I have a project which has some post build events that do some copying around for other projects. I unfortunately cannot change that, and have been asked to write a build script for use on a CI server.
Problem is that the post build steps run off the debug/release bin folders and I compile through the build script to a different folder. So one solution would be to let the project build as is, and then manually copy all files from the bin folders to the output folder I am using. However that feels like a bit of a hack, so I was wondering if there is a way for an MSBuild task to tell the solution it is building to ignore PostBuild events, I believe you could set a property PostBuildEvent='' but it didnt seem to stop them from happening...
Here is an example of the build script target:
<Target Name="Compile" DependsOnTargets="Clean;">
<MSBuild Projects="$(SourceDirectory)\SomeSolution.sln"
Properties="Configuration=Release; OutputPath=$(CompilationDirectory); PostBuildEvent=''" />
</Target>
Anyone had to do anything similar before?
To disable all PostBuildEvents, set the CustomAfterMicrosoftCommonTargets to C:\PostBuild.config (or whatever you name the file) and have PostBuild.config to be:
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<Target Name="PostBuildEvent"/>
</Project>
Add /p:CustomAfterMicrosoftCommonTargets="C:\PostBuild.config" to your msbuild command line
Or update your MsBuild task properties:
<MsBuild Projects="$(ProjectTobuild)" Properties="Configuration=$(Configuration);Platform=$(Platform);CustomAfterMicrosoftCommonTargets='C:\PostBuild.config'" Targets="Build"/>
To disable PostBuildEvents at project level for MSBuild, simply put these codes inside .csproj:
<Target Name="BeforeBuild">
<PropertyGroup>
<PostBuildEvent Condition="'$(BuildingInsideVisualStudio)' == 'false' Or '$(BuildingInsideVisualStudio)' != 'true'"></PostBuildEvent>
</PropertyGroup>
</Target>
Related
I'm currently writing an msbuild script to build a solution I've been working on, as well as run its tests. On my development machine, this works as expected. However, when I try to run the same build script on our build server, I get several failures. I've tracked the source of the problem down to the fact that my build script appears to be trying to run the .exe file associated with my application. This line during the script execution tipped me off, since it doesn't run that command on my dev box:
MSIAuthoring:
Building MSI
"C:\Program Files (x86)\Jenkins\workspace\Test Build\BuildArtifacts\MsiBuildTool.exe" "/MBSBUILD:MsiBuildTool"
I'm fairly new to build scripting, but my understanding is that the build script shouldn't be trying to run my program unless I explicitly tell it to do so. Does anyone know what might be causing this?
For reference, here is my build script:
<?xml version="1.0" encoding="utf-8"?>
<Project DefaultTargets="RunTests"
xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<ItemGroup>
<BuildArtifactsDir Include="BuildArtifacts\"/>
<SolutionFile Include="MsiBuildTool.sln"/>
<NUnitConsole Include="C:\Program Files (x86)\NUnit 2.6.4\bin\nunit-console.exe"/>
<UnitTestsDll Include="BuildArtifacts\MsiBuildToolUnitTests.dll"/>
<TestResultsPath Include="BuildArtifacts\TestResults.xml"/>
</ItemGroup>
<PropertyGroup>
<Configuration Condition="'$(Configuration)' == ''">Release</Configuration>
<Platform Condition="'$(Platform)' == ''">Any CPU</Platform>
</PropertyGroup>
<Target Name="Init" DependsOnTargets="Clean">
<MakeDir Directories="#(BuildArtifactsDir)"/>
</Target>
<Target Name="Clean">
<RemoveDir Directories="#(BuildArtifactsDir)"/>
</Target>
<Target Name ="Compile" DependsOnTargets="Init">
<MSBuild Projects="#(SolutionFile)"
Targets ="Build"
Properties ="OutDir=%(BuildArtifactsDir.FullPath);Configuration=$(Configuration);Platform=$(Platform)"/>
</Target>
<Target Name="RunTests" DependsOnTargets="Compile">
<Exec Command='"#(NUnitConsole)" #(UnitTestsDll) /xml=#(TestResultsPath)'/>
</Target>
</Project>
Update:
After some digging through the output, I found that "MSIAuthoring" step was the result of the Wix# library that I'm using. As described by this thread: https://wixsharp.codeplex.com/discussions/644609#
I disabled the MSIAuthoring step by removing this line in my .csproj files:
<Import Project="..\packages\WixSharp.1.0.22.3\build\WixSharp.targets" Condition="Exists('..\packages\WixSharp.1.0.22.3\build\WixSharp.targets')" />
You're building solution file, thus MSBuild will generate msbuild-xml script first and then will build it. To find why it's being called on build machine but not on your dev machine - follow this advice and obtain generated MSBuild scripts from your dev environment and your build server. Then compare it.
