I have table like below
ID User Date Location
1 Tom 6-Mar-2012 US
2 Tom 4-Feb-2012 UK
3 Tom 6-Jan-2012 Uk
4 Bob 6-Mar-2012 UK
5 Bob 4-Feb-2012 UK
6 Bob 6-Jan-2012 AUS
7 Dev 6-Mar-2012 US
8 Dev 4-Feb-2012 AUS
9 Nic 6-Jan-2012 US
I have to get each employee recent location in same table.
ID User Date Location CurrentLocation
1 Tom 6-Mar-2012 US US
2 Tom 4-Feb-2012 UK US
3 Tom 6-Jan-2012 Uk US
4 Bob 6-Mar-2012 UK UK
5 Bob 4-Feb-2012 UK UK
6 Bob 6-Jan-2012 AUS UK
7 Dev 6-Mar-2012 US US
8 Dev 4-Feb-2012 AUS US
9 Nic 6-Jan-2012 US US
I have tired with temp tables. can I get this done using single query. This is in middle of implementation. I have already created many temp tables.
Thanks in Advance.
Try this:
select *, CurrentLocation
from tbl x
outer apply
(
select top 1 location as CurrentLocation
from tbl
where [user] = x.[user]
and id <= x.id
order by id
) y
order by id
Output:
ID USER DATE LOCATION CURRENTLOCATION
1 Tom 2012-03-06 US US
2 Tom 2012-02-04 UK US
3 Tom 2012-01-06 Uk US
4 Bob 2012-03-06 UK UK
5 Bob 2012-02-04 UK UK
6 Bob 2012-01-06 AUS UK
7 Dev 2012-03-06 US US
8 Dev 2012-02-04 AUS US
9 Nic 2012-01-06 US US
Live test: http://www.sqlfiddle.com/#!3/83a6a/7
select
id,
user,
date,
location,
first_value(location) over(partition by user order by date desc) as current_location
from your_table s;
The above is valid only in Oracle.
This is my try in absence of first_value analytic function:
select
a.id,
a.usr,
a.date,
a.location,
m.location as current_location
from
a
join
(select usr, location
from
(select usr,
location,
row_number() over(partition by usr order by date desc) as rnk
from a
)b
where rnk = 1) m
on m.usr = a.usr;
The m inner query contains the records with most recent user entries.
After this I make a join with this view, to obtain users's location.
See here sqlfiddle test.
Related
I want to return all the data, from max count query with hospital that has most number of patients. What I seem to be getting when I try to nest queries is display of all rows of hospital data. I've tried to look at similar questions in stack overflow and other sites it seems to be a simple query to do but i am not getting it.
select max(highest_hospital) as max_hospital
from (select count(hospital) as highest_hospital
from doctor
group by hospital)
highest_hospital
-------------
3
Doc ID Doctor Patient Hospital Medicine Cost
------ ------- ------ --------- ------ --------
1 Jim Bob Patient1 Town 1 Medicine 1 4000
2 Janice Smith Patient2 Town 2 Medicine 3 3000
3 Harold Brown Patient3 Town 2 Medicine 5 2000
4 Larry Owens Patient4 Town 2 Medicine 6 3000
5 Sally Brown Patient5 Town 3 Medicine 7 4000
6 Bob Jim Patient6 Town 4 Medicine 8 6000
Outcome should be return of 3 rows
Doc ID Doctor Patient Hospital Medicine Cost
------ ------- ------ --------- ------ --------
2 Janice Smith Patient2 Town 2 Medicine 3 3000
3 Harold Brown Patient3 Town 2 Medicine 5 2000
4 Larry Owens Patient4 Town 2 Medicine 6 3000
You can use window functions:
select d.*
from (select d.*, max(hospital_count) over () as max_hospital_count
from (select d.*, count(*) over (partition by hospital) as hospital_count
from doctor d
) d
) d
where hospital_count = max_hospital_count;
Edit:
Using GROUP BY is a pain. If you are only looking for a single hospital (even when there are ties), then in Oracle 12C you can do:
select d.*
from doctor d
where d.hospital = (select d2.hospital
from doctor d2
group by d2.hospital
order by count(*) desc
fetch first 1 row only
);
You can do this in earlier versions of Oracle using an additional subquery.
The simple SELECT query would return the data as below:
Select ID, User, Country, TimeLogged from Data
ID User Country TimeLogged
1 Samantha SCO 10
1 John UK 5
1 Andrew NZL 15
2 John UK 20
3 Mark UK 10
3 Mark UK 20
3 Steven UK 10
3 Andrew NZL 15
3 Sharon IRL 5
4 Andrew NZL 25
4 Michael AUS 5
5 Jessica USA 30
I would like to return a sum of time logged for each user grouped by ID
But for only ID numbers where both of these values Country = UK and User = Andrew are included within their rows.
So the output in the above example would be
ID User Country TimeLogged
1 John UK 5
1 Andrew NZL 15
3 Mark UK 30
3 Steven UK 10
3 Andrew NZL 15
First you need to identify which IDs you're going to be returning
SELECT ID FROM MyTable WHERE Country='UK'
INTERSECT
SELECT ID FROM MyTable WHERE [User]='Andrew';
and based on that, you can then filter to aggregate the expected rows.
