I am having trouble figuring out how to check if a text field contains any of a few different strings. This is what I have, but it does not work:
- (IBAction)Submit:(id)sender {
if ([Input.text isEqualToString:#"axe"/"apple"/"angry"])
Output.text = #"CORRECT";
else Output.text = #"INCORRECT";
If the input text field contains "axe", "apple", or "angry" then the Output Label should display "CORRECT", otherwise it should display "INCORRECT".
I think this is what you want from what you said at the end of the question:
If the input text field = axe, apple or angry then the Output Label = correct but if not output label = Incorrect.
So this is the code:
if([Input.text isEqualToString:#"axe"] || [Input.text isEqualToString:#"apple"] || [Input.text isEqualToString:#"angry"]) {
Output.text = #"CORRECT";
}
else {
Output.text = #"INCORRECT";
}
You were looking for the "or" operator, which is "||".
You also said:
I am having trouble finding out if there is a way to compile a number of words into the same string.
To do that, you can try this:
NSString *str1 = #"axe";
NSString *str2 = #"apple";
NSString *str3 = #"angry";
NSString *combined = [NSString stringWithFormat:#"%# %# %#", str1, str2, str3];
I would suggest a slightly different approach:
// Create an array with all of the acceptable words:
NSArray *correctWords = [NSArray arrayWithObjects:#"axe",
#"apple",
#"angry", nil];
// Check to see if the input text matches one of the correct words
// (stored in the array), and set the Output text:
if ([correctWords containsObject:Input.text]) {
Output.text = #"CORRECT";
} else {
Output.text = #"INCORRECT";
}
Related
This question already has an answer here:
iOS: How to localize strings with multiple interpolated parameters?
(1 answer)
Closed 5 years ago.
How to localize the NSString with format.
int value = 20;
NSString *str = #"hello";
textLabel.text = [NSString stringWithFormat:#"%d %#", value, str];
I tried
textLabel.text = [NSString stringWithFormat:NSLocalizedString(#"%d %#", #"%d %#"), value, str];
but didn't work. Any help is appreciated.
Your localized string itself must be a format pattern:
"ValueAndStringFMT" = "Value %1$d and string %2$#";
And in your code:
textLabel.text = [NSString
stringWithFormat:NSLocalizedString(#"ValueAndStringFMT"),
value, str
];
Why %1$d and not just %d? So you can change the order. E.g. in some language you may like to have the order swapped:
"ValueAndStringFMT" = "Cadena %2$# y valor %1$d";
Of course, that is somewhat dangerous as if someone uses more placeholders than your string call offers or uses the wrong types, your app may crash. If you want to be safe, you do a search an replace instead:
"ValueAndStringFMT" = "Value [[VALUE]] and string [[STRING]]";
And in your code:
NSString * string = NSLocalizedString(#"ValueAndStringFMT");
string = [string stringByReplacingOccurrencesOfString:#"[[VALUE]]"
withString:#(value).stringValue
];
string = [string stringByReplacingOccurrencesOfString:#"[[STRING]]"
withString:str
];
textLabel.text = string;
That way the worst case scenario is that a placeholder is not expanded, meaning the placeholder is visibly printed on screen but at least your app won't crash because someone messed up the localization strings file.
If you need to localize one of the format variables, then you need to do that first in an own step:
NSString * str = NSLocalizedString(#"hello");
Here's my program so far. My intention is to have it so the if statement compares the letter in the string letterGuessed to a character in the string userInputPhraseString. Here's what I have. While coding in xCode, I get an "expected '['"error. I have no idea why.
NSString *letterGuessed = userInputGuessedLetter.text;
NSString *userInputPhraseString = userInputPhraseString.text;
int loopCounter = 0;
int stringLength = userInputPhraseString.length;
while (loopCounter < stringLength){
if (guessedLetter isEqualToString:[userInputPhraseString characterAtIndex:loopIndexTwo])
{
//if statement true
}
loopCounter++;
}
You are missing enclosing square brackets on this line:
if (guessedLetter isEqualToString:[userInputPhraseString characterAtIndex:loopIndexTwo])
It should be:
if ([guessedLetter isEqualToString:[userInputPhraseString characterAtIndex:loopIndexTwo]])
Edit that won’t fix your problem, though, because characterAtIndex: returns a unichar, not an NSString.
