I have a user table like this
FIRSTNAME | LASTNAME | ID |
--------------------------------
James | Hay | 1 |
Other | Person | 2 |
I also have an attendance table like this
EVENTID | USERID | ATTENDANCE | STATUS |
-----------------------------------------------
1 1 True 3
2 1 False 1
3 1 False 3
1 2 False 1
2 2 True 3
3 2 True 3
Basically, when a user is invited to an event, a row is added to the attendance table which has the event ID, their user ID, false attendance, and status 0.
Status is just an indicator of their response
0 = No Response
1 = Said No
2 = Said Yes
3 = Said yes and seats confirmed
My end result I want to get from querying these two tables is quite complicated and I can't figure out what I need to do.
I want to get a result like this
NAME | % of saying YES to an RSVP | % of attending after saying yes
-------------------------------------------------------------------------------
James Hay | 66 | 50
Other Person | 66 | 100
I'm sure you can work out how I got those numbers but to explain, James Hay had the 3 (yes) status to 2/3 events invited to. So % of saying yes is 66. Out of the 2 he said yes to, he only attended 1/2 so % of attending after saying yes is 50%
Any push in the right track would be much appreciated here since I can't get my head around this.
EDIT:
Also something quite important is that I want the results to include every user in the database even if they have 0 rows in the attendance table.
select
u.firstname, u.lastname
-- said yes, as percentage
,floor(100.0
* count(case when a.status in (2,3) then 1 end)
/ count(u.id)) yes
-- attended after saying yes, as percentage
,floor(100.0
* count(case when a.status in (2,3) and attendance='true' then 1 end)
/ nullif(count(case when a.status in (2,3) then 1 end),0)) attendance
--,count(u.id) rsvp -- total invites
from users u
left join attendance a on a.userid = u.id
group by u.firstname, u.lastname
Note: For the special case where the user has never received an invite, the statistics show as 0% and NULL.
Explanation of the terms:
count(case when a.status in (2,3) then 1 end)
represents how many times they said yes, used twice
count(u.id)
how many invites (recorded in attendance) received. Special case is when they have received none, in which case the LEFT JOIN makes it 1 (not important)
count(case when a.status in (2,3) and attendance='true' then 1 end)
count of how many times they attended, AFTER having said yes
SELECT A.NAME,B.PERCENTAGE_YES_RSVP,B.PERCENTAGE_AFTER_YES
FROM
(
SELECT U.ID AS ID,U.FIRSTNAME+''+U.LASTNAME AS NAME
FROM USERS U
) A,
(
SELECT A.USERID,A.PERCENTAGE_YES_RSVP,B.PERCENTAGE_AFTER_YES
FROM
(
SELECT B.USERID,ROUND((CAST(B.COUNT_YES_RSVP AS FLOAT)/B.TOTAL_COUNT)*100,0) AS PERCENTAGE_YES_RSVP
FROM
(SELECT A.USERID,
SUM(CASE WHEN A.STATUS=3 THEN 1 END)AS COUNT_YES_RSVP,
COUNT(*) AS TOTAL_COUNT
FROM ATTENDANCE A
GROUP BY A.USERID
) B
) A,
(
SELECT C.USERID,(CAST(C.COUNT_AFTER_YES_RSVP AS FLOAT)/C.TOTAL_COUNT)*100 AS PERCENTAGE_AFTER_YES
FROM
(SELECT A.USERID,
SUM(CASE WHEN A.STATUS=3 AND A.ATTENDANCE='TRUE' THEN 1 END)AS COUNT_AFTER_YES_RSVP,
SUM(CASE WHEN A.STATUS=3 THEN 1 END) AS TOTAL_COUNT
FROM ATTENDANCE A
GROUP BY A.USERID
) C
)B
WHERE A.USERID=B.USERID
) B
WHERE A.ID = B.USERID;
Edit:
Whoops, forgot to join on users :)
select firstname, lastname,
convert(decimal (5, 2), 1. * count(case when status in (2, 3) then 1 end) / count(*) * 100) SaidYes,
convert(decimal (5, 2), 1. * count(case when status in (2, 3) and attendance = 'True' then 1 end) / count(case when status in (2, 3) then 1 end) * 100) ActuallyAttended
from attendance a
join users u on a.userid = u.id
group by firstname, lastname
Related
I have this table:
total
user
wallet
storagesummary
chain
40
user1
wallet1
2
1
30
user1
wallet1
4
1
8
user1
wallet2
1
1
2
user2
wallet3
3
1
41
user2
wallet3
4
3
And this is what I'm trying to accomplish:
Type1, Type2, n... columns are a combination of storagesummary and chain
Just for the sake of example: if storagesummary == 2 and chain == 1, then it's gonna be Type1.
