I have a table like this:
TransId. LayerNo. AccountId.
100. 1. 2.
100. 2. 3.
120. 1. 5.
120. 2. 6.
120. 3. 12.
70. 1. 2.
I want to find transId(s) where:
(LayerNo = 1 and (accountId = 2 or 5))
and
(LayerNo = 2 and (accountId = 3 or 6))
And result set would be row no 1,2,3,4.
How could I write query to get the result?
My database is SQL server 2008 r2
Thanks in advance
Nima
SELECT TransId
FROM your_table
WHERE ( layerno = 1
AND accountid IN ( 2, 5 ) )
INTERSECT
SELECT TransId
FROM your_table
WHERE ( layerno = 2
AND accountid IN ( 3, 6 ) )
One approach is to ensure that each transID must have two records that satisfy the conditions you outlined.
SELECT * FROM
TABLE
WHERE TransID IN(
SELECT TransId
FROM table
WHERE ( layerno = 1
AND accountid IN ( 2, 5 ) )
OR ( layerno = 2
AND accountid IN( 3, 6 ) )
GROUP BY
TransId
HAVING Count(*) = 2
)
However this could be a problem if you can have multple records where layerno = 1. So you can use self joins instead to ensure the criteria.
SELECT DISTINCT a.transid
FROM table a
INNER JOIN table b
ON a.transid = b.transid
INNER JOIN table c
ON a.transid = c.transid
WHERE b.layerno = 1
AND accountid IN ( 2, 5 )
AND c.layerno = 2
AND accountid IN ( 3, 6 )
That said Martin's INTERSECT approach is probably the best
Do you mean:
SELECT
TransId,
LayerNo,
AccountId
FROM Table
WHERE (LayerNo = 1 AND AccountId IN (2, 5)) OR
(LayerNo = 2 AND AccountId IN (3, 7))
create table #temp
( rowId Int Identity(1,1), transId int)
INSERT INTO #temp(transId)
select TransId
from TableName
where (layerNo = 1 and accountID IN (2, 5))
OR (layerNo = 2 and accountId IN (3, 6))
select * from #temp
SELECT
base.TransId,
base.LayerNo,
base.AccountId
FROM TableX AS base
JOIN TableX AS a
ON a.TransId = base.TransId
AND a.LayerNo = 1 AND a.AccountId IN (2, 5)
JOIN TableX AS b
ON b.TransId = base.TransId
AND b.LayerNo = 2 AND b.AccountId IN (3, 7)
WHERE (base.LayerNo = 1 AND base.AccountId IN (2, 5))
OR (base.LayerNo = 2 AND base.AccountId IN (3, 7))
This intersection is empty. If you take the values where LayerNo = 1 and LayerNo = 2 and intersect them their intersection is empty because these events are mutually exclusive. I believe this error comes from how the question was originally stated. I might be wrong but the predicate should have been
(LayerNo = 1 and (accountId = 2 or 5)) OR (LayerNo = 2 and (accountId = 3 or 6))
Replace the AND with an OR. If the predicate was stated correctly then the intersect is correct but will always be empty.
SELECT *
FROM table
WHERE (LayerNo = 1 AND (AccountID = 2 OR AccountID = 5))
OR (LayerNo = 2 AND (AccountID = 3 OR AccountID = 6))
Related
Let's say I am returning the following table from a select
CaseId
DocId
DocumentTypeId
DocumentType
ExpirationDate
1
1
1
I797
01/02/23
1
2
2
I94
01/02/23
1
3
3
Some Other Value
01/02/23
I want to select ONLY the row with DocumentType = 'I797', then if there is no 'I797', I want to select ONLY the row where DocumentType = 'I94'; failing to find either of those two I want to take all rows with any other value of DocumentType.
Using SQL Server ideally.
I think I'm looking for an XOR clause but can't work out how to do that in SQL Server or to get all other values.
