Consider the following dataset:
id dataid data
1 3095 5
1 3096 9
1 3097 8
2 3095 4
2 3096 9
2 3097 15
Now, in this, the column someid identifies to certain data, so if I see 3095, I know what data the data column represents (name, address, etc.). I need to do a check so that for the group of ids (i.e. 1 and 2) dataid=3095 then data=5 AND dataid=3096 then data=9, and if this is true, the id group will be selected and operations will be done on it.
Edit: Now I use the following SQL query to do the above:
SELECT *
FROM table s0
JOIN table s1 USING (dataid)
JOIN table s2 USING (dataid)
WHERE s1.dataid=359 AND s1.data=5
AND s2.dataid=360 AND s2.data=6;
But how can I get the output from rows to columns. The property values I need are still as key:pair values in rows and I would like them as columns.
So the output for the above would be:
id 3095 3096 3097
1 5 9 8
whereas currently it is returning from the above query:
id dataid data dataid_1 data_1 dataid_2 data_2
1 3095 5 Unnecessary stuff because of JOIN
1 3096 9
1 3097 8
Thanks and sorry if this is confusing.
SELECT id
FROM (SELECT DISTINCT id
FROM table) as ids
WHERE EXISTS (SELECT '1'
FROM table t2
WHERE t2.id = ids.id AND dataid = 3095 AND data = 5)
AND EXISTS (SELECT '1'
FROM table t2
WHERE t2.id = ids.id AND dataid = 3096 AND data = 9)
Also, if you're querying additional tables besides the given one (one with id as a unique key, preferrably), consider including that, to remove the need to use DISTINCT
Related
I have the task to find out if all columns in a SQL Server table have exact the same value. The table content is created by a stored procedure and can vary in the number of columns. The first column is an ID, the second and the following columns must be compared if the all columns have exact the same value.
At the moment I do not have a clue how to achieve this.
The best solution would be to display only the rows, which have different values in one or multiple columns except the first column with ID.
Thank you so much for your help!!
--> Edit: The table looks this:
ID Instance1 Instance2 Instance3 Instance4 Instance5
=====================================================
A 1 1 1 1 1
B 1 1 0 1 1
C 55 55 55 55 55
D Driver Driver Driver Co-driver Driver
E 90 0 90 0 50
F On On On On On
The result should look like this, only the rows with one or multiple different column values should be display.
ID Instance1 Instance2 Instance3 Instance4 Instance5
=====================================================
B 1 1 0 1 1
D Driver Driver Driver Co-driver Driver
E 90 0 90 0 50
My table has more than 1000 rows and 40 columns
you can achieve this by using row_number()
Try the following code
With c as(
Select id
,field_1
,field_2
,field_3
,field_n
,row_number() over(partition by field_1,field_2,field_3,field_n order by id asc) as rn
From Table
)
Select *
From c
Where rn = 1
row_number with partition is going to show you if the field is repeated by assigning a number to a row based on field_1,field_2,field_3,field_n, for example if you have 2 rows with same field values the inner query is going to show you
rn field_1 field_2 field_3 field_n id
1 x y z a 5
2 x y z a 9
After that on the outer part of the query pick rn = 1 and you are going to obtain a query without repetitions based on fields.
Also if you want to delete repeated numbers from your table you can apply
With c as(
Select id
,field_1
,field_2
,field_3
,field_n
,row_number() over(partition by field_1,field_2,field_3,field_n order by id asc) as rn
From Table
)
delete
From c
Where rn > 1
The best solution would be to display only the rows, which have different values in one or multiple columns except the first column with ID.
You may be looking for a the following simple query, whose WHERE clause filters out rows where all fields have the same value (I assumed 5 fields - id not included).
SELECT *
FROM mytable t
WHERE NOT (
field1 = field2
AND field1 = field3
AND field1 = field4
AND field1 = field5
);
How can I transform this table from this
id name
1 sam
2 nick
3 ali
4 farah
5 josef
6 fadi
to
id1 name1 id2 name2 id3 name3 id4 name4
1 sam 2 nick 3 ali 4 farah
5 josef 6 fadi
the reason i need this is i have a database and i need to do a mail merge using word and I want to print every 4 rows on one page, MS word can only print one row per page, so using an SQL query I want one row to represent 4 rows
thanks in advance
Ali
You don't need to create a query for this in Access. Word has a merge field called <<Next Record>> which forces moving to the next record. If you look at how label documents are created using the Mail Merge Wizard, you'll see that's how it's done.
