Like the title says.
I would love to know how, with VimScript, I can do an if statement, that checks if %Y (for statusline) exists in the current file. This is what I have so far:
if expand('%:Y') != ""
let filetype=extend('%:Y')
let filetype+= ",\ "
else
let filetype=""
endif
This is, of course, for my statusline, for which I don't want to show the filetype comma and space if the filetype doesn't exist.
Thanks for all your help!
You cannot use expand() or similar to resolve options in 'statusline'; they are only interpreted inside the setting.
If you don't like the formatting returned by the option or want to combine options to a custom indicator, you have to emulate the option in a %{...} Vimscript expression. Most options can be completely or mostly emulated. For your %Y, this would be included in 'statusline' instead:
let &statusline .= '%{empty(&filetype) ? "" : "," . toupper(&filetype) . ", "}'
Instead of putting a large expression inline, you can also move it to a separate :function.
Related
I have a list of file names (about 4000).
For example:
A-67569
H-67985
J-87657
K-85897
...
I need to put an asterisk before and after each file name. And then make it a line format.
Example:
*A-67569* *H-67985* *J-87657* *K-85897* so on...
Note that there is a space between filenames.
Forgot to mention, I'm trying to do this with Notepad++
How can I do it?
Please advise.
Thanks
C# example for list to string plus edits
List<string> list = new List<string> { "A - 67569"), "H-67985", "J-87657", "K-85897"};
string outString = "";
foreach(string item in list)
{
outString += "*" + item + "* ";
}
content of outstring: *A - 67569* *H-67985* *J-87657* *K-85897*
Use the Replace of your Notedad++ (Search > Replace..)
Select Extended (\n \r \t \0 \x...) on the bottom of the Replace window
In the field Find what write '\r\n' and in the field Replace with write * *
Replace all
Note, that you should manually place the single asterisk before the first and after the last words.
If this won't work, in step 2. instead of \r\n try to use only \n or \r.
You can use Regular expression in the search Mode.
Find what:
(\S+)(\R|$)
Replace with:
*$1
Note the space after de number one
For the archive
A-67569
H-67985
J-87657
K-85897
Output:
*A-67569 *H-67985 *J-87657 *K-85897
Explication of regex:
(\S+) Mean find one or more caracters is not a blank.
(\R|$) Mean find any end of line or end of file
(\S+)(\R|$) Mean find any gorup of caracters not blank ho end with end of line or end of file.
Explication of Replace with
When you use the $ simpbol, you are using a reference to the groups finded, $1 is the first group, in this case the group (\S+).
I am currently trying to create a SQL-grammar for the Data Definition Language.
For my program, the parser only needs to recognize some specific sql-commands like "CREATE TABLE", "ALTER TABLE", etc.
Since I am working with automatically generated export files there is also a lot of overhead in the things I am gonna parse like "SET CURRENT PATH" etc. This is not necessary to be parsed and I am wondering if there is a way to ignore "everything else" that is not defined in the SQL-Statements. Hope anyone has some experience with this..
Here's the header part of my grammar:
list: sql_expression ENDOFFILE?;
sql_expression:
((create_statement|alter_table_statement|create_unique_index_statement|insert_statement) SEMICOLON)+
;
...
and I am wondering if it is possible to extend the sql_expression rule like this:
list: sql_expression ENDOFFILE?;
sql_expression:
((create_statement|alter_table_statement|create_unique_index_statement|insert_statement|else_stuff) SEMICOLON)+
;
Thanks in advance!
Yes you can achieve this.
You can ignore statements like "SET CURRENT PATH" or "CONNECT ..blah blah". These are nothing but SQL plus commands. You need to swallow everything which comes after particular keyword.
For e.g , in case of "ACCEPT ..blah.." , you can create following rule:
SQL_PLUS_ACCEPT
: 'accept' SPACE ( ~('\r' | '\n') )* (NEWLINE|EOF)
;
accept_key
: SQL_PLUS_ACCEPT
;
this will ignore "ACCEPT.. " command and u can parse whatever stmt u wnat to parse. You need to do this for other sql plus commands like SET, CONNECT, EXIT etc.
