Select Multiple Values in Where Time Clause Equals - sql

Question

My table looks like this:
Table 1:
Note: This table is very large in reality, with lots more columns (20ish) and rows (in the millions)
| Time | tmp | productionID |
| 10:00:00 | 2.2 | 5 |
| 10:00:05 | 5.2 | 5 |
| 10:00:11 | 7.4 | 5 |
| ...... | 3.2 | 5 |
| 10:10:02 | 4.5 | 5 |
Note: Timeis a varchar, so I assume I need to do something like this:
CONVERT(VARCHAR(8), DATEADD(mi, 10, time), 114)
What I need to do is:
select time, tmp
from mytable
where productionid = somevalue
and time = first_time_stamp associated to some productionID(ie. 10:00:00 table above)
time = 10 minutes after the first_time_stamp with some productionID
time = 20 minutes after the first_time_stamp with some productionID
...25, 30, 40, 60, 120, 180 minutes
I hope this makes sense. I'm not sure what the right way to do this is. I mean I thought of the following proccess:
-select first time stamp (with some productionID)
-add 10 minutes to that that time,
-add 20 minutes etc.. then use a pivot table and use joins to link to table 1
There must be an easier way.
Thank you in advance for the expertise.
Sample output expected:
| Time | tmp
| 10:00:00 | 2.2
| 10:10:02 | 4.5
| 10:20:54 | 2.3
| 10:30:22 | 5.3

Answer 1

If you create an interval table on-the-fly and cross join it with starting time for each ProductionID, you can extract records fromMyTable falling in the same category and choose to retrieve only the first one.
; with timeSlots (startSlot, endSlot) as (
select 0, 10
union all
select 10, 20
union all
select 25, 30
union all
select 30, 40
union all
select 40, 60
union all
select 60, 120
union all
select 120, 180
),
startTimes (ProductionID, minTime) as (
select ProductionID, min([Time])
from MyTable
group by ProductionID
),
groupedTime (ProductionID, [Time], [Tmp], groupOrder) as (
select myTable.ProductionID,
myTable.Time,
myTable.Tmp,
row_number () over (partition by myTable.productionid, timeSlots.startSlot
order by mytable.Time) groupOrder
from startTimes
cross join timeslots
inner join myTable
on startTimes.ProductionID = myTable.ProductionID
and convert(varchar(8), dateadd(minute, timeSlots.startSlot, convert(datetime, startTimes.MinTime, 114)), 114) <= mytable.Time
and convert(varchar(8), dateadd(minute, timeSlots.endSlot, convert(datetime, startTimes.MinTime, 114)), 114) > myTable.Time
)
select ProductionID, [Time], [Tmp]
from groupedTime
where groupOrder = 1
Sql Fiddle here.

Answer 2

This will work if there are no missing sequence in the time. I mean if there are time values for each increment of 10minutes then this will work.
create table times([Time] time,tmp float,productionID int)
INSERT INTO times
VALUES('10:10:00',2.2,5),
('10:00:05',5.2,5),
('10:00:11',7.4,5),
('10:00:18',3.2,5),
('10:10:02',4.5,5),
('10:20:22',5.3,5)
select * from times
Declare #min_time time
select #min_time = MIN(time) from times
;WITH times1 as (select row_number() over (order by (select 0)) as id,time, tmp from times where productionID = 5)
,times2 as(
select id,time,tmp from times1 where time=#min_time
union all
select t1.id,t1.time,t1.tmp from times2 t2 inner join times1 t1 on cast(t1.time as varchar(5))=cast(DATEADD(mi,10,t2.Time) as varchar(5)) --where t1.id-1=t2.id
)
,result as (select MAX(time) as time from times2
group by CAST(time as varchar(5)))
select distinct t2.Time,t2.tmp from times2 t2,Result r where t2.Time =r.time order by 1