Also enable diagnostic logging (/verbosity:diag in the command line) as Lex Li advised, and you'll see detailed decisions why each target being run or not - grep logs for something like "Conditions A, B, C on target BuildMSI evaluated to False" and this will show you the difference between environments.
It might be some type of post-build script on one of the projects which builds MSI only if it's being run not on dev environment - check actual build script to find where it comes from. Also check that it's really related to your build script, and it's not an extra build step in your Jenkins build configuration.
I am executing MSBuild from a batch file. The MSBuild script is in a different directory than the directory I want MSBuild to consider the working directory when running the script. When invoking MSBuild.exe, how do I change its working directory?
Edit: More details
Let's say I have an MSBuild script located on some other server. I want to run a command thusly:
msbuild.exe \\my_server\c$\My\Path\To\Scripts\TestScript.msbuild
I run that command with my command prompt at c:\temp. Let's say my TestScript.msbuild has a task to create a file. The file has no path just a filename. I would expect that the file gets created inside c:\temp. But it doesn't it gets created next to the msbuild file that is sitting on the server. This is the behavior I want to change.
Edit #2
Here is the script I'm using in my test:
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<ItemGroup>
<Files Include="HelloWorld.txt" />
</ItemGroup>
<Target Name="TouchFiles">
<Touch Files="#(Files)" AlwaysCreate="True" />
</Target>
</Project>
I am going into a command shell CDing into c:\temp and then executing the script. With or without the /p:OutDir switch that #Nick Nieslanik mentions, the HelloWorld.txt file appears in the folder where the *.msbuild file is and not c:\temp.
I ran across this while looking for a solution to my problem. Here's my solution (build script):
<?xml version="1.0" encoding="utf-8"?>
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<Target Name="Default">
<Exec Command="build.bat" WorkingDirectory="..\[your dir]\" />
</Target>
</Project>
I believe that's more what you were originally looking for?
My problem was that my batch file called another that it expected to be in the same directory, but since my ms build script was being run elsewhere, the batch file failed to find the second batch file.
#jkohlhepp - I see now. You are doing the opposite of what I described in my comment to some degree.
MSBuild common targets use the MSBuildProjectDirectory to determine the output folder unless you override that. So in your case, you could run
msbuild.exe \\my_server\c$\My\Pat\To\Scripts\TestScript.msbuild /p:OutDir=c:\temp
to force the output to be dropped in that location.
EDIT:
Given the project file above, you'd need to edit it to do something like the following for this to work:
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<OutDir Condition=" '$(OutDir)' == '' ">bin\debug\</OutDir>
</PropertyGroup>
<ItemGroup>
<!-- Without prefacing files with paths, they are assumed relative to the proj file -->
<FilesToCreate Include="$(OutDir)HelloWorld.txt" />
</ItemGroup>
<Target Name="TouchFiles">
<Touch Files="#(FilesToCreate)" AlwaysCreate="True" />
</Target>
</Project>
In current versions of MSBuild the well-known property MSBuildStartupDirectory can be used in the msbuild file to retrieve the absolute path of the folder where MSBuild is called.
https://learn.microsoft.com/en-us/visualstudio/msbuild/msbuild-reserved-and-well-known-properties?view=vs-2019
This option perhaps did not exist in msbuild around the time when the question was asked. I didn't want to spend too much time investigating it.
