Oracle CONNECT Operations - sql

I've read through the Oracle documentation concerning the CONNECT operations, but I can't seem to get my head around a database query we have in an existing application. Below is a simplified version of the query.
SELECT LEVEL,
CONNECT_BY_ROOT MY_MONTH MY_LABEL,
b.*
FROM (
SELECT ROWNUM AS ORDERING,
MY_AREA,
TRUNC (THE_MONTH, 'MONTH') AS MY_MONTH
FROM MY_TABLE
ORDER BY MY_AREA, MY_MONTH DESC
) b
WHERE LEVEL <= 3
START WITH 1 = 1
CONNECT BY PRIOR MY_AREA = MY_AREA
AND PRIOR ORDERING = ORDERING - 1
AND PRIOR MY_MONTH <= ADD_MONTHS(MY_MONTH, 6);
While I have a basic understanding of the CONNECT functionalities, this combination has me lost. Can anyone explain what is going on in this query?
I think the end says to get all of the rows that have the same area and a row number 1 less than the current row number and a date before 6 months in the future from the current date. I would guess this would only return 1 row (due to the row number criteria) or 0 rows if the other criteria weren't met. And then maybe the first CONNECT_BY_ROOT says to get that row's MY_MONTH value?

Start with b, which is a table of MY_AREA (a number?), MY_MONTH, which is a month-truncated date (i.e. the days are all set to 01), and an aliased ROWNUM, which is determined by the ORDER BY clause, which is ORDER BY MY_AREA, MY_MONTH DESC, e.g.:
+----------+---------+-----------+
| ORDERING | MY_AREA | MY_MONTH |
+----------+---------+-----------+
| 1 | 10 | 01-SEP-12 |
| 2 | 10 | 01-JAN-12 |
| 3 | 12 | 01-AUG-12 |
| 4 | 12 | 01-JUN-12 |
| 5 | 12 | 01-MAY-12 |
| 6 | 12 | 01-JAN-12 |
| 7 | 12 | 01-JAN-10 |
+----------+---------+-----------+
The WHERE clause doesn't come into play until later, so move on to START WITH, which says only 1 = 1. This means that every row in b will be used in the query; if you had had another condition here, e.g. my_area < 5 or whatever, only a certain set of rows would have been used.
Now, the CONNECT BY, which determines how the hierarchy should be built. This works like a WHERE clause, except for the special PRIOR keyword which tells the DB to look at the previous level in the hierarchy. So:
PRIOR MY_AREA = MY_AREA just means that the child node has to have the same value for `MY_AREA'
PRIOR ORDERING = ORDERING - 1 means that the child should come one row after the current node in b's ordering.
PRIOR MY_MONTH <= ADD_MONTHS(MY_MONTH, 6) means that in order to be joined into the hierarchy, the previous MY_MONTH should be 6 months or less after the date of the current node.
The whole hierarchy is then created. LEVEL (special for CONNECT BY...) is set to the level in the hierarchy, CONNECT_BY_ROOT gives the MY_MONTH value for the root of that hierarchy and aliases it to MY_LABEL. After this, the table would look something like the following table. I've added separators for each hierarchy for clarity.
+-------+-----------+----------+---------+-----------+
| LEVEL | MY_LABEL | ORDERING | MY_AREA | MY_MONTH |
+-------+-----------+----------+---------+-----------+
| 1 | 01-SEP-12 | 1 | 10 | 01-SEP-12 |
+-------+-----------+----------+---------+-----------+
| 1 | 01-JAN-12 | 2 | 10 | 01-JAN-12 |
+-------+-----------+----------+---------+-----------+
| 1 | 01-AUG-12 | 3 | 12 | 01-AUG-12 |
| 2 | 01-AUG-12 | 4 | 12 | 01-JUN-12 |
| 3 | 01-AUG-12 | 5 | 12 | 01-MAY-12 |
| 4 | 01-AUG-12 | 6 | 12 | 01-JAN-12 |
+-------+-----------+----------+---------+-----------+
| 1 | 01-JUN-12 | 4 | 12 | 01-JUN-12 |
| 2 | 01-JUN-12 | 5 | 12 | 01-MAY-12 |
| 3 | 01-JUN-12 | 6 | 12 | 01-JAN-12 |
+-------+-----------+----------+---------+-----------+
| 1 | 01-MAY-12 | 5 | 12 | 01-MAY-12 |
| 2 | 01-MAY-12 | 6 | 12 | 01-JAN-12 |
+-------+-----------+----------+---------+-----------+
| 1 | 01-JAN-12 | 6 | 12 | 01-JAN-12 |
+-------+-----------+----------+---------+-----------+
| 1 | 01-JAN-10 | 7 | 12 | 01-JAN-10 |
+-------+-----------+----------+---------+-----------+
So, as you can see, each of the rows appears at the top of its own hierarchy, with all nodes meeting the CONNECT BY criteria under it.
Finally, the WHERE clause is applied; this chops off all of the levels > 3 in every hierarchy, so you're left with a maximum of 3 levels. This affects only one row in the middle hierarchy, the one with LEVEL = 4.

