I have the following query that returns rows based on a comma seperated list
Select * from Table where RecordID in (22,15,105,1,65,32)
I would like the results of this query to return to in the order of the ID's in the list. Is that possible with SQL?
Thanks in advance
select * from Table
where RecordID in (22,15,105,1,65,32)
order by (
case RecordID
when 22 then 1
when 15 then 2
when 105 then 3
when 1 then 4
when 65 then 5
when 32 then 6 end)
If you need the output to appear in a particular order, then you need to specify that order, using something the server can sort. Not knowing which engine you're working against, the general scheme would be to create a temp table or use rowset constructors to pair each record ID with its desired sort order.
E.g. (SQL Server)
declare #T table (RecordID int,Position int)
insert into #T (RecordID,Position)
select 22,1 union all
select 15,2 union all
select 105,3 union all
select 1,4 union all
select 65,5 union all
select 32,6
select * from Table t inner join #T t2 on t.RecordID = t2.RecordID order by t2.Position
I'd to the ordering in the client, but if you really want to do it in SQL, do it like this:
declare #T table (id int identity(1,1), RecordID int)
insert into #T (RecordID)
values (22), (15), (105), (1), (65), (32)
select * from
[table] t
inner join #t s on t.id=s.recordid
where t.id in (22, 15, 105, 1, 65, 32)
order by s.id
(works in SQL Server 2008)
Yes. You add the ORDER BY recordedid clause at the end.
The last time I had to do this I ended up doing a union all and generating a select statement for each id, i.e.
select * from Table where RecordID = 22
union all
select * from table where recordid = 15
etc.
It was a pain but it worked.
Use ORDER BY against the RecordID
Select * from Table where RecordID in (22,15,105,1,65,32) ORDER BY RecordID
Related
I have the following query in SQL Server. How do I get the number of rows of previous select query as following format?
Sample Query
select ID, Name FROM Branch
UNION ALL
SELECT ROWCOUNT_BIG(), ''
Sample Output
If you use a CTE you can count the rows and union all together:
with cte as (
select ID, [Name]
from dbo.Branch
)
select ID, [Name]
from cte
union all
select count(*) + 1, ''
from cte;
I think you want to see total count of the select statement. you can do this way.
CREATE TABLE #test (id int)
insert into #test(id)
SELECT 1
SELECT id from #test
union all
SELECT rowcount_big()
Note: Here, the ID will be implicitly converted to BIGINT datatype, based on the datatype precedence. Read more
Presumably, you are running this in some sort of application. So why not use ##ROWCOUNT?
select id, name
from . . .;
select ##rowcount_big; -- big if you want a bigint
I don't see value to including the value in the same query. However, if the underlying query is an aggregation query, there might be a way to do this using GROUPING SETS.
Here are two ways. It's better to use a CTE to define the row set so further table inserts don't interfere with the count. Since you're using ROWCOUNT_BIG() these queries use COUNT_BIG() (which also returns bigint) to count the inserted rows. In order to make sure the total always appears as the last row an 'order_num' column was added to the SELECT list and ORDER BY clause.
drop table if exists #tTest;
go
create table #tTest(
ID int not null,
[Name] varchar(10) not null);
insert into #tTest values
(115, 'Joe'),
(116, 'Jon'),
(117, 'Ron');
/* better to use a CTE to define the row set */
with t_cte as (
select *
from #tTest)
select 1 as order_num, ID, [Name]
from t_cte
union all
select 2 as order_num, count_big(*), ''
from t_cte
order by order_num, ID;
/* 2 separate queries could give inconsistent result if table is inserted into */
select 1 as order_num, ID, [Name]
from #tTest
union all
select 2 as order_num, count_big(*), ''
from #tTest
order by order_num, ID;
Both return
order_num ID Name
1 115 Joe
1 116 Jon
1 117 Ron
2 3
I'll start directly by explaining with an example. Suppose I have a table which has 3 columns as shown.
Now what I am trying to achieve is, I want the first values of each individual column into a single column. So it would be something like this,
I have tried a few queries here including using TOP 1 and other incorrect ways. But I am still missing something here to achieve the exact output.
Need some guidance here on how to achieve this. Thank you.