I'm trying to make a batch file to publish the few ClickOnce application we have in one click. I'm using msbuild for that, and as an example the below command line shows how I'm doing it:
msbuild
MyApp.sln
/t:Publish
/p:Configuration=Release
/p:PublishUrl="C:\Apps\"
/v:normal > Log.txt
(wrapped for easier reading)
when I run the above command it builds and publish the application in the release directory, i.e. bin\release! Any idea why msbuild doesn't respect PublishUrl property in my example above?
PS: I tried also different combinations including remove 'Configuration', use 'Rebuild' and 'PublishOnly' as targets, and remove the the quotation marks but without any success.
You are setting the wrong property. Try PublishDir instead.
You can pass it into MSBuild as you are or you can set it in the project file (or maybe the sln file too, not sure I always use the project file.) like this
<PropertyGroup>
<PublishDir>C:\Dev\Release\$(BuildEnvironment)\</PublishDir>
</PropertyGroup>
I've just done a few blog posts on MsBuild and ClickOnce stuff, check it out you 'should' find them useful...
Some features are done by Visual-Studio and not by the MSBuild-script. So the click-once-deployment behaves differently when it's executed from the command-line.
The ApplicationRevision isn't increased with every build. This works only when is exectued from Visual Studio
In in somecases, the PublishUrl isn't used. Quote from MSDN:
For example, you could set the PublishURL to an FTP path and set the InstallURL to a Web URL. In this case, the PublishURL is only used in the IDE to transfer the files, but not used in the command-line builds. Finally, you can use UpdateUrl if you want to publish a ClickOnce application that updates itself from a separate location from which it is installed.
I've created a special MSBuild-file which does this things. It runs the publish-target and copies then the files to the right location.
An example of the build-file, as requested by alhambraeidos. It basically runs the regular VisualStudio-build and then copies the click-once data to the real release folder. Note that removed some project-specific stuff, so it's maybe broken. Furthermore it doesn't increase the build-number. Thats done by our Continues-Build-Server:
<?xml version="1.0" encoding="utf-8"?>
<Project ToolsVersion="4.0" DefaultTargets="Publish" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<!-- the folder of the project to build -->
<ProjLocation>..\YourProjectFolder</ProjLocation>
<ProjLocationReleaseDir>$(ProjLocation)\bin\Release</ProjLocationReleaseDir>
<ProjPublishLocation>$(ProjLocationReleaseDir)\app.publish</ProjPublishLocation>
<!-- This is the web-folder, which provides the artefacts for click-once. After this
build the project is actually deployed on the server -->
<DeploymentFolder>D:\server\releases\</DeploymentFolder>
</PropertyGroup>
<Target Name="Publish" DependsOnTargets="Clean">
<Message Text="Publish-Build started for build no $(ApplicationRevision)" />
<MSBuild Projects="$(ProjLocation)/YourProject.csproj" Properties="Configuration=Release" Targets="Publish"/>
<ItemGroup>
<SchoolPlannerSetupFiles Include="$(ProjPublishLocation)\*.*"/>
<SchoolPlannerUpdateFiles Include="$(ProjPublishLocation)\Application Files\**\*.*"/>
</ItemGroup>
<Copy
SourceFiles="#(SchoolPlannerSetupFiles)"
DestinationFolder="$(DeploymentFolder)\"
/>
<Copy
SourceFiles="#(SchoolPlannerUpdateFiles)"
DestinationFolder="$(DeploymentFolder)\Application Files\%(RecursiveDir)"
/>
<CallTarget Targets="RestoreLog"/>
</Target>
<Target Name="Clean">
<Message Text="Clean project:" />
<MSBuild Projects="$(ProjLocation)/YourProject.csproj" Properties="Configuration=Release" Targets="Clean"/>
</Target>
</Project>
I'll put in my 2 cents, this syntax seems to work (right or wrong):
/p:publishUrl="C:\\_\\Projects\\Samples\\artifacts\\Web\\"
For me, the soultion was to escape the path.
Instead of:
/p:PublishUrl="C:\Apps\"
Put:
/p:PublishUrl="C:\\Apps\\"
Some of my .csproj project files have special target "AssembleJS" that merges all .js files included in project in one big file (i.e. webcontrols.csproj has target "AssembleJS" with output "webcontrols.js").
