My where exists clause isn't working. What trivial thing am I missing?
select * from patient as p
where exists
(
select p.patientid, count(*) from tblclaims as c
inner join patient as p on p.patientid=c.patientid
and p.admissiondate = c.admissiondate
and p.dischargedate = c.dischargedate
group by p.patientid
having count(*)>500
)
patient and tblclaims are joined together by the three-field composite key as as you can see in the query.
The count(*) from tblclaims as c is unnecessary and could be throwing the query off.
Also, you have no WHERE clause joining patient p to your exists clause.
Not to mention you use p as an alias in both the main query and the exists clause, which is just confusing.
You probably want something like:
select * from patient
where exists
(
select p.patientid
from tblclaims as c
inner join patient as p on p.patientid=c.patientid
and p.admissiondate = c.admissiondate
and p.dischargedate = c.dischargedate
where patient.patientid = p.patientid
group by p.patientid
having count(*)>500
)
You don't need to use the inner join in the sub-query at all; that is actually the cause of your extra results. You should be referencing the "p" in the outer query.
select * from patient as p
where exists
(
select 1 from tblclaims as c
where p.patientid = c.patientid
and p.admissiondate = c.admissiondate
and p.dischargedate = c.dischargedate
group by c.patientid
having count(*)>500
)
I'm not much of a fan of exists. Maybe you can use other functions. Try this:
select * from patient as p
where patientid IN
(
select p.patientid from tblclaims as c
inner join patient as p on p.patientid=c.patientid
and p.admissiondate = c.admissiondate
and p.dischargedate = c.dischargedate
group by p.patientid
having count(*)>500
)
Related
I am trying to find sum of some columns using SQL like this:
select distinct c.customer,
c.customer_id,
sum(d.delay) as delay,
sum(d.delayed_amount) as delay_amt,
pd.product
from product pd
inner join mfg_company mfg on pd.product_id=mfg.product_id
inner join store s on mfg.store_id = s.store_id
inner join customer c on s.customer = c.customer_id
join delay_detail d on pd.product_id = d.material
where d.product_mfg_id = 466
group by c.customer,customer_id
order by c.customer,c.customer_id
The problem is mfg_company has duplicate product_id's(multiple mappings) ,So when I am trying to find the sum it's including those duplicates too.
Using product_id in group by clause doesn't help the result I want to see.So how to join only on distinct product_id's?
You can try below query if this helps -
select distinct c.customer
,c.customer_id
,sum(d.delay) as delay
,sum(d.delayed_amount) as delay_amt
,pd.product
from product pd
inner join (select distinct product_id
,store_id
from mfg_company) mfg on pd.product_id=mfg.product_id
inner join store s on mfg.store_id = s.store_id
inner join customer c on s.customer = c.customer_id
join delay_detail d on pd.product_id = d.material
where d.product_mfg_id = 466
group by c.customer,customer_id
order by c.customer,c.customer_id
I think the solution to your problem is to pre-aggregate the delays. It is entirely unclear if you want the product in the result set. Assuming you do not:
select c.customer, c.customer_id,
sum(d.delay) as delay, sum(d.delay_amt) as delay_amt
from product pd join
mfg_company mfg
on pd.product_id = mfg.product_id join
store s
on mfg.store_id = s.store_id
customer c
on s.customer = c.customer_id join
(select d.material, sum(d.delay) as delay, sum(d.delayed_amount) as delay_amt
from delay_detail d
group by d.material
) d
on pd.product_id = d.material
where d.product_mfg_id = 466
group by c.customer, customer_id
order by c.customer, c.customer_id;
Note that using select distinct with group by is almost never needed.
I have two tables in Oracle DB
Person (
id
)
Bill (
id,
date,
amount,
person_id
)
I need to get person and amount from last bill if exist.
I trying to do it this way
SELECT
p.id,
b.amount
FROM Person p
LEFT JOIN Bill b
ON b.person_id = p.id AND b.date = (SELECT MAX(date) FROM Bill WHERE person_id = 1)
WHERE p.id = 1;
But this query works only with INNER JOIN. In case of LEFT JOIN it throws ORA-01799 a column may not be outer-joined to a subquery
How can I get amoun from the last bill using left join?
Please try the below avoiding sub query to be outer joined
SELECT
p.id,
b.amount
FROM Person p
LEFT JOIN(select * from Bill where date =
(SELECT MAX(date) FROM Bill b1 WHERE person_id = 1)) b ON b.person_id = p.id
WHERE p.id = 1;
What you are looking for is a way to tell in bills, for each person, what is the latest record, and that one is the one to join with. One way is to use row_number:
select * from person p
left join (select b.*,
row_number() over (partition by person_id order by date desc) as seq_num
from bills b) b
on p.id = b.person_id
and seq_num = 1
You cannot have a subquery inside an ON statement.
Instead you need to convert your LEFT JOIN statement into a whole subquery.
Not tested but this should work.
SELECT
p.id,
b.amount
FROM Person p
LEFT JOIN (
SELECT id FROM Bill
WHERE person_id = p.id
AND date = (SELECT date FROM Bill WHERE person_id = 1)) b
WHERE p.id = 1;
I'm not quite sure why you would want to filter for the date though.