Similar to #siggemannen answer
select top 1 with ties
case when DocumentType='I797' then 1
when DocumentType='I94' then 2
else 3
end gr
,docs.*
from docs
order by
case when DocumentType='I797' then 1
when DocumentType='I94' then 2
else 3
end
Shortest:
select top 1 with ties
docs.*
from docs
order by
case when DocumentType='I797' then 1
when DocumentType='I94' then 2
else 3
end
Something like this perhaps:
select *
from (
select t.*, DENSE_RANK() OVER(ORDER BY CASE WHEN DocumentType = 'I797' THEN 0 WHEN DocumentType = 'I94' THEN 1 ELSE 2 END) AS prioorder
from
(
VALUES
(1, 1, 1, N'I797', N'01/02/23')
, (1, 2, 2, N'I94', N'01/02/23')
, (1, 3, 3, N'Some Other Value', N'01/02/23')
, (1, 4, 3, N'Super Sekret', N'01/02/23')
) t (CaseId,DocId,DocumentTypeId,DocumentType,ExpirationDate)
) x
WHERE x.prioorder = 1
The idea is to rank rows by 1, 2, 3 depending on document type. Since we rank "the rest" the same, you will get all rows if I797 and I94 is missing.
select * from YourTable where DocumentType = 'I797'
union
select * from YourTable t where DocumentType = 'I94' and (not exists (select * from YourTable where DocumentType = 'I797'))
union
select * from YourTable t where (not exists (select * from YourTable where DocumentType = 'I797' or DocumentType = 'I94' ))
I have this table with over 1,000,000 rows, and I am trying to return ONLY the records with the same [name] and have both NY = 1 and KS = 1, even though those will be in separate rows. For this example:
I want the query to return both records for James, because they both have NY = 1 and KS = 1, but if NY != 1 or KS != 1 for james, then I don't want the query to return it
There's probably a more efficient way, but you could give this a shot.
SELECT *
FROM
your_table AS a
WHERE
EXISTS(
SELECT TRUE
FROM your_table AS x
WHERE
a.number = x.number
AND x.KS = 1
)
AND EXISTS(
SELECT TRUE
FROM your_table AS x
WHERE
a.number = x.number
AND x.NY = 1
)
If you only want rows where one of these values is set:
SELECT t.*
FROM t
WHERE (x.NY = 1 AND
EXISTS (SELECT 1
FROM t t2
WHERE t2.number = t.number AND x.KS = 1
)
) AND
(x.KS = 1 AND
EXISTS (SELECT 1
FROM t t2
WHERE t2.number = t.number AND x.NY= 1
)
);
However, window functions might be a good bet:
select t.*
from (select t.*,
sum(ny) over (partition by number) as num_ny,
sum(ks) over (partition by number) as num_ks
from t
) t
where num_ny > 0 and num_ks > 0;
declare #table1 as table
(
sname varchar(50),
permno int,
symbol int,
groupdate date
)
insert into #table1(sname,permno,symbol,groupdate)
values
('ashan',1,0,'2019-01-01'),
('re',2,1,'2019-01-01'),
('saman',1,0,'2019-01-01'),
('ashan',0,1,'2019-01-01'),
('saman',1,1,'2019-01-01')
select * from #table1 a
inner join
(select x.sname from
(
select sname,count(sname)as xs
from #table1 group by sname
having count(sname)>1
)x)b on
a.sname=b.sname
where permno=1 and symbol=1
I have a table called recipes with following data.
page_no title
-----------------
1 pancake
2 pizza
3 pasta
5 cookie
page_no 0 is always blank, and missing page_no are blank, I want output as below, for the blank page NULL values in the result.
left_title right_title
------------------------
NULL pancake
Pizza pasta
NULL cookie
I have tried this SQL statement, but it's not returning the desired output:
SELECT
CASE WHEN id % 2 = 0
THEN title
END AS left_title,
CASE WHEN id %2 != 0
THEN title
END AS right_title
FROM
recipes
You are quite close. You just need aggregation:
select max(case when id % 2 = 0 then title end) as left_title,
max(case when id % 2 = 1 then title end) as right_title
from recipes
group by id / 2
order by min(id);
SQL Server does integer division, so id / 2 is always an integer.
Using CTE.. this should be give you a good CTE overview
DECLARE #table TABLE (
pageno int,
title varchar(30)
)
INSERT INTO #table
VALUES (1, 'pancake')
, (2, 'pizza')
, (3, 'pasta')
, (5, 'cookie')
;
WITH cte_pages
AS ( -- generate page numbers
SELECT
0 n,
MAX(pageno) maxpgno
FROM #table
UNION ALL
SELECT
n + 1 n,
maxpgno
FROM cte_pages
WHERE n <= maxpgno),
cte_left
AS ( --- even
SELECT
n,
ROW_NUMBER() OVER (ORDER BY n) rn
FROM cte_pages
WHERE n % 2 = 0),
cte_right
AS ( --- odd
SELECT
n,
ROW_NUMBER() OVER (ORDER BY n) rn
FROM cte_pages
WHERE n % 2 <> 0)
SELECT
tl.title left_title,
tr.title right_title --- final output
FROM cte_left l
INNER JOIN cte_right r
ON l.rn = r.rn
LEFT OUTER JOIN #table tl
ON tl.pageno = l.n
LEFT OUTER JOIN #table tr
ON tr.pageno = r.n
I need to write a stored procedure or table function to return a new data table as a new data source.