Updated - Doing this in SQL
The columns in simple SELECT statements are derived from the columns from the underlying table/query (or from expressions). If you want to define columns based on the data, you need to use a crosstab query.
First create a query with a running count for each person (say your table is called People), and calculate the row and column position from the running count:
SELECT People.id, Count(*)-1 AS RunningCount, int(RunningCount/4) AS RowNumber, RunningCount Mod 4 AS ColumnNumber
FROM People
LEFT JOIN People AS People_1 ON People.id >= People_1.id
GROUP BY People.id;
(You won't be able to view this in the Query Designer, because the JOIN isn't comparing with = but with >=.)
This query returns the following results:
id Rank RowNumber ColumnNumber
1 0 0 0
2 1 0 1
3 2 0 2
4 3 0 3
5 4 1 0
6 5 1 1
Assuming this query is saved as Positions, the following query will return the results:
TRANSFORM First(Item) AS FirstOfItem
SELECT RowNumber
FROM (
SELECT ID AS Item, RowNumber, "id" &( ColumnNumber + 1) AS ColumnHeading
FROM Positions
UNION ALL SELECT Name, RowNumber, "name" & (ColumnNumber +1)
FROM Positions
INNER JOIN People ON Positions.id = People.id
) AS AllValues
GROUP BY AllValues.RowNumber
PIVOT AllValues.ColumnHeading In ("id1","name1","id2","name2","id3","name3","id4","name4");
The UNION is there so each record in the People table will have two columns - one with the id, and one with the name.
The PIVOT clause forces the columns to the specified order, and not in alphabetical order (e.g. id1, id2 ... name1, name2...)
I have found similar solutions online but none that I've been able to apply to my specific problem.
I'm trying to "unique-ify" data from one table to another. In my original table, data looks like the following:
USERIDP1 USERIDP2 QUALIFIER DATA
1 2 TRUE AB
1 2 CD
1 3 EF
1 3 GH
The user IDs are composed of two parts, USERIDP1 and USERIDP2 concatenated. I want to transfer all the rows that correspond to a user who has QUALIFIER=TRUE in ANY row they own, but ignore users who do not have a TRUE QUALIFIER in any of their rows.
To clarify, all of User 12's rows would be transferred, but not User 13's. The output would then look like:
USERIDP1 USERIDP2 QUALIFIER DATA
1 2 TRUE AB
1 2 CD
So basically, I need to find rows with distinct user ID components (involving two unique fields) that also possess a row with QUALIFIER=TRUE and copy all and only all of those users' rows.
Although this nested query will be very slow for large tables, this could do it.
SELECT DISTINCT X.USERIDP1, X.USERIDP2, X.QUALIFIER, X.DATA
FROM YOUR_TABLE_NAME AS X
WHERE EXISTS (SELECT 1 FROM YOUR_TABLE_NAME AS Y WHERE Y.USERIDP1 = X.USERIDP1
AND Y.USERIDP2 = X.USERIDP2 AND Y.QUALIFIER = TRUE)
It could be written as an inner join with itself too:
SELECT DISTINCT X.USERIDP1, X.USERIDP2, X.QUALIFIER, X.DATA
FROM YOUR_TABLE_NAME AS X
INNER JOIN YOUR_TABLE_NAME AS Y ON Y.USERIDP1 = X.USERIDP1
AND Y.USERIDP2 = X.USERIDP2 AND Y.QUALIFIER = TRUE
For a large table, create a new auxiliary table containing only USERIDP1 and USERIDP2 columns for rows that have QUALIFIER = TRUE and then join this table with your original table using inner join similar to the second option above. Remember to create appropriate indexes.
