In the first start of my application I need to specify a path to save some files to it. But in the open file dialogue it seems like that I have to select a file to open. How can I just specify a folder without oppening a file
like C:\config\
Here is my code
If apppath = "" Then
Dim fd As OpenFileDialog = New OpenFileDialog()
fd.Title = "Select Application Configeration Files Path"
fd.InitialDirectory = "C:\"
fd.Filter = "All files (*.*)|*.*|All files (*.*)|*.*"
fd.FilterIndex = 2
fd.RestoreDirectory = True
If fd.ShowDialog() = DialogResult.OK Then
apppath = fd.FileName
End If
My.Computer.FileSystem.WriteAllText(apppath & "apppath.txt", apppath, False)
End If
I need to select a file in order for it to work, but I just want to select a folder. So what's the solution?
You want to use the FolderBrowserDialog class instead of the OpenFileDialog class. You can find more information about it here:
http://msdn.microsoft.com/en-us/library/system.windows.forms.folderbrowserdialog(v=vs.110).aspx
For instance, you could do this:
If apppath = "" Then
Dim dialog As New FolderBrowserDialog()
dialog.RootFolder = Environment.SpecialFolder.Desktop
dialog.SelectedPath = "C:\"
dialog.Description = "Select Application Configeration Files Path"
If dialog.ShowDialog() = Windows.Forms.DialogResult.OK Then
apppath = dialog.SelectedPath
End If
My.Computer.FileSystem.WriteAllText(apppath & "apppath.txt", apppath, False)
End If
If I understand correctly, you want to let the user choose a folder. If that is the case, then you want to use FolderBrowserDialog instead of OpenFileDialog.
Dim filedialog As New OpenFileDialog
filedialog.IntialDirectory = Application.StartupPath
filedialog.ShowDialog()
Or you can simply just make it less lines and very simple.
link: http://i.imgur.com/bMq0HNz.png
Start your dialog with a click:
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
FolderBrowserDialog1.ShowDialog()
End Sub
Add if you want to show the actual path that you choose from your dialog
Private Sub FolderBrowserDialog1_Disposed(sender As Object, e As EventArgs) Handles Button1.Click
TextBox1.Text = FolderBrowserDialog1.SelectedPath.ToString
End Sub
Use To:
Dim openFD As New OpenFileDialog()
Dim Directory As string = openFD.FileName
Try this
Private Sub BtnOpen_Click(sender As Object, e As EventArgs) Handles BtnOpen.Click
Dim openFileDialog1 As New OpenFileDialog()
openFileDialog1.InitialDirectory = "x_pathfileforsend"
openFileDialog1.Filter = "txt files (*.txt)|*.txt|*.zip|*.rar|*.ico|*.exe|*.png|*.bmp|All files (*.*)|*.*"
openFileDialog1.FilterIndex = 5
openFileDialog1.RestoreDirectory = True
If openFileDialog1.ShowDialog() = DialogResult.OK Then
txtpath.Text = openFileDialog1.FileName
End If
openFileDialog1.Dispose()
End Sub
Related
I am trying to rename the file extension of a file I selected from the dialog box. Right now, it is not changing format to ".txt". Where am I wrong?
Private Sub Button4_Click(sender As Object, e As EventArgs) Handles Button4.Click
'Sym File Open
Dim sym As OpenFileDialog = New OpenFileDialog()
''Defines the critieria of a Trace file type.
sym.Title = "Open File Dialog"
sym.InitialDirectory = "C:\My Computer\Documents"
sym.Filter = "Symbol files (*.sym*)|*.sym*"
sym.FilterIndex = 1
sym.RestoreDirectory = True
'Assigning path to textbox
If sym.ShowDialog() = DialogResult.OK Then
SymTextSelection.Text = sym.FileName
'Converting sym file into a text file
sym.FileName = sym.FileName.Replace(".sym", ".txt")
End If
End Sub
This worked for me
Private Sub Button4_Click(sender As Object, e As EventArgs) Handles Button4.Click
'Sym File Open
Dim sym As OpenFileDialog = New OpenFileDialog()
''Defines the critieria of a Trace file type.
sym.Title = "Open File Dialog"
sym.InitialDirectory = "C:\My Computer\Documents"
sym.Filter = "Symbol files (*.sym*)|*.sym*"
sym.FilterIndex = 1
sym.RestoreDirectory = True
'Assigning path to textbox
If sym.ShowDialog() = DialogResult.OK Then
SymTextSelection.Text = sym.FileName
'Converting sym file into a text file
File.Move(sym.FileName, Path.ChangeExtension(sym.FileName, ".xlsm"))
End If
End Sub
I have two Buttons and two OpenFileDialogs and I am facing an issue with InitialDirectory property. When I choose a file for my first OpenFileDialog and then click to choose a file for my second OpenFileDialog, I get the same InitialDirectory and not the ones I have set!!!
