Is it possible to create a composite key in sql 2000
code id
abc 1
abc 2
abc 3
def 1
def 2
ghi 1
where the id restarts the count at each change of code. I need the numbering to be exactly like that either by creating a table or other SELECT statement trickery.
how to do this in sql server 2000
Need Query Help
Here is one way to retrieve this data at runtime, without having to actually store it in the table, which is incredibly cumbersome to try and maintain. I'm using a #temp table here but you can pretend #a is your permanent table. As is, this will support up to 256 duplicates. If you need more, it can be adjusted.
CREATE TABLE #a(code VARCHAR(32));
INSERT #a SELECT 'abc'
UNION ALL SELECT 'abc'
UNION ALL SELECT 'abc'
UNION ALL SELECT 'def'
UNION ALL SELECT 'def'
UNION ALL SELECT 'ghi';
GO
SELECT x.code, id = y.number FROM
(
SELECT code, maxid = COUNT(*) FROM #a GROUP BY code
) AS x
CROSS JOIN
(
SELECT DISTINCT number FROM master..spt_values
WHERE number BETWEEN 1 AND 256
) AS y
WHERE x.maxid >= y.number;
DROP TABLE #a;
You can try this
INSERT INTO TABLENAME (code, id) VALUES( 'code',
(Select ISNULL(MAX(id), 0) FROM TableName where code = 'code')+1)
Related
I have the following query in SQL Server. How do I get the number of rows of previous select query as following format?
Sample Query
select ID, Name FROM Branch
UNION ALL
SELECT ROWCOUNT_BIG(), ''
Sample Output
If you use a CTE you can count the rows and union all together:
with cte as (
select ID, [Name]
from dbo.Branch
)
select ID, [Name]
from cte
union all
select count(*) + 1, ''
from cte;
I think you want to see total count of the select statement. you can do this way.
CREATE TABLE #test (id int)
insert into #test(id)
SELECT 1
SELECT id from #test
union all
SELECT rowcount_big()
Note: Here, the ID will be implicitly converted to BIGINT datatype, based on the datatype precedence. Read more
Presumably, you are running this in some sort of application. So why not use ##ROWCOUNT?
select id, name
from . . .;
select ##rowcount_big; -- big if you want a bigint
I don't see value to including the value in the same query. However, if the underlying query is an aggregation query, there might be a way to do this using GROUPING SETS.
Here are two ways. It's better to use a CTE to define the row set so further table inserts don't interfere with the count. Since you're using ROWCOUNT_BIG() these queries use COUNT_BIG() (which also returns bigint) to count the inserted rows. In order to make sure the total always appears as the last row an 'order_num' column was added to the SELECT list and ORDER BY clause.
drop table if exists #tTest;
go
create table #tTest(
ID int not null,
[Name] varchar(10) not null);
insert into #tTest values
(115, 'Joe'),
(116, 'Jon'),
(117, 'Ron');
/* better to use a CTE to define the row set */
with t_cte as (
select *
from #tTest)
select 1 as order_num, ID, [Name]
from t_cte
union all
select 2 as order_num, count_big(*), ''
from t_cte
order by order_num, ID;
/* 2 separate queries could give inconsistent result if table is inserted into */
select 1 as order_num, ID, [Name]
from #tTest
union all
select 2 as order_num, count_big(*), ''
from #tTest
order by order_num, ID;
Both return
order_num ID Name
1 115 Joe
1 116 Jon
1 117 Ron
2 3
It is often convenient in PosgreSQL to create "tables" on the fly so to refer to them, e.g.
with
selected_ids as (
select 1 as id
)
select *
from someTable
where id = (select id from selected_ids)
Is it impossible to provide multiple values as id this way? I found this answer that suggests using values for similar problem, but I have problem with translating it to the example below.
I would like to write subqueries such as
select 1 as id
union
select 2 as id
union
select 7 as id
or
select 1 as id, 'dog' as animal
union
select 7 as id, 'cat' as animal
in more condensed way, without repeating myself.
