I'm trying to clean this data: https://dl.dropbox.com/u/820037/local_council_election_data_w_occupation.gz
It's all the candidates for a local councils' election in Finland. In the column "Ammatti" there is the occupation of a candidate as reported by him/her.
I want to find all the students, but the problem is, that they can be "opiskelija" (student) or "yliopisto-opiskelija" (university student) and things like that.
I clicked the column title "Ammatti" and Filtered it with "opiskelija", then I created a "text facet" from the menu in column title.
That gives me the following facet:
agrol. opiskelija AMK 1
agrologiopiskelija 9
agronomiopiskelija 1
...and so on.
I'd want to change the value of "Ammatti" (occupation) to "opiskelija" (student) in everyone of these occasions.
To make thngs a bit more complicated the facet has also some occupations (mature students and administrative staff) I don't want to change to "opiskelija":
aikuisopiskelija 10
opiskelijakunnan hallituksen varapuheenjohtaja 1
opiskelijapalvelun päällikkö 1
opiskelijapalvelupäällikkö 1
I did this by hand clicking through the whole list in the facet and changing the occupations one by one.
I suppose there is a better way to do this, but could someone please tell me how I should've done it?
Using the 'include' option in the facet, select all the rows that you want to transform from the column "Ammatti". Then in for this column invoke the Transform function and replace "value" by "opiskelija"
This will replace all the value you have selected by "opiskelija".
Hope this help (and it doesn't come too late).
Related
So I feel like this isn't too complicated of a request, but I simply can't figure it out. On my WooCommerce site, I have some variable products. There are 3 dropdown variation attributes in the following order (top to bottom): Color, Type, and Part Number. Each variation has a unique part number (only 1 part number per combination), so there is literally no need for the user to select the part number after they have chosen color & type. However, I need that part number to display for purposes of my product feed and so the customer can see the part number they have chosen by the previous 2 options.
My question is; since selecting a "Color" and "Type" narrows the final field ("Part number") down to only 1 option, how do I instruct WooCommerce to automatically select the single "part number" option that's available?
You can do this with JS:
jQuery('a.toggle_component').click(function(e){
if(!(jQuery(e.target).parents('.component').find('select.component_options_select > option[selected=selected]').val())) {
jQuery(e.target).parents('.component').find('select.component_options_select > option:nth-child(2)').attr('selected','selected');
jQuery(e.target).parents('.component').find('select.component_options_select').change();
}
});
I'm trying to do an ad hoc search of records that contain duplicate values in the first and second elements of a multivalued UniData field. I was hoping something like this would work but I'm not having any luck.
LIST PERSON WITH EVAL "STATUS[1] = STATUS[2]"
After some testing it looks like I stumbled across a way of reading the field right to left that many characters. Interesting but not useful for what I need.
LIST PERSON NAME EVAL "NAME[3]" COL.HDG 'Last3'
PERSON Name Last3
0001 Smith ith
Any ideas on how to correctly select on specific field elements?
Apparently the EXTRACT function will let me specify an element but I still can't get a selection on it to work properly.
LIST PERSON STATUS EVAL "EXTRACT(STATUS,1,2,0)" COL.HDG 'Status2'
PERSON STATUS Status2
0001 Added Processed
Processed
I would use eval with #RECORD placeholder with the dynamic array notation as such (assuming that STATUS is in Attribute 11.
Edit:
Previous answer was how I would do this in UniVerse
SELECT PERSON WITH EVAL "#RECORD<11,1>" EQ EVAL "#RECORD<11,2>"
Script Wolf's more better way that works in UniVerse and UniData.
SELECT PERSON WITH EVAL "EXTRACT(#RECORD,11,1,0)" EQ EVAL "EXTRACT(#RECORD,11,2,0)"
Good Luck.
What would the custom expression be to sum data by a category, for each site.
Using the data below, I would like to Sum[X] for only values with category blue, for each site
What I have so far is Sum([X]) OVER [Site] --> Where / how do I put in the category qualifier?
the Intersect() function is a perfect fit here. it creates a hierarchy based on however many columns you list. more info in the documentation.
anyway, try the following:
Sum([X]) OVER (Intersect([Site], [Category]))
To do the same for only a single category, you can use an expression like
Sum(If([Category]="Blue",[X],0)) OVER ([Site])
This will leave a null/empty value when [X] is not "Blue" (case sensitive so beware!).
If you have multiple values, you can replace the condition with
If([X] in ("Blue", "Nurple", "Taupe"), ...)
what I found works best is: Sum(If([Category]="Blue",[X],0)) OVER ([Site])
I am a beginner in QTP and I am working on an application where there are two different web tables displayed.
The second web table is detail description of the first web table so it displays when we select a row in the first web table.
In other words, Each row in the first table is selectable and when selected corresponds to the second web table
Web table 1 contains something like below for a user
RelationShip | Name
Father | AAA
Mother | BBB
Brother | CCC
Sister | DDD
Sister2 | EEE
Web Table 2 Contains detailed information for each row in Web Table 1 as I earlier mentioned. SO for Father, the below table is reflected
Details
Name | AAA
Age | 50
Relationship | Father
and so on
Second User might/might not have brother/sister.
The problem now I am facing is retrieving data from second web table for different entity of first one since all the property of the web table are similar expect the below property
"html ID" which corresponds to - "DetailParty_randomno"
This random number is the one which defines the uniqueness of the second web table, which can be retrieved from the first web table though it isn't found in the properties section when we use the Object spy.