I wish to loop through the original table for every 5 rows base on the invoice ID column (it's possible not start from 1), the first 5 rows add to the left of the new table and the second 5 rows add to the right of the new table, the third 5 rows to the left and so on.
For example, Here is the original table:
Here is the expect table:
Thanks in advance!
declare #rowCount int = 5;
with cte as (
select *,( (IN_InvoiceID-1) / #rowCount ) % 2 group1
,( (IN_InvoiceID-1) / #rowCount ) group2
,IN_InvoiceID % #rowCount group3
from T
)
select * from cte
select T1.INID,T1.IN_InvoiceID,T1.IN_InvoiceAmount,T2.INID,T2.IN_InvoiceID,T2.IN_InvoiceAmount
from CTE T1
left join CTE T2 on T2.group1 = 1 and T1.group2 = T2.group2-1 and T1.group3 = T2.group3
where T1.group1 = 0
Test DDL
CREATE TABLE T
([INID] varchar(38), [IN_InvoiceID] int, [IN_InvoiceAmount] int)
;
INSERT INTO T
([INID], [IN_InvoiceID], [IN_InvoiceAmount])
VALUES
('DB3E17E6-35C5-41:121-93B1-F809BF6B2972', 1, 2999),
('3212F048-8213-4FCC-AB64-121485B77D4E43', 2, 3737),
('E3526373-A204-40F5-801C-7F8302A4E5E2', 3, 3175),
('76CC9C19-BF79-4E8A-8034-A33805AD3390', 4, 391),
('EC7A2FBC-B62D-4865-88DE-A8097975F125', 5, 1206),
('52AD3046-21331-4F0A-BD1D-67F232C54244', 6, 402),
('CA48F132-A9F5-4516-9E58-CDEE6644AAD1', 7, 1996),
('02E10C31-CAB2-4220-B66A-CEE5E67A9378', 8, 3906),
('98F1EEFF-B07A-4B65-87F4-E165264284DD', 9, 2575),
('91EBDD8B-B73C-470C-8900-DD66078483DB', 10, 2965),
('6E2490E5-C4DE-4833-877F-1590F7BDC1B8', 11, 1603),
('00985921-AC3C-4E3E-BAE1-7F58302F831A', 12, 1302)
;
Result:
Could you please check article Display Data in Multiple Columns using SQL showing with example case how a database developer can show the list of data rows in a columnar mode using Row_Number() function and mode arithmetic expression
You need to add additional columns from the same row that is different in the sample
Seems as if you want to split the table into 2 tables with alternating 5 rows. An easy way to do this would be:
Take data into a temp table having an extra column (lets say
grouping_id)
Update the grouping id so that each 5 rows have the same id. You can
use in_invoiceId % 5 (the nod function). After this step the first 5
rows will have grouping_id 0, next 5 will have 1, next will have 2
(assuming your invoice id is incremented +1 for all rows).
You can just do a normal select with where clause for odd and even grouping_id
Ideally, you can manage with the 2 tables Master and detail table.