SAMPLE TABLE
SELECT * INTO #TEMP
FROM
(
SELECT 1 BATCH_ID,'AAA' ASSIGNMENTTITLE,'FILE' ASSIGNMENTTYPE
UNION ALL
SELECT 1,'AAA1','FILE'
UNION ALL
SELECT 1,'AAA','FILE'
)TAB
If you need the second row specifically you can do the below
QUERY
;WITH CTE AS
(
-- Order row according to default format
SELECT ROW_NUMBER() OVER(ORDER BY (SELECT(0))) RNO,*
FROM #TEMP
)
SELECT CAST(BATCH_ID AS VARCHAR(20)) FROM CTE WHERE RNO=2
UNION ALL
SELECT ASSIGNMENTTITLE FROM CTE WHERE RNO=2
UNION ALL
SELECT ASSIGNMENTTYPE FROM CTE WHERE RNO=2
Click here to view result
UPDATE
Since there are 3 items in each record, it can be puzzled unless and otherwise an a column is for each items in a record.
;WITH CTE AS
(
-- Order row according to default format
SELECT ROW_NUMBER() OVER(ORDER BY (SELECT(0))) RNO,*
FROM #TEMP
)
SELECT CAST(BATCH_ID AS VARCHAR(20)),RNO
FROM CTE
UNION ALL
SELECT ASSIGNMENTTITLE,RNO
FROM CTE
UNION ALL
SELECT ASSIGNMENTTYPE,RNO
FROM CTE
ORDER BY RNO
Click here to view result
You can use the concat() function to create a column consisting of all the desired values
More info here
Simply you can try this. If want specific for a row use rowid. For all columns Use unpivot
create table #temp(id int, name varchar(100), title varchar(100))
insert into #temp values(1,'aaa','file')
insert into #temp values(1,'aaas','filef')
insert into #temp values(1,'aaaww','filefs')
select * from #temp
select top 1 cast(id as varchar) title from #temp
union
select top 1 name from #temp
union
select top 1 title from #temp
drop table #temp
This might help you
select top 1 convert(varchar(10), batch_id) ASSIGNMENTTITLE from table
union all
select top 1 ASSIGNMENTTITLE from table
union all
select top 1 ASSIGNMENTTYPE from table
If this is really what you want: "I want the first values of each individual column into a single column" it would be:
select ASSIGNMENTTITLE
from (
select min(convert(varchar(10), batch_id)) ASSIGNMENTTITLE,
1 ColOrder from table
union all
select min(ASSIGNMENTTITLE),
2 ColOrder from table
union all
select min(ASSIGNMENTTYPE),
3 ColOrder from table
) as data
order by ColOrder
Is it possible to create a composite key in sql 2000
code id
abc 1
abc 2
abc 3
def 1
def 2
ghi 1
where the id restarts the count at each change of code. I need the numbering to be exactly like that either by creating a table or other SELECT statement trickery.
how to do this in sql server 2000
Need Query Help
Here is one way to retrieve this data at runtime, without having to actually store it in the table, which is incredibly cumbersome to try and maintain. I'm using a #temp table here but you can pretend #a is your permanent table. As is, this will support up to 256 duplicates. If you need more, it can be adjusted.
CREATE TABLE #a(code VARCHAR(32));
INSERT #a SELECT 'abc'
UNION ALL SELECT 'abc'
UNION ALL SELECT 'abc'
UNION ALL SELECT 'def'
UNION ALL SELECT 'def'
UNION ALL SELECT 'ghi';
GO
SELECT x.code, id = y.number FROM
(
SELECT code, maxid = COUNT(*) FROM #a GROUP BY code
) AS x
CROSS JOIN
(
SELECT DISTINCT number FROM master..spt_values
WHERE number BETWEEN 1 AND 256
) AS y
WHERE x.maxid >= y.number;
DROP TABLE #a;
You can try this
INSERT INTO TABLENAME (code, id) VALUES( 'code',
(Select ISNULL(MAX(id), 0) FROM TableName where code = 'code')+1)
Please don't ask me why but there is a lot of duplicate data where every field is duplicated.
For example
alex, 1
alex, 1
liza, 32
hary, 34
I will need to eliminate from this table one of the alex, 1 rows
I know this algorithm will be very ineffecient, but it does not matter. I will need to remove duplicate data.
What is the best way to do this? Please keep in mind I do not have 2 fields, I actually have about 10 fields to check on.