You can use arguments in the query alias:
with selected_ids(id) as (
values (1), (3), (5)
)
select *
from someTable
where id = any (select id from selected_ids)
You can also use join instead of a subquery, example:
create table some_table (id int, str text);
insert into some_table values
(1, 'alfa'),
(2, 'beta'),
(3, 'gamma');
with selected_ids(id) as (
values (1), (2)
)
select *
from some_table
join selected_ids
using(id);
id | str
----+------
1 | alfa
2 | beta
(2 rows)
You can pass id and animal field in WITH like this
with selected_ids(id,animal) as (
values (1,'dog'), (2,'cat'), (3,'elephant'),(4,'rat')--,..,.. etc
)
select *
from someTable
where id = any (select id from selected_ids)
You should use union and IN statement like this:
with
selected_ids as (
select 1 as id
union
select 2 as id
union
select 3 as id
....
)
select *
from someTable
where id in (select id from selected_ids)
after reviewing wingedpanther's idea and looking for it, you can use his idea IF those id's are continuously like this:
with
selected_ids as (
SELECT * FROM generate_series(Start,End) --(1,10) for example
)
select *
from someTable
where id in (select id from selected_ids)
If they are not continuously , the only way you can do that is by storing those ID's in a different table(maybe you have it already and if not insert it)
And then:
select *
from someTable
where id in (select id from OtherTable)
I have the following query that returns rows based on a comma seperated list
Select * from Table where RecordID in (22,15,105,1,65,32)
I would like the results of this query to return to in the order of the ID's in the list. Is that possible with SQL?
Thanks in advance
select * from Table
where RecordID in (22,15,105,1,65,32)
order by (
case RecordID
when 22 then 1
when 15 then 2
when 105 then 3
when 1 then 4
when 65 then 5
when 32 then 6 end)
If you need the output to appear in a particular order, then you need to specify that order, using something the server can sort. Not knowing which engine you're working against, the general scheme would be to create a temp table or use rowset constructors to pair each record ID with its desired sort order.
E.g. (SQL Server)
declare #T table (RecordID int,Position int)
insert into #T (RecordID,Position)
select 22,1 union all
select 15,2 union all
select 105,3 union all
select 1,4 union all
select 65,5 union all
select 32,6
select * from Table t inner join #T t2 on t.RecordID = t2.RecordID order by t2.Position
I'd to the ordering in the client, but if you really want to do it in SQL, do it like this:
declare #T table (id int identity(1,1), RecordID int)
insert into #T (RecordID)
values (22), (15), (105), (1), (65), (32)
select * from
[table] t
inner join #t s on t.id=s.recordid
where t.id in (22, 15, 105, 1, 65, 32)
order by s.id
(works in SQL Server 2008)
Yes. You add the ORDER BY recordedid clause at the end.
The last time I had to do this I ended up doing a union all and generating a select statement for each id, i.e.
select * from Table where RecordID = 22
union all
select * from table where recordid = 15
etc.
It was a pain but it worked.
Use ORDER BY against the RecordID
Select * from Table where RecordID in (22,15,105,1,65,32) ORDER BY RecordID
I'm trying to write a query that will return all QUERY_ID values alongside all matching TABLE_ID values, where QUERY_ID is not specified in any table, and I can't create tables, so have to specify it in the query itself:
QUERY_ID TABLE_ID
1 1
2 NULL
3 3
4 4
5 NULL
I feel like there ought to be a simple way to do this, but I can't think of it for the life of me. Any help would be wonderful. Thanks!
select q.QUERY_ID, t.TABLE_ID
from (
select 1 as QUERY_ID
union all
select 2
union all
select 3
union all
select 4
union all
select 5
) q
left outer join MyTable t on q.QUERY_ID = t.TABLE_ID
one way by using the built in master..spt_values table
SELECT number AS QUERY_ID,TABLE_ID
FROM master..spt_values v
LEFT JOIN YourTable y ON y.QUERY_ID = y.TABLE_ID
WHERE TYPE = 'p'
AND number > 0
AND number <= (SELECT COUNT(*) FROM YourTable)
order by QUERY_ID
are you able to create #temp tables...can you do this?
create table #temp(QUERY_ID int identity,TABLE_ID varchar(200))
insert #temp(TABLE_ID)
select TABLE_ID
from YourTable
select * from #temp
order by QUERY_ID
drop table #temp
or like this
select identity(int,1,1) as QUERY_ID,TABLE_ID
into #temp
from YourTable
select * from #temp
order by QUERY_ID
On sql server 2005 and up there is the row_number function so maybe a reason to upgrade :-)
We have a table which is of the form:
ID,Value1,Value2,Value3
1,2,3,4
We need to transform this into.
