Full Join on two queries - sql

I'm trying to do a full join on two SQL queries, below:
1st Query:
SELECT
ID
,SUM(CASE WHEN reason = 4 THEN 0 ELSE quantity*price END) AS TValue
,COUNT(*) AS CountAll
FROM table1
WHERE Date>=#StartDate AND Date<=#EndDate
GROUP BY ID
2nd Query:
SELECT
ID
,SUM(CASE WHEN reason = 1 THEN 1 ELSE 0 END) AS New
,SUM(CASE WHEN reason = 6 THEN 1 ELSE 0 END) AS Amend
,SUM(CASE WHEN reason = 5 THEN 1 ELSE 0 END) AS Cancel
FROM Table2
WHERE Date2 >=#StartDate AND Date2<= #EndDate
GROUP BY ID
Result from query1
ID CountAll TValue
-------------------------
id1 24 1020
id2 13 2030
id3 4 120
Result from query 2:
ID New Amend Cancel
--------------------------------
id1 12 4 6
id2 7 6 1
id4 2 1 2
Needed output:
ID TValue CountAll New Amend Cancel Total(countall+new+amend+cancel)
----------------------------------------------------------------------------------------
Id1 1020 24 12 4 6 46
Id2 2030 13 7 6 1 27
id3 120 4 0 0 0 4
Id4 0 0 2 1 2 5
I'll post my current solution if requested, but it is pretty far from working.
I've been doing a bit of research and I think I need to either make a union to join the ID'S, or just do a Full Join. (Second day ever doing sql)

Try this,
SELECT *
FROM
(
SELECT ID ,
SUM(CASE WHEN reason = 4 THEN 0 ELSE quantity*price END) AS TValue,
COUNT(*) AS CountAll
FROM table1
WHERE Date>=#StartDate AND Date<=#EndDate
GROUP BY ID
) a FULL JOIN
(
SELECT ID ,
SUM(CASE WHEN reason = 1 THEN 1 ELSE 0 END) AS New ,
SUM(CASE WHEN reason = 6 THEN 1 ELSE 0 END) AS Amend ,
SUM(CASE WHEN reason = 5 THEN 1 ELSE 0 END) AS Cancel
FROM Table2
WHERE Date2 >=#StartDate AND Date2<= #EndDate
GROUP BY ID
) b ON a.ID = b.ID

I would write something like below:
select decode (a.id, null, b.id, a.id) as ID, a.TValue, CountAll, b.new, b.Amend, b.cancel
from (SELECT ID ,SUM(CASE WHEN reason = 4 THEN 0 ELSE quantity*price END)
AS TValue ,COUNT(*) AS CountAll
FROM table1
WHERE Date>=#StartDate AND Date<=#EndDate GROUP BY ID
) a FULL OUTER JOIN
(SELECT ID , SUM(CASE WHEN reason = 1 THEN 1 ELSE 0 END)
AS New ,SUM(CASE WHEN reason = 6
THEN 1 ELSE 0 END) AS Amend ,
SUM(CASE WHEN reason = 5 THEN 1 ELSE 0 END) AS Cancel
FROM Table2 WHERE Date2 >=#StartDate AND Date2<= #EndDate GROUP BY ID
) b
on a.id = b.id

have you tried this...
select isnull (a.id,b.id) as ID, a.TValue, CountAll, b.new, b.Amend, b.cancel
from (SELECT ID ,SUM(CASE WHEN reason = 4 THEN 0 ELSE quantity*price END) AS TValue ,COUNT(*) AS CountAll
FROM table1
WHERE Date>=#StartDate AND Date<=#EndDate GROUP BY ID ) a
FULL OUTER JOIN (SELECT ID , SUM(CASE WHEN reason = 1 THEN 1 ELSE 0 END) AS New ,SUM(CASE WHEN reason = 6 THEN 1 ELSE 0 END) AS Amend , SUM(CASE WHEN reason = 5 THEN 1 ELSE 0 END) AS Cancel
FROM Table2 WHERE Date2 >=#StartDate AND Date2<= #EndDate GROUP BY ID ) b on a.id = b.id