This should do the trick - if the id fields are stored as integers then you will need to convert / cast into Varchars
SELECT 1 as id1,2 as id2,'TRUE' as qualifier,'AB' as data into #sampled
UNION ALL SELECT 1,2,NULL,'CD'
UNION ALL SELECT 1,3,NULL,'EF'
UNION ALL SELECT 1,3,NULL,'GH'
;WITH data as
(
SELECT
id1
,id2
,qualifier
,data
,SUM(CASE WHEN qualifier = 'TRUE' THEN 1 ELSE 0 END)
OVER (PARTITION BY id1 + '' + id2) as num_qualifier
from #sampled
)
SELECT
id1
,id2
,qualifier
,data
from data
where num_qualifier > 0
Select *
from yourTable
INNER JOIN (Select UserIDP1, UserIDP2 FROM yourTable WHERE Qualifier=TRUE) B
ON yourTable.UserIDP1 = B.UserIDP1 and YourTable.UserIDP2 = B.UserIDP2
How about a subquery as a where clause?
SELECT *
FROM theTable t1
WHERE CAST(t1.useridp1 AS VARCHAR) + CAST(t1.useridp2 AS VARCHAR) IN
(SELECT CAST(t2.useridp1 AS VARCHAR) + CAST(t.useridp2 AS VARCHAR)
FROM theTable t2
WHERE t2.qualified
);
This is a solution in mysql, but I believe it should transfer to sql server pretty easily. Use a subquery to pick out groups of (id1, id2) combinations with at least one True 'qualifier' row; then join that to the original table on (id1, id2).
mysql> SELECT u1.*
FROM users u1
JOIN (SELECT id1,id2
FROM users
WHERE qualifier
GROUP BY id1, id2) u2
USING(id1, id2);
+------+------+-----------+------+
| id1 | id2 | qualifier | data |
+------+------+-----------+------+
| 1 | 2 | 1 | aa |
| 1 | 2 | 0 | bb |
+------+------+-----------+------+
2 rows in set (0.00 sec)
Let's say I have this table:
|Fld | Number|
1 5
2 2
And I want to make a select that retrieves as many Fld as the Number field has:
|Fld |
1
1
1
1
1
2
2
How can I achieve this? I was thinking about making a temporary table and instert data based on the Number, but I was wondering if this could be done with a single Select statement.
PS: I'm new to SQL
You can join with a numbers table:
SELECT Fld
FROM yourtable
JOIN Numbers
ON yourtable.Number <= Numbers.Number
A numbers table is just a table with a list of numbers:
Number
1
2
3
etc...
Not an great solution (since you still query your table twice, but maybe you can work from it)
SELECT t1.fld, t1.number
FROM table t1, (
SELECT ROWNUM number FROM dual
CONNECT BY LEVEL <= (SELECT MAX(number) FROM t1)) t2
WHERE t2.number<=t1.number
It generates maximum amount of rows needed and then filters it by each row.
I don't know if your RDBMS version supports it (although I rather suspect it does), but here is a recursive version:
WITH remaining (fld, times) as (SELECT fld, 1
FROM <table>
UNION ALL
SELECT a.fld, a.times + 1
FROM remaining as a
JOIN <table> as b
ON b.fld = a.fld
AND b.number > a.times)
SELECT fld
FROM remaining
ORDER BY fld
Given your source data table, it outputs this (count included for verification):
fld times
=============
1 1
1 2
1 3
1 4
1 5
2 1
2 2
I have result of two queries like:
Result of query 1
ID Value
1 4
2 0
3 6
4 9
Result of query 2
ID Value
1 6
2 4
3 0
4 1
I want to add values column "Value" and show final result:
Result of Both queries
ID Value
1 10
2 4
3 6
4 10
plz guide me...
select id, sum(value) as value
from (
select id, value from query1
uninon all
select id, value from query2
) x
group by id
Try using a JOIN:
SELECT
T1.ID,
T1.Value + T2.Value AS Value
FROM (...query1...) AS T1
JOIN (...query2...) AS T2
ON T1.Id = T2.Id
You may also need to consider what should happen if there is an Id present in one result but not in the other. The current query will omit it from the results. You may want to investigate OUTER JOIN as an alternative.
A not particularly nice but fairly easy to comprehend way would be:
SELECT ID,SUM(Value) FROM
(
(SELECT IDColumn AS ID,ValueColumn AS Value FROM TableA) t1
OUTER JOIN
(SELECT IDColumn AS ID,ValueColumn AS Value FROM TableB) t2
) a GROUP BY a.ID
It has the benefits of
a) I don't know your actual table structure so you should be able to work out how to get the two 'SELECT's working from your original queries
b) If ID doesn't appear in either table, that's fine