I am trying to recap on my sql skill, now I am trying to run a simple query on northwinddb to show me the top customer for each year, but as soon as I use the TOP function only 1 record gets display no matter on what I partition by, This is my T-SQL code
SELECT DISTINCT TOP 1 C.CompanyName
, YEAR(O.OrderDate) AS Year
, SUM(Quantity) OVER(PARTITION BY C.CompanyName, YEAR(O.OrderDate)) AS Total
FROM Customers C JOIN Orders O
ON C.CustomerID = O.CustomerID JOIN [Order Details] OD
ON O.OrderID = OD.OrderID
You can do this bit more compactly in SQL Server 2008 as follows:
select top (1) with ties
C.CompanyName,
Year(O.OrderDate) as Yr,
sum(OD.Quantity) as Total
from Orders as O
join Customers as C on C.CustomerID = O.CustomerID
join "Order Details" as OD on OD.OrderID = O.OrderID
group by C.CompanyName, Year(O.OrderDate)
order by
row_number() over (
partition by Year(O.OrderDate)
order by sum(OD.Quantity) desc
);
Thank you for the help. I found a way that allows me to change the number of top customers i want to see for each year. By using Sub queries and Row_Number
SELECT CompanyName
,yr
,Total
FROM(SELECT CompanyName
, yr
, Total
, ROW_NUMBER() OVER(PARTITION BY yr ORDER BY yr, Total DESC) AS RowNumber
FROM(SELECT DISTINCT CompanyName
, YEAR(O.OrderDate) AS yr
, SUM(OD.Quantity) OVER(PARTITION BY CompanyName
, YEAR(O.OrderDate)) As Total
FROM Customers C JOIN Orders O
ON C.CustomerID = O.CustomerID JOIN [Order Details] OD
ON O.OrderID = OD.OrderID) Tr)Tr2
Where RowNumber <= 1
Three steps: first sum quantities grouped by company and year, then order the results by quantity, then filter first row by group only.
; WITH sums as (
SELECT C.Companyname, YEAR(O.OrderDate) AS Year, sum (Quantity) Total
FROM Customers C JOIN Orders O
ON C.CustomerID = O.CustomerID JOIN [Order Details] OD
ON O.OrderID = OD.OrderID
group by C.Companyname, YEAR(O.OrderDate)
)
with ordering as (
select Companyname, Year, Total,
row_number() over (partition by CompanyName, Year order by Total desc) rownum
from sums
)
select *
from ordering
where rownum = 1
Related
I have 3 tables
Orders (orderID, CustomerID)
Orderlines (orderID, ProdID)
Products (ProdID, CategoryID)!
I want to find the customerID which has the most different "CategoryID" in one order!
To get you there, start with the basic query to get your info:
SELECT o.customer_id
,l.orderid
,COUNT(DISTINCT categoryid) category_cnt
FROM orders o
JOIN orderlines l on l.orderid = o.orderid
JOIN products p ON l.prodid = p.prodid
GROUP BY l.customner_id, l.orderid
order by COUNT(DISTINCT categoryid) desc;
Once you see that this works out, we will add an analytic to this to show you the rank() function
SELECT o.customer_id
,l.orderid
,COUNT(DISTINCT categoryid) category_cnt
, rank() over (order by COUNT(DISTINCT categoryid) desc) as count_rank
FROM orders o
JOIN orderlines l on l.orderid = o.orderid
JOIN products p ON l.prodid = p.prodid
GROUP BY l.customner_id, l.orderid
order by COUNT(DISTINCT categoryid) desc;
Following so far? OK, so now we just need to push this down into a sub-query to get the record(s) ranked #1 (in case more than one customer order matches the top count)
SELECT customer_id, order_id, category_cnt
FROM (
SELECT o.customer_id
,l.orderid
,COUNT(DISTINCT categoryid) category_cnt
, rank() over (order by COUNT(DISTINCT categoryid) desc) as count_rank
FROM orders o
JOIN orderlines l on l.orderid = o.orderid
JOIN products p ON l.prodid = p.prodid
GROUP BY l.customner_id, l.orderid)
WHERE count_rank = 1;
Try;
with data_a as ( --distinct CategoryID cnt
select
o.orderID,
o.customerID,
count(DISTINCT p.CategoryID) cnt
from Orders o
join Orderlines ol.orderID = o.orderID
join Products p on p.ProdID = ol.ProdID
group by o.orderID, o.customerID
),
data as ( --get all count rnk
select
orderID,
customerID,
rank() over (partition by orderID, customerID order by cnt desc) rnk
from data_a
)
select
orderID,
customerID
from data
where rnk = 1
Step by step: Count distinct categories per order first. Then rank your orders, so that the orders with the most categories get rank #1. Then find customers for all orders ranked #1.