Here is an example of my code...
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim FileDialog As New OpenFileDialog
Dim Path As String = Nothing
If Label1.Text IsNot Nothing And My.Computer.FileSystem.FileExists(Label1.Text) Then
Path = Label1.Text
Else
Path = "::{20D04FE0-3AEA-1069-A2D8-08002B30309D}"
End If
FileDialog.Title = "Open File Dialog"
FileDialog.InitialDirectory = Path
FileDialog.Filter = "Executable (*.exe)|*.exe"
FileDialog.RestoreDirectory = True
If FileDialog.ShowDialog() = DialogResult.OK Then
Label1.Text = FileDialog.FileName
End If
End Sub
Private Sub Button2_Click(sender As Object, e As EventArgs) Handles Button2.Click
Dim FileDialog As New OpenFileDialog
Dim Path As String = Nothing
If Label2.Text IsNot Nothing And My.Computer.FileSystem.FileExists(Label2.Text) Then
Path = Label2.Text
Else
Path = "::{20D04FE0-3AEA-1069-A2D8-08002B30309D}"
End If
FileDialog.Title = "Open File Dialog"
FileDialog.InitialDirectory = Path
FileDialog.Filter = "Executable (*.exe)|*.exe"
FileDialog.RestoreDirectory = True
If FileDialog.ShowDialog() = DialogResult.OK Then
Label2.Text = FileDialog.FileName
End If
End Sub
Well I found what was wrong...
I just had to set the Path variable like this Path = IO.Path.GetDirectoryName(Label1.Text) and not like this Path = Label1.Text. Because the first one gets file's directory path (which is required) and the second one gets file's path. And I was using the second one...
This is my code:
Private Sub HuraButton1_Click(sender As Object, e As EventArgs) Handles HuraButton1.Click
Dim openFileDialog1 As New OpenFileDialog()
openFileDialog1.FileName = "Select a Text File..."
openFileDialog1.Filter = "Text Files (*.txt) | *txt"
OpenFileDialog1.InitialDirectory = "C:\Users\Public\Desktop\"
OpenFileDialog1.Title = "Select a Files"
openFileDialog1.ShowDialog()
Dim Findstring = IO.File.ReadAllText(openFileDialog1.FileName)
Dim Lookfor As String = ""
Dim result = openFileDialog1.ShowDialog()
If openFileDialog1.FileName = Windows.Forms.DialogResult.Cancel Then
MsgBox("File Not Found")
End If
If Findstring.Contains(Lookfor) Then
MsgBox("Found")
Else
MsgBox("Not Found")
End If
End Sub
Error:
System.IO.FileNotFoundException: The File'D:\1DesktopFILE\RobeVisualStudio\ShaadyyTool\bin\Debug\Select a Text File' Not Found.
I want to make sure that those who close the "OpenFileDialog1" The app doesn't crash.
I Don't know why it doesn't work,
Can you write the correct code thanks.
Sorry for my eng.
I think this is what you want
Private Sub HuraButton1_Click(sender As Object, e As EventArgs) Handles HuraButton1.Click
Dim openFileDialog1 As New OpenFileDialog()
openFileDialog1.Filter = "Text Files (*.txt) | *txt"
openFileDialog1.InitialDirectory = "C:\Users\Public\Desktop\"
openFileDialog1.Title = "Select a Files"
openFileDialog1.CheckFileExists = True
If openFileDialog1.ShowDialog() = DialogResult.OK Then
'file selected now process it
Dim Findstring = IO.File.ReadAllText(openFileDialog1.FileName)
Dim Lookfor As String = ""
If Findstring.Contains(Lookfor) Then
MsgBox("Found")
Else
MsgBox("Not Found")
End If
Else
'file not selected or user cancelled
MsgBox("file not selected")
End If
End Sub
openFileDialog1.FileName = "Select a Text File..."
i think you miss understood the above statement to set as a dialog box's title ...it is not what you think...rather it is used to find/select a file in the opened directory
You want to make some changes to this. Use the dialog result to determine if you should move forward. If they didn't select a file, don't do the code.
If openFileDialog1.ShowDialog() = Windows.Forms.DialogResult.OK Then
Dim Findstring as String = IO.File.ReadAllText(openFileDialog1.FileName)
Dim Lookfor As String = ""
If Findstring.Contains(Lookfor ) Then
MsgBox("Found")
Else
MsgBox("Not Found")
End If
End If
Since the OpenFileDialog uses unmanaged code you really should put it in a Using block.