I can see this random number when I view the source code of the page. It's displayed as value entity in the tr tag
Value entity looks like "Party_randomno"
<tr style="background-color:yellow" value="Party_1" onclick="Call peoplehighlight("Party_1")" language="vbscript">
My question is if there a way to retrieve this value for each row and then use it in identifying the second web table?
However I did try to read from second table by hard coding "html id" in webtable property to see if it's being read but it didn't work
So my second question is with respect to the correctness of the below descriptive programming code. Is there something else I need to include/exclude in the WebTable property to find uniqueness.
I also did my research and found that it's useful to use index but I am not aware on how to find the index of a web table? Also the index changes for each user I am searching and hence I need to find the index of the table during run time before using it
BrowserName = Browser("micClass:=Browser").GetROProperty("name")
PageName= Browser("micClass:=Browser").Page("micClass:=Page")GetROProperty("name")
Set desc = Description.Create()
desc("html tag").Value = "tr"
Set Rows = Browser("B").Page("P").Webtable("WT").ChildObjects(desc)
RoCounter = Rows.Count-1
For valuecount = 0 To RoCounter
id= rows(i).Object.GetAttribute("value")
Next
'When the right ID is got, parsing it in the below for WT2 Identification
Set ObjTable = Browser("name:="&Browsername).Page("name:="& Pagename).WebTable("class:=Web_Table", "html id:=Detail"&id)
Update
I was able to get the value from the source code using Motti's code. needed to tweak a little and my descriptive programming had spaces between name and : so the objetct wasn't being recognized. It's solved now.
When looking at the description you gave to your WebTable I find it hard to see what you're trying to achieve. class in QTP is mapped to the html className property are you sure that Web_Table is correct className? Also there is (AFAIK) no class name property in QTP, if you mean the test object type then there's no need to add it since you already said that the object is a WebTable.
To answer your question, in order to add indexing you just add "index:=1" to the smart identification (or in the description if you're using the object repository), note that index is zero based so 1 is the second object that matches the description (if there are more than one, if there is only one the index is ignored).
In order to get the random number you can try something like this (untested)
Set desc = Description.Create()
desc("html tag").Value = "tr"
Set rows = Browser("B").Page("P").WebTable("T").ChildObjects(desc)
For i = 0 To rows.Count - 1
id = rows(i).GetROProperty("value") ' Or whatever you need here
Next
I'm trying to generate a new SharePoint list item directly using SQL server. What's stopping me is damn tp_DirName column. I have no ideas how to create this value.
Just for instance, I have selected all tasks from AllUserData, and there are possible values for the column: 'MySite/Lists/Task', 'Lists/Task' and even 'MySite/Lists/List2'.
MySite is the FullUrl value from Webs table. I can obtain it. But what about 'Lists/Task' and '/Lists/List2'? Where they are stored?
If try to avoid SQL context, I can formulate it the following way: what is the object, that has such attribute as '/Lists/List2'? Where can I set it up in GUI?
Just a FYI. It is VERY not supported to try and write directly to SharePoint's SQL Tables. You should really try and write something that utilizes the SharePoint Object Model. Writing to the SharePoint database directly mean Microsoft will not support the environment.
I've discovered, that [AllDocs] table, in contrast to its title, contains information about "directories", that can be used to generate tp_DirName. At least, I've found "List2" and "Task" entries in [AllDocs].[tp_Leaf] column.
So the solution looks like this -- concatenate the following 2 components to get tp_DirName:
[Webs].[FullUrl] for the web, containing list, containing item.
[AllDocs].[tp_Leaf] for the list, containing item.
Concatenate the following 2 components to get tp_Leaf for an item:
(Item count in the list) + 1
'_.000'
Regards,
Well, my previous answer was not very useful, though it had a key to the magic. Now I have a really useful one.
Whatever they said, M$ is very liberal to the MOSS DB hackers. At least they provide the following documents:
http://msdn.microsoft.com/en-us/library/dd304112(PROT.13).aspx
http://msdn.microsoft.com/en-us/library/dd358577(v=PROT.13).aspx
Read? Then, you know that all folders are listed in the [AllDocs] table with '1' in the 'Type' column.
Now, let's look at 'tp_RootFolder' column in AllLists. It looks like a folder id, doesn't it? So, just SELECT the single row from the [AllDocs], where Id = tp_RootFolder and Type = 1. Then, concatenate DirName + LeafName, and you will know, what the 'tp_DirName' value for a newly generated item in the list should be. That looks like a solid rock solution.
Now about tp_LeafName for the new items. Before, I wrote that the answer is (Item count in the list) + 1 + '_.000', that corresponds to the following query:
DECLARE #itemscount int;
SELECT #itemscount = COUNT(*) FROM [dbo].[AllUserData] WHERE [tp_ListId] = '...my list id...';
INSERT INTO [AllUserData] (tp_LeafName, ...) VALUES(CAST(#itemscount + 1 AS NVARCHAR(255)) + '_.000', ...)
Thus, I have to say I'm not sure that it works always. For items - yes, but for docs... I'll inquire into the question. Leave a comment if you want to read a report.
Hehe, there is a stored procedure named proc_AddListItem. I was almost right. MS people do the same, but instead of (count + 1) they use just... tp_ID :)
Anyway, now I know THE SINGLE RIGHT answer: I have to call proc_AddListItem.
UPDATE: Don't forget to present the data from the [AllUserData] table as a new item in [AllDocs] (just insert id and leafname, see how SP does it itself).