It's not clear what you are trying to do.. But I suppose that letterGuessed has one character... And that userInputPhraseString has many characters. So you want to know if letterGuessed is inside userInputPhraseString correct?
This is one solution without loops involved.. I replaced the input with fixed values for testing and tested the code.. It works.
NSString *letterGuessed = #"A"; //Change to your inputs
NSString *userInputPhraseString = #"BBBA"; //Since it has A it will be true in the test
NSCharacterSet *cset = [NSCharacterSet characterSetWithCharactersInString:letterGuessed];
NSRange range = [userInputPhraseString rangeOfCharacterFromSet:cset];
if (range.location != NSNotFound) { //Does letterGuessed is in UserInputPhraseString?
NSLog(#"YES"); //userInput Does contain A...
} else {
NSLog(#"NO");
}
In regards to your code... I fixed a couple of errors, first you are trying to get a UniChar (Integer) value for the character and want to compare it to a NSString which is an Object. Also fixed a couple of issues with syntax you had and used the right approach which is to return a range of characters. Again for doing what you want to accomplish the example above is the best approach I know, but for the sake of learning, here is your code fixed.
NSString *letterGuessed = #"A"; //Change to your inputs
NSString *userInputPhraseString = #"BBBA"; //Since it has A it will be true in the test
NSInteger loopCounter = 0; //Use NSInteger instead of int.
NSInteger stringLength = userInputPhraseString.length;
BOOL foundChar = NO; //Just for the sake of returning NOT FOUND in NSLOG
while (loopCounter < stringLength){
//Here we will get a letter for each iteration.
NSString *scannedLetter = [userInputPhraseString substringWithRange:NSMakeRange(loopCounter, 1)]; // Removed loopCounterTwo
if ([scannedLetter isEqualToString:letterGuessed])
{
NSLog(#"FOUND CHARACTER");
foundChar = YES;
}
loopCounter++;
}
if (!foundChar) NSLog(#"NOT FOUND");
NSRange holds the position, length.. So we move to a new position on every iteration and then get 1 character.
Also if this approach is what you want, I would strongly suggest a for-loop.
I am trying to grab a string in my array, change nth letter in the string to a ?, then print the result in a textfield. The problem is my NSMutableArray is being stored into a UIPickerView and I think it would be best just to read the string from the PickerView then change the nth char and print the result. I am struggling with how to grab the string from the picker and change the nth letter.
- (UIView *)viewForRow:(NSInteger)row forComponent:(NSInteger)component
{
if (row == 0 ) {
NSString *originalStringTwo = #"%#", *arrayDictionary;
NSRange two = [originalStringTwo rangeOfString:#"2"];
NSString *newStringTwo = [originalStringTwo stringByReplacingCharactersInRange:two withString:#"?"];
_resultLabel.text = newStringTwo;
}
if (row == 1 ) {
NSString *originalStringThree = #"%#", *arrayDictionary;
NSRange three = [originalStringThree rangeOfString:#"3"];
NSString *newStringThree = [originalStringThreestringByReplacingCharactersInRange:three withString:#"?"];
_resultLabel.text = newStringThree;
}
if ( row == 2 ) {
NSString *originalStringFour = #"%#", *arrayDictionary;
NSRange four = [originalStringFour rangeOfString:#"4"];
NSString *newStringFour = [originalStringFour stringByReplacingCharactersInRange:four withString:#"?"];
_resultLabel.text = newStringFour;
}
return 0;
}
That's not how you create an NSRange. Use NSMakeRange instead.
// Range from index 1 with length 1, eg. 2nd character:
NSRange two = NSMakeRange(2, 1);
NSString *newStringTwo = [originalStringTwo stringByReplacingCharactersInRange:two
withString:#"?"];
Note, that it's never a good idea to grab any data from a GUI element (except user input). What if the text field applies custom formatting?
You should keep your data in your array and use that.
What would be the most efficient way to convert a string like "ThisStringIsJoined" to "This String Is Joined" in objective-c?
I receive strings like this from a web service thats out of my control and I would like to present the data to the user, so I would just like to tidy it up a bit by adding spaces infront of each uppercase word. The strings are always formatted with each word beginning in an uppercase letter.
I'm quite new to objective-c so cant really figure this one out.