I tried something like this, but I don't think it's the best approach and I dunno what to do with the user/wallet columns:
SELECT (SELECT total from MyTable where storagesummary = 2 and chain == 1) as Total Type1 Count,
(SELECT total from MyTable where storagesummary = 4 and chain == 1) as Total Type2 Count,
.......
I cant' figure out how to achieve this.
This could use a bit of conditional aggregation to pivot that.
SELECT
CONCAT(t.user, ' / ', t.wallet) AS "User Wallet Address"
, SUM(CASE
WHEN t.storagesummary = 2 AND t.chain = 1
THEN t.total
ELSE 0
END) AS "Total Type1"
, SUM(CASE
WHEN t.storagesummary = 4 AND t.chain = 3
THEN t.total
WHEN t.storagesummary = 1 AND t.chain = 1
THEN t.total
ELSE 0
END) AS "Total Type2"
, SUM(CASE
WHEN t.storagesummary IN(2,5) AND t.chain >= 2
THEN t.total
ELSE 0
END) AS "Total Type3"
FROM MyTable t
GROUP BY t.user, t.wallet
ORDER BY t.user, t.wallet
Not sure if you need SUM or MAX though.
And the logic in the CASE's will needs corrections.
But if you get the concept, then you'll understand what to change.
I think what you are missing is matching internal column names with outer select, for example:
select action_id, next_action_id from ( select action_id, lead(action_id) over (order by action_id) next_action_id from action) where action_id <> next_action_id-1;
that's for oracle db, but normal SQL can fit without next/lead thing.
I want to select total,completed and renaming data from a certain ftable in respect of certain file name, date , degree name on a condition on username if username is present counted as completed if username is not present counted as remaining
----------------------------------------
file_nm | degree_nm| date_nm | user_nm
----------------------------------------
X | D_x |02/05/2013| USER3
X | D_x |02/05/2014| NULL
Y | D_y |02/05/2012| USER1
z | D_z |02/05/2015| NULL
Y | D_y |02/05/2013| USER1
z | D_z |02/05/2012| USER2
I want file_nm ,degree_nm,date_nm wise count total file, remaining file,completed
file total for x is 2 remaining for x is 1 completed file is 1
I am getting correct value in multiple single query but I want this as whole
select filenm,degree_name,date_name,COUNT(*) as total
from sameTable
group by filenm,degree_name,date_name
select filenm,degree_name,date_name,COUNT(*) as remaining
from sameTable
group by filenm,degree_name,date_name,username
having username is null
select filenm,degree_name,date_name,COUNT(*) as completed
from sameTable
group by filenm,degree_name,date_name,username
having username is not null
o/p that I want
filenm,degree_name,date_name,total,remaining,completed
Sum of case:
select filenm,
degree_name,
date_name,
COUNT(*) as total,
sum(case when username is null then 1 else 0 end) as remaining,
sum(case when username is not null then 1 else 0 end) as complete
from sameTable
group by filenm,degree_name,date_name
select filenm
,degree_name
,date_name
,total = COUNT(*)
,remaining = COUNT(DISTINCT CASE WHEN username is null THEN username ELSE NULL END)
,completed = COUNT(DISTINCT CASE WHEN username is not null THEN username ELSE NULL END)
from sameTable
group by filenm,degree_name,date_name
Given following table A
FlightID| Roles
1 | Pilot
1 | Steward
1 | Steward
2 | Pilot
2 | Co-Pilot
How can I determine the number of stewards on each distinct flight? The output should be like this:
FlightID| Count
1 | 2
2 | 0
First I tried:
select FlightID, count(Role) from A group by FlightID
but this gives me the total number of roles per flight. Then I tried:
select FlightID, count(Role) from A where Role="Steward" group by FlightID
this is partially right since it gives me the number of stewards per flight, but it does not take into account 0 stewards. How can I also include 0 stewards into the result?
You can use conditional aggregation.
select FlightID
,sum(case when Role = 'Steward' then 1 else 0 end)
--or count(case when Role = 'Steward' then 1 end)
from A
group by FlightID
Does your table really not have a primary key on it? If it does, this is a fairly easy LEFT JOIN:
SELECT a1.FlightId, COUNT(a2.FlightId)
FROM A a1 LEFT JOIN A a2 ON a1.id = a2.id
AND a2.Roles = 'Steward'
GROUP BY a1.FlightId;
http://ideone.com/BySBSx
My table has doctor ID, visit ID (one doctor can have several visits) and visit cause, it looks like this:
doctor_uid | visit_uid | visit_cause
11-11-11 22-22-11 1
22-22-22 44-44-22 2
11-11-11 23-23-23 1
I need to count all visits for each doctor, based on visit_cause (it should be equal '1'). Before I count all visits for each doctor without condition of visit_cause, I must have this in my query too:
SELECT
v.vra_uid,
COUNT(v.visit_uid) OVER (PARTITION BY v.vra_uid) AS number_of_visits
FROM visits v
It returns:
doctor_uid | number_of_visits
11-11-11 2
22-22-22 1
How can I count those visits, that have visit_cause = '1' for each doctor? so that it would look like:
doctor_uid | number_of_visits | visits_with_cause_equal_1
11-22-33 2 2
22-22-22 1 0
Thanks in advance!