But due to my curiosity, I am able to solve and give the answer as
Declare #table table(id int identity, invoice_id int)
; WITH Numbers AS
(
SELECT n = 1
UNION ALL
SELECT n + 1
FROM Numbers
WHERE n+1 <= 50
)
insert into #table SELECT n
FROM Numbers
Select (a.id )%5 ,* from #table a join #table b on a.id+5 = b.id and a.id != b.id
;WITH Numbers AS
(
SELECT n = 1, o = 5
UNION ALL
SELECT n + 10, o = o+10
FROM Numbers
WHERE n+1 <= 50
)
select a.id ParentId,a.invoice_id ParentInvoiceId, --b.n, b.o,
c.invoice_id childInvoiceID from #table a
join Numbers b on a.id between b.n and b.o
left join #table c on a.id + 5 = c.id
Here is my solution
First i create grps based on whether the in_invoiceid is divisible by 5 or not.(Ignore the remainders)
After that i create a category to indicate between alternative groups(ie by checking if the remainder is 0 or otherise)
Then its a matter of dense_ranking the records on the basis of the category field ordered by in_invoiceid
Lastly a join with category=1 rows with same dense_rank as those records in category=0
create table Invoicetable(IN_ID varchar(100), IN_InvoiceID int)
INSERT INTO Invoicetable (IN_ID, IN_InvoiceID)
VALUES
('2345-BCDE-6645-1DDF', 1),
('2345-BCDE-6645-3DDF', 2),
('2345-BCDE-6645-4DDF', 3),
('2345-BCDE-6645-5DDF', 4),
('2345-BCDE-6645-6DDF', 5),
('2345-BCDE-6645-7DDF', 6),
('2345-BCDE-6645-aDDF', 7),
('2345-BCDE-6645-sDDF', 8),
('2345-BCDE-6645-dDDF', 9),
('2345-BCDE-6645-dDDF', 10),
('2345-BCDE-6645-dDDF', 11),
('2345-BCDE-6645-dDDF', 12);
with data
as (
select *
,(in_invoiceid-1)/5 as grp
,case when ((in_invoiceid-1)/5)%2=0 then '1' else '0' end as category
,dense_rank() over(partition by case when ((in_invoiceid-1)/5)%2=0 then '1' else '0' end
order by in_invoiceid) as rnk
from invoicetable a
)
select *
from data a
left join data b
on a.rnk=b.rnk
and b.category=0
where a.category=1
Here is db fiddle link.
https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=287f101737c580ca271940764b2536ae
You may try with the following approach. Dividing the table is done with (((ROW_NUMBER() OVER (ORDER BY IN_InvoiceID) - 1) / 5) % 2 = 0) which groups records in left and right groups.
CREATE TABLE #InvoiceTable(
IN_ID varchar(24),
IN_InvoiceID int
)
INSERT INTO #InvoiceTable (IN_ID, IN_InvoiceID)
VALUES
('2345-BCDE-6645-1DDF', 1),
('2345-BCDE-6645-3DDF', 2),
('2345-BCDE-6645-4DDF', 3),
('2345-BCDE-6645-5DDF', 4),
('2345-BCDE-6645-6DDF', 5),
('2345-BCDE-6645-7DDF', 6),
('2345-BCDE-6645-aDDF', 7),
('2345-BCDE-6645-sDDF', 8),
('2345-BCDE-6645-dDDF', 9),
('2345-BCDE-6645-dDDF', 10),
('2345-BCDE-6645-dDDF', 11),
('2345-BCDE-6645-dDDF', 12);
WITH cte AS (
SELECT
IN_ID,
IN_InvoiceID,
CASE
WHEN (((ROW_NUMBER() OVER (ORDER BY IN_InvoiceID) - 1) / 5) % 2 = 0) THEN 'L'
ELSE 'R'
END AS IN_Position
FROM #InvoiceTable
),
cteL AS (
SELECT IN_ID, IN_InvoiceID, ROW_NUMBER() OVER (ORDER BY IN_InvoiceID) AS IN_RowNumber
FROM cte
WHERE IN_Position = 'L'
),
cteR AS (
SELECT IN_ID, IN_InvoiceID, ROW_NUMBER() OVER (ORDER BY IN_InvoiceID) AS IN_RowNumber
FROM cte
WHERE IN_Position = 'R'
)
SELECT cteL.IN_ID, cteL.IN_InvoiceID, cteR.IN_ID, cteR.IN_InvoiceID
FROM cteL
LEFT JOIN cteR ON (cteL.IN_RowNumber = cteR.IN_RowNumber)
Output:
IN_ID IN_InvoiceID IN_ID IN_InvoiceID
2345-BCDE-6645-1DDF 1 2345-BCDE-6645-7DDF 6
2345-BCDE-6645-3DDF 2 2345-BCDE-6645-aDDF 7
2345-BCDE-6645-4DDF 3 2345-BCDE-6645-sDDF 8
2345-BCDE-6645-5DDF 4 2345-BCDE-6645-dDDF 9
2345-BCDE-6645-6DDF 5 2345-BCDE-6645-dDDF 10
2345-BCDE-6645-dDDF 11 NULL NULL
2345-BCDE-6645-dDDF 12 NULL NULL
i have following table "vehicle_data" :
ID ALERT_TYPE VALUE
58 2 1
58 1 1
104 1 1
104 2 1
Here alert_type = 2 is for GPS value and alert_type=1 is for engine_value .
so if alert_type=2 and its value is =1 then it means its value is correct.
when alert_type=2 and its value is =0 then it means its value is wrong.
same for alert_type=1
so now here i want the following output:
ID gps engine_value
58 1 1
104 1 1
how can i perform this query??
You can do it like this.
