I've searched for adding multiple AVG calculations and have found a few entries, however I'm having to join another table and the examples of that are scarce.
closest answer I can find is this
but it deals with dates and no joins
here are my tables:
indicators:
StandardScore IndicatorID NID DID
0.033333 7 1 1
0.907723 9 1 1
0.574739 26 1 1
0.917391 21 1 1
.....
indexindicators:
IndexID IndicatorID
1 7
1 26
2 21
3 7
4 9
4 21
4 7
5 9
.......
My goal is to get the average for each IndexID (indexindicators) related to NID/DID (indicators) combination
a query to retrieve a single value would be
SELECT AVG(StandardScore) FROM `indicators` INNER JOIN indexindicators ON indicators.IndicatorId=indexindicators.IndicatorId WHERE nid=1 AND did=1 AND indexindicators.IndexId=1
ultimately there will be 6 (indexID) averages which then have to be rounded then * by 100 (should I do that part with PHP?)
This seems like such a simple query, but i just can't seem wrap my mind around it.
Thanks in advance for your help!
SELECT nid, did, indexid, 100.0 * AVG(StandardScore)
FROM 'indicators'
INNER JOIN 'indexindicators'
ON indicators.IndicatorId=indexindicators.IndicatorId
group by nid, did, indexid
Related
View of a table
ID
kWh
1
3
1
10
1
8
1
11
2
12
2
4
2
7
2
8
3
3
3
4
3
5
I want to recive
ID
kWh
1
32
2
31
3
12
The table itself is more complex and larger. But the point is this. How can this be done? And I can't know in advance the ID numbers of the first column.
SELECT T.ID,SUM(T.KWH)SUM_KWH
FROM YOUR_TABLE T
GROUP BY T.ID
Do you need this one?
Let's assume your database name is 'testdb' and table name is 'table1'.
SELECT * FROM testdb.table1;
SELECT id, SUM(kwh) AS "kwh2"
FROM stack.table1
WHERE id = 1
keep running the query will all (ids). you will get output.
By following this query you will get desired output.
Hope this helps.
I'm having difficulties figuring a query out, would someone be able to assist me with this?
Problem: 4 columns that represent results for the 2 separate tests. One of them taken in UK and another in US. Both of them are the same test and I need to find the highest and lowest score for the test taken in both countries. I also need to avoid using subqueries and temporary tables. Would appreciate theoretical ideas and actual solutions for the problem.
The table looks like this:
ResultID Test_UK Test_US Test_UK_Score Test_US_Score
1 1 2 48 11
2 4 1 21 24
3 3 1 55 71
4 5 6 18 78
5 7 4 19 49
6 1 3 23 69
7 5 2 98 35
8 6 7 41 47
The desired results I'm looking for:
TestID HighestScore LowestScore
1 71 23
2 35 11
3 69 55
4 49 21
5 98 18
6 78 41
7 47 19
I tried implementing a case of comparison, but I still ended up with subquery to pull out the final results. Also tried union, but it ends up in a sub query again. As far as I can think it shoul be a case when then query, but can't really come up with the logic for it, as it requires to match the ID's of the tests.
Thank you!
What I've tried and got the best results (still wrong)
select v.TestID,
max(case when Test_US_Score > Test_UK_Score then Test_UK_Score else null end) MaxS,
min(case when Test_UK_Score > Test_US_Score then Test_US_Score else null end) MinS
FROM ResultsDB rDB CROSS APPLY
(VALUES (Test_UK, 1), (Test_US, 0)
) V(testID, amount)
GROUP BY v.TestID
Extra
The answer provided by M. Kanarkowski is a perfect solution. I'm no expert on CTE, and a bit confused, how would it be possible to adapt this query to return the result ID of the row that min and max were found.
something like this:
TestID Result_ID_Max Result_ID_Min
1 3 6
2 7 1
3 6 3
Extra 2
The desired results of the query would me something like this.
The two last columns represent the IDs of the rows from the original table where the max and min values were found.