So if I have project parts.csproj
That has target AssembleJS.
References project webcontrols.csproj.
References utility project utils.csproj that does not have any JavaScript and does not have AssembleJS target.
I want target AssembleJS of parts.csproj execute AssembleJS in webcontrols.csproj (the same was as MSBuild works with standard Build target).
Something like
<MSBuild Project="#ReferencedProjects" Targets="AssembleJS"/>
does not work because utils.csproj does not have target AssembleJS.
Is there any way to filter #ReferencedProjects based on whether project has certain target?
Any other idea on how to handle this scenario?
You cannot do what you are requiring. But you might be able to acheive it with batching.
<Project xmlns=''>
<ItemGroup>
<ReferencedProjects Include="webcontrols.csproj">
<Type>Web</Type>
</ReferencedProjects>
<ReferencedProjects Include="utils.csproj">
<Type>NonWeb</Type>
</ReferencedProjects>
</ItemGroup>
<Target Name="BuildWebProjects">
<MSBuild Projects="#(ReferencedProjects)" Condition=" '%(ReferencedProjects.Type)' == 'Web' " />
</Target>
</Project>
Do a search for MSBuild Batching and find some results on sedodream.com for more
info.
Should I expand on this?
Here's what I'm trying to do:
A single build script
That script builds two executables from the same Visual Studio project.
The first compiled .exe has a small amount of code disabled.
The other compiled .exe has everything enabled.
I've been reading up on conditional compilation and that takes care of my needs as far as enabling/disabling blocks of code.
I just can't figure out how to control conditional compilation from a build script using msbuild.
Is there a way to manipulate conditional compilation variables from a build script or some other way to accomplish what I'm trying to do?
Use build configurations in your project file. Set the parameters in a PropertyGroup that is optionally included based on the configuration. The configuration can then also define the output path for the two different versions of the assembly.
For the version that needs to remove some code use a configuration that includes the PropertyGroup.
<PropertyGroup Condition=" '$(Configuration)|$(Platform)' == 'CompiledOutDebug|AnyCPU' ">
<DefineConstants>$(DefineConstants);MY_CONDITIONAL_COMPILATION_CONSTANT</DefineConstants>
</PropertyGroup>
Then use an MSBuild script that calls the project MSBuild script twice and uses the Properties attribute of the MSBuild task to specify the configuration to build:
<Target Name="Build">
<MSBuild Projects="MyProject.csproj;"
Targets="Build"
Properties="Configuration=Release" />
<MSBuild Projects="MyProject.csproj"
Targets="Build"
Properties="Configuration=CompiledOutDebug" />
</Target>
Hamish beat me to it.
Here's an alternate solution using the same concepts:
At the command line:
msbuild -t:Clean
msbuild
CopyOutputDirForWithoutDefine.cmd
msbuild -t:Clean
msbuild -property:DefineConstants=MY_CONDITIONAL_COMPILE_CONSTANT
CopyOutputDirForWithDefine.cmd
The 1st and 3rd 'msbuild -t:Clean' ensures that you don't have left over turds from previous builds. The 2nd 'msbuild' builds without the conditional define, while the 4rth builds with the conditional define.
If the above are just a couple on shot items, then a batch file maybe enough. I recommend learning a bit of MSBuild and actually scripting everything in a MSBuild file as Hamish has done.
If you don't want to create a separate target for the two compilations, you can do it by specifying the conditional define in the DefineConstants property when you call the build the second time:
<Target Name="Build">
<MSBuild Projects="MyProject.csproj;"
Targets="Build"
Properties="Configuration=Debug" />
<MSBuild Projects="MyProject.csproj"
Targets="Build"
Properties="Configuration=Debug;
AssemblyName=$(AssemblyName)_Conditional;
DefineConstants=$(DefineConstants);CONDITIONAL_DEFINE" />
</Target>
Note that if you do it this way, you need to also overwrite the AssemblyName, otherwise your second build might pick intermediate files from the first build.
You should also look at the MSBuild task docs on MSDN, there are some interesting tidbits there.