I have two SQL queries for counting the rows from the table tContentNode, depending on the type 2 or 3.
Query 1:
SELECT count(*) _countA FROM TCONTENTNODE WHERE type = '2'
AND parentid ='02b3abc2-4983-485a-ab09-1a8cb328b9b5';
Query 2:
SELECT count(*) _countB FROM TCONTENTNODE WHERE type = '3'
AND parentid ='02b3abc2-4983-485a-ab09-1a8cb328b9b5';
Now I want to get the values of _countA and _countB using only one query. How can I get the counts using one query. Is there any way to do that. I am using SQLite Database.
EDIT:
I want values of _countA and _countB separately, not both together(Not using IN).
I solved the problem using the following query:-
SELECT
COUNT(case TCONTENTNODE.type when '2' then 1 end) as _countA,
COUNT(case TCONTENTNODE.type when '3' then 1 end) as _countB
FROM TCONTENTNODE
WHERE TCONTENTNODE.parentid ="02b3abc2-4983-485a-ab09-1a8cb328b9b5";
Dont have SQLite to confirm but
select count(*), type FROM TCONTENTNODE WHERE (type = '2' or type = '3' )
AND parentid ='02b3abc2-4983-485a-ab09-1a8cb328b9b5' group by type
Just to clarify this will return
count type
23 2
23888 3
Try to use group by
SELECT type,count(*) as cnt
FROM TCONTENTNODE
WHERE parentid ='02b3abc2-4983-485a-ab09-1a8cb328b9b5';
group by type
for two variables:
SELECT
COUNT(case TCONTENTNODE.type when '2' then 1 end) as _countA,
COUNT(case TCONTENTNODE.type when '3' then 1 end) as _countB
FROM TCONTENTNODE
WHERE TCONTENTNODE.parentid ='02b3abc2-4983-485a-ab09-1a8cb328b9b5';
Use IN KeyWord
SELECT count(*) _countB FROM TCONTENTNODE WHERE (type IN (3,2) AND
parentid ='02b3abc2-4983-485a-ab09-1a8cb328b9b5');
Related
I have a table contain records as per below image. I want to do a count for each status and am able to do that by selecting each type of status. Which I will needs to exec 4 query to get the result. I would like to know how can I achieve that by using single query statement? Any advices or suggestion is welcome and highly appreciated. Thanks in advance.
WITH CTE(NO,STATUS)AS
(
SELECT 1,'OPEN' UNION ALL
SELECT 2,'OPEN'UNION ALL
SELECT 3,'BILLED'UNION ALL
SELECT 4,'CANCELLED'UNION ALL
SELECT 5,'BILLING'UNION ALL
SELECT 6,'BILLED'UNION ALL
SELECT 7,'CANCELLED'UNION ALL
SELECT 8,'BILLING'UNION ALL
SELECT 9,'CONFIRM'UNION ALL
SELECT 10,'IN PROGRESS'UNION ALL
SELECT 11,'OPEN'UNION ALL
SELECT 12,'CONFIRM'
)
SELECT
SUM(CASE WHEN C.STATUS='BILLED'THEN 1 ELSE 0 END)AS BILLED,
SUM(CASE WHEN C.STATUS='BILLING'THEN 1 ELSE 0 END)AS BILLING,
SUM(CASE WHEN C.STATUS='CANCELLED'THEN 1 ELSE 0 END)AS CANCELLED,
SUM(CASE WHEN C.STATUS NOT IN ('CANCELLED','BILLING','BILLED')THEN 1 ELSE 0 END)AS UNBILL
FROM CTE AS C
CTE is an example you have provided. Please replace reference to it with reference to your table
I have been building up a query today and I have got stuck. I have two unique Ids that identify if and order is Internal or Web. I have been able to split this out so it does the count of how many times they appear but unfortunately it is not providing me with the intended result. From research I have tried creating a Count Distinct Case When statement to provide me with the results.
Please see below where I have broken down what it is doing and how I expect it to be.
