Easy way
MYSQL:
SELECT 'filds' FROM 'table' WHERE 'where' LIMIT 'offset','per_page'
MSSQL:
SELECT 'filds' FROM 'table' WHERE 'where' ORDER BY 'any' OFFSET 'offset'
ROWS FETCH NEXT 'per_page' ROWS ONLY
ORDER BY is mandatory
This is a multi step approach that will work in SQL2000.
-- Create a temp table to hold the data
CREATE TABLE #foo(rowID int identity(1, 1), myOtherColumns)
INSERT INTO #foo (myColumns) SELECT myData order By MyCriteria
Select * FROM #foo where rowID > 10
SELECT
*
FROM
(
SELECT
top 20 -- ($a) number of records to show
*
FROM
(
SELECT
top 29 -- ($b) last record position
*
FROM
table -- replace this for table name (i.e. "Customer")
ORDER BY
2 ASC
) AS tbl1
ORDER BY
2 DESC
) AS tbl2
ORDER BY
2 ASC;
-- Examples:
-- Show 5 records from position 5:
-- $a = 5;
-- $b = (5 + 5) - 1
-- $b = 9;
-- Show 10 records from position 4:
-- $a = 10;
-- $b = (10 + 4) - 1
-- $b = 13;
-- To calculate $b:
-- $b = ($a + position) - 1
-- For the present exercise we need to:
-- Show 20 records from position 10:
-- $a = 20;
-- $b = (20 + 10) - 1
-- $b = 29;
If your ID is unique identifier type or your id in table is not sorted you must do like this below.
select * from
(select ROW_NUMBER() OVER (ORDER BY (select 0)) AS RowNumber,* from table1) a
where a.RowNumber between 2 and 5
The code will be
select * from limit 2,5
better use this in MSSQLExpress 2017.
SELECT * FROM
(
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 0)) as [Count], * FROM table1
) as a
WHERE [Count] BETWEEN 10 and 20;
--Giving a Column [Count] and assigning every row a unique counting without ordering something then re select again where you can provide your limits.. :)
One of the possible way to get result as below , hope this will help.
declare #start int
declare #end int
SET #start = '5000'; -- 0 , 5000 ,
SET #end = '10000'; -- 5001, 10001
SELECT * FROM (
SELECT TABLE_NAME,TABLE_TYPE, ROW_NUMBER() OVER (ORDER BY TABLE_NAME) as row FROM information_schema.tables
) a WHERE a.row > #start and a.row <= #end
If i remember correctly (it's been a while since i dabbed with SQL Server) you may be able to use something like this: (2005 and up)
SELECT
*
,ROW_NUMBER() OVER(ORDER BY SomeFields) AS [RowNum]
FROM SomeTable
WHERE RowNum BETWEEN 10 AND 20