Extract numbers from a text in SQL Server - sql

Question

i was searching script to extract number from text in sql server and i found this
CREATE FUNCTION [dbo].[GetNumbersFromText](#String VARCHAR(2000))
RETURNS #Number TABLE (Number INT)
AS
BEGIN
DECLARE #Count INT
DECLARE #IntNumbers VARCHAR(1000)
SET #Count = 0
SET #IntNumbers = ''
WHILE #Count <= LEN(#String)
BEGIN
--Find a numeric charactor
IF SUBSTRING(#String,#Count,1) >= '0' AND SUBSTRING(#String,#Count,1) <= '9'
BEGIN
SET #IntNumbers = #IntNumbers + SUBSTRING(#String,#Count,1)
END
--If the next charactor is not a numeric one, the current number ends, so add a separator
IF (SUBSTRING(#String,#Count+1,1) < '0'OR SUBSTRING(#String,#Count+1,1) > '9') AND SUBSTRING(#String,#Count,1) >= '0' AND SUBSTRING(#String,#Count,1) <= '9'
BEGIN
SET #IntNumbers = #IntNumbers + ','
END
SET #Count = #Count + 1
END
---Split string to give a table with the numbers in the text
INSERT INTO #Number
SELECT DISTINCT items FROM dbo.Split(#IntNumbers, ',')
return
END
and call it like
SELECT Number FROM Dbo.[GetNumbersFromText]('Give me 120 this week and 50 next week')
it works fine but i need more short code. can i use patindex to extract number from text.
please anyone share small & good logic to do so. thanks

Answer 1

This is a bit shorter. Turned it into Inline Table Function that uses a recursive CTE to find the numbers.
create function [dbo].[GetNumbersFromText](#String varchar(2000))
returns table as return
(
with C as
(
select cast(substring(S.Value, S1.Pos, S2.L) as int) as Number,
stuff(s.Value, 1, S1.Pos + S2.L, '') as Value
from (select #String+' ') as S(Value)
cross apply (select patindex('%[0-9]%', S.Value)) as S1(Pos)
cross apply (select patindex('%[^0-9]%', stuff(S.Value, 1, S1.Pos, ''))) as S2(L)
union all
select cast(substring(S.Value, S1.Pos, S2.L) as int),
stuff(S.Value, 1, S1.Pos + S2.L, '')
from C as S
cross apply (select patindex('%[0-9]%', S.Value)) as S1(Pos)
cross apply (select patindex('%[^0-9]%', stuff(S.Value, 1, S1.Pos, ''))) as S2(L)
where patindex('%[0-9]%', S.Value) > 0
)
select Number
from C
)
If you expect to have more than 100 numbers in the string you need to call it with option (maxrecursion 0).
declare #S varchar(max)
set #S = 'Give me 120 this week and 50 next week'
select number from GetNumbersFromText(#S) option (maxrecursion 0)

Answer 2

#Vikram's basic idea is not bad, but their query would return all the numbers as a single item. The following function returns a table containing separate numbers as found in the source string:
CREATE FUNCTION dbo.GetNumbersFromText (#String varchar(2000))
RETURNS TABLE
AS
RETURN (
WITH NumbersSplit AS (
SELECT
C = SUBSTRING(#String, number, 1),
i = number,
g = number - ROW_NUMBER() OVER (ORDER BY number)
FROM master..spt_values
WHERE type = 'P'
AND SUBSTRING(#String, number, 1) BETWEEN '0' AND '9'
),
NumbersAssembled AS (
SELECT
number = CAST(
(SELECT C + '' FROM NumbersSplit WHERE g = g.g ORDER BY i FOR XML PATH (''))
AS varchar(2000)
)
FROM NumbersSplit g
GROUP BY g
)
SELECT * FROM NumbersAssembled
)
Note: this solution would work in SQL Server 2005 or later.

Answer 3

try the following logic:
declare #thestring varchar(50)
set #thestring = 'Give me 120 this week and 50 next week'
declare #final varchar(50)
set #final = ''
select #final = #final + x.thenum
from
(
select substring(#thestring, number, 1) as thenum, number
from master..spt_values
where substring(#thestring, number, 1) like '[0-9]' and type='P'
) x
order by x.number
print #final

Answer 4

-- Try This Code...
-- Its OK!!!
CREATE FUNCTION [dbo].[udf_ExtractNumberFromString]
(
#pInputString VARCHAR(MAX)
)
RETURNS VARCHAR(MAX)
AS
BEGIN
DECLARE #OutputString varchar(MAX)=''
DECLARE #string varchar(MAX)
DECLARE #start INT
DECLARE #end INT
DECLARE #len INT
SET #string=#pInputString
--SET #string = 'the22478ddffafghrty12345TestAddressdd5aa789324-#345'
SET #string = replace(#string, ' ' , '')
WHILE PATINDEX('%[0-9]%',#string) <> 0
BEGIN
SET #len = len(#string)
-- PRINT #len
set #start = PATINDEX('%[0-9]%',#string)
-- PRINT #start
SET #end= PATINDEX('%[^0-9]%',SUBSTRING(#string,#start,#len-#start))
-- PRINT #end
IF #end=0
BEGIN
SET #end=#len-#start
SET #OutputString=SUBSTRING(#string,#start,#end+1)+'-'+#OutputString
BREAK
END
ELSE
BEGIN
SET #OutputString=SUBSTRING(#string,#start,#end-1)+'-'+#OutputString
SET #string=SUBSTRING(#string,#end+#start-1,#len-#end)
END
--PRINT #string
--PRINT #Output
--PRINT '---------------------'
END
IF LEN(#OutputString)>0
SET #OutputString=LEFT(#OutputString,LEN(#OutputString)-1)
--PRINT #OutputString
RETURN #OutputString
END

Answer 5

Here is an appropriate and working solution for this query
http://www.ittutorials.in/source/sql/sql-function-to-extract-only-numbers-from-string.aspx