How to find the day of the dates - sql

Question

Using SQL Server 2000
Table1
ID Date Value1 Value2
001 01/01/2012 100 0
001 02/01/2012 200 200
...
...
001 31/01/2012 250 0
002 01/01/2012 050 100
002 02/01/2012 100 0
...
002 31/01/2012 075
....
I want to display the value (value1 column) by date wise (date column) group by id
Output like
ID 01/01/2012 02/01/2012 ... 31/01/2012
001 100 200 .... 250
002 050 100 .... 075
.....
Query
DECLARE #loop int,#date Date,#sql nvarchar(4000)
DECLARE #TempTable TABLE
(
[Date] DATE
)
INSERT INTO #TempTable SELECT DISTINCT [Date] FROM table1 ORDER BY [Date]
SET #sql = ''
SET #loop = 1
WHILE (#loop<=31)
BEGIN
IF EXISTS(SELECT * FROM #TempTable WHERE DAY([Date])=#loop)
BEGIN
SET #date = (SELECT [Date] FROM #TempTable WHERE DAY([Date])=#loop)
SET #sql = #sql+ ',MAX(CASE CONVERT(nvarchar(10),[Date],103) WHEN '''+CONVERT(nvarchar(10),#date,103)+''' THEN [Value1] END) AS [DATE'+CONVERT(nvarchar(2),#loop)+']'
END
ELSE
SET #sql = #sql+ ', NULL AS [DATE'+CONVERT(nvarchar(2),#loop)+']'
SET #loop = #loop+1
END
EXEC('SELECT ID'+#sql+' FROM table1 GROUP BY ID')
The above query is working, from the above query i want to find the sunday, if it is sunday then date column should display a value from value2 column otherwise value1 column
should display
How to do this.
Need Query help

Answer 1

DATEPART function gives you integer day of the week. Sunday - Saturday become 1 - 7.
try change the line by this one
SET #sql = #sql+ ',MAX(CASE CONVERT(nvarchar(10),[Date],103) WHEN '''+CONVERT(nvarchar(10),#date,103)+''' THEN CASE DATEPART(weekday,[Date])WHEN 1 THEN [Value1] ELSE [Value2] END END) AS [DATE'+CONVERT(nvarchar(2),#loop)+']'
For total calculation per id
SELECT ID,
SUM(CASE WHEN DATEPART(weekday,[Date]) <> 1 THEN [Value1] END) AS Value1,
SUM(CASE DATEPART(weekday,[Date]) WHEN 1 THEN [Value2] END) AS Value2,
FROM table1 GROUP BY ID

Answer 2

It may turn out you don't need iteration, nor dynamic scripting. Consider the following:
SELECT
ID,
Day1 = MAX(CASE D WHEN 1 THEN V END),
Day2 = MAX(CASE D WHEN 2 THEN V END),
Day3 = MAX(CASE D WHEN 3 THEN V END),
Day4 = MAX(CASE D WHEN 4 THEN V END),
Day5 = MAX(CASE D WHEN 5 THEN V END),
Day6 = MAX(CASE D WHEN 6 THEN V END),
Day7 = MAX(CASE D WHEN 7 THEN V END),
Day8 = MAX(CASE D WHEN 8 THEN V END),
Day9 = MAX(CASE D WHEN 9 THEN V END),
Day10 = MAX(CASE D WHEN 10 THEN V END),
Day11 = MAX(CASE D WHEN 11 THEN V END),
Day12 = MAX(CASE D WHEN 12 THEN V END),
Day13 = MAX(CASE D WHEN 13 THEN V END),
Day14 = MAX(CASE D WHEN 14 THEN V END),
Day15 = MAX(CASE D WHEN 15 THEN V END),
Day16 = MAX(CASE D WHEN 16 THEN V END),
Day17 = MAX(CASE D WHEN 17 THEN V END),
Day18 = MAX(CASE D WHEN 18 THEN V END),
Day19 = MAX(CASE D WHEN 19 THEN V END),
Day20 = MAX(CASE D WHEN 20 THEN V END),
Day21 = MAX(CASE D WHEN 21 THEN V END),
Day22 = MAX(CASE D WHEN 22 THEN V END),
Day23 = MAX(CASE D WHEN 23 THEN V END),
Day24 = MAX(CASE D WHEN 24 THEN V END),
Day25 = MAX(CASE D WHEN 25 THEN V END),
Day26 = MAX(CASE D WHEN 26 THEN V END),
Day27 = MAX(CASE D WHEN 27 THEN V END),
Day28 = MAX(CASE D WHEN 28 THEN V END),
Day29 = MAX(CASE D WHEN 29 THEN V END),
Day30 = MAX(CASE D WHEN 30 THEN V END),
Day31 = MAX(CASE D WHEN 31 THEN V END)
FROM (
SELECT
ID,
V = CASE DATENAME(WEEKDAY, Date) WHEN 'Sunday' THEN Value2 ELSE Value1 END,
D = DAY(Date)
FROM Table1
WHERE … /* perhaps, a condition to retrieve a specific month is due here */
) s
GROUP BY ID
;