Related

Get users that have at least one product code and also more than 10 of the other product code

The table that needs to be queried looks like this:
ID
UserID
ProductCodes
1
33
9999
2
456
3051
3
456
9999
4
456
3051
4
33
9999
How would I write a SQL query to find out which users have at least one productCodes = '9999' and also have more than 10 productCodes <> '9999'?
You can use GROUP BY and HAVING:
SELECT
UserID
FROM dbo.YourTable
GROUP BY
UserId
HAVING SUM(CASE WHEN ProductCodes = '9999' THEN 1 ELSE 0 END) >= 1
AND COUNT(DISTINCT ProductCodes) >= 11
;
Use Case or Intersect (case is more performant)
SELECT UserID, SUM (case when ProductCodes='9999' then 1 else 0 end) PC9999
, SUM (case when ProductCodes<>'9999' then 1 else 0 end) PCNot9999
FROM dbo.Users
WHERE ProductCodes='9999'
GROUP BY UserID
HAVING SUM (case when ProductCodes='9999' then 1 else 0 end)>0
AND SUM (case when ProductCodes<>'9999' then 1 else 0 end) >10
I ended up going with this. It allows us to get specific with how many times a '9999' product code has been used in comparison with other codes.
SELECT
UserID
FROM Session_Hst
GROUP BY
UserID
HAVING SUM(CASE WHEN ProductCodes = '9999' THEN 1 ELSE 0 END) >= 1
AND COUNT(CASE WHEN ProductCodes <> '9999' THEN 1 ELSE null END ) >= 10
;

Creating a view from two tables, with case and sum on one table

I'm having some troubles trying to create a view from two tables, which includes a sum + case for the first table. I've tried multiple different joins/unions, and I can get just the XTS table to come over, or just the case count scenarios to work, but I cannot get both.
here are the tables. For Table 1, UWI is non-unique. For Table 2, UWI is Unique. new_view is what I'm hoping to achieve for my view.
TABLE 1
UWI ET
1 A
1 B
1 B
2 B
2 C
2 C
TABLE 2
UWI XTS
1 10
2 20
3 10
4 30
new_view
UWI XTS B_COUNT C_COUNT
1 10 4 3
2 20 3 4
3 10 4 5
4 30 3 2
Here's what I'm currently working with.
CREATE VIEW new_view AS
SELECT t1.UWI,
sum(case when t1.ET='B' then 1 else 0 end) as B_COUNT,
sum(case when t1.ET='C' then 1 else 0 end) as C_COUNT,
sum(case when t1.ET='D' then 1 else 0 end) as D_COUNT,
sum(case when t1.ET='E' then 1 else 0 end) as E_COUNT,
sum(case when t1.ET='F' then 1 else 0 end) as F_COUNT
FROM TABLE_1 t1
INNER JOIN (SELECT t2.UWI, t2.XTS AS TSC
from TABLE_2 t2)
on t1.UWI = t2.UWI
group by t1.UWI;
Your sample select does not match your sample data, so this is a guess but I think you just need to move the aggregation into an apply()
select t2.UWI, t2.XTS, s.*
from Table_2 t2
outer apply (
select
sum(case when t1.ET='B' then 1 else 0 end) as B_COUNT,
sum(case when t1.ET='C' then 1 else 0 end) as C_COUNT,
sum(case when t1.ET='D' then 1 else 0 end) as D_COUNT,
sum(case when t1.ET='E' then 1 else 0 end) as E_COUNT,
sum(case when t1.ET='F' then 1 else 0 end) as F_COUNT
from table_1 t1
where t1.UWI = t2.UWI
group by t1.UWI
)s