SELECT ID,
[User],
Country,
SUM(Timelogged) as Timelogged
FROM mytable
WHERE (Country='UK' OR [User]='Andrew')
AND ID IN( SELECT ID FROM MyTable WHERE Country='UK'
INTERSECT
SELECT ID FROM MyTable WHERE [User]='Andrew')
GROUP BY ID, [User], country;
So, you have described what you need to write almost perfectly but not quite. Your result table indicates that you want Country = UK OR User = Andrew, rather than AND
You need to select and group by, then include a WHERE:-
Select ID, User, Country, SUM(Timelogged) as Timelogged from mytable
WHERE Country='UK' OR User='Andrew'
Group by ID, user, country
I try to googling for this issue and still couldn't find the solution.
I have 2 column to combine like below:
First table:
ID Name Item
42 america 1433
42 america 1695
42 america 1234
8 london 1433
8 london 1705
8 london 1432
Second table:
ID CreatedBy
42 John
42 Erica
8 Amy Song
8 Alfred
If I just join both table it will become like this:
ID Name Item CreatedBy
42 america 1433 John
42 america 1695 John
42 america 1234 John
42 america 1433 Erica
42 america 1695 Erica
42 america 1234 Erica
8 london 1433 Amy Song
8 london 1705 Amy Song
8 london 1432 Amy Song
8 london 1433 Alfred
8 london 1705 Alfred
8 london 1432 Alfred
Column Created By is only related to ID, and not related to Name and Item.
I just want to insert CreatedBy as a new column into first table that only linked to ID, so the expected result will be like below.
Is there any way I could get result like this?
ID Name Item CreatedBy
42 america 1433 John
42 america 1695 Erica
42 america 1234 NULL
8 london 1433 Amy Song
8 london 1705 Alfred
8 london 1432 NULL
Let say we change second table like this:
Second table:
ID CreatedBy
42 John
8 Amy Song
Result will be like this:
ID Name Item CreatedBy
42 america 1433 John
42 america 1695 NULL
42 america 1234 NULL
8 london 1433 Amy Song
8 london 1705 NULL
8 london 1432 NULL
I really apreacite for your help, and thank you in advanced masta.
NOTE: Column CreatedBy is the independent column that only relate to ID and not relate to Name and Item.
So, I will answer you even though some guys that discussed it here on comments may disagree as there is no a proper logic to your problem.
It is important to note that this answer is for this SPECIFIC case if it won't get you the right data for a larger dataset you have to provide more info on it.
What I did:
I've created a subset from the first set ordering it (and indexing it, window function) by the name then I created another subset from the second set ordering it by the id so, i have:
select id, name, item, row_number() over (partition by name order by name) idx from tablea
And
select id, createdby, row_number() over (partition by id order by id) idx from tableb
Then I LEFT JOIN the tablea with tableb by the id and the order created colum idx so
select a.id, a.name, a.item, b.createdby
from (select id, name, item, row_number() over (partition by name order by name) idx from tablea) a
left join
(select id, createdby, row_number() over (partition by id order by id) idx from tableb) b
on (a.id = b.id and a.idx=b.idx)
order by a.name
The order by is just to get the result as you asked on your question.
See it here: http://sqlfiddle.com/#!3/7ef70/3
For your second sample data: http://sqlfiddle.com/#!3/675625/1
looking for some help limiting the results while querying combinations between 2 columns. Here's an example of the kind of table I am working with..
id name group state
1 Bob A NY
2 Jim A NY
3 Dan A NY
4 Mike A FL
5 Tim B NY
6 Sam B FL
7 Brad B FL
8 Glen B FL
9 Ben C FL
I am trying to display all records of all combinations of "group" and "state", but limiting to displaying only up to 2 records for each combination. The result should look like the following..
id name group state
1 Bob A NY
2 Jim A NY
4 Mike A FL
5 Tim B NY
6 Sam B FL
7 Brad B FL
9 Ben C FL
Thanks for the help.
Assuming you always want the two rows for each group and state combination with the lowest id
SELECT *
FROM (SELECT a.*,
row_number() over (partition by group, state
order by id asc) rnk
FROM your_table a)
WHERE rnk <= 2
Of course, since group is a reserved word, I assume your column is actually named something else... You'd need to adjust my query to use the correct column name.
I have a table GAMES with this information:
Id_Game Id_Player1 Id_Player2 Week
--------------------------------------
1211 Peter John 2
1215 John Louis 13
1216 Louis Peter 17
I would like to get a list of the last week when each player has played, and the number of games, which should be this:
Id_Player Week numberGames
-----------------------------
Peter 17 2
John 13 2
Louis 17 2
But instead I get this one (notice on Peter week):
Id_Player Week numberGames
-----------------------------
Peter 2 2
John 13 2
Louis 17 2
What I do is this:
SELECT Id_Player,
MAX(Week) AS Week,
COUNT(*) as numberGames
FROM ((SELECT Id_Player1 as Id_Player, Week
FROM Games)
UNION ALL
(SELECT Id_Player2 as Id_Player, Week
FROM Games)) AS g2
GROUP BY Id_Player;
Could anyone help me to find the mistake?
What is the datatype of the Week column? If the datatype of Week is varchar you would get this behavior.