Related

How to return the same period last year data with SQL?

I am trying to create a view in postgreSQL with the requirements as below:
The table needs to show the same period last year data for every records.
Sample data:
date_sk | location_sk | division_sk | employee_type_sk | value
20180202 | 6 | 8 | 4 | 1
20180202 | 7 | 2 | 4 | 2
20190202 | 6 | 8 | 4 | 1
20190202 | 7 | 2 | 4 | 1
20200202 | 6 | 8 | 4 | 1
20200202 | 7 | 2 | 4 | 3
In the table, date_sk, location_sk, division_sk and employee_type_sk are super keys which form an unique record in the table.
You can check the required output as below:
date_sk | location_sk | division_sk | employee_type_sk | value | value_last_year
20180202 | 6 | 8 | 4 | 1 | NULL
20180203 | 7 | 2 | 4 | 2 | NULL
20190202 | 6 | 8 | 4 | 1 | 1
20190203 | 7 | 3 | 4 | 1 | NULL
20200202 | 6 | 8 | 4 | 1 | 1
20200203 | 7 | 3 | 4 | 3 | 1
The records start on 20180202, therefore, the data for the same period last year is unavailable. At the 4th record, there is a difference in division_sk comparing with the same period last year - hence, the head_count_last_year is NULL.
My current solution is to create a view from the sample data with an addition column as same_date_last_year then LEFT JOIN the same table. The SQL queries are below:
CREATE VIEW test_view AS
SELECT *,
CONCAT(LEFT(date_sk, 4) - 1, RIGHT(date_sk, 4)) AS same_date_last_year
FROM test_table
SELECT
test_view.date_sk,
test_view.location_sk,
test_view.division_sk,
test_view.employee_type_sk,
test_view.value,
test_table.value AS value_last_year
FROM test_view
LEFT JOIN test_table ON (test_view.same_date_last_year = test_table.date_sk)
We have a lot of data in the table. My solution above is unacceptable in terms of performance.
Is there a different query which yields the same result and might improve the performance ?
You could simply use a correlated subquery here which is likely best for performance:
select *,
(
select value from t t2
where t2.date_sk=t.date_sk - interval '1' year and
t2.location_sk=t.location_sk and
t2.division_sk=t.division_sk and
t2.employee_type_sk=t.employee_type_sk
) as value_last_year
from t
WITH CTE(DATE_SK,LOCATION_SK,DIVISION_SK,EMPLOYEE_TYPE_SK,VALUE)AS
(
SELECT CAST('20180202' AS DATE),6,8,4,1 UNION ALL
SELECT CAST('20180203'AS DATE),7,2,4,2 UNION ALL
SELECT CAST('20190202'AS DATE),6,8,4,1 UNION ALL
SELECT CAST('20190203'AS DATE),7,2,4,1 UNION ALL
SELECT CAST('20200202'AS DATE),6,8,4,1 UNION ALL
SELECT CAST('20200203'AS DATE),7,2,4,3
)
SELECT C.DATE_SK,C.LOCATION_SK,C.DIVISION_SK,C.EMPLOYEE_TYPE_SK,C.VALUE,
LAG(C.VALUE)OVER(PARTITION BY C.LOCATION_SK,C.DIVISION_SK,C.EMPLOYEE_TYPE_SK ORDER BY C.DATE_SK ASC)LAGG
FROM CTE AS C
ORDER BY C.DATE_SK ASC;
Could you please try if the above is suitable for you. I assume,DATE_SK is a date column or can be CAST to a date

