I have the following tables:
T1
ID PRIORITY
1 1
2 1
3 2
4 4
T2
ID SERVICE
1 PSTN
1 ADSL
3 ADSL
T3
ID DEVICE
1 BSC1
3 BSC7
4 BSC7
I want as output
ID PRIORITY SERVICE/DEVICE
1 1 PSTN
1 1 ADSL
1 1 BSC1
2 1
3 2 ADSL
3 2 BSC7
How to bind those tables using UNION ALL? Also I must put WHERE clause for T1 WHERE PRIORITY!=4
Total number in output table for one id should be the summary of T2+T3 (FOR ID=1 2+1=3) but for ID=2 it also SHOULD exist in table output with blank second column.
Thank you
If you are okay using just a UNION and not UNION ALL this should give you what you want
SELECT t1.Id, t1.Priority, COALESCE(t2.Service, '') AS [Service/Device]
FROM t1
LEFT JOIN t2 ON t1.Id = t2.Id
WHERE t1.Priority != 4
UNION
SELECT t1.Id, t1.Priority, COALESCE(t3.Device, '') AS [Service/Device]
FROM t1
LEFT JOIN t3 ON t1.Id = t3.Id
WHERE t1.Priority != 4
SQL Fiddle example
select T1.id , T1.PRIORITY ,T2.SERVICE as service/Device from t1
left outer join T2 on T2.id=T1.id where T1.PRIORITY!=4
union all
select T1.id , T1.PRIORITY ,T3.DEVICE as service/Device from t1
left outer join T3 on T3.id=T1.id where PRIORITY!=4
Related
I have two tables like eg.
Table1
id title
1 t1
2 t2
3 t3
4 t4
5 t5
6 t6
7 t7
Table2
id tid parent_id
1 2 1
2 3 1
3 4 2
4 5 3
5 7 6
I am getting the results only for one level by inner join with the parent id and the query is:
SELECT id,title
from table1 INNER JOIN
table2
ON table2.tid = table1.id
where table2.parent_id = 1
I just want the output all the child and sub-child of parent id like.
let's suppose here i just want the all child and sub-child for the parent id 1 then output will come eg:
Output
id title
2 t2
3 t3
4 t4
5 t5
Because t2,t3 parent id is 1 and t4,t5 is under the 2 and 2 is under the 1 parent id as well as t3 also.
so I want all the child and subchild by the parent id.
If you have any confusion please let me know thanks
You want a recursive CTE:
with recursive cte as (
select t2.tid
from table2 t2
where t2.parent_id = 1
union all
select t2.tid
from cte join
table2 t2
on t2.parent_id = cte.tid
)
select t1.*
from cte join
table1 t1
on t1.id = cte.tid;
Find all descendants of top-level items
with recursive hier(topid, tid, parent_id, level) as(
select t1.id topid, t1.id tid, null parent_id, 1 level
from Table1 t1
where not exists(select 1 from Table2 where tid = t1.id)
union all
select h.topid, t2.tid, h.tid, level+1
from hier h
join Table2 t2 on h.tid = t2.parent_id
order by level desc
)
select h.topid parent, h.tid descendant, t.title, h.level
from hier h
join Table1 t on t.id = h.tid
where level > 1;
Fiddle
Let's say I have Two tables T1 and T2 with ID as the column. For example
T1:ID
1
2
3
4
5
T2:ID
4
5
6
7
8
How can get a column where my result is 1 2 3 6 7 8 I want to exclude the common IDs from both the table and display the result in one column.
Hmmm . . . one method is union all:
select t1.id
from table1 t1
where not exists (select 1 from table2 t2 where t2.id = t1.id)
union all
select t1.id
from table2 t2
where not exists (select 1 from table1 t1 where t2.id = t1.id);
use minus
select id from
(
select id from t1
union
select id from t2
) a
minus select id from (
select id from t1 join t2 on t1.id=t2.id
) b
If your DBMS support FULL OUTER JOIN then i would do :
select coalesce(t1.id, t2.id)
from t1 full outer join
t2
on t2.id = t1.id
where (t1.id is null or t2.id is null);
how to solve 3 table and group same id?