This should work:
select v.vra_uid, COUNT(v.visit_uid) as number_of_visits , SUM(case when v.visit_cause = 1 then 1 else 0 end) as visits_with_cause_equal_1
from visits v
group by v.vra_uid
have you tried CASE WHEN visit_cause = '1' THEN COUNT(*)
Imagine I have a table with data as below:
ROLE_ID | USER_ID | CODE
---------------------------------
14 | USER A | 001
15 | USER A | 002
11 | USER B | 004
13 | USER D | 005
13 | USER A | 001
15 | USER B | 009
15 | USER D | 005
12 | USER C | 004
15 | USER C | 008
13 | USER D | 007
15 | USER D | 007
I want to get the User ids and codes that only have 13 and 15 role_ids. So based on the data above I would like back the following
USER D | 005
USER D | 007
I have the query below, however, it only brings back one, not both.
SELECT a.user_id, a.code
FROM my_table a
WHERE a.ROLE_ID in (13,15,11,14)
group by a.USER_ID, a.code
having sum( case when a.role_id in (13,15) then 1 else 0 end) = 2
and sum( case when a.role_id in (11,14) then 1 else 0 end) = 0
ORDER BY USER_ID
The above query only brings
USER D | 005
rather than
USER D | 005
USER D | 007
Sometimes just listening to your own words in English translates into the easiest to read SQL:
SELECT DISTINCT a.user_id, a.code
FROM my_table a
WHERE a.user_id in
(SELECT b.user_id
FROM my_table b
WHERE b.ROLE_ID = 13)
AND a.user_id in
(SELECT b.user_id
FROM my_table b
WHERE b.ROLE_ID = 15)
AND a.user_id NOT IN
(SELECT b.user_id
FROM my_table b
WHERE b.ROLE_ID NOT IN (13,15))
I will:
SELECT a.user_id, a.code
FROM my_table a
GROUP BY a.user_id, a.code
HAVING sum(case when a.role_id in (13, 15) then 1 else 3 end) = 2
:)
As proven by EthanB, your query is working exactly as you desire. There must be something in your project data that is not represented in your question's fabricated data.
I do endorse a pivot as you have executed in your question, but I would write it as a single SUM expression to reduce the number of iterations over the aggregate data. I certainly do not endorse multiple subqueries on each row of the table (1, 2, 3) ...regardless of whether the optimizer is converting the subqueries to multiple JOINs.
Your pivot conditions:
having sum( case when a.role_id in (13,15) then 1 else 0 end) = 2
and sum( case when a.role_id in (11,14) then 1 else 0 end) = 0
My recommendation:
As the aggregate data is being iterated, you can keep a tally (+1) of qualifying rows and jump to a disqualifying outcome (+3) after each evaluation. This way, there is only one pass over the aggregate instead of two.
SELECT USER_ID, CODE
FROM my_table
WHERE ROLE_ID IN (13,15,11,14)
GROUP BY USER_ID, CODE
HAVING SUM(CASE WHEN ROLE_ID IN (13,15) THEN 1
WHEN ROLE_ID IN (11,14) THEN 3 END) = 2
Another way of expressing what these HAVING clauses are doing is:
Require that the first CASE is satisfied twice and that the second CASE is never satisfied.
Demo Link
Alternatively, the above HAVING clause could be less elegantly written as:
HAVING SUM(CASE ROLE_ID
WHEN 13 THEN 1
WHEN 15 THEN 1
WHEN 11 THEN 3
WHEN 14 THEN 3
END) = 2
Disclaimer #1: I don't swim in the [oracle] tag pool, I've not investigated how to execute this with PIVOT.
Disclaimer #2: My above advice assumes that ROLE_IDs are unique in the grouped USER_ID+CODE aggregate data. Fringe cases: (a demo)
a given group contains ROLE_ID = 13, ROLE_ID = 13, and ROLE_ID = 15 then of course the SUM will be at least 3 and the group will be disqualified.
a given group contains only ROLE_ID = 15 and ROLE_ID = 15 then of course the SUM will be 2 and the group will be unintentionally qualified.
To combat scenarios like these, make three separate MAX conditions.
HAVING MAX(CASE WHEN ROLE_ID = 13 THEN 1 END) = 1
AND MAX(CASE WHEN ROLE_ID = 15 THEN 1 END) = 1
AND MAX(CASE WHEN ROLE_ID IN (11,14) THEN 1 END) IS NULL
Demo
SELECT user_id, code FROM my_table
WHERE role_id = 13
INTERSECT
SELECT user_id, code FROM my_table
WHERE role_id = 15