how to iterate to print nos of given length in xslt? - xslt-1.0

Question

Im working on xslt 1.0
I need to print nos starting from 1 to given length.
e.g. if the given length is 5, then i need to iterate a loop that can iterate 5 times and prints nos like 1,2,3,4,5 this.
I tried using for loop but, I'm unable to decrement the value to print in each iterator.
Please any suggestion on above scenario?
Thanks inadvanvce

Answer 1

This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:call-template name="printNumbers">
<xsl:with-param name="pUpTo" select="5"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="printNumbers">
<xsl:param name="pUpTo"/>
<xsl:param name="pCurrent" select="1"/>
<xsl:if test="$pUpTo >= $pCurrent">
<xsl:value-of select="$pCurrent"/>
<xsl:text> </xsl:text>
<xsl:call-template name="printNumbers">
<xsl:with-param name="pUpTo" select="$pUpTo"/>
<xsl:with-param name="pCurrent" select="$pCurrent+1"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
when applied on any XML document (not used), produces the wanted, correct result:
1 2 3 4 5
For successfully generating huge number of items, use a DVC - style recursion as in my answer to this question:
Print numbers from one to one million
I recommend using the functions of the FXSL library in order to avoid spending too much time in writing explicit recursion and also to avoid any potential errors doing this.