If this is a stupid question, forgive me, I'm not very familiar with PostgreSQL.
I've collected inventory data from used car dealerships in my area and stored it in a postgreSQL table. I've got a second table with particular details regarding certain makes and models. For example:
The dealership table is structured like so:
-----------------------------------------
| Dealership | Make | Model | Year | ID |
----------------------------------------|
| A | Ford | F250 | 2003 | 1 |
| A | Chevy| Cobalt| 2005 | 2 |
| B | Ford | F250 | 2003 | 1 |
| B | Dodge| Chrgr | 2012 | 3 |
-----------------------------------------
The details table is structured like so:
-----------------------------------------
| ID | DetailA| DetailB| DetailC|
-----------------------------------------
| 1 | data | data | data |
| 2 | data | data | data |
| 3 | data | data | data |
| 4 | data | data | data |
-----------------------------------------
My goal is to retrieve vehicle matches from multiple dealerships and display the appropriate details. In the above example, I would like to see:
-----------------------------------------------------
| Make | Model | Year | DetailA | DetailB | DetailC |
-----------------------------------------------------
| Ford | F250 | 2003 | data | data | data |
-----------------------------------------------------
With this result, I will know that both A and B havea 2003 Ford F250 for sale, and can view the related details of the vehicle.
I've tried many different queries, but most are variations on something like this:
SELECT DISTINCT
dealership_table.make,
dealership_table.model,
dealership_table.year
details_table.detaila,
details_table.detailb,
details_table.detailc
FROM
dealership_table
INNER JOIN
details_table
ON
dealership_table.id = details_table.id
WHERE
dealership_table.dealership = 'A'
OR
dealership_table.dealership = 'B'
However this returns all of the distinct matches from the table where dealership is either A or B. I've tried multiple inner-joins, but I an error complaining details_table is specified multiple times.
If I'm doing something really silly, I apologize. Like I said before, I'm pretty much an SQL noob.
What am I doing wrong? How should I go about retrieving the desired results? Any suggestions, solutions, or advice is greatly appreciated!
You can write:
SELECT dealership_table1.make,
dealership_table1.model,
dealership_table1.year,
details_table.detaila,
details_table.detailb,
details_table.detailc
FROM dealership_table dealership_table1
JOIN dealership_table dealership_table2
ON dealership_table1.make = dealership_table2.make
AND dealership_table1.model = dealership_table2.model
AND dealership_table1.year = dealership_table2.year
JOIN details_table
ON dealership_table.id = details_table.id
WHERE dealership_table1.dealership = 'A'
AND dealership_table1.dealership = 'B'
;
(Note that the FROM dealership_table dealership_table1 and JOIN dealership_table dealership_table2 set up distinct "aliases", so you can use the same table multiple different times in the same query without getting name-conflicts.)
I may be misunderstanding your table layout, but I think you should consider changing to a different structure. Here's what I would propose:
Vehicle:
----------------------------
| ID | Make | Model | Year |
----------------------------
| 1 | Ford | F250 | 2003 |
| 2 | Chevy| Cobalt| 2005 |
| 3 | Dodge| Chrgr | 2012 |
----------------------------
Dealership:
----------------------------
| Dealership | ID | Detail |
----------------------------
| A | 1 | data |
| A | 2 | data |
| B | 1 | data |
| B | 3 | data |
----------------------------
This way you're not storing vehicle information (make/model/year) in more than one place.
Here's how you would write your desired query given the above schema:
SELECT Make, Model, Year, A.Detail, B.Detail, C.Detail
FROM Vehicle V
LEFT OUTER JOIN Dealership A on A.Dealership = 'A' and A.id = V.id
LEFT OUTER JOIN Dealership B on B.Dealership = 'B' and B.id = V.id
LEFT OUTER JOIN Dealership C on C.Dealership = 'C' and C.id = V.id
Related
We have various tables pertaining to different entities where we would like to globalize the stored values. We do not know how to proceed technically anymore and are open to any form of help, hints or tips.
