I got in my data base colums logs, data, type
How to get logs from year from now with month distinction
f.ex:
row
logs = 'error...'
data = 2012-11-05 11:24:08
type = 1
....
And I want get them in that view
month logs-count type
January 100 1
January 100 2
February 160 1
February 120 2
....
For mysql:
select monthname(data) as month, count(*) as logs-count, type
from table
group by month, type
You need to group by both date and type to get multiple rows per month.
try this one:
select datename(month, data) as month count(logs)as logscount, type from table
try this,If these columns are in same table
select monthname(data) as month,count(logs)as logs-count,type from table
group by month
Related
I would like to know if we can got values from date if the date is in the current month
For example, If I have :
date value
28/06/2021 50
02/07/2021 100
05/07/2021 18
Then I search to have :
02/07/2021 100
05/07/2021 18
because 28/06/2021 is not in the current month
thanks in advance !
In Mysql you can use now() and month() functions to get the current date ang extract the month.
Select *
from table
where <your filters>
having MONTH(NOW()) = MONTH( table.date_field)
Different databases like oracle , postrest change the name of this functions , so you must find it
TSQL
select * from tbl
where MONTH(date)=month(getdate())
You'll want to match the YEAR along with the MONTH if you will have data that spans more than a year.
SELECT date, value
FROM table
WHERE YEAR(date) = YEAR(GETDATE()) AND MONTH(date) = MONTH(GETDATE())
I want to calculate the monthly average of some data using SQL query where the data resides in redshift DB.
The data is present in the following format in the table.
s_date | sales
------------+-------
2020-08-04 | 10
2020-08-05 | 20
---- | --
---- | --
The data may not be present for all the date in a month. If the data is not present for a day, it should be considered as 0.
Following query using AVG() function "group by" month as gives the average of based on the data on available date.
select trunc(date_trunc('MONTH', s_date)::timestamp) as month, avg(sales) from sales group by month;
However it does not consider the data for missing dates as 0. What should be the right query to calculate the monthly average as expected?
One more expectation is that, for the current month, the average should be calculated based on the data till today. So it should not consider entire month (like 30 or 31 days).
Regards,
Paul
Using a calendar table might be the easiest way to go here:
WITH dates AS (
SELECT date_trunc('day', t)::date AS dt
FROM generate_series('2020-01-01'::timestamp, '2020-12-31'::timestamp, '1 day'::interval) t
),
cte AS (
SELECT t.dt, COALESCE(SUM(s.sales), 0) AS sales
FROM dates t
LEFT JOIN sales s ON t.dt = s.s_date
GROUP BY t.dt
)
SELECT
LEFT(dt::text, 7) AS ym,
AVG(sales) AS avg_sales
FROM cte
GROUP BY
LEFT(dt::text, 7);
The logic here is to first generate an intermediate table in the second CTE which has one record for each data in your data set, along with the total sales for that date. Then, we aggregate by year/month, and report the average sales.
I would like to make a calculation to get the difference between the departDate from my current row and the arriveDateNextStop from my previous row. I have a fact table which has multiple columns. The three most important columns are: id, departDate, arriveDateNextStop.
If I have for example these two rows in my fact table:
id departDate arriveDateNextStop
1 01-01-2019 03-01-2019
1 04-01-2019 07-01-2019
Explanation: On 1 January 2019 I depart to the next destination and I arrive there on 3 January 2019. On 4 January 2019 I again depart to the next destination and I arrive there on 7 January 2019.
Now I would like to know how many days the idle time was (the amount of days between the arrival and the next depart). So with this example the idle time would be 1, because between 3 January 2019 and 4 January 2019 is one day.
First, I made this 'calculation' in Management Studio as a SQL query. See query below:
SELECT s.Id, s.departDate as Depart_current_place, s.arriveDateNextStop as Arrival_next_stop, LAG(arriveDateNextStop) OVER (ORDER BY arriveDateNextStop) AS Arrival_current_stop, DATEDIFF(DAY, LAG(arriveDateNextStop) OVER (ORDER BY arriveDateNextStop), departDate) AS Amount_of_days
FROM MyTable s
WHERE Id = 9
GROUP BY s.departDate, s.Id, s.arriveDateNextStop
ORDER BY s.departDate
This query works fine, but how can I do this in my cube as a calculation in MDX?