select distinct cutomerid
from orders
where orderid in
(
select orderid
from
(
select orderid, rank() over (order by category_count desc) as rnk
from
(
select ol.orderid, count(distinct p.distinctcategroyid) as category_count
from orderlines ol
join products p on p.prodid = ol.prodid
group by ol.orderid
) counted
) ranked
where rnk = 1
);
Something like that i guess
SELECT o.customerID, t.category_cnt
FROM (SELECT l.orderid, COUNT(DISTINCT categoryid) category_cnt
FROM orderlines l
JOIN products p ON l.prodid = p.prodid
GROUP BY l.orderid
ORDER BY category_cnt DESC) t
JOIN orders o ON o.orderid = t.orderid
WHERE rownum < 2
I have a schema with customers, orders and order dates.
A customer can have orders in multiple dates. I need a calculated member to bring the first order date and the second order date with other associated metrics.
I was able to get the first order date and associated data using min(order date) as a first order but having issues querying for the second order date. Any suggestion would help! Thanks
my query
---I have all the information in one table so my query looks like
Select customerid, order id, min(orderdate) as firstorderdate,...
From customer Where first ordedate between 01/01/2015’ and GETDATE()
(since I only want those customers who made their first purchase this year)
Query their second purchase
Select customerid, orderid, orderdate from ( select customerid,
orderid, orderdate, rwo_number() over (partition by customerid,
orderid order by orderdate) rn from customer
Where rn<=2
Without seeing your current query, it's difficult to understand. I assume your current query is like this:
select c.customerid, o.orderid, min(od.orderdate)
from customers c
join orders o on c.customerid = o.customerid
join orderdates od on o.orderid = od.orderid
group by c.customerid, o.orderid
Another way of doing the same query is to use row_number. Doing it this way, you're not restricted to just the first in the group:
select customerid, orderid, orderdate
from (
select c.customerid, o.orderid, od.orderdate,
row_number() over (partition by c.customerid, o.orderid
order by od.orderdate) rn
from customers c
join orders o on c.customerid = o.customerid
join orderdates od on o.orderid = od.orderid
) t
where rn <= 2
I've produced a report of "Which and how many of Products been sold in each country". I'm using Northwind database, SQL Server 2012.
