I have field called CallingParty in My CDR table it contains data like this:
CallingParty
------------
267672668788
I want to select the first 3 number of each of those numbers like
CallingParty
------------
267
if CallingParty is of type int:
SELECT CAST(LEFT(CallingParty, 3) AS INT)
From CDR
SQL Server has a Left() function, but it works best on strings. (varchar/char in SQL)
Select left(cast(267672668788 as varchar), 3)
Use this query:
SELECT SUBSTRING(CAST(CallingParty AS VARCHAR(50)), 1, 3) FROM [CDR]
If the data length does not change then you can always divide by 10 * the digits you have
SELECT FLOOR(267672668788 / 1000000000)
=267
Try this:
SELECT Substring(callingparty, 1, Length(callingparty) - 9)
FROM cdr;
Related
I am using SSMS to pull some data from oracle via openquery and only need the first 9 digits of a number out of a column.
I have tried using "left(column1, 9)" and it returns "LEFT:invalid identifier"
SELECT *
FROM OPENQUERY(servername,'
SELECT left(sv.column2, 9) AS new_number
FROM server.servername sv
')
column2 = 0987654321
new_number = 098765432
You miss the "Select"
SELECT *
FROM OPENQUERY([SERVER\INSTANCE],' select left(sv.column, 9) AS new_number FROM BD.dbo.Table sv')
Good Code.
In Oracle, you would use substring(), so something like this:
SELECT SUBSTR(sv.column2, 1, 9) AS new_number
FROM server.servername sv
Are there any issues with this select statement ??
SELECT SUBSTR(FIELD_A,10,3) as MOVID,
MAX(LPAD((CAST(SUBSTR(FIELD_A,-3,3) as INT) + 1 ), 3, 0)) as NEXTMOVID
FROM ...
The field is a VARCHAR2.
I want to maintain 3 characters(which are numbers) and add 1 and concatenate with another varchar2
retrieve a portion of the FIELD_A
convert is to an integer
add 1
Left Pad it to 3 characters with 0
Grab the MAX
Later on I concatenate with another field
Wondering if there was a better way to do this ??
As I understand, you need following:
SELECT SUBSTR(FIELD_A,10,3) as MOVID,
to_char(to_number(SUBSTR(FIELD_A, -3, 3)) + 1), '000') as NEXTMOVID
FROM ...
I need to create a SQL Query.
This query need to select from a table where a column contains regular expression.
For example, I have those values:
TABLE test (name)
XHRTCNW
DHRTRRR
XHRTCOP
CPHCTPC
CDDHRTF
PEOFOFD
I want to select all the data who have "HRT" after 1 char (value 1, 2 and 3 - Values who looks like "-HRT---") but not those who might have "HRT" after 1 char (value 5).
So I'm not sure how to do it because a simple
SELECT *
FROM test
WHERE name LIKE "%HRT%"
will return value 1, 2, 3 and 5.
Sorry if I'm not really clear with what I want/need.
You can also change the pattern. Instead of using % which means zero-or-more anything, you can use _ which means exactly one.
SELECT * FROM test WHERE name like '_HRT%';
You can use substring.
SELECT * FROM test WHERE substring(name from 2 for 3) = 'HRT'
Are the names always 7 letters? Do:
SELECT substring (2, 4, field) from sometable
That will just select the 2-4th characters and then you can use like "%HRT"
I want to truncate a column to a max of 100 characters. How do you do this in SQL Server?
Try this:
SELECT LEFT (your_column, 100) FROM your_table
Edit:
you can also try something like this:
SELECT LEFT (your_column, LEN(your_column)-5) FROM your_table
for say if you want to trim the last 5 characters from a record.
You can also use the LEFT() function.
LEFT(col, 100)
SUBSTRING(myColumn, 1, 100)
See the docs: http://msdn.microsoft.com/en-us/library/ms187748.aspx
substring is the method:
SUBSTRING ( value_expression ,start_expression , length_expression )
from the help.
SELECT SUBSTR(COLUMN_NAME, 1, LENGTH) FROM TABLENAME where LENGTH(COLUMN_NAME) > LENGTH
Ex:
SELECT SUBSTR(DESCRIPTION,1,100) FROM STOREDETAILS where LENGTH(DESCRIPTION)>100
For those records, with length less than 100, the actual value would be shown.
Otherwise, some databases induce blank characters in the resultant records.
I want to compare and select a field from DB using Like keyword or any other technique.
My query is the following:
SELECT * FROM Test WHERE name LIKE '%xxxxxx_Ramakrishnan_zzzzz%';
but my fields only contain 'Ramakrishnan'
My Input string contain some extra character xxxxxx_Ramakrishnan_zzzzz
I want the SQL query for this. Can any one please help me?
You mean you want it the other way round? Like this?
Select * from Test where 'xxxxxx_Ramakrishnan_zzzzz' LIKE '%' + name + '%';
You can use the MySQL functions, LOCATE() precisely like,
SELECT * FROM WHERE LOCATE("Ramakrishnan",input) > 0
Are the xxxxxx and zzzzz bits always 6 and 5 characters? If so, then this is doable with a bit of string cutting.
with Test (id,name) as (
select 1, 'Ramakrishnan'
union
select 2, 'Coxy'
union
select 3, 'xxxxxx_Ramakrishnan_zzzzz'
)
Select * from Test where name like '%'+SUBSTRING('xxxxxx_Ramakrishnan_zzzzz', 8, CHARINDEX('_',SUBSTRING('xxxxxx_Ramakrishnan_zzzzz',8,100))-1)+'%'
Results in:
id name
1 Ramakrishnan
3 xxxxxx_Ramakrishnan_zzzzz
If they are variable lengths, then it will be a horrible construction of SUBSTRING,CHARINDEX, REVERSE and LEN functions.