Thanks
One way of achieving this is as follows:
NSString *string = #"ThisStringIsJoined";
NSRegularExpression *regexp = [NSRegularExpression
regularExpressionWithPattern:#"([a-z])([A-Z])"
options:0
error:NULL];
NSString *newString = [regexp
stringByReplacingMatchesInString:string
options:0
range:NSMakeRange(0, string.length)
withTemplate:#"$1 $2"];
NSLog(#"Changed '%#' -> '%#'", string, newString);
The output in this case would be:
'ThisStringIsJoined' -> 'This String Is Joined'
You might want to tweak the regular expression to you own needs. You might want to make this into a category on NSString.
NSRegularExpressions are the way to go, but as trivia, NSCharacterSet can also be useful:
- (NSString *)splitString:(NSString *)inputString {
int index = 1;
NSMutableString* mutableInputString = [NSMutableString stringWithString:inputString];
while (index < mutableInputString.length) {
if ([[NSCharacterSet uppercaseLetterCharacterSet] characterIsMember:[mutableInputString characterAtIndex:index]]) {
[mutableInputString insertString:#" " atIndex:index];
index++;
}
index++;
}
return [NSString stringWithString:mutableInputString];
}
Here's a category on NSString that will do what you want. This will handle non-ASCII letters. It will also split "IDidAGoodThing" properly.
#implementation NSString (SeparateCapitalizedWords)
-(NSString*)stringBySeparatingCapitalizedWords
{
static NSRegularExpression * __regex ;
static dispatch_once_t onceToken;
dispatch_once(&onceToken, ^{
NSError * error = nil ;
__regex = [ NSRegularExpression regularExpressionWithPattern:#"[\\p{Uppercase Letter}]" options:0 error:&error ] ;
if ( error ) { #throw error ; }
});
NSString * result = [ __regex stringByReplacingMatchesInString:self options:0 range:(NSRange){ 1, self.length - 1 } withTemplate:#" $0" ] ;
return result ;
}
#end
Here is Swift Code (objective c code by webstersx), Thanks !
var str: NSMutableString = "iLoveSwiftCode"
var str2: NSMutableString = NSMutableString()
for var i:NSInteger = 0 ; i < str.length ; i++ {
var ch:NSString = str.substringWithRange(NSMakeRange(i, 1))
if(ch .rangeOfCharacterFromSet(NSCharacterSet.uppercaseLetterCharacterSet()).location != NSNotFound) {
str2 .appendString(" ")
}
str2 .appendString(ch)
}
println("\(str2.capitalizedString)")
}
Output : I Love Swift Code
For anyone who came here looking for the similar question answered in Swift:
Perhaps a cleaner (adding to Sankalp's answer), and more 'Swifty' approach:
func addSpaces(to givenString: String) -> String{
var string = givenString
//indexOffset is needed because each time replaceSubrange is called, the resulting count is incremented by one (owing to the fact that a space is added to every capitalised letter)
var indexOffset = 0
for (index, character) in string.characters.enumerated(){
let stringCharacter = String(character)
//Evaluates to true if the character is a capital letter
if stringCharacter.lowercased() != stringCharacter{
guard index != 0 else { continue } //"ILoveSwift" should not turn into " I Love Swift"
let stringIndex = string.index(string.startIndex, offsetBy: index + indexOffset)
let endStringIndex = string.index(string.startIndex, offsetBy: index + 1 + indexOffset)
let range = stringIndex..<endStringIndex
indexOffset += 1
string.replaceSubrange(range, with: " \(stringCharacter)")
}
}
return string
}
You call the function like so:
var string = "iLoveSwiftCode"
addSpaces(to: string)
//Result: string = "i Love Swift Code"
Alternatively, if you prefer extensions:
extension String{
mutating func seperatedWithSpaces(){
//indexOffset is needed because each time replaceSubrange is called, the resulting count is incremented by one (owing to the fact that a space is added to every capitalised letter)
var indexOffset = 0
for (index, character) in characters.enumerated(){
let stringCharacter = String(character)
if stringCharacter.lowercased() != stringCharacter{
guard index != 0 else { continue } //"ILoveSwift" should not turn into " I Love Swift"
let stringIndex = self.index(self.startIndex, offsetBy: index + indexOffset)
let endStringIndex = self.index(self.startIndex, offsetBy: index + 1 + indexOffset)
let range = stringIndex..<endStringIndex
indexOffset += 1
self.replaceSubrange(range, with: " \(stringCharacter)")
}
}
}
}
Call the method from a string:
var string = "iLoveSwiftCode"
string.seperatedWithSpaces()
//Result: string = "i Love Swift Code"
You could try making a new string that is a lowercase copy of the original string. Then compare the two strings and insert spaces wherever the characters are different.
