Let's say I have two tables. A students table and an observations table. If the students table looks like:
Id Student Grade
1 Alex 3
2 Barney 3
3 Cara 4
4 Diana 4
And the observations table looks like:
Id Student_Id Observation_Type
1 1 A
2 1 B
3 3 A
4 2 A
5 4 B
6 3 A
7 2 B
8 4 B
9 1 A
Basically, the result I'd like from the query would be the following:
Student Grade Observation_A_Count
Alex 3 2
Barney 3 1
Cara 4 2
Diana 4 0
In other words, I'd like to gather data for each student from the students table and for each student count the number of A observations from the observations table and tack that onto the other information. How do I go about doing this?
This is a simple join and aggregate:
select
a.Student,
a.Grade,
count(b.Id) as Observation_A_Count
from
Student a left join
Observations b on a.Id = b.Student_Id
group by
a.Student,
a.Grade
order by
1
Or, you can use a correlated subquery:
select
a.Student,
a.Grade,
(select count(*) from observations x where x.Student_Id = a.Id) as Observation_A_Count
from
Student a
order by
a.Student
You can join the table with a specific condition, by doing this you can have a field for Observation_B_Count and Observation_C_Count, etc.
SELECT Student.Student, Student.Grade, COUNT(Observation_Type.*) AS Observation_A_Count
FROM Student
LEFT JOIN Observations ON Observations.Student_ID = Student.Student_ID AND Observations.Observation_Type = 'A'
GROUP BY Student.Student, Student.Grade
Related
I have three tables :
field:
f_id
f_start
f_end
1
10
20
2
15
25
3
5
10
person :
p_id
p_name
1
Roger
2
John
3
Alicia
affect :
id
fk_field
fk_person
1
2
1
2
1
2
3
3
3
And I would like to select the dates and the names associated to. Like this
p_name
f_start
f_end
Roger
15
25
John
10
20
Alicia
5
10
I'm new to SQL and I don't know if i have to use JOIN or not... Thanks
You must join all 3 tables on their related columns:
SELECT p.p_name, f.f_start, f.f_end
FROM person p
INNER JOIN affect a ON a.fk_person = p.p_id
INNER JOIN field f ON f.f_id = a.fk_field;
Depending on your requirement you may need LEFT instead of INNER joins, but for this sample data the INNER joins will do.
I have a two separate tables, one with vacancies, and one with applications to those vacancies. I want to select a new table which selects from the vacancies table with a number of other columns from that table, and another column that calculates how many applications there are for those vacancies. So my vacancy table looks like this:
ID Active StartDate JobID JobTypeID HoursPerWeek
1 1 2017-02-28 2 CE 0
2 1 2017-02-15 4 CE 40
3 1 2017-02-14 1 CE 40
4 1 2017-02-28 1 CE 48
My applications table looks like this:
ID VacancyID Forename Surname EmailAddress TelephoneNumber
1 1 John Smith jsmith#gmail.com 447777777777
2 2 John Smith jsmith#gmail.com 447748772641
3 2 John Smith jsmith#gmail.com 447777777777
4 2 John Smith jsmith#gmail.com 447700123456
5 4 John Smith jsmith#gmail.com 447400123569
6 4 John Smith jsmith#gmail.com 447400126547
7 4 John Smith jsmith#gmail.com 447555123654
I want a table that looks like this:
ID Active StartDate JobID HoursPerWeek NumberOfApplicants
1 1 2017-02-28 2 0 1
2 1 2017-02-15 4 40 3
3 1 2017-02-14 1 40 0
4 1 2017-02-28 1 48 3
How can I select that table using joins and count the number of applicants where the VacancyID is equal to the ID of the first vacancy table? I have tried:
select Vacancy.ID, VacancyID, count(*) as NumberOfApplications from VacancyApplication
join Vacancy on Vacancy.ID=VacancyID
group by VacancyID, Vacancy.ID
This obviously doesn't select all the other columns and it also does not select ID 3 because there are 0 applications for that - I want ID 3 to be there with a value of 0 as well as all the other columns. How do I do this? I've tried various forms of grouping and selecting but I'm quite new to SQL so I'm not really sure how this can be done.