As you said, yes this will be very inefficient, but you can try something like
DECLARE #TestTable TABLE(
Name VARCHAR(20),
SomeVal INT
)
INSERT INTO #TestTable SELECT 'alex', 1
INSERT INTO #TestTable SELECT 'alex', 1
INSERT INTO #TestTable SELECT 'liza', 32
INSERT INTO #TestTable SELECT 'hary', 34
SELECT *
FROM #TestTable
;WITH DuplicateVals AS (
SELECT *,
ROW_NUMBER() OVER (PARTITION BY Name, SomeVal ORDER BY (SELECT NULL)) RowID
FROM #TestTable
)
DELETE FROM DuplicateVals WHERE RowID > 1
SELECT *
FROM #TestTable
I understand this does not answer the specific question (eliminating dupes in SAME table), but I'm offering the solution because it is very fast and might work best for the author.
Speedy solution, if you don't mind creating a new table, create a new table with the same schema named NewTable.
Execute this SQL
Insert into NewTable
Select
name,
num
from
OldTable
group by
name,
num
Just include every field name in both the select and group by clauses.
Method A. You can get a deduped version of your data using
SELECT field1, field2, ...
INTO Deduped
FROM Source
GROUP BY field1, field2, ...
for example, for your sample data,
SELECT name, number
FROM Source
GROUP BY name, number
yields
alex 1
hary 34
liza 32
then simply delete the old table, and rename the new one. Of course, there are a number of fancy in-place solutions, but this is the clearest way to do it.
Method B. An in-place method is to create a primary key and delete duplicates that way. For example, you can
ALTER TABLE Source ADD sid INT IDENTITY(1,1);
which makes Source look like this
alex 1 1
alex 1 2
liza 32 3
hary 34 4
then you can use
DELETE FROM Source
WHERE sid NOT IN
(SELECT MIN(sid)
FROM Source
GROUP BY name, number)
which will give the desired result. Of course, "NOT IN" is not exactly the most efficient, but it will do the job. Alternatively, you can LEFT JOIN the grouped table (maybe stored in a TEMP table), and do the DELETE that way.
create table DuplicateTable(name varchar(10), number int)
insert DuplicateTable
values
('alex', 1),
('alex', 1),
('liza', 32),
('hary', 34);
with cte
as
(
select *, row_number() over(partition by name, number order by name) RowNumber
from DuplicateTable
)
delete cte
where RowNumber > 1
A bit different solution which requires primary key(or unique index):
Suppose you have a table your_table(id - PK, name, and num)
DELETE
FROM your_table
FROM your_table AS t2
WHERE
(select COUNT(*) FROM your_table y
where t2.name = y.name and t2.num = y.num) >1
AND t2.id !=
(SELECT top 1 id FROM your_table z
WHERE t2.name = z.name and t2.num = z.num);
I assumed that name and num are NOT NULL, if they can contain NULL values, you need to change wheres in sub-queries.
I'm trying to write a query that will return all QUERY_ID values alongside all matching TABLE_ID values, where QUERY_ID is not specified in any table, and I can't create tables, so have to specify it in the query itself:
QUERY_ID TABLE_ID
1 1
2 NULL
3 3
4 4
5 NULL
I feel like there ought to be a simple way to do this, but I can't think of it for the life of me. Any help would be wonderful. Thanks!
select q.QUERY_ID, t.TABLE_ID
from (
select 1 as QUERY_ID
union all
select 2
union all
select 3
union all
select 4
union all
select 5
) q
left outer join MyTable t on q.QUERY_ID = t.TABLE_ID
one way by using the built in master..spt_values table
SELECT number AS QUERY_ID,TABLE_ID
FROM master..spt_values v
LEFT JOIN YourTable y ON y.QUERY_ID = y.TABLE_ID
WHERE TYPE = 'p'
AND number > 0
AND number <= (SELECT COUNT(*) FROM YourTable)
order by QUERY_ID
are you able to create #temp tables...can you do this?
create table #temp(QUERY_ID int identity,TABLE_ID varchar(200))
insert #temp(TABLE_ID)
select TABLE_ID
from YourTable
select * from #temp
order by QUERY_ID
drop table #temp
or like this
select identity(int,1,1) as QUERY_ID,TABLE_ID
into #temp
from YourTable
select * from #temp
order by QUERY_ID
On sql server 2005 and up there is the row_number function so maybe a reason to upgrade :-)