SELECT ID
,CASE WHEN [ALERT_TYPE]=2 and [value ]=1 THEN 1 ELSE 0 END as gps
,CASE WHEN [ALERT_TYPE]=1 and [value ]=1 THEN 1 ELSE 0 END as engine
FROM vehicle_data
SELECT ID, alert_type=2 AS gps, alert_type=1 AS [engine] FROM vehicle_data WHERE value=1;
EDITED to account for your explanation of VALUE.
Schema
CREATE TABLE table3 (id int, ALERT_TYPE int)
INSERT table3 VALUES (58, 1), (58, 2), (104, 1), (104, 2)
Query
SELECT *
FROM (
SELECT ID
,ROW_NUMBER() OVER (
PARTITION BY id ORDER BY id
) AS row_num
,gps = CASE
WHEN ALERT_TYPE = 2
THEN 1
ELSE 0
END
,engine = CASE
WHEN ALERT_TYPE = 1
THEN 1
ELSE 0
END
FROM table3
) a
WHERE a.row_num = 1
Output
ID gps engine
58 1 0
104 0 1
One possible way using subqueries :
select
Ids.ID
, gps.VALUE 'gps'
, engine_value.VALUE 'engine_value'
from (select distinct ID from vehicle_data) Ids
left join
(select ID, VALUE from vehicle_data where ALERT_TYPE = 2) gps
on gps.ID = Ids.ID
left join
(select ID, VALUE from vehicle_data where ALERT_TYPE = 1) engine_value
on engine_value.ID = Ids.ID
[SQL Fiddle demo]
I hope this should work for you,
Select ID,sum(gps) as gps ,sum(engine) as engine from
(SELECT ID
,CASE WHEN [ALERT_TYPE]=2 and [value ]=1 THEN 1 ELSE 0 END as gps
,CASE WHEN [ALERT_TYPE]=1 and [value ]=1 THEN 1 ELSE 0 END as engine
FROM vehicle_data
)a
group by id
select x.id,x.alert_type as GPS,x.value as engine_value from (
select ID,alert_type,value,ROW_NUMBER() over (partition by id order by alert_type ) as Rnk from mytable
)x
where Rnk=1
Please check this query in SQL :
create table mytable (id int, alert_type int, value int);
insert into mytable (id, alert_type, value)
values (58, 2, 1),
(58, 1, 1),
(104, 1, 1),
(104, 2, 1);
SELECT distinct ID
,(select count (id) from mytable mt where mt.id=mytable.id and mt.[ALERT_TYPE]=2 and mt.[value ]=1) as gps
,(select count (id) from mytable mt where mt.id=mytable.id and mt.[ALERT_TYPE]=1 and mt.[value ]=1) as engine
FROM mytable
BASED ON YOUR QUESTION I BELIEVE YOU WANT THE DATA IN COLUMN AND TO SUIT YOUR REQUIREMENT I HAVE MADE A SQL FIDDLE WORKING - CODE IS ALSO MENTIONED BELOW -
HERE YOU GO WITH THE WORKING FIDDLE -
WORKING DEMO
SQL CODE FOR REFERNECE -
CREATE TABLE ALERTS (ID INT, ALERT_TYPE INT, VALUE INT)
INSERT INTO ALERTS VALUES (58,2,1)
INSERT INTO ALERTS VALUES (58,1,0)
INSERT INTO ALERTS VALUES (104,1,1)
INSERT INTO ALERTS VALUES (104,2,0)
CREATE TABLE ALERTSVALUE (ID INT, gps INT,engine INT)
INSERT INTO ALERTSVALUE VALUES (58,1,0)
INSERT INTO ALERTSVALUE VALUES (104,0,1)
SELECT A.ID,
CASE A.ALERT_TYPE WHEN 2 THEN 1 ELSE 0 END AS GPS,
CASE A.ALERT_TYPE WHEN 1 THEN 1 ELSE 0 END AS ENGINE_VALUE,
A.VALUE FROM ALERTS A WHERE A.VALUE = 1
EDIT BASED ON COMMENT - TO MERGE THE ROWS FOR BOTH GPS AND ENGINE_VALUE:
SELECT X.ID,X.ALERT_TYPE as GPS,X.VALUE as ENGINE_VALUE
FROM (
SELECT ID,ALERT_TYPE ,VALUE ,ROW_NUMBER() OVER (PARTITION BY ID ORDER BY alert_type ) AS [Rank] FROM ALERTS
)X
WHERE [Rank]=1
SQL FIDDLE DEMO