3 Query by column and create a new table

I have students, and these students have their meals, morning and evening. I want to print the number of meals each student eats in the morning and evening.
If the number of dishes that student eats in the morning is more than one, I want to print the number in the table and the ID of the food.
FoodType when 1(morning), and when 2(evening)
StudentId FoodId FoodType
3 1 1
3 2 1
3 3 1
3 4 2
4 3 1
4 1 2
4 2 2
4 4 2
5 4 2
5 1 1
6 1 1
6 2 1
6 3 2
6 4 2
Sample out;
StudentId MorningFoodCountOrId EveningFoodCountOrId
3 3 meals 4
4 3 3 meals
5 4 1
6 2 meals 2 meals
Use conditional aggregation. The logic that decides if we print the number of records or their value is not intuitive, but I would phrase it as follows:
select
studentId,
case when sum(case when foodtype = 1 then 1 else 0 end) = 1
then max(case when foodtype = 1 then foodId end)
else sum(case when foodtype = 1 then 1 else 0 end)
end MorningFoodCountOrId
case when sum(case when foodtype = 2 then 1 else 0 end) = 1
then max(case when foodtype = 2 then foodId end)
else sum(case when foodtype = 2 then 1 else 0 end)
end EveningFoodCountOrId
from mytable
group by studentId
You RDMBS should be able to optimize the query by not computing the conditional sums twice.
Note: you did not specify which RDMBS you are using. If this is MySQL, then it is possible to shorten the conditional sums a little, as follows:
select
studentId,
case when sum(foodtype = 1) = 1
then max(case when foodtype = 1 then foodId end)
else sum(foodtype = 1)
MorningFoodCountOrId
case when sum(foodtype = 2) = 1
then max(case when foodtype = 2 then foodId end)
else sum(foodtype = 2)
EveningFoodCountOrId
from mytable
group by studentId
Here's your query, select sum() and case.. will do this
select t1.studentid
, case when t1.m <= 1 then t2.FoodId else concat(t1.m, ' meals') end MorningFoodCountOrId
, case when t1.e <= 1 then t3.FoodId else concat(t1.e, ' meals') end EveningFoodCountOrId
from(
select studentid
, sum(case when FoodType = 1 then 1 else 0 end) as m
, sum(case when FoodType = 2 then 1 else 0 end) as e
from tableA
group by studentid) t1
left join tableA t2 on t2.studentId = t1.studentId and t1.m = 1 and t2.FoodType = 1
left join tableA t3 on t3.studentId = t1.studentId and t1.e = 1 and t3.FoodType = 2
order by t1.studentid
see dbfiddle
in postgresql
, case when t1.m <= 1 then t2.FoodId::text else concat(t1.m, ' meals') end MorningFoodCountOrId
, case when t1.e <= 1 then t3.FoodId::text else concat(t1.e, ' meals') end EveningFoodCountOrId