Use RIGHT JOIN instead of INNER JOIN and count the vacancyid column from vacancyapplication table. For the non matching records you will get count as 0
SELECT v.id, v.Active, v.StartDate, v.JobID, v.HoursPerWeek
Count(va.vacancyid) AS NumberOfApplications
FROM vacancyapplication va
RIGHT JOIN vacancy v
ON v.id = va.vacancyid
GROUP BY v.id, v.Active, v.StartDate, v.JobID, v.HoursPerWeek
Start using Alias names, it makes the query more readable
Hoping, i understood your problem correctly. Please try below query
select Vacancy.ID, VacancyID, count(*) as NumberOfApplications from VacancyApplication
left join Vacancy on Vacancy.ID=VacancyID
group by VacancyID, Vacancy.ID
You can use count as a window function using the OVER clause, thus eliminating he need for group by:
SELECT v.ID,
v.Active,
v.StartDate,
v.JobID,
v.JobTypeID,
COUNT(va.ID) OVER(PARTITION BY v.ID) HoursPerWeek
FROM Vacancy v
LEFT JOIN vacancyapplication va ON(v.ID = va.VacancyID)
Use left join and table aliases:
select v.ID, count(va.VacancyID) as NumberOfApplications
from Vacancy v join
VacancyApplication va
on v.ID = va.VacancyID
group by v.ID;
You seem to want all the columns. You could include them in the group by. However, a correlated subquery or outer apply is simpler:
select v.*, va.cnt
from vacancy v outer apply
(select count(*) as cnt
from VacancyApplication va
where v.ID = va.VacancyID
) va;
This is probably more efficient anyway, especially if you have an index on VacancyApplication(VacancyID).
I have two tables, and I only want to get the Student IDs where they have perfect attendance for all months (they do not have a PerfectAttendance value of N for any month). These tables will have hundreds of millions of rows, so I was trying to come up with an approach that doesn't require a full separate subquery. If anyone has any recommendations, please let me know:
Table Student:
ID Name
------------
1 A
2 B
Table Attendance:
ID Month PerfectAttendance
---------------------------------
1 1 Y
1 2 Y
1 3 Y
1 4 Y
1 5 Y
1 6 Y
1 7 Y
1 8 Y
1 9 Y
1 10 Y
1 11 Y
1 12 Y
2 1 Y
2 2 Y
2 3 Y
2 4 Y
2 5 Y
2 6 Y
2 7 Y
2 8 Y
2 9 Y
2 10 Y
2 11 Y
2 12 N
SELECT *
FROM dbo.Student S
WHERE NOT EXISTS(SELECT 1 FROM dbo.Attendance
WHERE PerfectAttendance = 'N'
AND ID = S.ID);
My suggestion for this would be to query the table and get the number of months that each student has perfect attendance. Once you've done that, you can filter on the count being 12 (since there are twelve months).
Try this:
SELECT s.id, s.name, COUNT(*) AS numPerfectMonths
FROM student s JOIN attendence a ON s.id = a.id
WHERE a.perfectAttendance = 'Y'
GROUP BY s.id
HAVING COUNT(*) = 12;
Here is the SQL Fiddle for you.
EDIT
I made the assumption you will have 12 rows for each student. However, let's say you ran this in October and you want to see which students have a perfect attendance up to that point. You can use a subquery to pull for students without perfect attendance, and filter them out using NOT IN like so:
SELECT id
FROM student
WHERE id
NOT IN(SELECT s.id
FROM student s JOIN attendance a ON s.id = a.id
WHERE a.perfectAttendance = 'N'
GROUP BY s.id
HAVING COUNT(*) > 0);
Have an updated SQL Fiddle. To test this one, try deleting one of the rows for id number 1, and you'll still see that they are returned with perfect attendance.
Assuming you have 12 records per student in attendance table based on your data , you can do it with GROUP BY and HAVING clause.