Language
ID | Culture | Description |
---+---------+-------------+
1 | EN | English |
2 | FR | French |
3 | ES | Spanish |
Job
ID | Description |
---+-------------+
1 | Doctor |
2 | Firefighter |
JobGlobalization
ID | JobID | Description | Culture |
---+-------+-------------+---------+
1 | 1 | Docteur | FR |
2 | 1 | Doctora | ES |
We attempted to use CROSS JOIN to obtain something of the following:
ID | Description | Culture |
---+-------------+---------+
1 | Doctor | EN |
1 | Doctor | FR |
1 | Doctor | ES |
2 | Firefighter | ES |
2 | Firefighter | ES |
2 | Firefighter | ES |
Query used:
SELECT Job.ID, Job.Description, Language.Culture
CROSS JOIN Language
ORDER BY Job.ID
We experienced with different joins on the child globalization table in order to correlate the entities together, however the results set kept multiplying itself in the wrong way.
We would like that for every parent entity, whether it has any related child entities, a row is selected for every culture in the Language table. The description column will default to the parent entity in the case where there are no associated records in the child table.
The resulting table should be as follows:
ID | Description | Culture |
---+-------------+---------+
1 | Doctor | EN |
1 | Docteur | FR |
1 | Doctora | ES |
2 | Firefighter | EN |
2 | Firefighter | FR |
2 | Firefighter | ES |
We had in mind a condition that would select the 'Description' column from the parent table 'Job' if there were no corresponding record for it in the child table.
e.g.
IIF(JobGlobalization.Description IS NOT NULL, JobGlobalization.Description, Job.Description)
We attempted to use CROSS JOIN to obtain something of the following:
This should produce the result set you describe:
SELECT j.ID, j.Description, l.Culture
FROM Job j CROSS JOIN
Language l
ORDER BY j.ID, l.Culture;
You can insert this into JobGlobalization (although you might want to truncate it first). Or you can use CREATE TABLE AS (or the equivalent for your database) to create JobGlobalization from scratch.
You would then need to update this table with the appropriate values for the culture.
I have the following data:
select * from art_skills_table;
+----+------+---------------------------+
| ID | Name | skills |
+----+------+---------------------------|
| 1 | Anna | ["painting","photography"]|
| 2 | Bob | ["drawing","sculpting"] |
| 3 | Cat | ["pastel"] |
+----+------+---------------------------+
select * from computer_table;
+------+------+-------------------------+
| ID | Name | skills |
+------+------+-------------------------+
| 1 | Anna | ["word","typing"] |
| 2 | Cat | ["code","editing"] |
| 3 | Bob | ["excel","code"] |
+------+------+-------------------------+
I would like to write an SQL statement which results in the following table.
+------+------+-----------------------------------------------+
| ID | Name | skills |
+------+------+-----------------------------------------------+
| 1 | Anna | ["painting","photography","word","typing"] |
| 2 | Bob | ["drawing","sculpting","excel","code"] |
| 3 | Cat | ["pastel","code","editing"] |
+------+------+-----------------------------------------------+
I've tried something like SELECT * from art_skills_table LEFT JOIN computer_table ON name. However it doesn't give what I need. I've read about array_cat but I'm having a bit of trouble implementing it.
if the skills column from both tables are arrays, then you should be able to get away with this:
SELECT a.ID, a.name, array_cat(a.skills, c.skills)
FROM art_skills_table a LEFT JOIN computer_table c
ON c.id = a.id
That said, While you used LEFT join in your sample, I think either an INNER or FULL (OUTER) join might serve you better.
First, i wondered why the data are stored in such a model.
Was of the opinion that NoSQL databases lack ability for joins and ...
... a semantic triple would be in the form of subject–predicate–object.
... a Key-value (KV) stores use associative arrays.
... a relational database would be normalized.
A few information about the use case would have helped.
Nevertheless, you can select the data with CONCAT and REPLACE for the desired form.