The following is the code:
SELECT
o.ShipCountry AS 'Country',od.ProductID,
p.ProductName, p.UnitPrice,
SUM(od.Quantity) AS 'Number of Units Sold'
FROM
Products p
INNER JOIN
[Order Details] od ON od.ProductID = p.ProductID
INNER JOIN
Orders o ON o.OrderID = od.OrderID
GROUP BY
p.ProductName, od.ProductID, p.UnitPrice, o.ShipCountry
ORDER BY
o.ShipCountry, 'Number of Units Sold' DESC
The result shows over 900 rows, each country has about 10 to 20 rows:
But I want to take it up a notch, and now I want to produce "Top 3 products sold per country"
So I tried ROW_NUMBER() OVER (PARTITION BY but I'm clumsy at using Row_NUMBER()
The below is my wrong code:
WITH CTE AS
(
SELECT
o.ShipCountry AS 'Country',od.ProductID,
p.ProductName, p.UnitPrice,
SUM(od.Quantity) AS 'Number of Units Sold',
ROW_NUMBER() OVER (PARTITION BY o.ShipCountry ORDER BY ('Number of Units Sold') DESC) AS 'Number of Units Sold'
FROM
Products p
INNER JOIN
[Order Details] od ON od.ProductID = p.ProductID
INNER JOIN
Orders o ON o.OrderID = od.OrderID)
SELECT
'Country', ProductID,
ProductName, UnitPrice, 'Number of Units Sold'
FROM
CTE
WHERE
'Number of Units Sold' < 4
GROUP BY
p.ProductName, od.ProductID, p.UnitPrice, o.ShipCountry
ORDER BY
o.ShipCountry DESC
Try this:
WITH CTE AS
(
SELECT
o.ShipCountry, od.ProductID,
p.ProductName, p.UnitPrice,
SUM(od.Quantity) AS UnitsSold,
RowNum = ROW_NUMBER() OVER (PARTITION BY o.ShipCountry ORDER BY SUM(od.Quantity) DESC)
FROM
Products p
INNER JOIN
[Order Details] od ON od.ProductID = p.ProductID
INNER JOIN
Orders o ON o.OrderID = od.OrderID
GROUP BY
p.ProductName, od.ProductID, p.UnitPrice, o.ShipCountry
)
SELECT *
FROM CTE
WHERE CTE.RowNum <= 3
Basically, in the CTE, you define the columns you want - word of caution: don't use column names with spaces and stuff like that! Makes for a nice presentation on screen, but really hard to use in a query!
Then you add the ROW_NUMBER() that will number each entry for each country starting at 1.
And finally, you select from the CTE, and you take only those rows with a RowNum <= 3 ==> the TOP 3 for each country.
;with CTE as(
SELECT o.ShipCountry AS 'Country',
od.ProductID,
p.ProductName,
p.UnitPrice,
SUM(od.Quantity) AS 'Number of Units Sold'
FROM Products p
INNER JOIN [Order Details] od
ON od.ProductID=p.ProductID
INNER JOIN Orders o
ON o.OrderID=od.OrderID
GROUP BY p.ProductName, od.ProductID, p.UnitPrice, o.ShipCountry
)
,CTE2 as
( Select
CTE.Country,
CTE.ProductID,
CTE.ProductName,
CTE.UnitPrice,
CTE.[Number of Units Sold],
ROW_NUMBER() OVER (PARTITION BY CTE.Country
ORDER BY CTE.[Number of Units Sold] DESC) AS rownum
from CTE
)
select CTE2.Country,
CTE2.ProductID,
CTE2.ProductName,
CTE2.UnitPrice,
CTE2.[Number of Units Sold]
FROM CTE2
WHERE CTE2.rownum<4
ORDER BY CTE2.Country, CTE2.[Number of Units Sold] DESC
Try this :
SELECT Country, ProductID,
ProductName,UnitPrice,Number_of_Units_Sold
FROM
(
SELECT o.ShipCountry AS Country, od.ProductID as ProductID,
p.ProductName as ProductName, p.UnitPrice as UnitPrice,
SUM(od.Quantity) AS Number_of_Units_Sold,
ROW_NUMBER() OVER (PARTITION BY o.ShipCountry ORDER BY (SUM(od.Quantity)) DESC) AS MYRANK
FROM Products p
INNER JOIN [OrderDetails] od
ON od.ProductID=p.ProductID
INNER JOIN Orders o
ON o.OrderID=od.OrderID
GROUP BY o.ShipCountry, p.ProductName, od.ProductID, p.UnitPrice, o.ShipCountry
) tmp
where MYRANK <= 3
ORDER BY Country, Number_of_Units_Sold DESC
I have two tables
Order with columns:
OrderID,OrderDate,CID,EmployeeID
And OrderItem with columns:
OrderID,ItemID,Quantity,SalePrice
I need to return the CustomerID(CID), number of orders per customer, and each customers total amount for all orders.