SELECT S.ID, S.NAME
FROM Student S
JOIN Attendance A
on S.ID = A.ID
AND A.PerfectAttendance = 'Y'
GROUP BY S.ID, S.NAME
HAVING COUNT(*) = 12
I think Lamak's answer is probably the clearest and best-performing, but here is another variation on the GROUP BY method suggested by others, when you don't specifically look for a total of 12 months:
;WITH PerfectAttendance AS (
SELECT a.id
FROM Attendance a
GROUP BY a.id
HAVING MIN(a.PerfectAttendance) = 'Y'
)
SELECT s.id, s.Name
FROM PerfectAttendance p
JOIN Student s ON p.id = s.id;
I have to fetch data from two tables
(PK) = Primary Key
(FK) = Foreign Key
TABLE1- [STUDENTS]
s_id(PK) name other
1 a z
2 b z
3 c z
TABLE2- [CLASSES]
c_id(PK) class_name
1 5th
2 6th
3 7th
TABLE3- [STUDENT-CLASS]
id(PK) student_id(FK) class_id(FK)
1 1 1
2 1 2
3 2 1
4 2 2
5 3 1
6 1 3
I want to display students with current classes(Last assigned class)
tables relations is as
when student gets admitted it is assigned class 1
after 1 year a new record is inserted in [STUDENT-CLASS] table assigning new class to each or some student
I want to display like this
s_id name other [STUDENT-CLASS].Class_id [CLASSES].class_nam
1 a z 3 7th
2 b z 2 6th
3 c z 1 5th
Try something like this
Select S.studentid, s.name, s.other, c.classid, c.classname
from
(Select studentid, Max(Classid) as 'currentclassid' from StudentClassTable group by studentid) A
inner join StudentTable S on A.studentid = S.Studentid
inner join ClassTable C on A.CurrentClassid = C.Classid
The following query will do the job.
SELECT student_id, name, other, b.last_class_id, c.class_name
FROM STUDENTS a
LEFT JOIN (SELECT student_id, max(class_id) As last_class_id
FROM student_class
GROUP BY student_id) b ON a.student_id = b.student_id
LEFT JOIN CLASSES c ON c.class_id = b.last_class_id
id address retailer
1 A 11
2 A 11
3 A 11
4 A 12
5 A 13
6 B 12
7 B 12
8 B 13
My output should be
id address retailer
1 A 11
4 A 12
5 A 13
6 B 12
8 B 13
i.e my query should return id's which have same address but not same retailer.
How toget this?
Try to use group by clause as below:
select min(id), address, retailer
from tab
group by address, retailer
Assuming you're joining on columns with no duplicates, which is by far the most common case:
An inner join of A and B gives the result of A intersect B, i.e. the inner part of a venn diagram intersection.
An outer join of A and B gives the results of A union B, i.e. the outer parts of a venn diagram union.
Examples:
Suppose you have two Tables, with a single column each, and data as follows:
A B
- -
1 3
2 4
3 5
4 6
Note that (1,2) are unique to A, (3,4) are common, and (5,6) are unique to B.
Inner join:
An inner join using either of the equivalent queries gives the intersection of the two tables, i.e. the two rows they have in common.
select *
from a
INNER JOIN b on a.a = b.b;
select a.*,b.*
from a,b
where a.a = b.b;
a | b
--+--
3 | 3
4 | 4
Left outer join:
A left outer join will give all rows in A, plus any common rows in B.
select *
from a
LEFT OUTER JOIN b on a.a = b.b;
select a.*,b.*
from a,b
where a.a = b.b(+);
a | b
--+-----
1 | null
2 | null
3 | 3
4 | 4
Full outer join:
A full outer join will give you the union of A and B, i.e. All the rows in A and all the rows in B. If something in A doesn't have a corresponding datum in B, then the B portion is null, and vice versa.
select *
from a
FULL OUTER JOIN b on a.a = b.b;
a | b
-----+-----
1 | null
2 | null
3 | 3
4 | 4
null | 6
null | 5
select min(id) as id,address, retailer
from table1
group by address, retailer
order by id
The query you need is:
SELECT min(id), address, retailer
FROM table1 AS t1
group by address, retailer
order by address
Here's the source
Use This: It's working:
SELECT * FROM `sampletable` GROUP BY address, retailer