looking for some help limiting the results while querying combinations between 2 columns. Here's an example of the kind of table I am working with..
id name group state
1 Bob A NY
2 Jim A NY
3 Dan A NY
4 Mike A FL
5 Tim B NY
6 Sam B FL
7 Brad B FL
8 Glen B FL
9 Ben C FL
I am trying to display all records of all combinations of "group" and "state", but limiting to displaying only up to 2 records for each combination. The result should look like the following..
id name group state
1 Bob A NY
2 Jim A NY
4 Mike A FL
5 Tim B NY
6 Sam B FL
7 Brad B FL
9 Ben C FL
Thanks for the help.
Assuming you always want the two rows for each group and state combination with the lowest id
SELECT *
FROM (SELECT a.*,
row_number() over (partition by group, state
order by id asc) rnk
FROM your_table a)
WHERE rnk <= 2
Of course, since group is a reserved word, I assume your column is actually named something else... You'd need to adjust my query to use the correct column name.
Related
I want to join two tables and use the column they both share to group the results, including a null result for those accountIds which only appear in one table.
Table a
AccountId
productApurchases
Steve
1
Jane
5
Bill
10
Abed
2
Table b
AccountId
productApurchases
Allan
1
Jane
10
Bill
2
Abed
1
Mike
2
Desired output
AccountId
productApurchases
productBpurchases
Steve
1
0
Jane
5
10
Bill
10
2
Abed
2
1
Mike
0
2
I've been trying with various joins but cannot figure out how to group by all the account ids.
Any advice much appreciated, thanks.
Use full join:
select accountid,
coalesce(productApurchases, 0) as productApurchases,
coalesce(productBpurchases, 0) as productBpurchases
from a full join
b
using (accountid);
I want to return all the data, from max count query with hospital that has most number of patients. What I seem to be getting when I try to nest queries is display of all rows of hospital data. I've tried to look at similar questions in stack overflow and other sites it seems to be a simple query to do but i am not getting it.
select max(highest_hospital) as max_hospital
from (select count(hospital) as highest_hospital
from doctor
group by hospital)
highest_hospital
-------------
3
Doc ID Doctor Patient Hospital Medicine Cost
------ ------- ------ --------- ------ --------
1 Jim Bob Patient1 Town 1 Medicine 1 4000
2 Janice Smith Patient2 Town 2 Medicine 3 3000
3 Harold Brown Patient3 Town 2 Medicine 5 2000
4 Larry Owens Patient4 Town 2 Medicine 6 3000
5 Sally Brown Patient5 Town 3 Medicine 7 4000
6 Bob Jim Patient6 Town 4 Medicine 8 6000
Outcome should be return of 3 rows
Doc ID Doctor Patient Hospital Medicine Cost
------ ------- ------ --------- ------ --------
2 Janice Smith Patient2 Town 2 Medicine 3 3000
3 Harold Brown Patient3 Town 2 Medicine 5 2000
4 Larry Owens Patient4 Town 2 Medicine 6 3000
You can use window functions:
select d.*
from (select d.*, max(hospital_count) over () as max_hospital_count
from (select d.*, count(*) over (partition by hospital) as hospital_count
from doctor d
) d
) d
where hospital_count = max_hospital_count;
Edit:
Using GROUP BY is a pain. If you are only looking for a single hospital (even when there are ties), then in Oracle 12C you can do:
select d.*
from doctor d
where d.hospital = (select d2.hospital
from doctor d2
group by d2.hospital
order by count(*) desc
fetch first 1 row only
);
You can do this in earlier versions of Oracle using an additional subquery.
The simple SELECT query would return the data as below:
Select ID, User, Country, TimeLogged from Data
ID User Country TimeLogged
1 Samantha SCO 10
1 John UK 5
1 Andrew NZL 15
2 John UK 20
3 Mark UK 10
3 Mark UK 20
3 Steven UK 10
3 Andrew NZL 15
3 Sharon IRL 5
4 Andrew NZL 25
4 Michael AUS 5
5 Jessica USA 30
I would like to return a sum of time logged for each user grouped by ID
But for only ID numbers where both of these values Country = UK and User = Andrew are included within their rows.
So the output in the above example would be
ID User Country TimeLogged
1 John UK 5
1 Andrew NZL 15
3 Mark UK 30
3 Steven UK 10
3 Andrew NZL 15
First you need to identify which IDs you're going to be returning
SELECT ID FROM MyTable WHERE Country='UK'
INTERSECT
SELECT ID FROM MyTable WHERE [User]='Andrew';
and based on that, you can then filter to aggregate the expected rows.