So far I have two separate queries. One gives me the count of customer orders....
SELECT CID, Count(Order.OrderID) AS TotalOrders
FROM [Order]
Where CID = CID
GROUP BY CID
Order BY Count(Order.OrderID) DESC;
And the other gives me the total sales. I'm having trouble combining them...
SELECT CID, Sum(OrderItem.Quantity*OrderItem.SalePrice) AS TotalDollarAmount
FROM OrderItem, [Order]
WHERE OrderItem.OrderID = [Order].OrderID
GROUP BY CID
I'm doing this in Access 2010.
You would use COUNT(DISTINCT ...) in other SQL engines:
SELECT CID,
Count(DISTINCT O.OrderID) AS TotalOrders,
Sum(OI.Quantity*OI.SalePrice) AS TotalDollarAmount
FROM [Order] O
INNER JOIN [OrderItem] OI
ON O.OrderID = OI.OrderID
GROUP BY CID
Order BY Count(DISTINCT O.OrderID) DESC
Which Access unfortunately does not support. Instead you can first get the Order dollar amounts and then join them before figuring the order counts:
SELECT CID,
COUNT(Orders.OrderID) AS TotalOrders,
SUM(OrderAmounts.DollarAmount) AS TotalDollarAmount
FROM [Orders]
INNER JOIN (SELECT OrderID, Sum(Quantity*SalePrice) AS DollarAmount
FROM OrderItems GROUP BY OrderID) AS OrderAmounts
ON Orders.OrderID = OrderAmounts.OrderID
GROUP BY CID
ORDER BY Count(Orders.OrderID) DESC
If you need to include Customers that have orders with no items (unusual but possible), change INNER JOIN to LEFT OUTER JOIN.
Create a query which uses your 2 existing queries as subqueriers, and join the 2 subqueries on CID. Define your ORDER BY in the parent query instead of in a subquery.
SELECT
sub1.CID,
sub1.TotalOrders,
sub2.TotalDollarAmount
FROM
(
SELECT
CID,
Count(Order.OrderID) AS TotalOrders
FROM [Order]
GROUP BY CID
) AS sub1
INNER JOIN
(
SELECT
CID,
Sum(OrderItem.Quantity*OrderItem.SalePrice)
AS TotalDollarAmount
FROM OrderItem INNER JOIN [Order]
ON OrderItem.OrderID = [Order].OrderID
GROUP BY CID
) AS sub2
ON sub1.CID = sub2.CID
ORDER BY sub1.TotalOrders DESC;
The ORDER BY clause below is causing an error. How can I reference the TotalPrice column in ORDER BY clause:
SELECT * FROM
(
SELECT O.OrderID,
(SELECT SUM(SubTotal) FROM DB_OrderDetails OD WHERE OD.OrderID = O.OrderID) AS TotalPrice,
ROW_NUMBER() OVER (ORDER BY TotalPrice) AS RowNum
FROM DB_Orders O
) Orders
You cannot reference it by its name in the same sub-query, you nave to do it in the outer query:
SELECT orders.*,
ROW_NUMBER() OVER (ORDER BY TotalPrice) AS RowNum FROM
(
SELECT O.OrderID,
(SELECT SUM(SubTotal) FROM DB_OrderDetails OD
WHERE OD.OrderID = O.OrderID) AS TotalPrice
FROM DB_Orders O
) Orders
How about this:
select
o.orderID,
sum(od.SubTotal) as TotalPrice,
row_number() over (order by sum(od.SubTotal)) as RowNum
from DB_Orders o
join DB_OrderDetails od
on o.OrderID = od.OrderID
group by o.OrderID
Here is the example: SQL Fiddle