Simply filtering for the person_id should do the trick
you should join Person and Bill to the result for max date in bill related to person_id
select Person.id, bill.amount
from Person
left join bill on bill.person_id = person.id
left join (
select person_id, max(date) as max_date
from bill
group by person_id ) t on t.person_id = Person.id and b.date = t.max_date
Hey you can do like this
SELECT
p.id,
b.amount
FROM Person p
LEFT JOIN Bill b
ON b.person_id = p.id AND b.date = (SELECT max(date) FROM Bill WHERE person_id = 1)
WHERE p.id = 1
SELECT
p.id,
b.amount
FROM Person p
LEFT JOIN Bill b
ON b.person_id = p.id
WHERE (SELECT max(date) FROM bill AS sb WHERE sb.person_id=p.id LIMIT 1)=b.date;
SELECT
p.id,
c.amount
FROM Person p
LEFT JOIN (select b.person_id as personid,b.amount as amount from Bill b where b.date1= (select max(date1) from Bill where person_id=1)) c
ON c.personid = p.id
WHERE p.id = 1;
try this
select * from person p
left join (select MAX(id) KEEP (DENSE_RANK FIRST ORDER BY date DESC)
from bills b) b
on p.id = b.person_id
I use GREATEST() function in join condition:
SELECT
p.id,
b.amount
FROM Person p
LEFT JOIN Bill b
ON b.person_id = p.id
AND b.date = GREATEST(b.date)
WHERE p.id = 1
This allows you to grab the whole row if necessary and grab the top x rows
SELECT p.id
,b.amount
FROM person p
LEFT JOIN
(
SELECT * FROM
(
SELECT date
,ROW_NUMBER() OVER (PARTITION BY person_id ORDER BY date DESC) AS row_num
FROM bill
)
WHERE row_num = 1
) b ON p.id = b.person_id
WHERE p.id = 1
;
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Using TOP:
SELECT TOP 1
PID, NAME, AGE
FROM (
SELECT
p.*, h.HID
FROM Performer p
INNER JOIN Concert c
ON c.PID = p.PID
INNER JOIN Hall h
ON h.HID = c.HID
INNER JOIN Tickets t
ON t.CID = c.CID
GROUP BY p.PID, p.NAME, p.AGE, h.HID, h.CAPACITY
HAVING COUNT(t.TID) = h.CAPACITY
) t
GROUP BY PID, NAME, AGE
ORDER BY COUNT(*) DESC
This should return expected result
;with Cte1 AS (
select C.CID, P.Name AS PerformerName, H.Name AS HallName, H.Capacity, H.HID
from #Performer P
inner join #Concert C on C.PID = P.PID
inner join #Hall H on H.HID = C.HID
)
, Cte2 AS (
select C.CID, H.HID, COUNT(*) SellCount
from #Concert C
inner join #Hall H on H.HID = C.HID
inner join #Tickets T on T.CID = C.CID
group by C.CID, H.HID
)
select Cte1.CID, Cte1.PerformerName, Cte1.HallName, Cte2.SellCount
from Cte1 inner join Cte2 on Cte2.CID = Cte1.CID AND Cte2.HID = Cte1.HID
where Cte1.Capacity = Cte2.SellCount
This subquery produces the correct table. But now I want to get the average of the averages, and I'm getting an error "Missing FROM-clause entry for table "c"".
SELECT
c.name,
AVG(avgvalue)
FROM
(
SELECT
c.name,
p.name,
AVG(a."value") AS avgvalue
FROM answers a INNER JOIN survey_responses sr ON sr.id = a.survey_response_id AND a.question_id = 13
INNER JOIN answers category_answer ON category_answer.survey_response_id = sr.id AND category_answer.question_id = 264
INNER JOIN answers_categories ac ON category_answer.id = ac.answer_id
INNER JOIN categories c ON c.id = ac.category_id
INNER JOIN products p ON p.id = a.product_id
WHERE c.name IN ('Accounting')
GROUP BY c.name, p."name"
HAVING count(p.name)>10
) as ProductAverages
GROUP BY c.name;
You are naming the ProductAverages, so your table aliases should reference it, not c - which can be used only in the inner query:
SELECT
name, -- Here
AVG(avgvalue)
FROM
(
SELECT
c.name,
p.name,
AVG(a."value") AS avgvalue
FROM answers a INNER JOIN survey_responses sr ON sr.id = a.survey_response_id AND a.question_id = 13
INNER JOIN answers category_answer ON category_answer.survey_response_id = sr.id AND category_answer.question_id = 264
INNER JOIN answers_categories ac ON category_answer.id = ac.answer_id
INNER JOIN categories c ON c.id = ac.category_id
INNER JOIN products p ON p.id = a.product_id
WHERE c.name IN ('Accounting')
GROUP BY c.name, p."name"
HAVING count(p.name)>10
) as ProductAverages
GROUP BY name; -- and here
I'm having trouble with this full text search query I'm trying to run. I need to do a full text search on two tables. If any of the terms are in either table I need to return the records from the first table.
select R.* from Request R
inner join Patients P on R.PatientID = P.PatientID
inner join containstable(Request,(*),#keywords)AS KEY_TBL
ON R.RequestID = KEY_TBL.[Key]
full outer join
(select R.* from Request R
inner join Patients P on R.PatientID = P.PatientID
inner join containstable(Patients,(*),#keywords) AS KEY_TBL2
ON P.PatientID = KEY_TBL2.[Key]) as b on R.RequestID = b.RequestID
All I needed was a Union instead of a full outer join.
select R.* from Request R
inner join Patients P on R.PatientID = P.PatientID
inner join containstable(Request,(*),#keywords)AS KEY_TBL
ON R.RequestID = KEY_TBL.[Key]
UNION
select R.* from Request R
inner join Patients P on R.PatientID = P.PatientID
inner join containstable(Patients,(*),#keywords) AS KEY_TBL2
ON P.PatientID = KEY_TBL2.[Key]