SELECT art_skills_table.ID, computer_table.name,
CONCAT(
REPLACE(art_skills_table.skills, '}',','),
REPLACE(computer_table.skills, '{','')
)
FROM art_skills_table JOIN computer_table ON art_skills_table.ID = computer_table.ID
The query returns the following result:
+----+------+--------------------------------------------+
| ID | Name | Skills |
+----+------+--------------------------------------------+
| 1 | Anna | {"painting","photography","word","typing"} |
| 2 | Cat | {"drawing","sculpting","code","editing"} |
| 3 | Bob | {"pastel","excel","code"} |
+----+------+--------------------------------------------+
I've used the ID for the JOIN, even though Bob has different values.
The JOIN should probably be done over the name.
JOIN computer_table ON art_skills_table.Name = computer_table.Name
BTW, you need to tell us what SQL engine you're running on.
With DCM's Data Transfer v2 you get 3 main tables of data in GCS:
p_activity_166401
p_click_166401
p_impression_166401
Along with a plethora of match tables like:
p_match_table_advertisers_166401
p_match_table_campaigns_166401
Table 1: p_activity_166401
Row | Event_time | User_ID | Advertiser_ID | Campaign_ID |
------ | ------------- | ------- | ------------- | ----------- |
1 | 149423090566 | AMsySZa | 5487307 | 9638421 |
2 | 149424804284 | 2vmdsXS | 5487307 | 10498283 |
Table 2: p_match_table_advertisers_166401
Row | Advertiser_ID | Advertiser |
------ | ------------- | ----------- |
1 | 5487307 | Company A |
2 | 5487457 | Company B |
How do I reference a value from Table 1 in Table 2 and return the value from Table 2 in a query?
I'd like a result like:
Row | Advertiser | User_ID |
------ | ---------- | ----------- |
1 | Company A | AMsySZa |
2 | Company A | 2vmdsXS |
Been searching around here and online and I just can't seem to find a clear reference on how to do the lookups across table, apologies in advance is this is a really simple thing I'm missing :)
EDIT
So with a nudge in the right direction I have found the JOIN function...
SELECT
*
FROM
[dtftv2_sprt.p_activity_166401]
INNER JOIN
[dtftv2_sprt.p_match_table_advertisers_166401]
ON
[p_activity_166401.Advertiser_ID] =
p_match_table_advertisers_166401.Advertiser_ID]
LIMIT
100;
Error: Field 'p_activity_166401.Advertiser_ID' not found.
That is definitely a field in the table.
So this query works great in creating a view with all the data in it.
SELECT
*
FROM
[dtftv2_sprt.p_activity_166401]
INNER JOIN
[dtftv2_sprt.p_match_table_advertisers_166401]
ON
dtftv2_sprt.p_activity_166401.Advertiser_ID = dtftv2_sprt.p_match_table_advertisers_166401.Advertiser_ID;
Using the view I can now run smaller queries to pull the data I want out. Thanks for guiding me in the right direction Mikhail Berlyant.
Okay, so I'm trying to link together four different tables, and its getting very difficult. I provided snippets of each table in the hopes you all could help out
Table 1: data
+--------+--------+-----------+
| charge | amount | date |
+--------+--------+-----------+
| 123 | 10000 | 2/10/2016 |
| 456 | 10000 | 1/28/2016 |
| 789 | 10000 | 3/30/2016 |
+--------+--------+-----------+
Table 2: data_metadata
+--------+------------+------------+
| charge | key | value |
+--------+------------+------------+
| 123 | identifier | trrkfll212 |
| 456 | code | test |
| 789 | ID | 123xyz |
+--------+------------+------------+
Table 3: buyer
+-----+-----------+----------+----------+
| id | date | discount | plan |
+-----+-----------+----------+----------+
| ABC | 2/13/2016 | yes | option a |
| DEF | 2/1/2016 | yes | option a |
| GHI | 1/22/2016 | no | option a |
+-----+-----------+----------+----------+
Table 4: buyer_metadata
+--------------+-----------+--------+
| id | |key| | value |
+--------------+-----------+--------+
| ABC | migration | TRUE |
| DEF | emid | foo |
| GHI | ID | 123xyz |
+--------------+-----------+--------+
Okay, so the tables data and data_metadata are obviously connected by the charge column.