You can refer to this link
I need my VB.net to write a file containing the following line
objWriter.WriteLine ("TEXTA " (FILEA) " TEXTB")
Unfortunatly the variable (FILEA) is causing problems i now get the error
Comma, ')', or valid expression continuation expected.
Could someone explain this please?
You're not concatenating (joining) the strings proerly...
objWriter.WriteLine ("TEXTA " & FILEA & " TEXTB")
A better style to get into the habit of using is:
objWriter.WriteLine (string.format("TEXTA {0} TEXTB", FILEA))
The FILEA variable replaces the {0} placeholder in the format string. Depending on what the writer you're using is, you may have a formatted overload so you could just do:
objWriter.WriteLine ("TEXTA {0} TEXTB", FILEA)
And since you asked for an explanation;
The compiler is asking you what exactly you want it to do - you've given it 3 variables (String, variable, String) and haven't told it that you want to join them together - It's saying that after the first string "TEXTA", there should either be the closing bracket (to end the method call), a comma (to pass another parameter to the method) OR a "valid continuation expression" - ie something that tells it what to do with the next bit. in this case, you want a continuation expression, specifically an ampersand to signify "concatenate with the next 'thing'".
Presumably you're looking for string concatenation? Try this:
objWriter.WriteLine("TEXTA" & FILEA & "TEXTB");
Note that FILEA isn't exactly a conventional variable name... which leads me to suspect there may be something else you're trying to achieve. Could you give more details?
I would like to reformat some code which looks like this :
if (cond) {
foo;
}
to
if (cond)
{
foo;
}
Since this is C code, I have been looking at cindent/cinoptions to use with = but it seems it does not deal with multiline rules.
I have been looking at formatoptionsto use with gq, and it does not seem to be possible either.
So is it possible using default Vim options or should I use a specific plugin or function ?
:%s/^\(\s*\).*\zs{\s*$/\r\1{/
Breakdown:
^\(\s*\) = capture the whitespace at the beginning of the line
.* = everything else
\zs = start replacement after this
{ = open curly brace
\s*$ = trailing whitespace before line end
\r\1{ = newline, captured whitespace, brace
I don't know if this completely solves your problem, but if this is a one-shot operation, you might want to try regular expressions:
:%s/^\(\s*\)\(.*)\)\s*{\s*$/\1\2^M\1{/
Note that ^M is a control character that is usually generated (depending on your terminal) by pressing CTRL-V followed by ENTER.
EDIT: As pointed out in the comments by Jay and Zyx, \r is a better way of inserting a line break into the replaced string. I wasn't aware of that, many thanks for the hint.
If you install Artistic Style you can do something like:
:set formatprg=astyle\ -b
Then use gq to reformat chunks of code.emphasized text
If you want this enabled every time you edit a C file,
you can add the following to your .vimrc file.
autocmd BufNewFile,BufRead *.c set formatprg=astyle\ -b
I don't know if you can do it within vim itself, but you can try the BSD indent command with the -bl option. With the cursor on the first {, you can type !%indent -blEnter.
I frequently come across this problem. I have a file:
something
something2
something3
which I want output as:
"something","something2","something3"
any quick tool for this, preferably online?
If its just a one off thing, it'd be pretty easy to just do it with a search & replace in any advanced-ish text editor...
For example in notepad++:
Do a Replace (CTRL+H)
Set "Search Mode" to "Extended"
Find: \r\n
Replace with: ","
(of course you'll need an extra quote at the very start & very end of the file).
If you need to do it more than once, writing a small script/program that did a regular expression replace over the file would be fairly straight forward too.
Edit: If you really wanted to do it online, you could use an online regular expression tester (in this case you want to use \n as the regex and "," as your replace pattern, leaving the other settings alone).
A quick Python hack?
lines = open('input.txt').xreadlines()
txt = ','.join(['"%s"' % x for x in lines])
open('output.txt', 'w').write(txt)