t1
----------
Id a
1 100
1 600
2 800
t2
----------
Id b
1 600
2 700
3 400
t3
----------
Id c
2 400
3 800
4 100
i want result like this:
Id a b c
------------------------------
1 700 600
2 800 700 400
3 400 800
4 100
Same id group by
do the fact you have id in several table youn should get, eg: using union ,all the id you need for join
select t.id, t1.a, t2.b, t3.c
from (
select id
from t1
union
select id
from t2
union
select id
from t3 ) AS t
left join t1 on t.id = t1.id
left join t2 on t.Id = t2.Id
left join t3 on t.Id = t3.Id
and if you need sum for a,b,c
select t.id, sum(t1.a), sum(t2.b), sum(t3.c)
from (
select id
from t1
union
select id
from t2
union
select id
from t3 ) AS t
left join t1 on t.id = t1.id
left join t2 on t.Id = t2.Id
left join t3 on t.Id = t3.Id
group by t.id
To ensure that you are taking all possible values use full outer join. Though this will not work in mySQL. If that is the case then look at this answer
select coalesce(t1.id,t2.id,t3.id) as id, sum(t1.a) as a, sum(t2.b) as b,sum(t3.c) as c
from t1
outer join t2
on t1.id = t2.id
outer join t3
on t1.id = t3.id
or t2.id = t3.id
group by id
Might be misunderstanding you, but looks like you just need to join the table more than doing a Union Operation on them. Below statement will only return records where all three tables have at least one record with the same id.
SQL would be:
SELECT TBL1.ID,
TBL1.A,
TBL2.B,
TBL3.C
FROM A TBL1 (NOLOCK)
INNER JOIN B TBL2 (NOLOCK) ON TBL1.ID = TBL2.ID
INNER JOIN C TBL3 (NOLOCK) ON TBL1.ID = TBL3.ID
Two questions:
1. Which SQL engine to you use?
2. and do you need to return values where one table does not have the id?
I have two tables:
id
1
2
3
4
t1 AND t2
id | related_id
1 | 2
1 | 3
Where t2 is relationship table between t1 records. What is the best way to get desired output?
t1.id | t1_copy.id
1 | NULL -- want to get this NULL row
1 | 2
1 | 3
Simple JOIN would almost work, however it doesn't give me the first NULL row.
SELECT t1.id, t1_copy.id FROM t1
LEFT JOIN t2 ON t1.id = t2.id
LEFT JOIN t1 t1_copy ON t1_copy.id = t2.related_id
WHERE t1.id = 1
P.S: Yes, I do realize that desired output is wacky.
Seems like a simple UNION should do the trick
SELECT
id,
null as copy_id
FROM
t1
WHERE
exists (select * from t2 where t1.id = t2.id)
UNION ALL
SELECT
t1.id,
t2.related_id
FROM
t1
INNER JOIN t2
ON t1.id = t2.id
SQL Fiddle
SELECT DISTINCT t1.id, t1_copy.id FROM t1
LEFT OUTER JOIN t2 ON t1.id = t2.id
WHERE t1.id = 1
I have two tables:
TABLE 1
ID VALUE
1 ABC
2 DEF
3 GHI
4 JKL
5 XYZ
TABLE 2
ID T1_ID VALUE
1 1 A
2 1 B
3 2 A
4 3 A
5 3 B
6 4 B
I want to select all rows from TABLE 1 which have a TABLE 2 row for Values A AND B.
This would be rows 1 and 3 (not 2 because it has only A, not 4 because it has only B).
Can I do this without a subquery?
(Note: I also need to query against values in table 1 so I can't just query table 2.)
Tadaaah! Without a subquery.
select distinct
t1.*
from
Table1 t1
inner join Table2 t2a on t2a.t1_ID = t1.ID and t2a.VALUE = 'A'
inner join Table2 t2b on t2b.t1_ID = t1.ID and t2b.VALUE = 'B'
SELECT t1.ID,
t1.VALUE
FROM Table1 t1
JOIN Table2 t2
ON t1.ID = t2.T1_ID
WHERE t2.VALUE IN ( 'A', 'B' )
GROUP BY t1.ID,
t1.VALUE
HAVING COUNT(DISTINCT t2.VALUE) = 2