group by and select max with value null

I have a next problem with query
SELECT
T.DETALLE_BECA_ANIO anio,
T.DETALLE_BECA_MES mes,
T.DETALLE_BECA_NIVEL_EDU_ID edu_id,
T.DETALLE_BECA_TRAMO_ID tr_id,
MAX(
CASE
WHEN T.DETALLE_BECA_TIPO_BENE_ID IS NULL
THEN NVL(DETALLE_BECA_VALOR,0)
ELSE 0
END) mant ,
MAX(
CASE
WHEN T.DETALLE_BECA_TIPO_BENE_ID = 1
THEN NVL(DETALLE_BECA_VALOR,0)
ELSE 0
END) tras
FROM
(SELECT DETALLE_BECA_NIVEL_EDU_ID,
DETALLE_BECA_BECA_ID,
DETALLE_BECA_TIPO_BENE_ID,
DETALLE_BECA_VALOR,
DETALLE_BECA_MES,
DETALLE_BECA_REGION_ID,
DETALLE_BECA_PROVINCIA_ID,
DETALLE_BECA_ANIO,
DETALLE_BECA_TRAMO_ID,
DETALLE_BECA_COMUNA_ID
FROM TBL_DETALLE_BECAS
WHERE (DETALLE_BECA_TIPO_BENE_ID = 1
OR DETALLE_BECA_TIPO_BENE_ID IS NULL)
and DETALLE_BECA_BECA_ID = 1
and detalle_beca_mes = 3
) T
GROUP BY T.DETALLE_BECA_BECA_ID,
T.DETALLE_BECA_TRAMO_ID,
T.DETALLE_BECA_REGION_ID,
T.DETALLE_BECA_PROVINCIA_ID,
T.DETALLE_BECA_ANIO,
T.DETALLE_BECA_MES,
T.DETALLE_BECA_NIVEL_EDU_ID,
T.DETALLE_BECA_COMUNA_ID
ORDER BY T.DETALLE_BECA_BECA_ID,
T.DETALLE_BECA_MES,
T.DETALLE_BECA_NIVEL_EDU_ID
output:
"ANIO" "MES" "EDU_ID" "TR_ID" "MANT" "TRAS"
2017 3 2 0.62 0 NULL
2017 3 3 1.24 6 NULL
2017 3 NULL 1.0 NULL 1
I need that sum value where EDU_ID is null with value 2,3 in TR_ID and replace value null in "tras" with value from EDU is null
"ANIO" "MES" "EDU_ID" "TR_ID" "MANT" "TRAS"
2017 3 2 1.62 0 1
2017 3 3 2.24 6 1
I writed query with min(edu_id) or max(edu_id ) but could not solve my problem.
The other thing that occurred to me is to make a join with the same table
First, this makes more sense as your query:
SELECT T.DETALLE_BECA_ANIO as anio, T.DETALLE_BECA_MES as mes,
T.DETALLE_BECA_NIVEL_EDU_ID as edu_id, T.DETALLE_BECA_TRAMO_ID as tr_id,
MAX(CASE WHEN T.DETALLE_BECA_TIPO_BENE_ID IS NULL
THEN NVL(DETALLE_BECA_VALOR, 0)
ELSE 0
END) as mant ,
MAX(CASE WHEN T.DETALLE_BECA_TIPO_BENE_ID = 1
THEN NVL(DETALLE_BECA_VALOR,0)
ELSE 0
END) tras
FROM TBL_DETALLE_BECAS
WHERE (DETALLE_BECA_TIPO_BENE_ID = 1 OR DETALLE_BECA_TIPO_BENE_ID IS NULL) AND
DETALLE_BECA_BECA_ID = 1 AND
detalle_beca_mes = 3
GROUP BY T.DETALLE_BECA_ANIO, T.DETALLE_BECA_MES,
T.DETALLE_BECA_NIVEL_EDU_ID, T.DETALLE_BECA_TRAMO_ID
ORDER BY T.DETALLE_BECA_BECA_ID, T.DETALLE_BECA_MES, T.DETALLE_BECA_NIVEL_EDU_ID;
This eliminates the subquery (unnecessary) and only aggregates by the columns being returned. A proper query might fix your problem.
But, you seem to want to use NULL to be "all" for the other columns. If so, something like this will work:
WITH t as (
SELECT T.DETALLE_BECA_ANIO as anio, T.DETALLE_BECA_MES as mes,
T.DETALLE_BECA_NIVEL_EDU_ID as edu_id, T.DETALLE_BECA_TRAMO_ID as tr_id,
MAX(CASE WHEN T.DETALLE_BECA_TIPO_BENE_ID IS NULL
THEN NVL(DETALLE_BECA_VALOR, 0)
ELSE 0
END) as mant ,
MAX(CASE WHEN T.DETALLE_BECA_TIPO_BENE_ID = 1
THEN NVL(DETALLE_BECA_VALOR,0)
ELSE 0
END) tras
FROM TBL_DETALLE_BECAS
WHERE (DETALLE_BECA_TIPO_BENE_ID = 1 OR DETALLE_BECA_TIPO_BENE_ID IS NULL) AND
DETALLE_BECA_BECA_ID = 1 AND
detalle_beca_mes = 3
GROUP BY T.DETALLE_BECA_ANIO, T.DETALLE_BECA_MES,
T.DETALLE_BECA_NIVEL_EDU_ID, T.DETALLE_BECA_TRAMO_ID
)
SELECT t.ANIO, t.MES, t.EDU_ID,
COALESCE(t.TR_ID, 0) + COALESCE(tnull.TR_ID, 0) as TR_ID,
t.MANT,
COALESCE(t.TRAS, 0) + COALESCE(tnull.TRAS, 0) as TRAS
FROM t LEFT JOIN
(SELECT t.*
FROM t
WHERE t.edu_id IS NULL
) tnull
ON tnull.ANIO = t.ANIO AND tnull.MES = t.MES
WHERE t.edu_id IS NOT NULL
ORDER BY T.DETALLE_BECA_BECA_ID, T.DETALLE_BECA_MES, T.DETALLE_BECA_NIVEL_EDU_ID;