SELECT ID,
[User],
Country,
SUM(Timelogged) as Timelogged
FROM mytable
WHERE (Country='UK' OR [User]='Andrew')
AND ID IN( SELECT ID FROM MyTable WHERE Country='UK'
INTERSECT
SELECT ID FROM MyTable WHERE [User]='Andrew')
GROUP BY ID, [User], country;
So, you have described what you need to write almost perfectly but not quite. Your result table indicates that you want Country = UK OR User = Andrew, rather than AND
You need to select and group by, then include a WHERE:-
Select ID, User, Country, SUM(Timelogged) as Timelogged from mytable
WHERE Country='UK' OR User='Andrew'
Group by ID, user, country
I've been playing with this for days, and can't seem to come up with something. I have this query:
select
v.emp_name as Name
,MONTH(v.YearMonth) as m
,v.SalesTotal as Amount
from SalesTotals
Which gives me these results:
Name m Amount
Smith 1 123.50
Smith 2 40.21
Smith 3 444.21
Smith 4 23.21
Jones 1 121.00
Jones 2 499.00
Jones 3 23.23
Jones 4 41.82
etc....
What I need to do is use a JOIN or something, so that I get a NULL value for each month (1-12), for each name:
Name m Amount
Smith 1 123.50
Smith 2 40.21
Smith 3 444.21
Smith 4 23.21
Smith 5 NULL
Smith 6 NULL
Smith ... NULL
Smith 12 NULL
Jones 1 121.00
Jones 2 499.00
Jones 3 23.23
Jones 4 41.82
Jones 5 NULL
Jones ... NULL
Jones 12 NULL
etc....
I have a "Numbers" table, and have tried doing:
select
v.emp_name as Name
,MONTH(v.YearMonth) as m
,v.SalesTotal as Amount
from SalesTotals
FULL JOIN Number n on n.Number = MONTH(v.YearMonth) and n in(1,2,3,4,5,6,7,8,9,10,11,12)
But that only gives me 6 additional NULL rows, where what I want is actually 6 NULL rows for each group of names. I've tried using Group By, but not sure how to use it in a JOIN statement like that, and not even sure if that's the correct route to take.
Any advice or direction is much appreciated!
Here's one way to do it:
select
s.emp_name as Name
,s.Number as m
,st.salestotal as Amount
from (
select distinct emp_name, number
from salestotals, numbers
where number between 1 and 12) s left join salestotals st on
s.emp_name = st.emp_name and s.number = month(st.yearmonth)
Condensed SQL Fiddle
You could do:
SELECT EN.emp_name Name,
N.Number M,
ST.SalesTotal Amount
FROM ( SELECT Number
FROM NumberTable
WHERE Number BETWEEN 1 AND 12) N
CROSS JOIN (SELECT DISTINCT emp_name
FROM SalesTotals) EN
LEFT JOIN SalesTotals ST
ON N.Number = MONTH(ST.YearMonth)
AND EN.emp_name = ST.emp_name
I have table like below
ID User Date Location
1 Tom 6-Mar-2012 US
2 Tom 4-Feb-2012 UK
3 Tom 6-Jan-2012 Uk
4 Bob 6-Mar-2012 UK
5 Bob 4-Feb-2012 UK
6 Bob 6-Jan-2012 AUS
7 Dev 6-Mar-2012 US
8 Dev 4-Feb-2012 AUS
9 Nic 6-Jan-2012 US
I have to get each employee recent location in same table.
ID User Date Location CurrentLocation
1 Tom 6-Mar-2012 US US
2 Tom 4-Feb-2012 UK US
3 Tom 6-Jan-2012 Uk US
4 Bob 6-Mar-2012 UK UK
5 Bob 4-Feb-2012 UK UK
6 Bob 6-Jan-2012 AUS UK
7 Dev 6-Mar-2012 US US
8 Dev 4-Feb-2012 AUS US
9 Nic 6-Jan-2012 US US
I have tired with temp tables. can I get this done using single query. This is in middle of implementation. I have already created many temp tables.
Thanks in Advance.
Try this:
select *, CurrentLocation
from tbl x
outer apply
(
select top 1 location as CurrentLocation
from tbl
where [user] = x.[user]
and id <= x.id
order by id
) y
order by id
Output:
ID USER DATE LOCATION CURRENTLOCATION
1 Tom 2012-03-06 US US
2 Tom 2012-02-04 UK US
3 Tom 2012-01-06 Uk US
4 Bob 2012-03-06 UK UK
5 Bob 2012-02-04 UK UK
6 Bob 2012-01-06 AUS UK
7 Dev 2012-03-06 US US
8 Dev 2012-02-04 AUS US
9 Nic 2012-01-06 US US
Live test: http://www.sqlfiddle.com/#!3/83a6a/7
select
id,
user,
date,
location,
first_value(location) over(partition by user order by date desc) as current_location
from your_table s;
The above is valid only in Oracle.
This is my try in absence of first_value analytic function:
select
a.id,
a.usr,
a.date,
a.location,
m.location as current_location
from
a
join
(select usr, location
from
(select usr,
location,
row_number() over(partition by usr order by date desc) as rnk
from a
)b
where rnk = 1) m
on m.usr = a.usr;
The m inner query contains the records with most recent user entries.
After this I make a join with this view, to obtain users's location.
See here sqlfiddle test.