Count Distinct Values FROM Column - sql

Question

I have Written a query which returns multiple column.Out of which One Column contains repetitive entries.
FAULT_SHORT_NAME
ATM DOWN DUE TO LINK PROBLEM
ATM DOWN DUE TO LINK PROBLEM
ALL CASSETTES FAULTED
ALL CASSETTES FAULTED
ATM IS MARK DOWN
ATM IS MARK DOWN
Now I want to Modify My query in Such a way that it will show me Value Count as
ATM DOWN DUE TO LINK PROBLEM ALL CASSETTES FAULTED ATM IS MARK DOWN
2 2 2
There Can be Different "FAULT_SHORT_NAME" Values so Cant Hard Code them.My Original Query is
Select * From ATMStatus S Left Join ATM A on S.ATM=A.Code
Left Join EventMsg E On S.Fault=E.Code
Where A.ATMStatus=0 AND S.TicketBooked <> 0
FAULT_SHORT_NAME is Column of Table "EventMsg"

Answer 1

It looks like you want a PIVOT since you want the values as columns instead of rows. there are two ways to do this either a Static or dynamic pivot.
Static Pivot, you hard-code the values of the columns:
SELECT *
FROM
(
Select *
From ATMStatus S
Left Join ATM A
on S.ATM=A.Code
Left Join EventMsg E
On S.Fault=E.Code
Where A.ATMStatus=0
AND S.TicketBooked <> 0
) x
PIVOT
(
count(*)
for FAULT_SHORT_NAME in ([ATM DOWN DUE TO LINK PROBLEM],
[ALL CASSETTES FAULTED], [ATM IS MARK DOWN])
) p
Dynamic Pivot, the columns are generated at run-time:
DECLARE #cols AS NVARCHAR(MAX),
#query AS NVARCHAR(MAX)
select #cols = STUFF((SELECT distinct ',' + QUOTENAME(FAULT_SHORT_NAME)
from EventMsg
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set #query
= 'SELECT ' + #cols + ' from
(
Select *
From ATMStatus S
Left Join ATM A
on S.ATM=A.Code
Left Join EventMsg E
On S.Fault=E.Code
Where A.ATMStatus=0
AND S.TicketBooked <> 0
) x
pivot
(
count(*)
for FAULT_SHORT_NAME in(' + #cols + ')
) p '
execute(#query)
Both will produce the same results. If you provide additional details about the tables and some sample data, then I could provide a more exact example.