Original data looks like:
Company Name Order Date Order Items Orders Value REF
-------------------------------------------------------------------------------
CompanyA 03/01/2019 Item1 Order1 170 INT1
CompanyA 03/01/2019 Item2 Order1 0 INT1
CompanyA 03/01/2019 Item3 Order2 160 WEB2
CompanyA 03/01/2019 Item4 Order2 0 WEB2
How I expect it to be:
Company Name Order Date Order Items Orders Value WEB INT
-----------------------------------------------------------------------------------------
CompanyA 03/01/2019 4 2 330 1 1
What currently comes out
Company Name Order Date Order Items Orders Value WEB INT
-----------------------------------------------------------------------------------------
CompanyA 03/01/2019 4 2 330 2 2
As you can see from my current result it is counting every line even though it is the same reference. Now it is not a hard and fast rule that it is always doubled up. This is why I think I need a Count Distinct Case When. Below is my query I am currently using. This pull from a Progress V10 ODBC that I connect through Excel. Unfortunately I do not have SSMS and Microsoft Query is just useless.
My Current SQL:
SELECT
Company_0.CoaCompanyName
, SopOrder_0.SooOrderDate
, Count(DISTINCT SopOrder_0.SooOrderNumber) AS 'Orders'
, SUM(CASE WHEN SopOrder_0.SooOrderNumber IS NOT NULL THEN 1 ELSE 0 END) AS 'Order Items'
, SUM(SopOrderItem_0.SoiValue) AS 'Order Value'
, SUM(CASE WHEN SopOrder_0.SooParentOrderReference LIKE 'INT%' THEN 1 ELSE 0 END) AS 'INT'
, SUM(CASE WHEN SopOrder_0.SooParentOrderReference LIKE 'WEB%' THEN 1 ELSE 0 END) AS 'WEB'
FROM
SBS.PUB.Company Company_0
, SBS.PUB.SopOrder SopOrder_0
, SBS.PUB.SopOrderItem SopOrderItem_0
WHERE
SopOrder_0.SopOrderID = SopOrderItem_0.SopOrderID
AND Company_0.CompanyID = SopOrder_0.CompanyID
AND SopOrder_0.SooOrderDate > '2019-01-01'
GROUP BY
Company_0.CoaCompanyName
, SopOrder_0.SooOrderDate
I have tried using the following line but it errors on me when importing:
, Count(DISTINCT CASE WHEN SopOrder_0.SooParentOrderReference LIKE 'INT%' THEN SopOrder_0.SooParentOrderReference ELSE 0 END) AS 'INT'
Just so know the error I get when importing at the moment is syntax error at or about "CASE WHEN sopOrder_0.SooParentOrderRefer" (10713)
Try removing the ELSE:
COUNT(DISTINCT CASE WHEN SopOrder_0.SooParentOrderReference LIKE 'INT%' THEN SopOrder_0.SooParentOrderReference END) AS num_int
You don't specify the error, but the problem is probably that the THEN is returning a string and the ELSE a number -- so there is an attempt to convert the string values to a number.
Also, learn to use proper, explicit, standard JOIN syntax. Simple rule: Never use commas in the FROM clause.
count distinct on the SooOrderNumber or the SooParentOrderReference, whichever makes more sense for you.
If you are COUNTing, you need to make NULL the thing that your are not counting. I prefer to include an else in the case because it is more consistent and complete.
, Count(DISTINCT CASE WHEN SopOrder_0.SooParentOrderReference LIKE 'INT%' THEN SopOrder_0.SooParentOrderReference ELSE null END) AS 'INT'
Gordon Linoff is correct regarding the source of your error, i.e. datatype mismatch between the case then value else value end. null removes (should remove) this ambiguity - I'd need to double check.
Editing my earlier answer...
Even though it looks, as you say, like count distinct is not supported in Pervasive PSQL, CTEs are supported. So you can do something like...
