I want to print labels in words as returned by a SQL query such as follow.
1 2 3
4 5 6
When I want to print the reverse of those labels, I have to print them as follow
3 2 1
6 5 4
In my real case, I have 5 colums by 2 rows, how can I formulate my query so that my records are ordered like the second one.
The normal ordering is handled by word, so my query is like
SELECT * FROM Products ORDER BY Products.id
I'm using MS Access =(
EDIT :
Just to make it clear
I'd like my records to be ordered such as
3 2 1 6 5 4 9 8 7 12 11 10
EDIT2 :
my table looks like this
ID ProductName
1 Product1
2 Product2
3 Product3
n Product[n]
I want the ids to be returned as I mentioned above
SELECT * FROM Products ORDER BY Products.id desc
Alternately if your query at the moment is really giving you this:
select col1, col2, col3 from products order by products.id;
why not use
select col3, col2, col1 from products order by products.id;
Related
View of a table
ID
kWh
1
3
1
10
1
8
1
11
2
12
2
4
2
7
2
8
3
3
3
4
3
5
I want to recive
ID
kWh
1
32
2
31
3
12
The table itself is more complex and larger. But the point is this. How can this be done? And I can't know in advance the ID numbers of the first column.
SELECT T.ID,SUM(T.KWH)SUM_KWH
FROM YOUR_TABLE T
GROUP BY T.ID
Do you need this one?
Let's assume your database name is 'testdb' and table name is 'table1'.
SELECT * FROM testdb.table1;
SELECT id, SUM(kwh) AS "kwh2"
FROM stack.table1
WHERE id = 1
keep running the query will all (ids). you will get output.
By following this query you will get desired output.
Hope this helps.
We have a process that creates a table of duplicate records based on some arbitrary rules (details not relevant).
Every record gets checked against all other records and if a suspected duplicate is found both it and the duplicate are stored in a dupes table to be manually reviewed.
This results in a table something like this:
dupId, originalId, duplicateId
1 1 2
2 1 3
3 1 4
4 2 3
5 2 4
6 3 4
7 5 6
8 5 7
9 6 7
10 8 9
You can see here record #1 has 3 other records it is similar to (#2,#3 and #4) and they are each similar to each other.
Record #5 has 2 duplicates (#6 and #7) and record #8 has only 1 (#9).
I want to query the duplicates into sets, so my results would look something like this:
setId recordId
1 1
1 2
1 3
1 4
2 5
2 6
2 7
3 8
3 9
But I am too old/slow/tired/rubbish and a bit out of my depth here.
Currently, when checking for duplicates if the record pairing is already in the table we don't insert it twice (i.e. you don't see both sides of the duplicate pairing) but can easily do so if it makes the querying simpler.
Any advice much appreciated!
Duplicates seems to be transitive, so you have all pairs. That is, the "original" id has the information you need.
But it is not included in the duplicates and you want that. So:
select dense_rank() over (order by originalid) as setid, duplicateid
from ((select originalid, duplicateid
from t
where not exists (select 1 from t t2 where t.originalid = t2.duplicateid)
) union all
(select distinct originalid, originalid
from t
where not exists (select 1 from t t2 where t.originalid = t2.duplicateid)
)
) i
order by setid;
I'm attempting to have a function or view that is able to calculate and roll up various counts while being able to search on a many to many affiliation.
Here is an example data set:
Invoice Table:
InvoiceID LocationID StatusID
1 5 1
2 5 1
3 5 1
4 5 2
5 7 2
5 7 1
5 7 2
Group Table:
GroupID GroupName
1 Group 1
2 Group 2
GroupToLocation Table:
GroupToLocationID GroupID LocationID
1 1 5
2 2 5
3 2 7
I have gotten to the point where I could sum up the various statuses per location and get this:
LocationID Status1 Status2
5 3 1
7 1 2
Location 5 has 3 Invoices with a status of 1, and 1 invoice with a status of 2 while Location 7 has 1 status 1 and 2 status 2
There are two groups, and Location 5 is in both, while Location 7 is only in the second. I need to be able to set it up where I can append a where statement like this:
select * from vw_GroupCounts
where GroupName = 'Group 2'
or
select Invoice, SUM(*) from vw_GroupCounts
where GroupName = 'Group 2'
And that result in only getting Location 7. Whenever I do this, as I have to use left joins or something along those lines, the counts are duplicating for each group the the Location is affiliated with. I know I could do something along the lines of a subquery and pass in the GroupName into that, but the system I am working with uses a dynamic query builder that appends WHERE statements based on user input.
I don't mind using view, or functions, or any number of functions inside of functions, but I hope there is a way to do what I'm looking for.
Since locations 5 and 7 are in Group 2, if you search for group 2 in the where clause after joining all the tables, then you would get all records in this case, this isn't duplication, just the way the data is. A different join wouldn't change this, only changing the data. Let me know if I am misunderstanding something though.
Here is how you would join them to do that search.
Here it is with your first example of the location and status count.
I have three tables: the first has a list of category IDs, the second has dataset information, and the third has import information.
What I have
select dataset.pc_id , count(*)
from import
join dataset on CAST (dataset.internal_id as varchar(20)) = import.product_id
group by dataset.pc_id, order by pc_id asc
This will output:
3 4
4 5
6 200
7 192
8 1000
Where product_category comes into play is this: I want the output to look like:
1 0
2 0
3 4
4 5
6 200
...
16 0
The 16 are the number of different product categories from the product_category table that I currently cannot figure out how to fit into that statement.
What is the way to get all the id's from product category into this list with the information joined occupying the result?
Figured it out, needed to get rid of selecting dataset.pc_id and just go with product_category.id and then right join product_category.
By using SQlite, I'd like to get all rows that show in a specific column only one single distinct value. Like from following table:
A B
1 2
2 1
3 2
4 3
5 1
6 1
7 2
8 4
9 2
Here I'd like to get only row Nr. 4 an 8 as there values (3 and 4) occur only once in the entire column.
You could use a query like this:
SELECT *
FROM mytable
WHERE B IN (SELECT B FROM mytable GROUP BY B HAVING COUNT(DISTINCT A)=1)
Please see fiddle here.
Subquery will return all B values that are present only once (you could also use HAVING COUNT(*)=1 in this case), the outer query will return all rows where B is returned by the subquery.