Use the NSString method to turn to lowercase.
- (NSString *)lowercaseString
How do you check if an NSString begins with a certain character (the character *).
The * is an indicator for the type of the cell, so I need the contents of this NSString without the *, but need to know if the * exists.
You can use the -hasPrefix: method of NSString:
Objective-C:
NSString* output = nil;
if([string hasPrefix:#"*"]) {
output = [string substringFromIndex:1];
}
Swift:
var output:String?
if string.hasPrefix("*") {
output = string.substringFromIndex(string.startIndex.advancedBy(1))
}
You can use:
NSString *newString;
if ( [[myString characterAtIndex:0] isEqualToString:#"*"] ) {
newString = [myString substringFromIndex:1];
}
hasPrefix works especially well.
for example if you were looking for a http url in a NSString, you would use componentsSeparatedByString to create an NSArray and the iterate the array using hasPrefix to find the elements that begin with http.
NSArray *allStringsArray =
[myStringThatHasHttpUrls componentsSeparatedByString:#" "]
for (id myArrayElement in allStringsArray) {
NSString *theString = [myArrayElement description];
if ([theString hasPrefix:#"http"]) {
NSLog(#"The URL is %#", [myArrayElement description]);
}
}
hasPrefix returns a Boolean value that indicates whether a given string matches the beginning characters of the receiver.
- (BOOL)hasPrefix:(NSString *)aString,
parameter aString is a string that you are looking for
Return Value is YES if aString matches the beginning characters of the receiver, otherwise NO. Returns NO if aString is empty.
As a more general answer, try using the hasPrefix method. For example, the code below checks to see if a string begins with 10, which is the error code used to identify a certain problem.
NSString* myString = #"10:Username taken";
if([myString hasPrefix:#"10"]) {
//display more elegant error message
}
Use characterAtIndex:. If the first character is an asterisk, use substringFromIndex: to get the string sans '*'.
NSString *stringWithoutAsterisk(NSString *string) {
NSRange asterisk = [string rangeOfString:#"*"];
return asterisk.location == 0 ? [string substringFromIndex:1] : string;
}
Another approach to do it..
May it help someone...
if ([[temp substringToIndex:4] isEqualToString:#"http"]) {
//starts with http
}
This might help? :)
http://developer.apple.com/mac/library/documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/Reference/NSString.html#//apple_ref/occ/instm/NSString/characterAtIndex:
Just search for the character at index 0 and compare it against the value you're looking for!
This nice little bit of code I found by chance, and I have yet to see it suggested on Stack. It only works if the characters you want to remove or alter exist, which is convenient in many scenarios. If the character/s does not exist, it won't alter your NSString:
NSString = [yourString stringByReplacingOccurrencesOfString:#"YOUR CHARACTERS YOU WANT TO REMOVE" withString:#"CAN either be EMPTY or WITH TEXT REPLACEMENT"];
This is how I use it:
//declare what to look for
NSString * suffixTorRemove = #"</p>";
NSString * prefixToRemove = #"<p>";
NSString * randomCharacter = #"</strong>";
NSString * moreRandom = #"<strong>";
NSString * makeAndSign = #"&";
//I AM INSERTING A VALUE FROM A DATABASE AND HAVE ASSIGNED IT TO returnStr
returnStr = [returnStr stringByReplacingOccurrencesOfString:suffixTorRemove withString:#""];
returnStr = [returnStr stringByReplacingOccurrencesOfString:prefixToRemove withString:#""];
returnStr = [returnStr stringByReplacingOccurrencesOfString:randomCharacter withString:#""];
returnStr = [returnStr stringByReplacingOccurrencesOfString:moreRandom withString:#""];
returnStr = [returnStr stringByReplacingOccurrencesOfString:makeAndSign withString:#"&"];
//check the output
NSLog(#"returnStr IS NOW: %#", returnStr);
This one line is super easy to perform three actions in one:
Checks your string for the character/s you do not want
Can replaces them with whatever you like
Does not affect surrounding code
NSString* expectedString = nil;
if([givenString hasPrefix:#"*"])
{
expectedString = [givenString substringFromIndex:1];
}