I have already looked at this question but there was no solution.
Here is the problem.
po [myNumberFormatter stringFromNumber:myNumber]
Output--> (id) $4 = 1.500,00
p (char) [(NSString *)[myNumberFormatter stringFromNumber:myNumber] characterAtIndex:1]
Output--> (char) $5 = '\xa0'
po [(NSString *)[myNumberFormatter stringFromNumber:myNumber] stringByReplacingOccurrencesOfString:#"\xa0" withString:#" "]
Output--> (id) $6 = 1.500,00
One thing to note though is that on the screen, the value 1.500,00 looks like 1 500,00.
But is there any way to convert the '\xa0' character to a #" " within the string?
This following solution already works, but it has the problem of converting everything not included into a blank character.
po [(NSString *)[myNumberFormatter stringFromNumber:myNumber] stringByReplacingSequenceOfCharactersInSet:(NSCharacterSet *)[[NSCharacterSet characterSetWithCharactersInString:#"0123456789,."] invertedSet] with:#" "]
Edit --------------
I've tried the answer below and i thought it was wrong becuase
po [(NSString *)[numberFormatter stringFromNumber:theNumber] stringByReplacingOccurrencesOfString:#"\u00a0" withString:#" "]
still produced the same result (the \xa0 char was still not removed). But when I did not place it in the debugger, but instead placed it in a NSString within the code, the correct answer was stored and the \xa0 character was removed. Guess I should not depend on debugger log alone.
NSString *str = // string to cleanup
str = [str stringByReplacingOccurrencesOfString:#"\u00a0" withString:#" "];
The \u00a0 will get replaced at compile time with an actual no-break space.
In my opinion replacing "\u00a0" is not a generic solution because there are chances that nect time server may send any other unicode character then the code will not be able to handle that. Also "\u00a0" isnot a string its a character.PFB the code that i used to filter out only digits from server response that was:
phoneNumber= "000 \U00a0950";
Since i just wanted numbers in phoneNumber i wrote:
self.phoneNumber = [NSMutableString stringWithCapacity:[[_storeDetails objectForKey "phone"] length]]; //which is 000 \U00a0950
NSCharacterSet *numberCharacterSet = [NSCharacterSet decimalDigitCharacterSet];
for (int i = 0; i < [[_storeDetails objectForKey "phone"] length]; i++)
{
unichar characterOfPhoneNumber = [[_store objectForKey "phone"] characterAtIndex:i];
if ([numberCharacterSet characterIsMember:characterOfPhoneNumber])
{ [self.phoneNumber appendString:[NSString stringWithFormat "%c",characterOfPhoneNumber]];
}
}
//in the above code i parsed each character and checked if that was a number, added that in an array and hence the array is unicode free.
PS:\U00a0 is a character
Related
Could anyone give some advise please.
In my iOS app I am parsing XML (with a help of third-party-library) and have a problem with extra whitespaces/newLines at the beginning/end of the strings. Initial string, that return this third-party-library, it's a C++ std::wstring that I convert to NSString (the encoding should be right as the content of new NSString is equal to proper part of my XML-file). After the trim length of "empty" elements (that contain only whitespaces and new lines) doesn't become zero but change it's value by half.
The code is below....
std::wstring val;
NSString *initial = [[NSString alloc] initWithBytes:val.data() length:sizeof (wchar_t)*val.size() encoding:NSUTF16LittleEndianStringEncoding];
NSString *trimmed = [initial stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
If try to output like NSLog(#"bybyby'%#'bebebe", trimmed); 'bebebe have never displayed. Looks like that there are left some new lines, whitespaces that can't be detected.
wchar_t is a 32-bit integer (on iOS and OS X), therefore you must use NSUTF32LittleEndianStringEncoding for the conversion to NSString.
Example:
std::wstring val (L" Hello World ");
NSString *initial = [[NSString alloc] initWithBytes:val.data() length:sizeof (wchar_t)*val.size() encoding:NSUTF32LittleEndianStringEncoding];
NSString *trimmed = [initial stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
NSLog(#"'%#'", trimmed);
// Output: 'Hello World'
What probably happened in your case (with NSUTF16LittleEndianStringEncoding)
is that every second character in the initial string is a NUL character,
which acts as a terminator when printed.
i just updated to ios 7 sdk, and I would like to trim/replace the whitespace between characters of a string whereby the numbers are taken out from ABAddressBook.