Using openFileDialog1 as OpenFileDialog = New OpenFileDialog
openFileDialog1.Filter = "Text Files (*.txt) | *txt"
...
End Using
That way you can be sure that it is removed from memory completely, even if there is an exception inside the Using block.
Then you should give your OpenFileDialog an element to which it will open modally, otherwise it can happen that your OpenFileDialog vanishes in the background and your application seems unresponsive (because it waits for the OpenFileDialog to return but the user doesn't see that).
Since you seem to be in a Form anyway, just do
openFileDialog1.ShowDialog(Me)
Then you should check for the return value of openFileDialog1.ShowDialog() and only proceed if there really has a file been selected.
If openFileDialog1.ShowDialog(Me) = DialogResult.Ok Then
...
End If
If the result of openFileDialog1.ShowDialog() is not DialogResult.Ok then openFileDialog1.FileName might be Nothing.
I hope this helps a little bit.
It is possible to add open only files with *.bin extension in openfile dialog ?
Here is my code. Maybe somebody can fix it.
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim OFD As New OpenFileDialog
Dim fullFile() As Byte
If OFD.ShowDialog = Windows.Forms.DialogResult.OK Then
fullFile = File.ReadAllBytes(OFD.FileName)
TextBox1.AppendText(fullFile(&H1E).ToString("X2") & " ")
TextBox1.AppendText(fullFile(&H1F).ToString("X2"))
End If
If file have another extension msg,box : Wrong file
You need to use the Filter property: MSDN
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim OFD As New OpenFileDialog
OFD.Filter = "BIN Files (*.bin)|*.bin"
Dim fullFile() As Byte
If OFD.ShowDialog = Windows.Forms.DialogResult.OK Then
fullFile = File.ReadAllBytes(OFD.FileName)
TextBox1.AppendText(fullFile(&H1E).ToString("X2") & " ")
TextBox1.AppendText(fullFile(&H1F).ToString("X2"))
End If
End Sub
The pipe | character is used in the filter string to separate it into chunks: the first is what the user sees in the dropdown, and the second is the actual filter that is run on the files. You can have multiple filters available, too. Here's another example of a filter string: Text files (*.txt)|*.txt|All files (*.*)|*.*
You need to use javax.swing.JFileChooser.
Use this:
FileNameExtensionFilter filter = new FileNameExtensionFilter("Binary Files", "bin");
JFileChooser fileChooser = new JFileChooser();
fileChooser.setFileFilter(filter);
I'm making a file downloader and I want it to download files to either my selected directoy or default directory.
Downloading code is here:
Private Sub Button1_Click(sender As System.Object, e As System.EventArgs) Handles Button1.Click
Button1.Enabled = False
Button1.Text = "Updating..."
WebBrowser1.Visible = True
Dim uri As System.Uri = New System.Uri("http://199.91.154.170/e9f6poiwfocg/pei02c8727sa720/Ultra+v08.zip")
Dim webclient As System.Net.WebClient = New System.Net.WebClient()
Dim path As String =
If apppath = Nothing then
New String(System.IO.Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData), "test\\Test.zip"))
Else New String
(apppath)
End if
Dim fileInfo As System.IO.FileInfo = New System.IO.FileInfo(path)
If Not System.IO.Directory.Exists(fileInfo.Directory.FullName) Then
System.IO.Directory.CreateDirectory(fileInfo.Directory.FullName)
End If
AddHandler webclient.DownloadFileCompleted, AddressOf webclient_DownloadDataCompleted
webclient.DownloadFileAsync(uri, path)
End Sub
Private Sub
And user selected path apppath is defined here:
If apppath = "" Then
Dim dialog As New FolderBrowserDialog()
dialog.RootFolder = Environment.SpecialFolder.Desktop
dialog.SelectedPath = Path.Combine(Environment.GetFolderPath( _
Environment.SpecialFolder.ApplicationData))
dialog.Description = "Select directory where to install the files"
If dialog.ShowDialog() = Windows.Forms.DialogResult.OK Then
apppath = dialog.SelectedPath
End If
My.Computer.FileSystem.WriteAllText(apppath & " apppath.txt", apppath, False)
End If
How to fix Dim path As String else statement?
Thanks in advance!
If I am understanding your question correctly then I believe there is a simple solution, which is this:
Dim path As String
If apppath = Nothing then
path = New String(System.IO.Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData), "test\Test.zip"))
Else New String
path = apppath
End if
If I have not understood your requirements correctly, then please provide more information.