Get values between ranges - sql

Question

The more I think of it the more I am confused, could be because it is quite a while that i wrote some complex sql.
I have a table that has a range for a value. Lets call it a range:
RANGE
RANGE_ID RANGE_SEQ MIN MAX FACTOR
1 1 0 10 1
1 2 11 100 1.5
1 3 101 2.5
2 1 0 18 1
2 2 19 2
And I have anothe table that uses these ranges. Lets call it application
APPLICATION
APP_ID RAW_VALUE RANGE_ID FINAL_VALUE
1 20.0 1 30.0 /*In Range 1, 20 falls between 11 and 100, so 1.5 is applied)*/
2 25.0 2 50.0
3 18.5 2 18.5
I want to get those RAW_VALUES that fall between the ranges. So for range 2, I want those APP_IDs that have a RAW_VALUE between 18 and 19. Similarly for range 1, I want those APP_IDs that have a RAW_VALUE between 10 and 11 and 100 and 101.
I want to know whether this is possible with SQL, and some pointers on what I can try. I don't need the sql itself, just some pointers to the approach.

Answer 1

Try this to get you close
select app_id,raw_value,aa.range_id,raw_value * xx.factor as FinaL_Value
from Application_table aa
join range_table xx on (aa.raw_value between xx.min and xx.max)
and (aa.range_id=xx.range_id)
To get non-matches (i.e. raw_values that do not exist in the table), try this
select app_id,raw_value,aa.range_id
from Application_table aa
left join range_table xx on (aa.raw_value between xx.min and xx.max)
and (aa.range_id=xx.range_id)
where xx.range_id is null

Answer 2

create table tq84_range (
range_id number not null,
range_seq number not null,
min_ number not null,
max_ number,
factor number not null,
--
primary key (range_id, range_seq)
);
insert into tq84_range values (1, 1, 0, 10, 1.0);
insert into tq84_range values (1, 2, 10, 100, 1.5);
insert into tq84_range values (1, 3,101,null, 2.5);
insert into tq84_range values (2, 1, 0, 18, 1.0);
insert into tq84_range values (2, 2, 19,null, 2.0);
create table tq84_application (
app_id number not null,
raw_value number not null,
range_id number not null,
primary key (app_id)
);
insert into tq84_application values (1, 20.0, 1);
insert into tq84_application values (2, 25.0, 2);
insert into tq84_application values (3, 18.5, 2);
You want to use a left join.
With such a left join, you ensure that each record of the left
table (the table appearing prior to left join in the
select statement text) will be returned at least once,
even though the where condition doesn't find a record
in the right table.
If tq84_range.range is null then you know that the join
condition didn't find a record in tq84_range, therefore, there
seems to be a gap. So you print Missing:.
Since tq84_application.max_ can be null and null appears to
indicate infinity or upper bound you test the upper limit
with nvl(tq84_range.max_, tq84_application.raw_value
Thus, the select statement will become something like:
select
case when tq84_range.range_id is null then 'Missing: '
else ' '
end,
tq84_application.raw_value
from
tq84_application left join
tq84_range
on
tq84_application.range_id = tq84_range.range_id
and
tq84_application.raw_value between
tq84_range.min_ and nvl(tq84_range.max_, tq84_application.raw_value);

Answer 3

From what I understand you're saying you only want results from the application table that don't fit in any range? This, for example, would return only the row for app_id = 3 (my own column names and guess at real minimum and maximum amounts):
select *
from APP1 A
where not exists
(select null
from RANGE1 R
where R.RANGE_ID = A.RANGE_ID and A.RAW_VALUE between nvl(R.MINNUM, 0) and nvl(R.MAXNUM, 999999));
But, of course, it won't return a factor amount as it matches no rows in the range table so why would the result for app_id = 3 in your example above match up with factor = 1? If your raw_value column is going to be decimal then I would expect the ranges to be decimal too.