Need Help on Oracle Select Query

I am finding difficulty to frame a select query.
PFB, for the table and corresponding data:
ID DLS MATCH_STATUS LAST_UPDATE_TIME BO CH FT
1 0 0 09-07-2013 00:00:00 IT TE NA
1 1 1 09-07-2013 00:01:01 IT TE NA
2 0 0 09-07-2013 10:00:00 IP TE NA
3 0 0 09-07-2013 11:00:00 IT YT NA
3 2 2 09-07-2013 11:01:00 IT YT NA
Here
Match_Status 0-->Initial Record
1-->Singel Match
2-->Multi Match
For every record there will be a initial entry with match_status 0 and subsequent matching process end other number such as 1,2 will be update.
I am trying to retrieve records such as total record , waiting match ,single match and multi match group by BO, CH and FT
Below is the expected out put:
BO CH FT TOTAL_RECORD AWAITNG_MATCH SINGLE_MATCH MULTI_MATCH
IT TE NA 1 0 1 0
IP TE NA 1 1 0 0
IT YT NA 1 0 0 2
I have tried below query :
select BO,CH,FT,sum(case when match_status=0 then 1 else 0 end) as TOTAL_RECORD,
sum(case when match_status = 0 then 1 else 0 end) as AWAITING_MATCH,
sum(case when match_status = 1 then 1 else 0 end) as SINGLE_MATCH,
sum(case when match_status = 2 then 1 else 0 end) as MULTI_MATCH from
table1 where last_update_time >= current_timestamp-1
group by BO,CH,FT;
problem with the above query is, awaiting_match is getting populated same as total record as I understand because of match_status=0
Similarly I tried with
select BO,CH,FT,sum(case when match_status=0 then 1 else 0 end) as TOTAL_RECORD,
select (sum(case when t1.ms=0 then 1 else 0 end) from
(select max(match_status) as ms from table1 where last_update_time >= current_timestamp-1 group by id)t1) )awaiting_match,
sum(case when match_status = 1 then 1 else 0 end) as SINGLE_MATCH,
sum(case when match_status = 2 then 1 else 0 end) as MULTI_MATCH from
table1 where last_update_time >= current_timestamp-1
group by BO,CH,FT;
problem with the approach is awaiting_match is getting populated with the same value for subsequent row entry.
Please help me with a suitable query for the desired format.
Thanks a lot in advance.
It seems that you want the last match status. I am guessing that this is actually the maximum of the statuses. If so, the following solves the problem by first grouping on id and then doing the grouping to summarize:
select BO, CH, FT,
count(*) as TOTAL_RECORD,
sum(case when lastms = 0 then 1 else 0 end) as AWAITING_MATCH,
sum(case when lastms = 1 then 1 else 0 end) as SINGLE_MATCH,
sum(case when lastms = 2 then 1 else 0 end) as MULTI_MATCH
from (select id, bo, ch, ft, MAX(match_status) as lastms
from table1
where last_update_time >= current_timestamp-1
group by id, bo, ch, ft
) t
group by BO, CH, FT;
If you actually want the last update to provide the status for the id, then you can use row_number() to enumerate the rows for each id, order by update time descending, and choose the first one:
select BO, CH, FT,
count(*) as TOTAL_RECORD,
sum(case when lastms = 0 then 1 else 0 end) as AWAITING_MATCH,
sum(case when lastms = 1 then 1 else 0 end) as SINGLE_MATCH,
sum(case when lastms = 2 then 1 else 0 end) as MULTI_MATCH
from (select id, bo, ch, ft, match_status,
ROW_NUMBER() over (partition by id order by last_update_time desc) as seqnum
from table1
where last_update_time >= current_timestamp-1
) t
where seqnum = 1
group by BO, CH, FT;