I don't have the same example, but the similar cube structure with Completed/Received date:
with
member departDate as [Received].[Year Qtr Month].CurrentMember.Member_Key
member arriveDate as [Completed].[Year Qtr Month].CurrentMember.Member_Key
member arriveDateNextStop as [Completed].[Year Qtr Month].CurrentMember.Lead(1).Member_Key
member idleDays as departDate-arriveDateNextStop
SELECT NON EMPTY { departDate,arriveDate,arriveDateNextStop,idleDays } ON 0
, NON EMPTY
{ ([Completed].[Year Qtr Month].[Date].ALLMEMBERS
* [Received].[Year Qtr Month].[Date].ALLMEMBERS ) } ON 1
FROM ( SELECT ( { [Completed].[Year Qtr Month].[Date].&[6213] } ) ON COLUMNS
FROM [MyCube])
I also have integer key for a date dimension (CurrentMember.Member_Key). 1 = 1998-01-01, 2 = 1998-01-02 etc. till today. You need to create a property in a Date dimension if your Date key is classic YYYYMMDD (which you cannot subtract to get days difference, I can do that in my example). And use it like CurrentMember.Properties("property name") instead of Member_Key.
Main formula part: Lag/Lead function to get prev. or next member.
Please update in case of questions.
I'm trying to create three columns based on date in seconds format.
My user.updated_at = 1521533490
I would like to get year, month and day separately and put these formatted values to columns for example:
year -> 2018, month -> 11, day -> 23
Does someone know how can I do that in pgSQL?
I would like to get year, month and day separately and put these formated values to columns
Don't do that.
Use a single column of type date or timestamp, depending on your application. Not every combination of your three columns will be a valid date. But every value in a single column of type date will be a valid date.
If you need the parts of a date separately, use PostgreSQL's date/time functions.
Try this approche to get differents arguments, then you can do whatever you want:
SELECT to_timestamp(1521533490); //2018-03-20T08:11:30.000Z
SELECT to_char(to_timestamp(1521533490), 'HH'); // 08 Hour
SELECT to_char(to_timestamp(1521533490), 'MI'); // 11 Minutes
SELECT to_char(to_timestamp(1521533490), 'SS'); // 30 Seconds
SELECT to_char(to_timestamp(1521533490), 'DD'); // 20 Day
SELECT to_char(to_timestamp(1521533490), 'Mon'); // MAR Month
SELECT to_char(to_timestamp(1521533490), 'YYYY'); // 2018 Year
Use the EXTRACT function.
SELECT to_timestamp(updated_at) "Date",
EXTRACT(YEAR FROM (to_timestamp(updated_at))) "Year",
EXTRACT(MONTH FROM (to_timestamp(updated_at))) "Month",
EXTRACT(DAY FROM (to_timestamp(updated_at))) "Day"
FROM users
Output
Date Year Month Day
2018-03-20T08:11:30Z 2018 3 20
SQL Fiddle: http://sqlfiddle.com/#!15/afe0e/15/0
More information on the EXTRACT function.
I have a SQL table with the following schema:
fruit_id INT
price FLOAT
date DATETIME
This table contains many records where the price of a given fruit is recorded at a given time. There may be multiple records in a single day, there may be
I would like to be able to fetch a list of prices for a single fruit over the last 12 months inclusive of the current month. So given a fruit_id of 2 and datetime of now(), what would the price values be for December, January, February, ... October, November?
Given the above requirements, what strategy would you use to get this data? Pure sql, fetch all prices and process in code?
Thanks for you time.
Are you talking about min price, max price, average price, or something else?
Here's a quick query to get you started, which includes min, max, and average price for each month for fruit_id 2:
select left(date,7) as the_month, min(price),max(price),avg(price)
from fruit_price
where fruit_id = 2
and date >= concat(left(date_sub(curdate(), interval 11 month),7),'-01')
group by the_month;
If I understand it correctly from -
I would like to be able to fetch a list of prices for a single fruit over the last 12 months inclusive of the current month. So given a fruit_id of 2 and datetime of now(), what would the price values be for December, January, February, ... October, November?
You want the total price for every month for a single year based on the date and fruit_if you pass in.
So,this won't give all months of an year but all months which had a price for year..in case you want all months..you would need to create a dimdate table which will have all the dates...and then join with it..
declare #passeddate=Now() --date to be calculated
declare #fruit_id=2 --fruit id to be calculated
Select
fruit_id as FruitId,
Sum(price) as MonthPrice,
Month(date) as FruitMonth
from SQL_Table
group by FruitMonth,FruitId
where fruit_id=#fruit_id and
Year(date)=Year(#passeddate)
select month(date) as "Month", distinct(price) as "Unique Price" where fruit_id = 2 group by month(date);
I'd try to state as much as possible in SQL that does not require unindexed access to data because it's usually fast(er) than processing it with the application.