I've a table with NAMES and STATUS with C(completed) and N(not completed) status. I want check how many tasks are not completed for each name. I tried the following code and it is returning all '0' values:
select name, (select count(status) from alteon where status= 'n') / (select count(status) from alteon) from alteon group by name;
I'm expecting the result as not completed / total assigned where total assigned = complete+not completed.
as mentioned earlier, I'm getting value as '0' beside each employee name.
I think the following query does what you want:
select name,
sum(case when status = 'n' then 1 else 0 end) as n_status,
avg(case when status = 'n' then 1.0 else 0 end) as n_status_ratio
from alteon;
Here is the query which gives the result as you explained above.
select count(status)as Total_assigned,
sum(IF(status='n', 1, 0)) as Not_completed,name
from alteon group by name ;
Here is the sqlfiddle
You don't have to use multiple select statements. Use CASE to count the incomplete tasks.
select name, count(case when status = 'n' then 1 else null end)/count(status)
from alteon
group by name;
sqlfiddle.
Related
I have below tables
Table1: "Demo"
Columns: SSN, sales, Create_DT,Update_Dt
Table2: "Agent"
Columns: SSN,sales, Agent_Name, Create_Dt, Update_DT
Scenario 1 and desired result set:
I want output as 0 if the count of SSN in Demo table is matched with the count of SSN in Agent table
if the count is not matched then I want result as 1
Scenario 2 and desired result set:
I want output as 0 if the sum of sales in Demo table is matched with the sum of sales in Agent table
if the sum is not matched then I want result as 1
Please help on this query part
Thanks
You can write two queries separately to take counts within the result query
SELECT (SELECT count(Demo.SSN) as SSN1 from Demo)!=(SELECT count(Agent.SSN) as SSN2 from Agent) AS Result;
Basically what the inner queries does is it checked whether the counts are equal or not and outputs 1 if it is true and 0 if it is false. Since you have asked to output 1 if it is false I used '!=' sign.
You can try the same procedure in scenario 2 also
For scenario 1
select (Case when (select count(ssn) from Demo)=(select count(ssn) from Agent) then 0 else 1 end) as desired_result
If you want to count unique ssn then:
select (Case when (select count(distinct ssn) from Demo)=(select count(distinct ssn) from Agent) then 0 else 1 end) as desired_result
For scenario 2:
select (Case when (select sum(sales) from Demo)=(select sum(sales) from Agent) then 0 else 1 end) as desired_result
I would suggest one query with both sets of information:
select (d.num_ssn <> a.num_ssn) as have_different_ssn_count,
(d.sales <> a.sales) as have_different_sales
from (select count(distinct ssn) as num_ssn,
coalesce(sum(sales), 0) as sales
from demo
) d cross join
(select count(distinct ssn) as num_ssn,
coalesce(sum(sales), 0) as sales
from agent
) a;
Note: This returns boolean values -- true/false rather than 1/0. If you really want 0/1, then use case:
select (case when d.num_ssn <> a.num_ssn then 1 else 0 end) as have_different_ssn_count,
(case when d.sales <> a.sales then 1 else 0 end) as have_different_sales
It would not surprise me if you were not only interested in the total counts but also that the agent/sales combinations are the same in both tables. If that is the case, please ask a new question with a clear explanation. Sample data and desired results help.
I have a table STATUSES which contain columns NAME and ACTIVE_FLAG.The column value of NAME may have new, pending, cancel. I want to generate a new output for the count of each NAME with ACTIVE_FLAG=Y
By thinking to use EXISTS to select records for single NAME,
SELECT COUNT(*) AS PENDING
FROM STATUSES
WHERE EXISTS (select NAME from STATUSES where NAME='Pending' and ACTIVE_FLAG = 'Y')
Anyway if I can join other statuses count in a single SQL?
Seems like count and group by
SELECT
name
, count(*)
FROM statuses
WHERE active_flag = 'Y'
GROUP BY name
You can use something like this as i don't see any need to use EXISTS :
SELECT sum(case when name='Pending' then 1 else 0 end) AS PENDING,
sum(case when name='new' then 1 else 0 end) AS NEW,
sum(case when name='cancel' then 1 else 0 end) AS CANCEL
FROM STATUSES
WHERE ACTIVE_FLAG = 'Y'
SQL HERE
I have a table of requests with columns RequestType,status .Status column values can be in-progress,complated etc.
I would like to get the list like
RequestType In-Progress Completed Total
Type1 10 5 15
Type2 10 10 20
I tried with group by using the 2 columns( RequestType,status) ,but it does not give me the exact result.
Please help me with the sql query.
Thanks in advance
Subin
One way to do it is using conditional aggrigation:
SELECT RequestType,
SUM(CASE WHEN Status = 'In-Progress' THEN 1 ELSE 0 END) As 'In-Progress',
SUM(CASE WHEN Status = 'Completed' THEN 1 ELSE 0 END) As 'Completed',
COUNT(Status) As 'Total'
FROM TableName
WHERE Status IN('In-Progress', 'Completed')
GROUP BY RequestType
Use PIVOT
select *, [In-Progress]+[Completed] total
from TableName
pivot ( count(status) for status in ([In-Progress], [Completed])) as p
I am including a SQLFiddle to show as an example of where I am currently at. In the example image you can see that simply grouping you get up to two lines per user depending on their status and how many of those statuses they have.
http://sqlfiddle.com/#!3/9aa649/2
The way I want it to come out is to look like the image below. Having a single line per user with two totaling columns one for Fail Total and one for Pass Total. I have been able to come close but since BOB only has Fails and not Passes this query leaves BOB out of the results. which I want to show BOB as well with his 6 Fail and 0 Pass
select a.PersonID,a.Name,a.Totals as FailTotal,b.Totals as PassTotals from (
select PersonID,Name,Status, COUNT(*) as Totals from UserReport
where Status = 'Fail'
group by PersonID,Name,Status) a
join
(
select PersonID,Name,Status, COUNT(*) as Totals from UserReport
where Status = 'Pass'
group by PersonID,Name,Status) b
on a.PersonID=b.PersonID
The below picture is what I want it to look like. Here is another SQL Fiddle that shows the above query in action
http://sqlfiddle.com/#!3/9aa649/13
Use conditional aggregation if the number of values for status column is fixed.
Fiddle
select PersonID,Name,
sum(case when "status" = 'Fail' then 1 else 0 end) as failedtotal,
sum(case when "status" = 'Pass' then 1 else 0 end) as passedtotals
from UserReport
group by PersonID,Name
Use conditional aggregation:
select PersonID, Name,
sum(case when Status = 'Fail' then 1 else 0 end) as FailedTotal,
sum(case when Status = 'Pass' then 1 else 0 end) as PassedTotal
from UserReport
group by PersonID, Name;
With conditional aggregation:
select PersonID,
Name,
sum(case when Status = 'Fail' then 1 end) as Failed,
sum(case when Status = 'Passed' then 1 end) as Passed
from UserReport
group by PersonID, Name
I have a table that has a column called 'status'. This can be set to 0 or 1
Is it possible for me to count both the 0's and 1's in a single query?
Thanks in advance
James
Yes, just group on the value of status:
SELECT status, COUNT(*)
FROM yourtable
GROUP BY status
That will give you exactly two rows since the value can only be 0 or 1, and the COUNT(*) column will be the number of times each status value appears in the table.
SELECT SUM(CASE WHEN status = 0 THEN 1 ELSE 0 END) AS 'number of zeroes',
SUM(CASE WHEN status = 1 THEN 1 ELSE 0 END) AS 'number of ones'
FROM yourtable;