How to check if a view controller can perform a segue - objective-c

Question

This might be a very simple question but didn't yield any results when searching for it so here it is...
I am trying to work out a way to check if a certain view controller can perform a segue with identifier XYZ before calling the performSegueWithIdentifier: method.
Something along the lines of:
if ([self canPerformSegueWithIdentifier:#"SegueID"])
[self performSegueWithIdentifier:#"SegueID"];
Possible?

Answer 1

To check whether the segue existed or not, I simply surrounded the call with a try-and-catch block. Please see the code example below:
#try {
[self performSegueWithIdentifier:[dictionary valueForKey:#"segue"] sender:self];
}
#catch (NSException *exception) {
NSLog(#"Segue not found: %#", exception);
}
Hope this helps.

Answer 2

- (BOOL)canPerformSegueWithIdentifier:(NSString *)identifier
{
NSArray *segueTemplates = [self valueForKey:#"storyboardSegueTemplates"];
NSArray *filteredArray = [segueTemplates filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:#"identifier = %#", identifier]];
return filteredArray.count>0;
}

Answer 3

This post has been updated for Swift 4.
Here is a more correct Swift way to check if a segue exists:
extension UIViewController {
func canPerformSegue(withIdentifier id: String) -> Bool {
guard let segues = self.value(forKey: "storyboardSegueTemplates") as? [NSObject] else { return false }
return segues.first { $0.value(forKey: "identifier") as? String == id } != nil
}
/// Performs segue with passed identifier, if self can perform it.
func performSegueIfPossible(id: String?, sender: AnyObject? = nil) {
guard let id = id, canPerformSegue(withIdentifier: id) else { return }
self.performSegue(withIdentifier: id, sender: sender)
}
}
// 1
if canPerformSegue("test") {
performSegueIfPossible(id: "test") // or with sender: , sender: ...)
}
// 2
performSegueIfPossible(id: "test") // or with sender: , sender: ...)

Answer 4

As stated in the documentation:
Apps normally do not need to trigger segues directly.
Instead, you configure an object in Interface Builder associated with
the view controller, such as a control embedded in its view hierarchy,
to trigger the segue. However, you can call this method to trigger a
segue programmatically, perhaps in response to some action that cannot
be specified in the storyboard resource file. For example, you might
call it from a custom action handler used to process shake or
accelerometer events.
The view controller that receives this message must have been loaded
from a storyboard. If the view controller does not have an associated
storyboard, perhaps because you allocated and initialized it yourself,
this method throws an exception.
That being said, when you trigger the segue, normally it's because it's assumed that the UIViewController will be able to respond to it with a specific segue's identifier. I also agree with Dan F, you should try to avoid situations where an exception could be thrown. As the reason for you not to be able to do something like this:
if ([self canPerformSegueWithIdentifier:#"SegueID"])
[self performSegueWithIdentifier:#"SegueID"];
I am guessing that:
respondsToSelector: only checks if you are able to handle that message in runtime. In this case you can, because the class UIViewController is able to respond to performSegueWithIdentifier:sender:. To actually check if a method is able to handle a message with certain parameters, I guess it would be impossible, because in order to determine if it's possible it has to actually run it and when doing that the NSInvalidArgumentException will rise.
To actually create what you suggested, it would be helpful to receive a list of segue's id that the UIViewController is associated with. From the UIViewController documentation, I wasn't able to find anything that looks like that
As for now, I am guessing your best bet it's to keep going with the #try #catch #finally.

Answer 5

You can override the -(BOOL)shouldPerformSegueWithIdentifier:sender: method and do your logic there.
- (BOOL) shouldPerformSegueWithIdentifier:(NSString *)identifier sender:(id)sender {
if ([identifier isEqualToString:#"someSegue"]) {
if (!canIPerformSegue) {
return NO;
}
}
return YES;
}
Hope this helps.

Answer 6

Reference CanPerformSegue.swift
import UIKit
extension UIViewController{
func canPerformSegue(identifier: String) -> Bool {
guard let identifiers = value(forKey: "storyboardSegueTemplates") as? [NSObject] else {
return false
}
let canPerform = identifiers.contains { (object) -> Bool in
if let id = object.value(forKey: "_identifier") as? String {
return id == identifier
}else{
return false
}
}
return canPerform
}
}

Answer 7

Swift version of Evgeny Mikhaylov's answer, which worked for me:
I reuse a controller for two views. This helps me reuse code.
if(canPerformSegueWithIdentifier("segueFoo")) {
self.performSegueWithIdentifier("segueFoo", sender: nil)
}
else {
self.performSegueWithIdentifier("segueBar", sender: nil)
}
func canPerformSegueWithIdentifier(identifier: NSString) -> Bool {
let templates:NSArray = self.valueForKey("storyboardSegueTemplates") as! NSArray
let predicate:NSPredicate = NSPredicate(format: "identifier=%#", identifier)
let filteredtemplates = templates.filteredArrayUsingPredicate(predicate)
return (filteredtemplates.count>0)
}

Answer 8

It will be useful, before call performSegue, check native storyboard property on base UIViewController (for example screen was from StoryBoard or Manual Instance)
extension UIViewController {
func performSegueWithValidate(withIdentifier identifier: String, sender: Any?) {
if storyboard != nil {
performSegue(withIdentifier: identifier, sender: sender)
}
}
}
enter image description here

Answer 9

There is no way to check that using the standard functions, what you can do is subclass UIStoryboardSegue and store the information in the source view controller (which is passed to the constructor). In interface builder select "Custom" as the segue type as type the class name of your segue, then your constructor will be called for every segue instantiated and you can query the stored data if it exists.
You must also override the perform method to call [source presentModalViewController:destination animated:YES] or [source pushViewController:destination animated:YES] depending on what transition type you want.