SQl Query Results by Year - sql

Question

I have a Client table with the following columns.
Admit_date Gender Homeless Unemployed Deleted
4/2/2012 Male Yes Yes 0
1/1/2011 Female Yes Yes 0
12/2/2011 Male No No 0
5/23/2009 Female Yes Yes 0
4/3/2009 Male No No 0
7/4/2010 Male Yes Yes 0
9/2/2010 Male Yes Yes 0
I need to show the percent of each group in each year. I think this will require a pivot table:
2009 2010 2011 2012
Admitted 2 2 2 1
Male 50% 100% 50% 100%
Female 50% 0 50% 0%
Homeless 50% 100% 50% 100%
Unemployed 50% 100% 50% 100%
This query gives me the count for each year:
select year(admit_date_c) as Year_of_Admit,count((admit_date_c)) as Admitted
from clients where deleted = '0'
group by year(admit_date_c)
Year_of_Admit Admitted
2009 2
2010 2
2011 2
2012 1
I tried numerous query iterations using Case Count but can't figure out how to get a count or percentage of Gender, Homeless and Unemployement. Once I have that, I think I can pivot the table to get the display I need.

Answer 1

I think this should do it:
select year(admit_date) as year_of_admit,
sum(case when gender='Male' then 1 else 0 end)*100/count(*) as Male,
sum(case when gender='Female' then 1 else 0 end)*100/count(*) as Female,
sum(case when homeless='Yes' then 1 else 0 end)*100/count(*) as Homeless
from client
group by year(admit_date)
I don't know if you can have values other than Male/Female or Yes/No, like "unknown". In that case you'd have to decide whether, say, 10 males, 5 females, and 5 unknowns means 50% male, i.e. 50% are known to be male, or 66% males, i.e. 66% of those whose gender is known are male.