This is what you are trying to do but it is not supported...
with
dups as
(
select 1 as id, 'A' as col1 union all select 1, 'A' union all select 1, 'B' union all select 2, 'B'
)
select id
,count(distinct col1) as col_count
from dups
group by id;
Stick another CTE in the query to de-duplicate the data first. Then count as normal. That should work...
with
dups as
(
select 1 as id, 'A' as col1 union all select 1, 'A' union all select 1, 'B' union all select 2, 'B'
)
,de_dup as
(
select id
,col1
from dups
group by id
,col1
)
select id
,count(col1) as col_count
from de_dup
group by id;
These 2 versions should give the same result set.
There is always a way!!
I cannot explain the error you are getting. You are mistakenly using single quotes for alias names, but I don't actually think this is causing the error.
Anyway, I suggest you aggregate your order items per order first and only join then:
SELECT
c.coacompanyname
, so.sooorderdate
, COUNT(*) AS orders
, SUM(soi.itemcount) AS order_items
, SUM(soi.ordervalue) AS order_value
, COUNT(CASE WHEN so.sooparentorderreference LIKE 'INT%' THEN 1 END) AS int
, COUNT(CASE WHEN so.sooparentorderreference LIKE 'WEB%' THEN 1 END) AS web
FROM sbs.pub.company c
JOIN sbs.pub.soporder so ON so.companyid = c.companyid
JOIN
(
SELECT soporderid, COUNT(*) AS itemcount, SUM(soivalue) AS ordervalue
FROM sbs.pub.soporderitem
GROUP BY soporderid
) soi ON soi.soporderid = so.soporderid
GROUP BY c.coacompanyname, so.sooorderdate
ORDER BY c.coacompanyname, so.sooorderdate;
I have table whose column is just the length of a session and I would like to return the number of session that have zero length and the number of sessions that have length greater than zero.
I can do that with two separate commands
select count(session_length) from my_table where session_length=0
select count(session_length) from my_table where session_length>0
But I would like to see the results combined in one table
You can do it with one query using conditional aggregation.
select
count(case when session_length = 0 then 1 end),
count(case when session_length > 0 then 1 end)
from my_table
select 1 as QryNo, count(session_length) as SessLen
from my_table
where session_length=0
union
select 2 as QryNo, count(session_length) as SessLen
from my_table
where session_length>0
or
select
case
when session_length = 0 then 1
else 2
end as QryNo,
count(session_length) as SessLen
from my_table
This may be too simple so apologies if I have misread your query but Can you use
select count(session_length) from my_table where session_length >= 0
Again, Apologies if this is not what you're looking for.
I've a table with NAMES and STATUS with C(completed) and N(not completed) status. I want check how many tasks are not completed for each name. I tried the following code and it is returning all '0' values:
select name, (select count(status) from alteon where status= 'n') / (select count(status) from alteon) from alteon group by name;
I'm expecting the result as not completed / total assigned where total assigned = complete+not completed.
as mentioned earlier, I'm getting value as '0' beside each employee name.
I think the following query does what you want:
select name,
sum(case when status = 'n' then 1 else 0 end) as n_status,
avg(case when status = 'n' then 1.0 else 0 end) as n_status_ratio
from alteon;
Here is the query which gives the result as you explained above.
select count(status)as Total_assigned,
sum(IF(status='n', 1, 0)) as Not_completed,name
from alteon group by name ;
Here is the sqlfiddle
You don't have to use multiple select statements. Use CASE to count the incomplete tasks.
select name, count(case when status = 'n' then 1 else null end)/count(status)
from alteon
group by name;
sqlfiddle.
I have two queries:
Select count(*) as countOne where field = '1'
Select count(*) as countTwo where field = '2'
What I want to see after executing these queries in my results viewer:
countOne | countTwo
23 | 123
How can I get the results from both queries by only running one query?
SELECT COUNT(CASE WHEN field = '1' THEN 1 END) AS countOne,
COUNT(CASE WHEN field = '2' THEN 1 END) AS countTwo
FROM YourTable
WHERE field IN ( '1', '2' )
The simplest way is to run each as a subselect eg.
SELECT
(
Select count(*) where field = '1' as countOne,
Select count(*) where field = '2' as countTwo
)
BUt this is not necesarily the best way
Another wayto do it would be to Group by field and then do PIVOT to select out each group as a separate column.