Postgres Query Based on Previous and Next Rows

I'm trying to solve the bus routing problem in postgresql which requires visibility of previous and next rows. Here is my solution.
Step 1) Have one edges table which represents all the edges (the source and target represent vertices (bus stops):
postgres=# select id, source, target, cost from busedges;
id | source | target | cost
----+--------+--------+------
1 | 1 | 2 | 1
2 | 2 | 3 | 1
3 | 3 | 4 | 1
4 | 4 | 5 | 1
5 | 1 | 7 | 1
6 | 7 | 8 | 1
7 | 1 | 6 | 1
8 | 6 | 8 | 1
9 | 9 | 10 | 1
10 | 10 | 11 | 1
11 | 11 | 12 | 1
12 | 12 | 13 | 1
13 | 9 | 15 | 1
14 | 15 | 16 | 1
15 | 9 | 14 | 1
16 | 14 | 16 | 1
Step 2) Have a table which represents bus details like from time, to time, edge etc.
NOTE: I have used integer format for "from" and "to" column for faster results as I can do an integer query, but I can replace it with any better format if available.
postgres=# select id, "busedgeId", "busId", "from", "to" from busedgetimes;
id | busedgeId | busId | from | to
----+-----------+-------+-------+-------
18 | 1 | 1 | 33000 | 33300
19 | 2 | 1 | 33300 | 33600
20 | 3 | 2 | 33900 | 34200
21 | 4 | 2 | 34200 | 34800
22 | 1 | 3 | 36000 | 36300
23 | 2 | 3 | 36600 | 37200
24 | 3 | 4 | 38400 | 38700
25 | 4 | 4 | 38700 | 39540
Step 3) Use dijkstra algorithm to find the nearest path.
Step 4) Get the upcoming buses from the busedgetimes table in the earliest first order for the nearest path detected by dijkstra algorithm.
Problem: I am finding it difficult to make the query for the Step 4.
For example: If I get the path as edges 2, 3, 4, to travel from source vertex 2 to target vertex 5 in the above records. To get the first bus for the first edge, it's not so hard as I can simply query with from < 'expected departure' order by from desc but for the second edge, the from condition requires to time of first result row. Also, query requires edge ids filter.
How can I achieve this in a single query?
I am not sure if I understood your problem correctly. But getting values from other rows this can be done by window functions (https://www.postgresql.org/docs/current/static/tutorial-window.html):
demo: db<>fiddle
SELECT
id,
lag("to") OVER (ORDER BY id) as prev_to,
"from",
"to",
lead("from") OVER (ORDER BY id) as next_from
FROM bustimes;
The lag function moves the value of the previous row into the current one. The lead function does the same with the next row. So you are able to calculate a difference between last arrival and current departure or something like that.
Result:
id prev_to from to next_from
18 33000 33300 33300
19 33300 33300 33600 33900
20 33600 33900 34200 34200
21 34200 34200 34800 36000
22 34800 36000 36300
Please notice that "from" and "to" are reserved words in PostgreSQL. It would be better to chose other names.

Oracle: sql query for deleting duplicate rows based on a group

i need a SQL-Query to delete duplicates from a table. Lets start with my tables
rc_document: (there are more entries, this is just an example)
+----------------+-------------+----------------------+
| rc_document_id | document_id | rc_document_group_id |
+----------------+-------------+----------------------+
| 1 | 1 | 1 |
| 2 | 2 | 1 |
| 3 | 3 | 1 |
| 4 | 4 | 1 |
| 5 | 1 | 2 |
| 6 | 3 | 2 |
+----------------+-------------+----------------------+
(document_id can be exists in mulitple rc_document-group´s)
rc_document_group:
+----------------------+----------+
| rc_document_group_id | priority |
+----------------------+----------+
| 1 | 1 |
| 2 | 2 |
+----------------------+----------+
Each rc_document can be joined with the rc_document_group. In the rc_document_group is the priority for each rc_document.
I want to delete the rc_document rows with document_id which have not the highest priority in the rc_document_group. Because the document_id can be exists in multiple rc_document-group´s .. i just want to keep that one, with the highest priority.
here is my expected rc_document table after deleting duplicate document_id´s:
+----------------+-------------+----------------------+
| rc_document_id | document_id | rc_document_group_id |
+----------------+-------------+----------------------+
| 2 | 2 | 1 |
| 4 | 4 | 1 |
| 5 | 1 | 2 |
| 6 | 3 | 2 |
+----------------+-------------+----------------------+
the rc_document´s with rc_document_id 1 and 3 must be deleted, because there document_id 1 and 3 are in another rc_document_group with higher priority.
Im new in sql and i have no idea how to write these sql query ... thank for your help!!
First, you could join the two tables in order to get the corresponding priority on each row. After that, you could use the analytic function MAX() to get, for each row, the max priority within each group of document_id. At this point, you filter out the rows where the priority is not equal to the max priority in the group.
Try this query:
SELECT t.rc_document_id,
t.document_id,
t.rc_document_group_id
FROM (SELECT d.*,
g.priority,
MAX(g.priority) OVER(PARTITION BY document_id) max_priority
FROM rc_document d
INNER JOIN rc_document_group g
ON d.rc_document_group_id = g.rc_document_group_id) t
WHERE t.priority = t.max_priority

How do I do multiple selection based on a flowchart of criteria?