TestID HighestScore LowestScore Result_ID_Of_Max Result_ID_Of_Min
1 71 23 3 6
2 35 11 7 1
3 69 55 6 3
For example you can use union to have results from both countries togehter and then just pick the maximum and the minimum for your data.
with cte as (
select Test_UK as TestID, Test_UK_Score as score from yourTable
union all
select Test_US as TestID, Test_US_Score as score from yourTable
)
select
TestID
,max(score) as HighestScore
,min(score) as LowestScore
from cte
group by TestID
order by TestID
Extra:
I assumed that you want to have the additional column with the previous result. If not just take the above select and replace Test_UK_Score and Test_US_Score with ResultID.
with cte as (
select Test_UK as TestID, Test_UK_Score as score, ResultID from yourTable
union all
select Test_US as TestID, Test_US_Score as score, ResultID from yourTable
)
select
TestID
,max(score) as HighestScore
,min(score) as LowestScore
,max(ResultID) as Result_ID_Max
,min(ResultID) as Result_ID_Min
from cte
group by TestID
order by TestID
I am learning SQL and I am stuck with a certain question for a while. I have a huge data set looking like:
id v1
1 3
2 3
3 -
4 5
5 3
6 5
7 3
I need to count how many times each id is in v1. The output i seek is:
id count
1 0
2 0
3 4
4 0
5 2
6 0
7 0
Have been looking for an answer on many forums. The problem is that there are a lot of ids so that I can`t search by number "1" and so on. If I use something like id=v1 i get how many times a row has equal values in these columns. Looking for some help. Please.
Try this:
SELECT t1.id, COUNT(t2.v1)
FROM mytable AS t1
LEFT JOIN mytable AS t2 ON t1.id = t2.v1
GROUP BY t1.id
ORDER BY t1.id
Demo here
I'm trying to make a query and need a little help (SQL Server).
Imagine the following scenario: user is viewing a web page which has several related categories. According to some rules, the page should not be displayed if a specific category has been put together with another category.
For this I've got 2 tables:
1) Has the page Id and the related categories:
Pk CategoryNumber
--------------------
1 30
1 31
1 45
2 30
3 21
3 26
3 64
4 25
4 12
5 25
5 31
5 30
5 45
2) Rules table. First row means: when viewing a page with the category 30 it should not be retrieved if it also has the 45 category.
WhenViewingCategoryNumber HideEverythingWithCategoryNumber
-------------------------------------------------------
30 45
25 31
Output expected:
2
3
4
I've spent a few hours around this and I'm not going anywhere, so I would appreciate if someone could help. If possible, would be better an answer with a SELECT statement to integrate it directly within a larger CTE statement. Many thanks.
You can use the following query to identify those page ids related to conflicting categories:
SELECT DISTINCT c1.PageId
FROM Categories AS c1
INNER JOIN Rules AS r ON c1.ItemNumber = r.WhenViewingCategoryNumber
INNER JOIN Categories AS c2 ON c1.PageId = c2.PageId
AND r.HideEverythingWithCategoryNumber = c2.ItemNumber
This will return:
PageId
------
1
5
Now you can get expected result by simply using NOT IN:
SELECT DISTINCT PageId
FROM Categories
WHERE PageId NOT IN ( ... above query here ....)
Demo here
I have three tables: the first has a list of category IDs, the second has dataset information, and the third has import information.
What I have
select dataset.pc_id , count(*)
from import
join dataset on CAST (dataset.internal_id as varchar(20)) = import.product_id
group by dataset.pc_id, order by pc_id asc
This will output:
3 4
4 5
6 200
7 192
8 1000
Where product_category comes into play is this: I want the output to look like:
1 0
2 0
3 4
4 5
6 200
...
16 0
The 16 are the number of different product categories from the product_category table that I currently cannot figure out how to fit into that statement.
What is the way to get all the id's from product category into this list with the information joined occupying the result?
Figured it out, needed to get rid of selecting dataset.pc_id and just go with product_category.id and then right join product_category.