I have tried using the replace " " with "" code below, but this code doesnt seems to work in ios7 sdk, it works fine in ios 6 sdk by the way.
NSString *TrimmedNumberField = [self.numberField.text
stringByReplacingOccurrencesOfString:#" " withString:#""];
is there any other way I could do it in IOS 7?
EDIT:
It's a phone number type that I'm trying.
Input: "+65 12 345 6789"
The output i got from NSLog is " 12 345 6789"
I realized that when I added into NSDictionary and view it in NSLog, it appears that it contains a unix code representation of \u00a0 which is similar to the "dot in the middle" which is not equals to a fullstop.
thanks in advance.
Found the answer from here
phoneNumber = [phoneNumber stringByReplacingOccurencesOfString:#"." withString:#""];
// where #"." was created by typing Option+ Spacebar
The number is extracted from ABAddressbook.
You can loop over the string and remove whitespace as long as there is any
NSString *someString = #"A string with multiple spaces and other whitespace.";
NSMutableString *mutableCopy = [someString mutableCopy];
// get first occurance of whitespace
NSRange range = [mutableCopy rangeOfCharacterFromSet:[NSCharacterSet whitespaceCharacterSet]];
// If there is a match for the whitespace ...
while (range.location != NSNotFound) {
// ... delete it
[mutableCopy deleteCharactersInRange:range];
// and get the next whitespace
range = [mutableCopy rangeOfCharacterFromSet:[NSCharacterSet whitespaceCharacterSet]];
}
// no more whitespace. You can get back to an immutable string
someString = [mutableCopy copy];
The result with the string above is Astringwithmultiplespacesandotherwhitespace.
Try This:
NSString *str = #" untrimmed string ";
NSString *trimmed = [str stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
Try This
[yourString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
whitespaceCharacterSet Apple Documentation for iOS says
Returns an NSData object encoding the receiver in binary format.
(NSData *)bitmapRepresentation
Return Value
An NSData object encoding the receiver in binary format.
Discussion
This format is suitable for saving to a file or otherwise transmitting or archiving.
A raw bitmap representation of a character set is a byte array of 2^16 bits (that is, 8192 bytes). The value of the bit at position n represents the presence in the character set of the character with decimal Unicode value n. To test for the presence of a character with decimal Unicode value n in a raw bitmap representation, use an expression such as the following:
So Try This
NSString *testString = #" Eek! There are leading and trailing spaces ";
NSString *trimmedString = [testString stringByTrimmingCharactersInSet:
[NSCharacterSet whitespaceAndNewlineCharacterSet]];
I'm trying to loop through a NSString, character by character, but I'm getting a EXC_BAD_ACCESS error. Do you have an idea how to do this right? I've been googling for hours now but can't figure it out.
Here is my code (.m):
self.textLength = [self.text length];
for (int position=0; position < self.textLength; position++) {
NSLog(#"%#", [self.text characterAtIndex:position]);
if ([[self.text characterAtIndex:position] isEqualToString:#"."]){
NSLog(#"it's a .");
}
}
Thanks a lot!
Characters are not object. characterAtIndex returns unichar, which is actually an integer type unsigned short. You need to use %C instead of %# in NSLog. Also character is not a NSString, so you can't send it isEqualToString. You need to use ch == '.' to compare ch against '.'.
unichar ch = [self.text characterAtIndex:position];
NSLog(#"%C", ch);
if (ch == '.') {} // single quotes around dot, not double quotes
Note that, 'a' is character, "a" is C string and #"a" is NSString. They all are different types.
When you are using %# with unichar ch in NSLog, it is trying to print an object from memory location ch which is invalid. Thus you are getting a EXC_BAD_ACCESS.
characterAtIndex: returns a unichar, so you should use NSLog(#"%C", ...) instead of #"%#".
You also cannot use isEqualToString for a unichar, just use == '.' is fine.