Table name: Copies
+------------------------------------------------------------------------------------+
| group_id | my_id | previous | in_this | higher_value | most_recent |
+----------------------------------------------------------------------------------------------------------------
| 900 | 1 | null | Y | 7 | May16 |
| 900 | 2 | null | Y | 3 | Oct 16 |
| 900 | 3 | null | N | 9 | Oct 16 |
| 901 | 4 | 378 | Y | 3 | Oct 16 |
| 901 | 5 | null | N | 2 | Oct 16 |
| 902 | 6 | null | N | 5 | May16 |
| 902 | 7 | null | N | 9 | Oct 16 |
| 903 | 8 | null | Y | 3 | Oct 16 |
| 903 | 9 | null | Y | 3 | May16 |
| 904 | 10 | null | N | 0 | May 16 |
| 904 | 11 | null | N | 0 | May16
--------------------------------------------------------------------------------------
Output table
+---------------------------------------------------------------------------------------------------+
| group_id | my_id | previous | in_this | higher_value |most_recent|
+----------------------------------------------------------------------------------------------------
| 900 | 1 | null | Y | 7 | May16 |
| 902 | 7 | null | N | 9 | Oct 16 |
| 903 | 8 | null | Y | 3 | Oct 16 |
---------------------------------------------------------------------------------------------------------
Hi all, I need help with a query that returns one record within a group based on the importance of the field. The importance is ranked as follows:
previous- if one record within the group_id is not null, then neither record within a group_id is returned (because according to our rules, all records within a group should have the same previous value)
in_this- If one record is Y, and the other is N within a group_id, then we keep the Y; If all records are Y or all are N, then we move to the next attribute
Higher_value- If all records in the ‘in_this’ field are equal, then we need to select the record with the greater value from this field. If both records have an equal value, we move to the next attribute
Most_recent- If all records were of equal value in the ‘higher_value’ field, then we consider the newest record. If these are equal, then nothing is returned.
This is a simplified version of the table I am looking at, but I just would like to get the gist of how something like this would work. Basically, my table has multiple copies of records that have been grouped through some algorithm. I have been tasked with selecting which of these records within a group is the ‘good’ one, and we are basing this on these fields.
I’d like the output to actually show all fields, because I will likely attempt to refine the query to include other fields (there are over 40 to consider), but the most important is the group_id and my_id fields. It would be neat if we could also somehow flag why each record got picked, but that isn’t necessary.
It seems like something like this should be easy, but I have a hard time wrapping my head around how to pick from within a group_id. Thanks for your help.
You can use analytic functions for this. The trick is establishing the right variables for each condition:
select t.*
from (select t.*,
max(in_this) over (partition by group_id) as max_in_this,
min(higher_value) over (partition by group_id) as min_higher_value,
max(higher_value) over (partition by group_id) as max_higher_value,
row_number() over (partition by group_id, higher_value order by my_id) as seqnum_ghv,
min(most_recent) over (partition by group_id) as min_most_recent,
max(most_recent) over (partition by group_id) as max_most_recent,
row_number() over (partition by group_id order by most_recent) as seqnum_mr
from t
) t
where max_in_this is not null and
( (min_higher_value <> max_higher_value and seqnum_ghv = 1) or
(min_higher_value = max_higher_value and min_most_recent <> max_most_recent and seqnum_mr = 1
)
);
The third condition as stated makes no sense, but you should get the idea for how to implement this.

SQL: Add values according to index columns only for lines sharing an id

Yesterday I asked this question: SQL: How to add values according to index columns but I found out that my problem is a bit more complicated:
I have an array like this
id | value| position | relates_to_position |type
19 | 100 | 2 | NULL | 1
19 | 50 | 6 | NULL | 2
19 | 20 | 7 | 6 | 3
20 | 30 | 3 | NULL | 2
20 | 10 | 4 | 3 | 3
From this I need to create the resulting table, which adds all the lines where the relates_to_position value matches the position value, but only for lines sharing the same id!
The resulting table should be
id | value| position |type
19 | 100 | 2 | 1
19 | 70 | 6 | 2
20 | 40 | 3 | 2
I am using Oracle 11. There is only one level of recursion, meaning a line would not refer to a line which has the relates_to_pos field set.
I think the following query will do this:
select id, coalesce(relates_to_position, position) as position,
sum(value) as value, min(type) as type
from t
group by id, coalesce(relates_to_position, position);