ID,Name,Value
1,'Value1',2
1,'Value2',3
1,'Value3',4
Is there a clever way of doing this in one SELECT statement (i.e without UNIONs)? The column names Value1,Value2 and Value3 are fixed and constant.
The database is oracle 9i.
Give a union a shot.
select ID, 'Value1' as Name, Value1 as Value from table_name union all
select ID, 'Value2', Value2 as Value from table_name union all
select ID, 'Value3', Value3 as Value from table_name
order by ID, Name
using union all means that the server won't perform a distinct (which is implicit in union operations). It shouldn't make any difference with the data (since your ID's should HOPEFULLY be different), but it might speed it up a bit.
This works on Oracle 10g:
select id, 'Value' || n as name,
case n when 1 then value1 when 2 then value2 when 3 then value3 end as value
from (select rownum n
from (select 1 from dual connect by level <= 3)) ofs, t
I think Oracle 9i had recursive queries? Anyway, I'm pretty sure it has CASE support, so even if it doesn't have recursive queries, you can just do "(select 1 from dual union all select 2 from dual union all select 3 from dual) ofs" instead. Abusing recursive queries is a bit more general- for Oracle. (Using unions to generate rows is portable to other DBs, though)
You can do it like this, but it's not pretty:
SELECT id,'Value 1' AS name,value1 AS value FROM mytable
UNION
SELECT id,'Value 2' AS name,value2 AS value FROM mytable
UNION
SELECT id,'Value 3' AS name,value3 AS value FROM mytable
Unioning three select statements should do the trick:
SELECT ID, 'Value1', Value1 AS Value
FROM TABLE
UNION
SELECT ID, 'Value2', Value2 AS Value
FROM TABLE
UNION
SELECT ID, 'Value3', Value3 AS Value
FROM TABLE
If you're using SQL Server 2005+ then you can use UNPIVOT
CREATE TABLE #tmp ( ID int, Value1 int, Value2 int, Value3 int)
INSERT INTO #tmp (ID, Value1, Value2, Value3) VALUES (1, 2, 3, 4)
SELECT
*
FROM
#tmp
SELECT
*
FROM
#tmp
UNPIVOT
(
[Value] FOR [Name] IN (Value1, Value2, Value3)
) uPIVOT
DROP TABLE #tmp
A UNION ALL, as others have suggested, is probably your best bet in SQL. You might also want to consider handling this in the front end depending on what your specific requirements are.
CTE syntax may be different for Oracle (I ran it in Teradata), but I only used CTE to provide test data, those 1 2 3 and 4. You can use temp table instead. The actual select statement is plain vanilla SQL and it will on any relational database.
For Sql Server, consider UNPIVOT as an alternative to UNION:
SELECT id, value, colname
FROM #temp t
UNPIVOT (Value FOR ColName IN (value1,value2,value3)) as X
This will return the column name as well. I'm unsure what the X is used for, but you can't leave it out.
Try this:
CTE creates a temp table with 4 values. You can run this as is in any database.
with TEST_CTE (ID) as
(select * from (select '1' as a) as aa union all
select * from (select '2' as b) as bb union all
select * from (select '3' as c) as cc union all
select * from (select '4' as d) as dd )
select a.ID, 'Value'|| a.ID, b.ID
from TEST_CTE a, TEST_CTE b
where b.ID = (select min(c.ID) from TEST_CTE c where c.ID > a.ID)
Here is the result set:
1 Value1 2
2 Value2 3
3 Value3 4
Enjoy!
Some afterthoughts.
^^^ CTE syntax may be different in Oracle. I could only run it in Teradata. You can substitute it with temp table or fix the syntax to make it Oracle compatible. The select statement is plain vanilla SQL that will work on any database.
^^^ Another thing to note. If ID field is numeric, you might need to cast it into CHAR in order to concatenate it with "Value".