The tables buyer and buyer_metadata are connected by the id column.
But I want to link all of them together. I'm pretty sure the way to accomplish this is through linking the metadata tables together through the common field in the "value" column (in this example: 123xyz).
Could anyone help?
This might look like something like that if all "link" columns are unique :
SELECT *
FROM data d
JOIN data_metadata dm ON d.charge = dm.charge
JOIN buyer_metada bm ON dm.value = bm.value
JOIN buyer b ON bm.id = b.id
If not, I think you'll have to use something like GROUP BY clause
Let's take it in two steps, first create composite tables for data and buyer. Composite table for data:
SELECT data.charge, data.amount, data.date,
data_metadata.key, data_metadata.value
FROM [data] AS data
JOIN (SELECT charge, key, value FROM [data_metadata]) AS data_metadata
ON data.charge = data_metadata.charge
And composite table for buyer:
SELECT buyer.id, buyer.date, buyer.discount, buyer.plan,
buyer_metadata.key, buyer_metadata.value
FROM [buyer] AS buyer
JOIN (SELECT key, value FROM [buyer_metadata]) AS buyer_metadata
ON buyer.id = buyer_metadata.id
And then let's join the two composite tables
SELECT composite_data.*, composite_buyer.*
FROM (
SELECT data.charge, data.amount, data.date,
data_metadata.key, data_metadata.value
FROM [data] AS data
JOIN (SELECT charge, key, value FROM [data_metadata]) AS data_metadata
ON data.charge = data_metadata.charge) AS composite_data
JOIN (
SELECT buyer.id, buyer.date, buyer.discount, buyer.plan,
buyer_metadata.key, buyer_metadata.value
FROM [buyer] AS buyer
JOIN (SELECT key, value FROM [buyer_metadata]) AS buyer_metadata
ON buyer.id = buyer_metadata.id) AS composite_buyer
ON composite_data.value = composite_buyer.value
I haven't tested it but it's probably close.
For reference, here is the page on BigQuery JOINs. And have you seen this SO?
I'm sure this has been asked but I can't quite find the right search terms.
Given a schema like this:
| CarMakeID | CarMake
------------------------
| 1 | SuperCars
| 2 | MehCars
| CarMakeID | CarModelID | CarModel
-----------------------------------------
| 1 | 1 | Zoom
| 2 | 1 | Wow
| 3 | 1 | Awesome
| 4 | 2 | Mediocrity
| 5 | 2 | YoureSettling
I want to produce a dataset like this:
| CarMakeID | CarMake | CarModels
---------------------------------------------
| 1 | SuperCars | Zoom, Wow, Awesome
| 2 | MehCars | Mediocrity, YoureSettling
What do I do in place of 'AGG' for strings in SQL Server in the following style query?
SELECT *,
(SELECT AGG(CarModel)
FROM CarModels model
WHERE model.CarMakeID = make.CarMakeID
GROUP BY make.CarMakeID) as CarMakes
FROM CarMakes make
http://www.simple-talk.com/sql/t-sql-programming/concatenating-row-values-in-transact-sql/
It is an interesting problem in Transact SQL, for which there are a number of solutions and considerable debate. How do you go about producing a summary result in which a distinguishing column from each row in each particular category is listed in a 'aggregate' column? A simple, and intuitive way of displaying data is surprisingly difficult to achieve. Anith Sen gives a summary of different ways, and offers words of caution over the one you choose...
If it is SQL Server 2017 or SQL Server VNext, Azure SQL database you can use String_agg as below:
SELECT make.CarMakeId, make.CarMake,
CarModels = string_agg(model.CarModel, ', ')
FROM CarModels model
INNER JOIN CarMakes make
ON model.CarMakeId = make.CarMakeId
GROUP BY make.CarMakeId, make.CarMake
Output:
+-----------+-----------+---------------------------+
| CarMakeId | CarMake | CarModels |
+-----------+-----------+---------------------------+
| 1 | SuperCars | Zoom, Wow, Awesome |
| 2 | MehCars | Mediocrity, YoureSettling |
+-----------+-----------+---------------------------+