If you want to find the position of all '.'s, you can use rangeOfString. Refer to:
String Programming Guide: Searching, Comparing, and Sorting Strings
Position of a character in a NSString or NSMutableString
characterAtIndex: returns a unichar, which is declared as typedef unsigned short unichar; The format specifier you are using in your calls to NSLog are incorrect, you could just do NSLog(#"%u",[self.text characterAtIndex:position]); or NSLog(#"%C",[self.text characterAtIndex:position]); if you want the actual character to print out.
Also, as a result of unichar being defined the way that it is, it's not a string, so you cannot compare it to other strings. Try something like:
unichar textCharacter = '.';
if ([self.text characterAtPosition:position] == testCharacter) {
// do stuff
}
If you want to find the location of a character in a string you can use this:
NSUInteger position = [text rangeOfString:#"."].location;
if the character or text is not found you will get a NSNotFound:
if(position==NSNotFound)
NSLog(#"text not found!");
I have read that to left-pad an NSString all you need to do is this:
NSString *paddedStr = [NSString stringWithFormat:#"%-20.20# %-20.20#",
aString, anotherSting];
But, that does not work !! I don´t know why. I have tried a lot of combinations without success. Examples:
NSString *paddedStr = [NSString stringWithFormat:#"%-20s#", " ", myString];
but that way is ugly and ... ugly. It just append 20 times the char (" ") before the string (myString) and that is not what we need right?
The goal is to have an NSString formatted to present two or more columns of 20 chars each one no matter the length of the string within a row.
Example Goal Output:
Day Hour Name Age
Does anybody know how to do this right?
I'm using ARC and iOS 5.
And actually, the formatted string is going to be written to file using NSFileHandle.
Thanks to all of you folks !!
Edit:
I have noticed that this works:
NSString *str = [NSString stringWithFormat:#"%-10.10s %-10.10s",
[strOne UTF8String], [strTwo UTF8String]];
But... We don't want C-style strings either.
Here is a way to do that :
NSString *paddedStr = [NSString stringWithFormat:#"%#%#",
[#"day" stringByPaddingToLength:20
withString:#" "
startingAtIndex:0],
[#"Hour" stringByPaddingToLength:20
withString:#" "
startingAtIndex:0]];
I'm receiving an NSString which uses commas as delimiters, and a backslash as an escape character. I was looking into splitting the string using componentsSeparatedByString, but I found no way to specify the escape character. Is there a built-in way to do this? NSScanner? CFStringTokenizer?
If not, would it be better to split the string at the commas, and then rejoin tokens that were falsely split (after inspecting them for a (non-escaped) escape character at the end) or looping through each character trying to find a comma, and then looking back one character to see if the comma is escaped or not (and then one more character to see if the escape character is escaped).
Now that I think about it, I would need to check that the amount of escape characters before a delimiter is even, because only then is the delimiter itself not being escaped.
If someone has a method that does this, I'd appreciate it if I could take a look at it.
I think the most straightforward method to do this would be to go through the string character by character as you suggest, appending into new string objects. You can follow two simple rules:
if you find a backslash, ignore but copy the next character (if exists) unconditionally
if you find a comma, end of that section
You could do this manually or use some of the functionality of NSScanner to help you (scanUpToCharactersFromSet:intoString:)
I would prefer to use a regular expression based parser to weed out the escape characters and then possibly doing a split operation (of some type) on the string.
Okay, (I hope) this is what wipolar suggested. It's the first implementation that works. I've just started with a non-GC-collected language, so please post a comment if you think this code can be improved, especially in the memory-management department.
- (NSArray *) splitUnescapedCharsFrom: (NSString *) str atChar: (char) delim withEscape: (char) esc
{
NSMutableArray * result = [[NSMutableArray alloc] init];
NSMutableString * currWord = [[NSMutableString alloc] init];
for (int i = 0; i < [str length]; i++)
{
if ([str characterAtIndex:i] == esc)
{
[currWord appendFormat:#"%c", [str characterAtIndex:++i]];
}
else if ([str characterAtIndex:i] == delim)
{
[result addObject:[NSString stringWithString:currWord]];
[currWord release];
currWord = [[NSMutableString alloc] init];
}
else
{
[currWord appendFormat:#"%c", [str characterAtIndex:i]];
}
}
[result addObject:[NSString stringWithString:currWord]];
[currWord release];
return [NSArray arrayWithArray:result];
}